Class 8 Mathematics Chapter 12: Tales by Dots and Lines
- 3 topics
- 75 MCQs
- 21 short answers
- 9 long answers
- 51 flashcards
- 15 games
- ~110 min read
- English
The mean as a balance point
The mean is not the midpoint between the extremes. It is the one place where the distances below it and the distances above it come to the same total.
What you will be able to do
- Explain what makes the mean the centre of a set of data.
- Show that only one such centre exists.
- Predict how adding a value moves the mean.
- Add or remove values without moving the mean.
- Prove what happens when every value is shifted or scaled.
Key points
The mean is the total divided by the number of values.
For two numbers the mean lies exactly halfway between them.
For more values it is not the midpoint of the extremes.
The distances below the mean total the distances above it.
No other value has that property, so the centre is unique.
A new value above the mean lifts it, and one below lowers it.
A new value equal to the mean leaves it exactly as it was.
Adding a fixed number to every value adds it to the mean.
Multiplying every value by a number multiplies the mean by it.
Full explanation
Two familiar measures
To find the mean of some data, total its values and share that total out over however many values went into it. The median is instead whichever value lands in the middle once the data is sorted. Both are already familiar, and this topic looks at the mean from a new angle.
Start with two numbers
Take 3 and 7. Their mean is 10 over 2, which is 5. Take 8 and 9 instead and the mean is 17 over 2, which is 8.5. Drawn as dots on a line, the mean sits exactly halfway between the two values each time.
A tempting generalisation
That suggests the mean is always the midpoint between the smallest and the largest value. It is a reasonable guess from two numbers, and it is wrong as soon as there are three.
What is actually true
The mean is called a measure of central tendency because it marks the centre of the data. But the centre is not the midpoint of the extremes. It is the place where the total distances on either side are equal.
Seeing it on a set
Take 10, 10, 11 and 17. Their total is 48 and there are 4 values, so the mean is 12. Now measure the distances. Below the mean: 2, then 2, then 1, which is 5 in all. Above it: 5. The two totals match exactly.
Why the midpoint guess fails
The midpoint of the extremes here would be halfway between 10 and 17, which is 13.5. That is nowhere near 12. The three small values pull the balance point down, and the mean records that pull while the midpoint ignores it.
Could there be a second centre?
Suppose some value larger than 12 also balanced the data. Moving right from 12, every distance on the left grows and every distance on the right shrinks, so the left total now outweighs the right. The balance is lost.
The same argument the other way
Moving left from 12 does the reverse: the left distances shrink and the right ones grow. So no value above or below 12 can balance the data either. There is exactly one centre.
Adding a value
What happens to the mean when a new value joins? If the new value is above the mean, it adds to the total on the high side, and the balance point must move up to restore equality. So the mean increases.
And the other cases
A new value below the mean pulls the other way, so the mean decreases. And a value exactly equal to the mean adds nothing to either side, so the mean does not move at all.
Checking that on real numbers
Take 4, 6, 8, 10 and 12, whose mean is 8. Add 20 and the mean becomes 60 over 6, which is 10. Add 8 instead and the mean is 48 over 6, which is still 8. Both predictions hold.
Two values that cancel
This suggests a trick. Add two values, one as far above the mean as the other is below, and the two pulls cancel. Adding 4 and 12 to that same set gives a total of 56 over 7 values, which is 8 again.
Three values that cancel
It works with three as well, so long as the pulls still balance. Two values below the mean can be offset by one far enough above it, which is worth trying out on a dot plot.
Shifting every value
Now a different question. What if every value in the data goes up by the same fixed amount? Raising 4, 6, 8, 10 and 12 each by 5 gives 9, 11, 13, 15 and 17, whose mean is 13. The mean has gone up by 5 as well.
Proving the shift
Let the n values be x1 up to xn, with mean a, so their total is n times a. Adding 3 to every value adds 3n to the total. Dividing the new total by n gives a plus 3. So the new mean is 3 more than the old one.
Scaling every value
What if every value is multiplied instead? Trebling 4, 6, 8, 10 and 12 gives 12, 18, 24, 30 and 36, whose mean is 24. The old mean was 8, so the mean has trebled too.
Proving the scaling
The same algebra works. Multiplying every value by 5 makes the new total 5 times x1 plus 5 times x2 and so on, which the distributive property turns into 5 times the old total. Dividing by n gives 5 times a.
What the two results mean
So shifting the data shifts the mean by the same amount, and scaling the data scales the mean by the same factor. In both cases the mean keeps its relative position among the values, which is exactly what a centre should do.
Concepts and terms
The total of the values, shared out over however many of them there are.
The distances from the mean to the smaller values total the distances to the larger ones.
Move away from the mean and one total grows while the other shrinks, so no second centre exists.
Adding a fixed number to every value adds that number to the mean, and nothing else changes.
Multiplying every value by a number multiplies the mean by the same number.
