Kit Library / Science / Physical Chemistry / Spectroscopy

⚡ Topic Learning Kit

Vibrational Spectra: IR and Raman Spectroscopy

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💡 Key Idea

Molecules Vibrate at Quantized Frequencies

Bonds behave like tiny springs.

Every chemical bond acts like a spring connecting two masses. When it vibrates, it does so only at specific, quantized frequencies — and spectroscopy detects these transitions.

↳ Vibrational spectra are fingerprints of molecular bonds — each mode reveals structure.

📖 Definition

Key Terms in Vibrational Spectroscopy

Speak the language of spectra.

↳ Master these five terms before interpreting any spectrum.

➗ Formula

Harmonic Oscillator: The Spring Model

One equation explains every stretch.

↳ Bond strength and atomic mass together set the vibrational frequency.

⚖️ Comparison

IR vs Raman: Two Windows into Vibrations

Same vibrations, different physics.

↳ IR and Raman are complementary — together they reveal the full vibrational picture.

💡 Key Idea

Mutual Exclusion Rule for Centrosymmetric Molecules

Symmetry splits the spectrum in two.

In molecules with a center of inversion (e.g., CO₂, benzene), no vibrational mode can be both IR and Raman active.

↳ Mutual exclusion is a powerful symmetry diagnostic for centrosymmetric molecules.

⚙️ Process

How a Vibrational Spectrum Is Recorded

From sample to spectrum in four steps.

The resulting plot shows absorption bands (IR) or scattering peaks (Raman) at characteristic wavenumbers.

↳ Sample prep and detection mode differ, but both techniques map intensity against wavenumber.

⭐ Important Fact

Characteristic Wavenumber Regions

Know the zones, read the spectrum.

↳ The 4000–1500 cm⁻¹ region identifies functional groups; below 1500 cm⁻¹ is the fingerprint.

⚠️ Common Mistake

Not Every Vibration Shows Up

Silent modes are not missing modes.

↳ A missing band doesn't mean a missing bond — it may be forbidden by selection rules.

✏️ Example

Reading Acetone's IR Spectrum

One sharp peak tells the story.

↳ Carbonyl position is a sensitive probe of electronic environment.

🌍 Real World

Where Vibrational Spectroscopy Is Used

From pharmacies to Mars rovers.

↳ Vibrational spectroscopy is a workhorse for non-destructive chemical identification.

🧠 Memory Trick

Remember the Selection Rules

Dipole for IR, polarizability for Raman.

IR = Involves Redistribution of Dipole (Δμ). Raman = Requires Alteration of Molecular Anisotropy (Δα).

↳ Two mnemonics, two rules — never mix them up.

🎯 Exam Tip

Exam Strategy for Vibrational Spectra

Score marks with these moves.

↳ Selection rules + mode count + characteristic ranges = full marks.

❓ Did You Know

Raman Won the Nobel Before IR Became Routine

A ship voyage led to a Nobel Prize.

C. V. Raman discovered the Raman effect in 1928 during a sea voyage, noticing that scattered sunlight changed colour through liquids. He won the Nobel Prize in Physics in 1930.

↳ Raman's discovery turned light scattering into a structural tool.

🛠️ Application

Choosing IR or Raman for a Sample

Pick the right tool for the job.

↳ Match the technique to the sample's polarity and environment.

💡 Prerequisite

What You Need Before This Topic

Build on these basics first.

↳ A solid grasp of bonding and light makes vibrational spectra intuitive.

Smart notes

What you'll study, topic by topic

1

Vibrational Spectra: IR and Raman Spectroscopy

18 min

Vibrational spectroscopy studies how molecules absorb or scatter light as their bonds stretch and bend. IR and Raman spectroscopy reveal molecular structure by probing vibrational transitions, with selection rules determ…

  • Vibrational spectra arise from transitions between quantised vibrational energy levels of molecules.
  • A bond is modelled as a harmonic oscillator with frequency $\nu = \frac{1}{2\pi}\sqrt{k/\mu}$.
  • The force constant $k$ measures bond stiffness; stronger bonds give higher vibrational frequencies.

Full explanation, worked examples & memory tricks in the app

Leveled MCQ practice

Try the smart MCQs from this kit

All 20 questions, laddered from warm-up to topper-level, each with its answer and the reasoning behind it.

Warm-up · 9 questions

Q1. Which equation gives the vibrational frequency of a bond modelled as a harmonic oscillator?

Beginner
A $\nu = \frac{1}{2\pi}\sqrt{\frac{k}{\mu}}$
B $\nu = \frac{1}{2\pi}\sqrt{\frac{\mu}{k}}$
C $\nu = 2\pi\sqrt{\frac{k}{\mu}}$
D $\nu = \frac{1}{2\pi}\frac{k}{\mu}$

Answers and explanations are in the Veda app.

Q2. How many vibrational modes does a non-linear molecule with $N$ atoms have?

Beginner
A $3N - 3$
B $3N - 6$
C $3N$
D $3N - 5$

Answers and explanations are in the Veda app.

Q3. Which statement correctly describes the IR selection rule?

Beginner
A A vibration must change the dipole moment of the molecule.
B A vibration must change the polarizability of the molecule.
C A vibration must change the bond length.
D A vibration must involve a bending motion.

Answers and explanations are in the Veda app.

Q4. Which region of an IR spectrum is most useful for matching an unknown compound to a known one?

