Heredity and Evolution — Class 10 NCERT Chapter 8: 17 MCQs with answers
All 17 multiple-choice questions from this kit, free and with no sign-up.
Warm-up · 6 questions
Q1. Which term describes the passing of traits from parents to offspring?
BeginnerShow the answer
A · Heredity
Heredity is the transmission of traits from parents to offspring, while variation refers to differences among individuals.
Q2. A pea plant has the genotype Tt. What is its phenotype for height?
BeginnerShow the answer
B · Tall
T (tall) is dominant over t (dwarf), so a Tt plant shows the dominant tall phenotype.
Q3. Which of the following is the genotypic ratio in the F2 generation of a monohybrid cross?
BeginnerShow the answer
D · 1:2:1
The F2 genotypic ratio is 1 TT : 2 Tt : 1 tt, i.e., 1:2:1.
Q4. What is the phenotypic ratio in the F2 generation of a monohybrid cross?
BeginnerShow the answer
D · 3:1
Three tall (TT or Tt) to one dwarf (tt) gives a 3:1 phenotypic ratio.
Q5. In humans, which chromosome combination results in a male child?
BeginnerShow the answer
B · XY
Males have one X and one Y chromosome (XY); females are XX.
Q6. Mendel's monohybrid cross on pea plants produced a 3:1 phenotypic ratio in the F2 generation.
BeginnerShow the answer
A · True
Mendel's monohybrid cross on pea plants produced a 3:1 phenotypic ratio in the F2 generation.
Building up · 6 questions
Q7. A couple has four daughters. What is the probability that their next child will be a boy?
IntermediateShow the answer
D · 50%
Each birth is an independent event; the probability of a boy remains 50% regardless of previous children.
Q8. Which of the following correctly describes a carrier?
IntermediateShow the answer
D · An individual with one dominant and one recessive allele who shows the dominant trait
A carrier is heterozygous (e.g., Tt) and shows the dominant phenotype but can pass the recessive allele to offspring.
Q9. Two parents, both with genotype Tt, have a child. What is the probability that the child will show the recessive trait?
IntermediateShow the answer
B · 25%
The cross Tt × Tt gives TT, Tt, Tt, tt; only tt (1 out of 4) shows the recessive trait, so probability is 25%.
Q10. In a dihybrid cross, what phenotypic ratio is observed in the F2 generation?
IntermediateShow the answer
B · 9:3:3:1
Mendel's dihybrid cross produced four phenotypes in a 9:3:3:1 ratio, showing independent assortment.
Q11. Which statement best explains why a recessive trait can skip a generation?
IntermediateShow the answer
C · Carriers show the dominant trait but can pass the recessive allele to offspring.
Heterozygous carriers (Tt) do not show the recessive trait but can transmit the recessive allele, allowing it to reappear in later generations.
Q12. A plant with genotype Tt is crossed with a plant with genotype tt. What proportion of offspring will be dwarf?
IntermediateShow the answer
B · 50%
The cross Tt × tt gives Tt and tt in equal numbers, so 50% are dwarf (tt).
Topper level · 5 questions
Q13. Which of the following is a correct statement about dominant alleles?
AdvancedShow the answer
A · A dominant allele expresses itself even when only one copy is present.
Dominance refers to expression when one copy is present, not to frequency or disease status.
Q14. In a cross between two heterozygous tall pea plants (Tt × Tt), what is the expected ratio of tall to dwarf offspring?
AdvancedShow the answer
A · 3 tall : 1 dwarf
The Punnett square gives TT, Tt, Tt, tt; three show tall and one shows dwarf, so 3:1.
Q15. A woman with free earlobes (dominant trait) has a child with attached earlobes (recessive trait). What can you infer about the woman's genotype?
AdvancedShow the answer
C · She must be heterozygous (Ee).
To have a child with attached earlobes (ee), the mother must contribute an e allele; since she has free earlobes, she must be Ee.
Q16. Which of the following best explains why sexual reproduction is advantageous in changing environments?
AdvancedShow the answer
D · It generates genetic variation, which is the raw material for natural selection.
Sexual reproduction reshuffles alleles, creating variation that helps populations adapt to changing environments.
Q17. In a dihybrid cross between two pea plants, one with genotype RrYy (round yellow seeds) and another with genotype RrYy, what is the expected phenotypic ratio of the offspring?
AdvancedShow the answer
B · 9:3:3:1
The correct option is 9:3:3:1 because this ratio represents the expected phenotypic outcomes when two traits are independently assorted during a dihybrid cross, as demonstrated by Mendel's experiments.
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