Watch out
Common misconceptions
Three claims about a class test
Scenario:
A teacher has marked a test. The five marks are 4, 6, 8, 10 and 12 out of 15, and she notes the mean. A pupil says the mean must be 8 because that is halfway between 4 and 12. A second pupil arrives late, scores 8 himself, and the first pupil predicts the mean will rise because there is now more data. The teacher then decides to award every pupil 5 bonus marks, and a third pupil claims the mean will be multiplied by 5. All three want to know who is right.
Analysis:
One got the right answer for the wrong reason, one has forgotten the equal case, and one has swapped the shift result for the scale one.
Shift and scale a set of data
Title:
Shift and scale a set of data
Safety:
Nothing here is risky, but write the first mean down before you change anything.
What You Notice:
The first change adds 7 to the mean and the second multiplies it by 4. Both predictions can be made without adding the new values up at all, which is the point of proving them.
Did you know
The mean is the only value in a set of data with the balance property. Shift away from it in either direction and one side immediately outweighs the other.
Two values can be added to a set without moving its mean at all, so long as one sits as far above the mean as the other sits below.
Memory tricks
Distances balance, not endpoints — The mean is not halfway between the smallest and the largest. It is where the pull from each side is equal.
Practice MCQs with answers (25)
- A dividing the total by the largest value
- B dividing the total by two and no more
- C subtracting the smallest of the values
- D dividing by how many values there are
Show answer
Why:
The median is the middle value once sorted instead.
- A 5 and 8
- B 5 and 8.5
- C 4 and 8.5
- D 10 and 17
Show answer
Why:
Ten over 2, and 17 over 2.
- A closer to the smaller one
- B exactly halfway between them
- C closer to the larger one
- D outside the pair
Show answer
Why:
Which is what makes the next step so tempting.
- A wrong as soon as there are three values
- B right for any number of values
- C right only when all the values are even
- D wrong even for two values
Show answer
Why:
Two values is the one case where it happens to hold.
- A the number of values on either side is the same
- B the largest and smallest values are equally far
- C the distances on either side total the same
- D every distance is the same size
Show answer
Why:
Distances, not endpoints, and not counts either.
- A 13.5
- B 11
- C 48
- D 12
Show answer
Why:
Forty-eight divided by 4 values.
- A 5 and 5
- B 5 and 17
- C 3 and 5
- D 6 and 4
Show answer
Why:
Below: 2, 2 and 1. Above: 5.
- A the two extremes were measured wrongly
- B the mean has to be a whole number throughout
- C the midpoint is always the larger of them
- D the three small values pull the balance down
Show answer
Why:
The midpoint ignores everything between the extremes.
- A every left distance shrink and every right one grow
- B all of the distances grow together
- C every left distance grow and every right one shrink
- D all of the distances shrink together
Show answer
Why:
So the left total now outweighs the right and the balance is lost.
- A Both true, and the reason explains the assertion
- B Both true, but the reason does not explain it
- C The assertion is true and the reason is false
- D The assertion is false and the reason is true
Show answer
Why:
Both statements are true, but the second does not explain the first. Uniqueness follows from what happens to the two totals of distances when you move away from the mean, not from the formula.
- A decreases
- B increases
- C stays exactly the same
- D may move either way
Show answer
Why:
The high side has gained, so the balance point moves up.
- A increases a little
- B decreases a little
- C stays exactly the same
- D moves towards the larger values
Show answer
Why:
It adds nothing to either side of the balance.
- A 10
- B 8
- C 9
- D 12
Show answer
Why:
The new total of 60 over 6 values.
- A 9
- B 7
- C 8
- D 10
Show answer
Why:
Forty-eight over 6 values, and 8 was the mean already.
- A one is as far above the mean as the other is below
- B both of them happen to equal the largest value
- C both of them lie somewhere below the mean
- D their sum comes out equal to the mean itself
Show answer
Why:
The two pulls then cancel exactly.
- A 9, slightly higher
- B 7, slightly lower
- C 8, unchanged
- D 16, doubled
Show answer
Why:
The total becomes 56 over 7 values.
- A 8
- B 18
- C 40
- D 13
Show answer
Why:
Nine, 11, 13, 15 and 17 total 65 over 5 values.
- A leaving the mean exactly as it was
- B multiplying the mean by that number
- C making the mean impossible to find
- D adding that number to the mean
Show answer
Why:
The relative position of the mean is untouched.
- A 3n
- B 3
- C n
- D 3 over n
Show answer
Why:
Dividing the new total by n then gives a plus 3.
- A 24
- B 8
- C 11
- D 120
Show answer
Why:
Twelve, 18, 24, 30 and 36 total 120 over 5 values.
- A adds that same factor on to it
- B multiplies it by that same factor
- C leaves it exactly where it was before
- D divides it by that same factor
Show answer
Why:
The old mean of 8 became 24 when the values were trebled.
- A the commutative property
- B the distributive property
- C the associative property
- D the closure property
Show answer
Why:
Five times x1 plus 5 times x2 becomes 5 times the whole total.
- A I and II only
- B II and III only
- C I and III only
- D I, II and III
Show answer
Why:
The second and third hold. The first is false: adding a fixed number to every value ADDS it to the mean, and multiplying is the separate result.