Beginner
A Around $3000\ \text{cm}^{-1}$
B Above $4000\ \text{cm}^{-1}$
C Below about $1500\ \text{cm}^{-1}$
D $1600$–$1800\ \text{cm}^{-1}$

Answers and explanations are in the Veda app.

Q5. Which pair of functional groups gives stretches in the $1600$–$1800\ \text{cm}^{-1}$ region?

Beginner
A C–H and C–D
B O–H and N–H
C S–S and C–S
D C=O and C=C

Answers and explanations are in the Veda app.

Q6. Which statement about stretching and bending modes is correct?

Beginner
A Stretching modes generally appear at higher wavenumbers than bending modes.
B Bending modes generally appear at higher wavenumbers than stretching modes.
C Stretching and bending modes always appear at the same wavenumber.
D Bending modes do not appear in IR spectra.

Answers and explanations are in the Veda app.

Q7. Which of the following is a bending mode?

Beginner
A Symmetric stretch
B Asymmetric stretch
C Scissoring
D Overtone

Answers and explanations are in the Veda app.

Q8. Which technique is complementary to IR because it detects vibrations that do not change the dipole moment?

Beginner
A Nuclear magnetic resonance
B UV–visible spectroscopy
C Raman spectroscopy
D Mass spectrometry

Answers and explanations are in the Veda app.

Q9. For a molecule with $N$ atoms, the number of vibrational modes is $3N - 6$ if non-linear and $3N - 5$ if linear.

Beginner
A True
B False

Answers and explanations are in the Veda app.

Building up · 6 questions

Q10. A C–H stretch appears near $3000\ \text{cm}^{-1}$. The corresponding C–D stretch appears at about $2200\ \text{cm}^{-1}$. What is the main reason for the shift?

Intermediate
A The C–D bond is much stiffer than the C–H bond.
B Deuterium has a larger reduced mass with carbon, lowering the frequency.
C Deuterium changes the dipole moment of the bond.
D The C–D bond is anharmonic while the C–H bond is harmonic.

Answers and explanations are in the Veda app.

Q11. Carbon dioxide is a linear molecule with $N = 3$. How many vibrational modes does it have?

Intermediate
A 5
B 4
C 6
D 3

Answers and explanations are in the Veda app.

Q12. The symmetric stretch of $\text{CO}_2$ is silent in the IR spectrum. Why?

Intermediate
A It is a bending mode rather than a stretch.
B It does not change the dipole moment of the molecule.
C It is an overtone rather than a fundamental.
D Its frequency lies outside the IR range.

Answers and explanations are in the Veda app.

Q13. A student runs an IR spectrum of an aqueous sample and finds the spectrum dominated by water absorption. Which technique would be a better choice?

Intermediate
A IR spectroscopy in the fingerprint region only.
B IR spectroscopy at a higher temperature.
C IR spectroscopy with a more concentrated sample.
D Raman spectroscopy, because water interference is weak.

Answers and explanations are in the Veda app.

Q14. Why do vibrational levels of a real molecule crowd together at higher energy?

Intermediate
A Because the reduced mass decreases at higher energy.
B Because overtones are forbidden transitions.
C Because the force constant increases at higher energy.
D Because the bond potential is anharmonic.

Answers and explanations are in the Veda app.

Q15. A small peak appears at roughly twice the frequency of a strong fundamental. What is it most likely to be?

Intermediate
A An overtone
B A combination band
C A bending mode
D A fingerprint band

Answers and explanations are in the Veda app.

Topper level · 5 questions

Q16. A molecule has two oscillators sharing a central atom with similar frequencies. What effect does this produce in the spectrum?

Advanced
A The modes become IR-inactive.
B The two modes couple and appear at shifted frequencies.
C The two modes disappear from the spectrum.
D The modes become overtones.

Answers and explanations are in the Veda app.

Q17. A molecule with 4 atoms exhibits a vibrational spectrum. Calculate the number of vibrational modes it has if it is non-linear. What does this imply about the types of vibrations present?

Advanced
A 7 vibrational modes, indicating only bending vibrations
B 6 vibrational modes, indicating a mix of stretching and bending vibrations
C 2 vibrational modes, indicating only bending vibrations
D 5 vibrational modes, indicating only stretching vibrations

Answers and explanations are in the Veda app.

Q18. Given the vibrational frequency equation $$ u = \frac{1}{2\pi}\sqrt{\frac{k}{\mu}}$$, if the force constant $k$ of a bond is doubled while the reduced mass $\mu$ remains constant, how does the frequency change?

Advanced
A The frequency increases by a factor of \sqrt{2}
B The frequency increases by a factor of 2
C The frequency remains the same
D The frequency increases by a factor of 4

Answers and explanations are in the Veda app.

Q19. In a Raman spectrum, a peak appears at a frequency corresponding to a combination band of two vibrational modes. If the fundamental frequencies of these modes are $1000\ ext{cm}^{-1}$ and $1500\ ext{cm}^{-1}$, what is the expected frequency for the combination band?

Advanced
A 2500\ ext{cm}^{-1}
B 2500\ ext{cm}^{-1} (1000 + 1500)
C 500\ ext{cm}^{-1}
D 1500\ ext{cm}^{-1}

Answers and explanations are in the Veda app.

Q20. A student observes that a certain vibrational mode is absent in the IR spectrum but present in the Raman spectrum. What can be concluded about the nature of this vibrational mode?

Advanced
A It does not change the dipole moment but changes polarizability
B It is an overtone of a fundamental mode
C It does not change the bond length
D It is a bending mode only

Answers and explanations are in the Veda app.

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