Kit Library / Science / Physical Chemistry / Spectroscopy

⚡ Topic Learning Kit

Electronic Spectra

English 18 leveled MCQs 20 flashcards 9 games Free

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💡 Key Idea

Electrons Jump, Light Tells the Story

Electron jumps create the colors we see.

Electronic spectra arise when electrons transition between energy levels, absorbing or emitting photons of specific wavelengths — usually in the UV-visible region.

↳ The energy gap between electronic levels determines the wavelength of light absorbed or emitted.

📖 Definition

Key Terms in Electronic Spectroscopy

Master these terms before diving deeper.

↳ These terms form the vocabulary for describing and interpreting electronic spectra.

➗ Formula

Beer-Lambert Law: Quantifying Absorption

Absorbance links concentration to light.

This law is the foundation of quantitative UV-visible spectroscopy.

↳ Absorbance is directly proportional to concentration and path length.

⚙️ Process

How an Electronic Spectrum is Recorded

From light source to spectrum in four steps.

↳ A spectrophotometer automates these steps to produce an absorption spectrum.

⚖️ Comparison

Atomic vs Molecular Electronic Spectra

Lines or bands? The difference matters.

↳ Molecular spectra are more complex because electronic transitions couple with vibrational and rotational motions.

✏️ Example

Why Leaves Look Green

Chlorophyll absorbs red and blue.

↳ Electronic absorption in the visible region explains the colors of many natural and synthetic substances.

⚠️ Common Mistake

Don't Confuse Absorption with Emission

Absorption and emission are not the same.

↳ Absorption goes up in energy; emission comes down with a red shift.

⭐ Important Fact

UV-Vis Region Spans 200–800 nm

Most electronic transitions live here.

Electronic transitions of interest typically occur in the ultraviolet (200–400 nm) and visible (400–800 nm) regions, corresponding to energy gaps of about 150–600 kJ/mol.

↳ UV-visible spectroscopy probes electronic transitions in this energy window.

🛠️ Application

Real-World Uses of Electronic Spectra

From drug testing to DNA analysis.

↳ Electronic spectroscopy is a workhorse technique in analytical, biochemical, and industrial labs.

🎯 Exam Tip

Exam Tip: Relate Energy, Wavelength, and Color

Higher energy means shorter wavelength.

↳ Use the inverse relationship to quickly deduce energy gaps from spectral data.

🧠 Memory Trick

Remember the Order: UV Then Visible

UV comes before visible in energy.

Ultraviolet has Ultra-high energy (shorter wavelength) compared to Visible — just remember UV is more energetic.

↳ UV light carries more energy per photon than visible light.

❓ Did You Know

Ozone Layer Absorbs UV via Electronic Transitions

Ozone's electrons shield life on Earth.

Ozone ($O_3$) absorbs harmful UV-B and UV-C radiation through electronic transitions, protecting life on Earth.

↳ Electronic spectra have planetary-scale importance in atmospheric chemistry.

Smart notes

What you'll study, topic by topic

1

Electronic Spectra

15 min

Electronic spectra arise from transitions of electrons between energy levels in atoms and molecules, typically in the UV-visible region. They reveal electronic structure, bonding, and concentration through absorption and…

  • An electronic spectrum arises from transitions of electrons between quantised energy levels.
  • Energy gap and photon energy are related by $h\nu = \Delta E$.
  • Electronic transitions typically need UV or visible light (a few eV).

Full explanation, worked examples & memory tricks in the app

Leveled MCQ practice

Try the smart MCQs from this kit

All 18 questions, laddered from warm-up to topper-level, each with its answer and the reasoning behind it.

Warm-up · 6 questions

Q1. What is an electronic spectrum?

Beginner
A The pattern of bond vibrations in a molecule
B The pattern of molecular rotations
C The pattern of nuclear spin transitions
D The pattern of light absorbed or emitted during electron jumps between energy levels

Answers and explanations are in the Veda app.

Q2. Which equation relates the energy gap $\Delta E$ to the frequency $\nu$ of the absorbed photon?

Beginner
A $\Delta E = h/\nu$
B $\Delta E = h\nu^2$
C $\Delta E = \nu/h$
D $\Delta E = h\nu$

Answers and explanations are in the Veda app.