- A 6
- B 7
- C 9
- D 35
Show answer
Why:
Thirty-five divided by 5 values.
- A 5 and 7
- B 6 and 4
- C 6 and 6
- D 7 and 6
Show answer
Why:
Below: 5 and 1. Above: 2 and 4.
Important short questions (7)
The total is 27 over 3 values, so the mean is 9. The midpoint of 6 and 13 is 9.5, so the mean is not the midpoint.
The total is 32 over 4 values, so the mean is 8. Below it the distances are 3 and 3, which is 6. Above it the distance is 6.
Nothing at all. The new value sits exactly at the balance point, so it adds nothing to either side.
Any pair as far above as below, such as 11 and 19. Their pulls on the balance point cancel exactly.
The new mean is 19. Each of the n values gains 7, so the total gains 7n, and dividing by n adds 7 to the mean.
The new mean is 36. The distributive property takes the factor 4 out of the total, so the total is 4 times as large, and so is the mean.
Suppose a value above the mean also balanced the data. Moving right from the mean grows every distance to the smaller values and shrinks every distance to the larger ones, so the lower side now outweighs the upper and the balance is lost. Moving left does the reverse. Neither direction works, so the centre is unique.
Long answer questions (3)
Start by working the mean out. The four values total 48, and 48 divided by 4 is 12. Now look at the midpoint of the extremes. The smallest value is 10 and the largest is 17, so halfway between them is 13.5. That is a long way from 12, which settles the question: the mean is not the midpoint of the extremes. What makes it the centre is a statement about distances. Measure from 12 to each value below it and the distances are 2, 2 and 1, totalling 5. Measure from 12 to the one value above it and the distance is 5 as well. The two totals match, so 12 balances the data. The midpoint fails because it looks only at the two ends, while three of these four values sit at the low end and pull the balance down.
Think of the mean as a balance point, with the distances below it totalling the distances above it. A new value above the mean adds to the total on the high side. The balance point must then move up to restore the equality, so the mean increases. A new value below the mean does the opposite, and the mean decreases. A new value exactly equal to the mean adds nothing to either side, so the mean does not move at all. Now check two of those on the set 4, 6, 8, 10 and 12, whose total is 40 and whose mean is 8. Adding 20, which is above the mean, gives a total of 60 over 6 values, so the mean rises to 10. Adding 8, which equals the mean, gives 48 over 6 values, which is 8 again.
Let the data be the n values x1, x2 and so on up to xn, and let their mean be a. That means the sum of the values divided by n equals a, so the sum itself is n times a. Take the shift first. Adding 3 to every value gives x1 plus 3, x2 plus 3 and so on. Each of the n values has gained 3, so the new total is the old total plus 3n. Dividing by n gives a plus 3, so the mean has gained 3 as well. Now the scaling. Multiplying every value by 5 gives a new total of 5 times x1 plus 5 times x2 and so on. The distributive property turns that into 5 times the old total. Dividing by n gives 5 times a, so the mean has been multiplied by 5.
Flashcards (17)
Play this topic
- Memory match
- Match the idea
- Does the mean move?
- Fact or myth
- Show the mean balances a set of data
Median, frequencies, and finding an unknown
The median answers to counts rather than to distances, so it moves differently from the mean. And a mean can be run backwards to recover a value nobody wrote down.
What you will be able to do
- Predict how adding a value moves the median.
- Recover a missing value from a known mean.
- Correct a mean after a value is found to be wrong.
- Find a mean from a frequency table.
- Find a median from cumulative frequencies.
Key points
The median is the middle value once the data is sorted.
An equal number of values lie below it and above it.
A new value above the median raises it.
With an even count, the median is the average of the two middle values.
A mean times the number of values gives the total.
That total can be used to recover a missing value.
A frequency table needs every value counted as often as it occurs.
The mean is then the sum of value times frequency over the total frequency.
Cumulative frequencies locate the median without listing every value.
Full explanation
Back to the median
The median is the middle value once the data has been sorted, so that as many values lie below it as above it. Unlike the mean, it answers to counts rather than to distances, and that makes it move differently.
Adding a value above it
Take a set whose median is 8 and add the value 11. The new value is above the old median, so there are now more values above 8 than below it, and 8 can no longer be the middle. The median must rise.
Where it lands
With an even number of values there is no single middle one, so the median is the average of the two middle values. Here those are 8 and 11, so the new median is 9.5. A value below the median would have pulled it down in the same way.
A value nobody wrote down
Coach Balwan recorded the weights of ten wrestlers and their mean, but one weight got smudged. The nine readable weights are 42, 40, 39, 33, 48, 38, 42, 35 and 32, and the mean was 39.2 kg.
Running the mean backwards
The mean is the total divided by the number of values, so the total is the mean times that number: 39.2 times 10, which is 392. The nine readable weights total 349, so the missing weight is 392 less 349, which is 43 kg.
