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JEE Main Physics Exam Prep

English 21 leveled MCQs Free

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1

JEE Main Physics Exam Prep

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4 marks Medium answer

Maximum amplitude in a standing wave is 6cm. A point P is between a node and the immediate next antinode, dividing the distance in the ratio 1:2 Amplitude at P is _____ cm

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2 cm

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4 marks Medium answer

In a closed organ pipe of length 105cm, standing waves corresponding to the third overtone are set up. What is the distance of the closest pressure node from the closed end ? (in cm)

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21 cm

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4 marks Medium answer

Two sound source emitting sound of wavelength 1m are located at points P and Q as shown in figure. All sides of the polygon are equal and of length 1m. The intensity of sound at M due to both the individual sources is $I_0$. The intensity of sound at point M when both the sources are on is $mI_0$. value of m is

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4

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4 marks Medium answer

A student is experimenting with resonance tube apparatus in Physics lab to find the speed of sound at room temperature. He got resonating lengths of air column as 17 cm and 51 cm, using tuning fork of frequency 512 Hz. If speed of sound at room temperature is $12v m/s$. Find $v$.

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34 m/s

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