Kit Library / Science / Applied Physics & Quantum Mechanics

⚡ Topic Learning Kit

Quantum Mechanics

English 19 leveled MCQs 17 flashcards 7 games Free

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💡 Key Idea

The Core Discovery

Matter waves confirmed experimentally.

The Davisson-Germer experiment (1927) provided the first experimental confirmation of de Broglie's hypothesis that matter exhibits wave-like behavior. By scattering electrons off a nickel crystal, they observed a diffraction pattern, which is a wave phenomenon. This proved that electrons, previously considered…

↳ Electrons diffract like waves, proving matter has wave nature.

🕰️ Timeline

Historical Context

From hypothesis to experiment.

↳ The experiment was a pivotal step in quantum mechanics.

⚙️ Process

Experimental Setup

How the experiment was done.

↳ Electrons scattered off a crystal produce an interference pattern.

➗ Formula

de Broglie Wavelength of Electron

Calculating the expected wavelength.

For an electron accelerated through a potential $V$, the kinetic energy is $eV$, so the momentum is $p = \sqrt{2 m e V}$. This gives the theoretical de Broglie wavelength.

↳ The wavelength depends on the accelerating voltage.

➗ Formula

Bragg's Law for Diffraction

Condition for constructive interference.

In the experiment, the diffraction peak occurs when the path difference between waves scattered from adjacent crystal planes is an integer multiple of the wavelength.

↳ Diffraction maxima occur when Bragg's condition is satisfied.

✏️ Example

Observed Diffraction Peak

A concrete result.

For a nickel crystal with interplanar spacing $d = 0.91 \, \text{Å}$, a strong diffraction maximum was observed at an accelerating potential of $54 \, \text{V}$ and a scattering angle of $50^\circ$. The corresponding glancing angle $\theta$ is $65^\circ$ (since $\theta = 90^\circ - \phi/2$).

↳ The measured wavelength matched de Broglie's prediction.

⚖️ Comparison

Experimental vs Theoretical Wavelength

Agreement confirms theory.

↳ The close agreement validated de Broglie's hypothesis.

💡 Key Idea

Wave-Particle Duality Confirmed

Electrons are both particle and wave.

The experiment demonstrated that electrons produce interference patterns, a property of waves. Yet they also behave as particles (e.g., in particle detectors). This duality is a fundamental principle of quantum mechanics.

↳ Matter exhibits both particle and wave characteristics.

🛠️ Application

Electron Microscopy

Using wave nature for imaging.

The wave nature of electrons is exploited in electron microscopes, which use electron beams to achieve much higher resolution than optical microscopes because electron wavelengths are much smaller than visible light.

↳ Electron microscopes rely on matter waves.

⚠️ Common Mistake

Scattering Angle vs Glancing Angle

Don't mix up the angles.

In the experiment, the scattering angle $\phi$ is the angle between the incident and scattered beams. The glancing angle $\theta$ used in Bragg's law is the complement: $\theta = 90^\circ - \phi/2$. Using the wrong angle gives an incorrect wavelength.

↳ Always convert scattering angle to glancing angle.

🎯 Exam Tip

Remember the Key Numbers

Quick recall for exams.

↳ Memorize these values for typical exam questions.

🧠 Memory Trick

Mnemonic for the Experiment

Remember the key elements.

Davisson Germer Nickel Electrons: Diffraction Gives New Evidence. This helps recall the setup and outcome.

↳ Use the mnemonic to recall the experiment's essence.

❓ Did You Know

Accidental Discovery

A fortunate accident.

The diffraction pattern was discovered accidentally when a vacuum tube was opened to air, causing an oxide layer to form on the nickel surface. Heating the crystal to remove the oxide created larger crystal grains, which produced the sharp diffraction pattern.

↳ The discovery was partly due to a laboratory accident.

Smart notes

What you'll study, topic by topic

1

Davisson-Germer Experiment: Wave Nature of Matter

8 min

The Davisson-Germer experiment confirmed the wave nature of electrons by observing diffraction patterns from a nickel crystal. The measured wavelength matched de Broglie's prediction, providing direct evidence for matter…

  • The experiment confirmed de Broglie's hypothesis that matter exhibits wave-like behavior.
  • Electrons were scattered off a nickel crystal, producing a diffraction pattern.
  • The observed wavelength matched the de Broglie wavelength calculated from the accelerating voltage.

Full explanation, worked examples & memory tricks in the app

Leveled MCQ practice

Try the smart MCQs from this kit

All 19 questions, laddered from warm-up to topper-level, each with its answer and the reasoning behind it.

Warm-up · 7 questions

Q1. What did the Davisson-Germer experiment conclusively demonstrate?

Beginner
A Light is purely a particle
B Atoms are indivisible
C Particles have no wave nature
D Electrons exhibit wave nature
Show the answer

D · Electrons exhibit wave nature

The experiment showed diffraction of electrons, confirming de Broglie's hypothesis of wave-particle duality.

Q2. In the Davisson-Germer experiment, electrons were scattered off a crystal of:

Beginner
A Copper
B Nickel
C Silicon
D Graphite
Show the answer

B · Nickel

Davisson and Germer used a nickel crystal to observe diffraction patterns.