When a value turns out to be wrong
Venkayya averaged his coconut harvest at 25.6 per tree across 15 trees. His son then found that one tree had been written down as 3 more than it really yielded. What is the correct average?
Solving it without the data
The individual counts are not given, and they are not needed. The total must be 25.6 times 15, which is 384. Three of those were never picked, so the true total is 381, and the correct average is 381 over 15, which is 25.4.
Why that worked
Notice what made it possible. A mean carries all the information about the total, so any question about the total can be answered from the mean alone. The separate values only matter when the question asks about one of them.
Data that repeats
Now a different shape of problem. A class records how many people live in each pupil’s family, and the answers run from 3 to 10. Rather than a long list, the data is collected into a table of frequencies.
A tempting wrong average
The table lists eight different family sizes, from 3 to 10, and adding those and dividing by 8 gives 52 over 8, which is 6.5. That is wrong, and it is wrong for one clear reason.
What the frequencies are for
Finding a mean means adding all the VALUES in the data, not all the different values. Three occurs three times over, 4 occurs eleven times, and so on. A calculation that ignores the frequencies has thrown most of the data away.
Doing it properly
Multiply each value by its own frequency and add those products: 3 times 3, plus 4 times 11, plus 5 times 9, and so on. That gives 9 plus 44 plus 45 plus 42 plus 21 plus 8 plus 9 plus 10, which is 188.
Dividing by the right number
The divisor must be the number of values in the data, which is the total of the frequencies. That total is 3 plus 11 plus 9 plus 7 plus 3 plus 1 plus 1 plus 1, which is 36. So the mean family size is 188 over 36, which is 5.22.
The median of the same table
There are 36 values, an even number, so the median is the average of the 18th and 19th values in order. Writing out all 36 numbers would work, but there is a much quicker way.
Counting up the frequencies
Add the frequencies from the smallest value upwards. Three gives 3, so positions 1 to 3 hold the value 3. Adding the 11 fours gives 14, so positions 4 to 14 hold 4. Adding the 9 fives gives 23, so positions 15 to 23 all hold 5.
Reading off the answer
Positions 18 and 19 both fall inside that range, so both of those values are 5, and the median is 5. The whole thing took one column of addition and no sorting at all.
A median with room to move
One last point about the median. Take the eleven values 12, 47, 8, 73, 18, 35, 39, 8, 29, 25 and p. The median is 29 when p is 29, 30, 40, 47 or 100, but not when p is 10 or 25.
Why that is
With eleven values the median is the sixth in order. Without p, the sorted list puts 29 sixth already, so any p at or above 29 leaves it there. A p below 29 pushes an extra small value in front of it, and the sixth place falls back to 25.
Concepts and terms
The middle value of the sorted data, with as many values below it as above it.
Then there is no single middle, so the median is the average of the two middle values.
The mean times the number of values gives the total, from which a missing value follows.
Multiply each value by its frequency, add those products, and divide by the total frequency.
A running total of the frequencies, which says what value sits at any given position.
Watch out
Common misconceptions
Tidying up the sports records
Scenario:
A games teacher is checking three records. Ten shot-put throws have a mean of 8.4 metres, but one throw is illegible, and the nine readable ones total 75 metres. A table of press-up counts lists the values 5 to 9 with frequencies 4, 6, 8, 5 and 2, and an assistant has averaged the five values and reported 7. Finally the teacher notes that last term’s median height was 142 cm, and a new pupil of 150 cm has just joined.
Analysis:
One record needs the mean run backwards, one ignores the frequencies, and one asks which way a median moves.
Hide a value and recover it
Title:
Hide a value and recover it
Safety:
Keep the scissors pointing away from you and cut on a flat table.
What You Notice:
One hidden value can always be recovered, because the mean fixes the total exactly. Two cannot: the mean fixes only their sum, and many pairs share a sum.
Did you know
A mean can be run backwards even when none of the individual values are known. Fifteen trees averaging 25.6 coconuts must have yielded 384 between them, whatever each tree did.
Cumulative frequencies find a median without writing out the data. Thirty-six family sizes can be put in order on one line of arithmetic.
Memory tricks
Mean times how many gives the total — Whenever a value is missing, turn the mean back into a total first. Everything else follows from that total.
Practice MCQs with answers (25)
- A the mean
- B the mode
- C the median
- D the range
Show answer
Why:
Unlike the mean, it answers to counts rather than distances.
- A the median must fall
- B the median must rise
- C the median cannot change
- D the median becomes 11
Show answer
Why:
There are now more values above 8 than below it.
- A the average of the two middle values
- B the smaller of the two middle values
- C the larger of the two middle values
- D undefined
Show answer
Why:
Since there is no single middle value to pick.
- A 8
- B 11
- C 19
- D 9.5
Show answer
Why:
The average of the two middle values.
- A 349 kg
- B 392 kg
- C 43 kg
- D 3,920 kg
Show answer
Why:
The mean times the number of values.
- A 39.2 kg
- B 35 kg
- C 43 kg
- D 741 kg
Show answer
Why:
Three hundred and ninety-two less 349.