Q3. In which region of the electromagnetic spectrum do electronic transitions typically occur?

Beginner
A Radio
B Ultraviolet and visible
C Infrared
D Microwave

Answers and explanations are in the Veda app.

Q4. An absorption spectrum shows:

Beginner
A A continuous rainbow with no lines
B Dark lines or bands on a bright background
C Only a single bright line
D Bright lines or bands on a dark background

Answers and explanations are in the Veda app.

Q5. Why do atomic spectra consist of sharp lines?

Beginner
A Atomic nuclei have spin
B Atoms have many vibrational sub-levels
C Atoms rotate rapidly
D Atomic energy levels are discrete and quantised

Answers and explanations are in the Veda app.

Q6. The energy gap for an electronic transition is related to the photon wavelength by $\Delta E = hc/\lambda$; a gap of about $2\ \text{eV}$ corresponds to visible light near $620\ \text{nm}$.

Beginner
A True
B False

Answers and explanations are in the Veda app.

Building up · 7 questions

Q7. Molecular electronic spectra appear as broad bands because:

Intermediate
A All transitions are forbidden
B The spectrometer has low resolution
C Each electronic level is split into many vibrational and rotational sub-levels
D Molecules have no quantised energy levels

Answers and explanations are in the Veda app.

Q8. The Franck–Condon principle explains:

Intermediate
A The Beer–Lambert law
B The spin selection rule
C The position of atomic lines
D The intensity pattern of vibronic bands

Answers and explanations are in the Veda app.

Q9. Which selection rule states that $\Delta S = 0$ for allowed electronic transitions?

Intermediate
A Spin selection rule
B Beer–Lambert rule
C Laporte rule
D Rydberg rule

Answers and explanations are in the Veda app.

Q10. According to the Laporte rule, which transition is forbidden in a centrosymmetric molecule?

Intermediate
A $g \leftrightarrow u$
B Any transition with $\Delta S = 0$
C $u \leftrightarrow g$
D $g \leftrightarrow g$

Answers and explanations are in the Veda app.

Q11. Forbidden transitions are:

Intermediate
A Weak but not impossible
B Only seen in atoms
C Completely impossible
D Always strong

Answers and explanations are in the Veda app.

Q12. The Beer–Lambert law relates absorbance to:

Intermediate
A Spin and parity
B Temperature and pressure
C Concentration, path length, and molar absorptivity
D Wavelength and frequency

Answers and explanations are in the Veda app.

Q13. A chromophore is:

Intermediate
A A unit of absorbance
B A selection rule
C A type of spectrometer
D The part of a molecule responsible for its colour

Answers and explanations are in the Veda app.

Topper level · 5 questions

Q14. Extending conjugation in a molecule typically causes:

Advanced
A A decrease in molar absorptivity
B A blue shift (absorption at shorter wavelengths)
C A red shift (absorption at longer wavelengths)
D No change in absorption

Answers and explanations are in the Veda app.

Q15. The observed colour of a substance is:

Advanced
A Independent of absorption
B The same as the absorbed wavelengths
C Complementary to the absorbed wavelengths
D Always blue

Answers and explanations are in the Veda app.

Q16. Which hydrogen series appears in the visible region?

Advanced
A Brackett series
B Lyman series
C Paschen series
D Balmer series

Answers and explanations are in the Veda app.

Q17. Given a molecule with a chromophore that has a HOMO-LUMO gap of 2.5 eV, which of the following statements is true regarding its electronic absorption spectrum?

Advanced
A The molecule will have sharp lines in its spectrum.
B The molecule will exhibit a red shift if conjugation is extended.
C The molecule will absorb light in the visible region.
D The molecule will only absorb UV light.

Answers and explanations are in the Veda app.

Q18. A spectrophotometer measures the absorbance of a solution and produces a spectrum with peaks at certain wavelengths. If the intensity at a peak is significantly higher than at neighboring wavelengths, what can be inferred about the electronic transition responsible for this peak?

Advanced
A The transition is likely to be a spin-forbidden transition.
B The transition indicates a forbidden electronic transition with high oscillator strength.
C The transition is likely a strong allowed transition, such as a π to π* transition.
D The transition corresponds to a weak vibrational coupling.

Answers and explanations are in the Veda app.

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