Q3. The Davisson-Germer experiment is often cited as evidence for:

Beginner
A Wave nature of matter
B Dual nature of light
C Wave nature of light
D Particle nature of light
Show the answer

A · Wave nature of matter

It demonstrated that electrons, which are matter, behave as waves.

Q4. The Davisson-Germer experiment was performed in which year?

Beginner
A 1927
B 1905
C 1932
D 1913
Show the answer

A · 1927

Davisson and Germer published their experiment in 1927.

Q5. The Davisson-Germer experiment provided direct evidence for the wave nature of matter, supporting the hypothesis proposed by:

Beginner
A Louis de Broglie
B Niels Bohr
C Erwin Schrödinger
D Albert Einstein
Show the answer

A · Louis de Broglie

De Broglie proposed that matter has wave-like properties, which this experiment confirmed.

Q6. The Davisson-Germer experiment demonstrated that electrons behave as waves.

Beginner
A True
B False
Show the answer

A · True

The observed diffraction pattern confirmed the wave nature of electrons.

Q7. The Davisson-Germer experiment used a copper crystal to scatter electrons.

Beginner
A True
B False
Show the answer

B · False

The experiment used a nickel crystal, not copper.

Building up · 11 questions

Q8. The diffraction pattern observed in the Davisson-Germer experiment is due to:

Intermediate
A Photoelectric effect
B Bragg reflection of electron waves
C Compton scattering
D X-ray interference
Show the answer

B · Bragg reflection of electron waves

The electron waves reflected from crystal planes interfere constructively according to Bragg's law.

Q9. The accelerating voltage used in the Davisson-Germer experiment that produced the strongest diffraction was approximately:

Intermediate
A 12 V
B 200 V
C 54 V
D 100 V
Show the answer

C · 54 V

At 54 V, the electron wavelength matched the spacing, giving a pronounced diffraction maximum.

Q10. The de Broglie wavelength of an electron accelerated through a potential difference V is given by:

Intermediate
A $\lambda = \frac{h}{p}$
B $\lambda = \frac{h}{\sqrt{2meV}}$
C $\lambda = \frac{h}{\sqrt{2mE}}$
D $\lambda = \frac{h}{mv}$
Show the answer

B · $\lambda = \frac{h}{\sqrt{2meV}}$

For an electron accelerated from rest, kinetic energy = eV, so momentum p = sqrt(2meV), giving λ = h/sqrt(2meV).

Q11. In the Davisson-Germer experiment, the scattered electron intensity was measured as a function of:

Intermediate
A Pressure
B Magnetic field
C Temperature
D Scattering angle
Show the answer

D · Scattering angle

The detector measured electron intensity at various angles to observe interference maxima.

Q12. The experimental result of Davisson-Germer matched the theoretical prediction of:

Intermediate
A Bohr's atomic model
B Einstein's photoelectric equation
C de Broglie's wavelength formula
D Heisenberg's uncertainty principle
Show the answer

C · de Broglie's wavelength formula

The observed diffraction angle and electron wavelength agreed with de Broglie's relation λ = h/p.

Q13. The crystal used in the experiment acted as a:

Intermediate
A Polarizer
B Lens
C Prism
D Diffraction grating
Show the answer

D · Diffraction grating

The regular arrangement of atoms in the crystal diffracted the electron waves, similar to a grating.

Q14. If the accelerating voltage is increased, the de Broglie wavelength of electrons:

Intermediate
A Decreases
B Increases
C Becomes zero
D Remains constant
Show the answer

A · Decreases

Since λ ∝ 1/√V, increasing V reduces the wavelength.

Q15. The diffraction peak observed at 54 V occurred at a scattering angle of approximately:

Intermediate
A 30°
B 180°
C 90°
D 50°
Show the answer

D · 50°

The maximum intensity was observed at about 50° for 54 V electrons.

Q16. The Davisson-Germer experiment confirmed the de Broglie hypothesis for:

Intermediate
A Electrons
B Protons
C Photons
D Neutrons
Show the answer

A · Electrons

It specifically demonstrated wave behavior of electrons.

Q17. The Davisson-Germer experiment is analogous to which of the following experiments?

Intermediate
A Rutherford's gold foil experiment
B Faraday's ice pail experiment
C Millikan's oil-drop experiment
D Young's double-slit experiment with light
Show the answer

D · Young's double-slit experiment with light

Both show wave interference patterns, one for light and the other for electrons.

Q18. In the Davisson-Germer experiment, the electron gun accelerates electrons through a variable potential difference. This is done to:

Intermediate
A Align the electron spins
B Produce monochromatic light
C Change the electron's wavelength
D Increase the electron's charge
Show the answer

C · Change the electron's wavelength

Changing the accelerating voltage changes the electron's kinetic energy and hence its de Broglie wavelength.

Topper level · 1 questions

Q19. Which of the following is NOT a conclusion of the Davisson-Germer experiment?

Advanced
A Electrons have wave nature
B Matter waves are electromagnetic waves
C The wavelength of electrons matches de Broglie's formula
D The experiment supports wave-particle duality
Show the answer

B · Matter waves are electromagnetic waves

Matter waves are not electromagnetic; they are probability waves.

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