- A dividing it by the number of values
- B adding the number of values to it
- C subtracting the smallest value from it
- D multiplying it by the number of values
Show answer
Why:
Everything else follows from that total.
- A 149
- B 134
- C 2,010
- D 8.93
Show answer
Why:
The mean times the number of values.
- A 381 coconuts
- B 400 coconuts
- C 384 coconuts
- D 256 coconuts
Show answer
Why:
Twenty-five point six times 15.
- A 387 coconuts
- B 384 coconuts
- C 381 coconuts
- D 369 coconuts
Show answer
Why:
Three coconuts were counted that were never picked.
- A 25.6
- B 25.4
- C 25.2
- D 26.0
Show answer
Why:
Three hundred and eighty-one over 15.
- A Both true, and the reason explains the assertion
- B Both true, but the reason does not explain it
- C The assertion is true and the reason is false
- D The assertion is false and the reason is true
Show answer
Why:
The assertion is true, since the total is the mean times the number of values. The reason is false: a mean says nothing at all about the extremes.
- A having to find the mean of the class at all
- B counting up the number of pupils altogether
- C using any division in the working
- D writing out a long list of every answer
Show answer
Why:
The table holds the same data far more compactly.
- A uses the wrong eight numbers
- B ignores how often each size occurs
- C divides when it should multiply
- D leaves out the size 10
Show answer
Why:
Finding a mean means adding all the values, not all the different values.
- A its own frequency
- B the number of different sizes
- C the total of all the frequencies
- D the largest frequency
Show answer
Why:
Three times 3, plus 4 times 11, and so on.
- A 52
- B 36
- C 180
- D 188
Show answer
Why:
That is the sum of all 36 family sizes.
- A the number of different sizes, 8
- B the total of the frequencies, 36
- C the largest family size, 10
- D the largest frequency, 11
Show answer
Why:
Every pupil contributes one value.
- A 5.22
- B 6.5
- C 4.7
- D 36
Show answer
Why:
One hundred and eighty-eight over 36.
- A 18 and 19
- B 17 and 18
- C 18 and 20
- D 36 and 37
Show answer
Why:
The two middle positions of 36.
- A each running total says where the next value begins in order
- B the running totals always add up to the mean of the table
- C the largest of the running totals is itself the median
- D a running total removes the need to count the values at all
Show answer
Why:
The totals say which value sits at any given position.
- A 4
- B 3
- C 23
- D 5
Show answer
Why:
The running total reached 14 at the fours and 23 at the fives.
- A 5.22
- B 5
- C 4
- D 6.5
Show answer
Why:
Both middle values are 5, so their average is 5.
- A I and II only
- B II and III only
- C I and III only
- D I, II and III
Show answer
Why:
The first and second hold. The third is false: the mean is 5.22 and the median is 5, so they are close but not equal.
- A the fifth
- B the seventh
- C the middle pair
- D the sixth
Show answer
Why:
With eleven values there is a single middle position.
- A at or above 29
- B below 29
- C exactly 29
- D above 73
Show answer
Why:
A p below 29 pushes an extra small value in front, so the sixth place falls back to 25.
Important short questions (7)
The median is the middle value once the data is sorted. It answers to counts of values, while the mean balances distances.
It rises. The new value is above 12, so there are now more values above 12 than below it, and 12 can no longer be the middle.
The total must be 29 times 5, which is 145. The four readings total 115, so the missing one is 30.
The recorded total was 24 times 10, which is 240. The true total is 234, so the corrected mean is 23.4.
The products are 2, 10, 24, 12 and 10, which total 58. The frequencies total 20, so the mean is 58 over 20, which is 2.9.
There are 20 values, so the median is the average of the 10th and 11th. The running totals are 2, then 7, then 15, so positions 8 to 15 all hold the value 3. The median is 3.
The mean is the total divided by the number of values, so multiplying it back by that number recovers the total exactly. Nothing in the mean records how the total was split up, though. The same mean can come from values that are all alike or from values spread very far apart, so the largest value could be almost anything.
Long answer questions (3)
The method turns on one move: a mean can be run backwards into a total. The mean is the total divided by the number of values. So the total must be the mean multiplied by that number. Here there are ten wrestlers and the mean is 39.2 kilograms. The ten weights together therefore come to 39.2 times 10, which is 392 kilograms. Now add up the nine weights that can be read: 42 plus 40 plus 39 plus 33 plus 48 plus 38 plus 42 plus 35 plus 32 comes to 349 kilograms. The missing weight is whatever makes the total right. So it is 392 less 349, which is 43 kilograms. Checking, 349 plus 43 is 392, and 392 over 10 is 39.2.
Averaging the eight different sizes gives 3 plus 4 and so on up to 10, which is 52, divided by 8, which is 6.5. That is wrong because finding a mean means adding all the values IN the data, not all the different values that appear. The size 4 occurs eleven times over, and a calculation that counts it once has thrown most of the data away. Done properly, each size is multiplied by its own frequency: 3 times 3, plus 4 times 11, plus 5 times 9, and so on. Those products are 9, 44, 45, 42, 21, 8, 9 and 10, which total 188. The divisor is the number of values, which is the total of the frequencies, namely 36. So the mean family size is 188 over 36, which is 5.22.
There are 36 values in the table, which is the total of the frequencies. Thirty-six is even, so the median is the average of the values at positions 18 and 19 once the data is sorted. Writing out all 36 numbers in order would work, but there is a shortcut. Add the frequencies from the smallest value upwards and keep a running total. The three threes give a running total of 3, so positions 1 to 3 hold the value 3. Adding the eleven fours brings the total to 14, so positions 4 to 14 hold the value 4. Adding the nine fives brings it to 23, so positions 15 to 23 all hold the value 5. Positions 18 and 19 both lie in that stretch, so both middle values are 5 and the median is 5.
Flashcards (17)
Play this topic
- Memory match
- Match the idea
- Can the mean alone answer it?
- Fact or myth
- Find the mean and median of a frequency table
Line graphs, and reading data honestly
A line graph shows how a quantity moves over time. Reading one properly means two separate steps: first setting down what is given, and only then saying what it means.
What you will be able to do
- Say when a line graph is the right picture to draw.
- Read the axes, the scale and the series of a graph.
- Separate what a graph shows from what it suggests.
- Compare two series on one pair of axes.
- Judge whether a claim is supported by a graph.
Key points
A line graph joins points to show change over time.
Reading one has two steps: identify, then infer.
The first step records the axes, the scale and the series.
The second step says what the pattern means.
Different marker shapes help when colour is unavailable.
How the data was gathered tells you its scope and limits.
Punjab varies by about 19 degrees across a year.
Kerala varies by only about 4 degrees.
A claim a graph does not touch is not supported by it.
Full explanation
Another way to draw data
Pictographs, bar graphs and dot plots are already familiar. A line graph is one more: the values are marked as points and then joined up by lines. That joining is the whole point of it.
What the joining is for
Lines between points suggest movement from one to the next, which makes a line graph the natural picture for data across TIME. A clustered column graph can carry the same numbers, but the line shows the direction of travel at a glance.
Two steps, kept apart
Reading a graph well means doing two separate things, and not muddling them. The first step is to identify what is given. The second is to infer and interpret. Rushing to the second is where most misreadings come from.
Step one in practice
Take a graph of monthly maximum temperature for Kerala and Punjab. Notice how the data is organised: each state has its own marked points joined by its own line. Notice the axes: months along the bottom, temperature in degrees up the side.
Why the markers differ in shape
The two series are drawn in different colours, but also with different marker shapes. That matters. A graph printed in black and white, or read by someone who finds colours hard to tell apart, still has to be distinguishable.
Step two for Punjab
Now interpret. Punjab’s monthly maximum climbs from about 19 degrees in January to a high of 38 in June. It then drops to just under 35 in July, stays near there until September, and falls steadily to about 23 by December.
Step two for Kerala
Kerala behaves quite differently. Its line stays nearly flat all year, peaking around 33 degrees in April and dipping to around 29 in July. Its monthly maximum in summer is much the same as in winter.
Putting the two together
The comparison is the useful part. Punjab reaches both colder and warmer figures than Kerala, swinging about 19 degrees across the year against Kerala’s 4. Punjab’s spread is close to five times as wide.
Where the numbers came from
It is worth asking how such a figure is produced. A state has several weather stations recording local temperature, and the monthly maximum is the largest value recorded anywhere in the state that month.
Why that question matters
Knowing how data was gathered tells you what it actually covers. It also shows up the limits: a missing station, or a bias in where the stations are, affects what the graph can honestly be used to say.
Questions a graph provokes
A good graph raises questions it cannot answer. Why do these two states behave so differently? What else decides a region’s temperature? Which other states look like Punjab, and what do they have in common? None of that is a failing of the graph. Showing a pattern clearly enough to provoke the question is most of what a graph is for.
Infographics
A line graph is not the only compact picture. An infographic can carry a great deal at once. One example maps, state by state, the difference between how much rice and how much wheat each person eats, shading each state by that difference.
Reading its scale carefully
The scale runs from minus 100 to plus 100, with a colour key in the corner. Plus 100 marks the largest difference in favour of rice. It does NOT mean the state eats no wheat at all, which is a quite different claim.
What such a picture can show
Read properly, the map shows something a table would hide: the preferences split along a clear geographical line. States near the middle of the scale are the ones eating roughly as much of one as the other.
Judging a claim against a graph
The last skill is the most useful. Given a graph and a statement, ask whether the graph supports it, contradicts it, or says nothing about it at all. The third case is the one people miss.
An example of the third case
A graph of lighting sources over the years can show that kerosene use fell and electricity use rose. It cannot show that there were no power cuts in 2023. Nothing on those axes records power cuts at all.
And a claim about a share
Equally, a graph showing that 10 per cent of urban households used electricity in some year supports a statement about that share. It supports nothing about how many households there were, unless the graph records that too.
Concepts and terms
Points joined by lines, used to show how a quantity changes across time.
First set down the axes, the scale and the series; only afterwards say what they mean.
Different shapes for different series, so the graph still reads in black and white.
What the figures actually cover, which depends on how and where they were gathered.
A statement the graph says nothing about, which the graph therefore cannot confirm.
Watch out
Common misconceptions
Four claims on the noticeboard
Scenario:
A school magazine prints a line graph of monthly maximum temperature for Kerala and Punjab, with months along the bottom and degrees up the side. Four pupils each pin a claim of their own beneath it. The first of them says Punjab varies far more across the year than Kerala. The second says Punjab is warmer than Kerala in every month. The third says the graph shows why the two states differ. The fourth says the graph proves that July was the wettest month in Kerala.
Analysis:
One claim the graph supports, one it contradicts, one asks for a cause, and one is about a quantity the graph never measured.
Test four claims against one graph
Title:
Test four claims against one graph
Safety:
Use a graph that is already published. Ask before cutting up anything that belongs to someone else.
What You Notice:
The disagreements are almost always about the third category. A claim that sounds reasonable can still be one the graph never measured.
Did you know
Giving each series its own marker shape, not just its own colour, keeps a graph readable in black and white and for readers who find colours hard to tell apart.
On the rice and wheat infographic, a value of plus 100 does not mean a state eats no wheat. It marks the largest difference in favour of rice, which is a different claim altogether.
Memory tricks
Identify before you infer — Write down what the graph actually shows first. Only then say what it means.
Practice MCQs with answers (25)
- A a dot plot
- B a pictograph
- C a clustered column graph
- D a line graph
Show answer
Why:
The joining is what sets it apart from the others.
- A place
- B category
- C colour
- D time
Show answer
Why:
Months, years and days all suit it.
- A infer what it means
- B identify what is given
- C compare it with another graph
- D estimate the missing values
Show answer
Why:
Rushing to interpretation causes most misreadings.
- A what caused the pattern
- B whether the trend will continue
- C which state is warmer
- D which series is which
Show answer
Why:
All of that belongs to identifying, not to inferring.
- A the graph is drawn to a large scale
- B the two states have the same temperature
- C the months are listed out of order
- D the graph is printed in black and white
Show answer
Why:
It also helps readers who find colours hard to tell apart.
- A 38 degrees
- B 35 degrees
- C 33 degrees
- D 23 degrees
Show answer
Why:
It then drops to just under 35 in July.
- A climbs again to a second peak in November
- B stays flat for the rest of the year
- C falls steadily to about 23 by December
- D rises sharply in October
Show answer
Why:
January is the lowest of its monthly maxima.
- A swings more than Punjab’s
- B stays nearly flat all year
- C has no clear peak at all
- D is highest in December
Show answer
Why:
It peaks around 33 degrees in April and dips to around 29 in July.
- A 9 degrees
- B 4 degrees
- C 14 degrees
- D 19 degrees
Show answer
Why:
Which makes Punjab’s spread close to five times as wide.
- A varies far more across the year than Kerala
- B is warmer than Kerala in every single month
- C is colder than Kerala in every single month
- D has much the same pattern as Kerala
Show answer
Why:
It reaches both colder and warmer figures than Kerala does.
- A the average across all of its weather stations
- B the reading at the capital city that month
- C the largest value recorded anywhere in the state
- D the smallest value recorded at any station
Show answer
Why:
Which is worth knowing before the figure is interpreted.
- A what the data actually covers, and its limits
- B whether every bit of the arithmetic is correct
- C which graph ought to be drawn next
- D how many values there are altogether
Show answer
Why:
A missing station or a bias in where they sit both matter.
- A Both true, and the reason explains the assertion
- B Both true, but the reason does not explain it
- C The assertion is true and the reason is false
- D The assertion is false and the reason is true
Show answer
Why:
The assertion is false and the reason is true. The graph records the movement but never its cause, which is exactly the kind of question a good graph provokes without answering.
- A an infographic
- B a line graph
- C a dot plot
- D a frequency table
Show answer
Why:
Compact and quick to read.
- A from minus 100 to plus 100
- B from 0 to 100
- C from minus 50 to plus 50
- D from 0 to 1
Show answer
Why:
With a colour key in the corner.
- A the difference in favour of rice is the largest
- B no wheat at all is eaten
- C rice and wheat are eaten in equal quantity there
- D exactly 100 kg of rice is eaten per head
Show answer
Why:
Which is a quite different claim from eating no wheat.
- A very little of either of the two grains is eaten
- B a great deal of both of the grains is eaten
- C the data was never collected at all
- D roughly as much of one grain is eaten as the other
Show answer
Why:
The scale measures the DIFFERENCE between the two.
- A rice is eaten more than wheat in the country overall
- B the figures have all been given per head
- C the preferences split along a clear geographical line
- D some of the states are larger than the others
Show answer
Why:
Which is the reason to draw a map rather than a table.
- A supports it or else contradicts it, nothing more
- B proves it or disproves it, and nothing besides
- C supports it, contradicts it, or is silent on it
- D is simply an accurate graph or an inaccurate one
Show answer
Why:
The third possibility is the one people miss.
- A kerosene use fell over the period
- B there were no power cuts in 2023
- C electricity use rose over the period
- D both series changed over the period
Show answer
Why:
Nothing on those axes records power cuts at all.
- A I and II only
- B II and III only
- C I and III only
- D I, II and III
Show answer
Why:
The first and third hold. The second is false: a graph settles only what its own axes record, and a claim it never measures is simply outside it.
- A what the percentage was
- B how many households there were
- C which year it was
- D whether the households were urban
Show answer
Why:
A share is not a count unless the total is recorded too.
- A what the temperature was in June
- B which month was coldest
- C what the vertical scale measures
- D why two states behave so differently
Show answer
Why:
The other three can all be read straight off it.
- A uses rather fewer numbers on the page
- B needs no vertical scale drawn in at all
- C shows the direction of travel at a glance
- D cannot be misread by any of its readers
Show answer
Why:
The lines make the movement visible.
- A identified everything before inferring
- B used the wrong axis of the two given
- C inferred before identifying what is given
- D read the scale on the wrong axis
Show answer
Why:
The two steps have a order for a reason.
Important short questions (7)
It marks the values as points and joins them with lines. It suits data that changes across time, since the lines suggest movement from one point to the next.
First identify what is given, such as the axes, the scale and the series. Then infer and interpret what the pattern means.
So that the graph still reads when it is printed in black and white. It also helps readers who find colours hard to tell apart.
Punjab swings about 19 degrees across the year, from about 19 in January to 38 in June. Kerala stays nearly flat, between about 29 and 33, so its spread is about 4 degrees.
Because it tells you what the figures actually cover. It also shows up limits, such as a missing station or a bias in where the stations sit, which affect what the graph can honestly be used to say.
That the difference in favour of rice is the largest on the scale. It does not mean that no wheat at all is eaten there.
The graph records which lighting source households mainly used, year by year. Nothing on either axis records power cuts, so the graph is simply silent on the question. A graph can support a claim, contradict it, or say nothing about it, and this is the third case.
Long answer questions (3)
The method keeps two things apart. The first step is to identify what is given, without interpreting any of it. Here that means noting the axes: months along the bottom and temperature in degrees up the side. It also means noting that each state has its own line, and that the two series carry different marker shapes as well as different colours. The second step is to infer. Punjab’s line climbs from about 19 degrees in January to a peak of 38 in June. It drops to just under 35 in July, holds near that until September, then falls to about 23 by December. Kerala’s line stays nearly flat, peaking around 33 in April and dipping to around 29 in July. So Punjab swings about 19 degrees across the year against Kerala’s 4, and reaches both colder and warmer figures.
A figure means nothing until you know what it measures. A state’s monthly maximum temperature is not one thermometer reading. Several weather stations across the state record local temperature through the month, and the monthly maximum is the largest value recorded anywhere in the state. Knowing that fixes the scope of the figure: it describes the hottest spot in the state on its hottest day, not a typical day anywhere. It also shows up the limits. If a region has no station, its temperatures never enter the figure at all. If the stations happen to sit mostly in cities, which are usually warmer than open country, the figure is biased upwards. Either way, knowing how the data was produced tells you how confidently the graph may be used.
A graph can support a claim, contradict it, or say nothing about it at all, and the third case is the one most often missed. Take a graph of household lighting sources across several decades, with one line for rural areas and one for urban. It SUPPORTS the claim that kerosene use as a main lighting source fell over the period, since both lines show exactly that. It CONTRADICTS the claim that electricity use fell, since the lines move the other way. And it says NOTHING about the claim that there were no power cuts in 2023, because power cuts appear nowhere on either axis. The test is simple: ask what the axes actually record. A claim about something they never measured is outside the graph, however reasonable it may sound.
Flashcards (17)
Play this topic
- Memory match
- Match the idea
- Identify or infer?
- Fact or myth
- Read a line graph properly
Class 8 Mathematics Chapter 12 — frequently asked questions
The total is 27 over 3 values, so the mean is 9. The midpoint of 6 and 13 is 9.5, so the mean is not the midpoint.
The total is 32 over 4 values, so the mean is 8. Below it the distances are 3 and 3, which is 6. Above it the distance is 6.
Nothing at all. The new value sits exactly at the balance point, so it adds nothing to either side.
The median is the middle value once the data is sorted. It answers to counts of values, while the mean balances distances.
It rises. The new value is above 12, so there are now more values above 12 than below it, and 12 can no longer be the middle.
The total must be 29 times 5, which is 145. The four readings total 115, so the missing one is 30.
It marks the values as points and joins them with lines. It suits data that changes across time, since the lines suggest movement from one point to the next.
First identify what is given, such as the axes, the scale and the series. Then infer and interpret what the pattern means.
So that the graph still reads when it is printed in black and white. It also helps readers who find colours hard to tell apart.
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