Class 7 Mathematics Chapter 15: Finding the Unknown

Finding the Unknown is Chapter 15 of NCERT / CBSE Class 7 Mathematics. This page has the complete chapter notes across 3 topics , 75 practice MCQs with answers and explanations , 30 important short and long questions and 51 flashcards — all written to the NCERT / CBSE syllabus and free to read.

What an equation says

An equation states that two expressions have the same value, as 3b + 4 = 19 states for a balanced scale. A solution is a value for the letter that makes the two sides agree, and any value can be tested by substituting it. Trial and error finds solutions reliably but slowly.

What you will be able to do

  • Write a balanced weighing scale as an equation, naming the letter.
  • State what an equation claims, and name its two sides.
  • Decide whether a given value is a solution, by substituting.
  • Form an equation from a situation and solve it by trying values.
  • Say what trial and error is good for, and where it is weak.

Key points

  • A level scale means its two pans weigh exactly the same.

  • Three bags and four blocks against nineteen gives 3b + 4 = 19.

  • An equation states that two expressions have the same value.

  • Its two sides are the parts beside the equals sign.

  • An equation claims the sides match; it never states the value.

  • A solution is a value making the two sides agree, as 5 does here.

  • Any value can be tested by substituting, and 6 gives 22, so fails.

  • Trial and error solves 2n + 1 = 41 at 20, and proves its answer.

  • It is slow, and nothing says which value to try next.

Full explanation

A scale that balances

Picture a weighing scale that is perfectly level. On the left pan sit three identical bags and four loose blocks. On the right pan sit nineteen loose blocks.

The scale balances, so the two pans weigh the same. How heavy is one bag?

Writing the balance down

Call the weight of one bag b, counted in blocks. Then the left pan weighs 3b + 4 and the right pan weighs 19.

Balanced means equal. So 3b + 4 = 19.

That is an equation

A statement that two expressions have the same value is called an equation. The line 3b + 4 = 19 is one.

The part on the left of the equals sign is the left side. The part on the right is the right side.

An equation is a claim

Notice what the equation does and does not say. It does not tell you what b is.

It makes a claim: whatever b stands for, these two amounts match. Finding that value is called solving the equation.

What a solution is

A solution is a value for the letter that makes the two sides agree.

Try b as 5. The left side becomes 3 times 5 plus 4, which is 19. The right side is 19. They agree, so 5 is the solution.

A value that is not a solution

Now try b as 6. The left side becomes 3 times 6 plus 4, which is 22, while the right side is still 19.

Twenty-two is not 19, so 6 is not a solution. Any value can be tested this way, which is one of the best features of an equation.

Forming an equation from a situation

Equations usually arrive as words rather than as symbols. A pattern of matchsticks might need 2n + 1 sticks at position n.

Asking which position uses 41 sticks is asking for the n that makes 2n + 1 equal 41. So the equation is 2n + 1 = 41.

Trying values

One way to find n is simply to try numbers. Start somewhere easy.

At n as 10 the left side is 21, far below 41. At n as 15 it is 31, closer but still short.

Closing in

At n as 19 the left side reaches 39. That is near, and only 2 away.

At n as 20 the left side is 41 exactly. So 20 is the solution, and the position wanted is the twentieth.

This method has a name

Trying values until one works is called the trial and error method. It is an honest method, and it always confirms its own answer.

It is also the first thing most people invent for themselves, which is a point in its favour.

But it is slow

Trial and error is slow, and it gets worse as the numbers grow. Solving 2n + 1 = 4001 by trying values would take a long while.

It is slower still when the answer is not a whole number. Nothing tells you which value to try next.

So something better is needed

Look again at the balance of bags and blocks. Nobody solves that by guessing bag weights.

You take four blocks off each pan, so the pans still match, and the problem gets smaller. That idea is the subject of the next topic.

One letter, one value

A last point about notation. In one equation the same letter always stands for the same number.

So in 5x - 4 = 26 both appearances of the number 5 and the single x behave consistently, and x turns out to be 6, since 5 times 6 is 30 and 30 less 4 is 26.

Two sides, two expressions

One more habit worth forming. Read each side of an equation as an expression in its own right.

The left side of 3b + 4 = 19 is an expression with a letter in it. The right side is an expression too, just a very short one.

An equation is not a formula

A formula tells you how to work something out, and every value is allowed. An equation makes a claim that only some values satisfy.

The difference matters. Asking to solve a formula makes no sense, and checking an equation always does.

What carries forward

An equation says two expressions have the same value, and the parts either side of the equals sign are its two sides. A solution is a value for the letter that makes those two sides agree, and you can always test a value by substituting it.

Trial and error finds solutions by trying values, as 20 solves 2n + 1 = 41. It is reliable but slow, and it offers no hint about what to try next. The balance suggests a better way: change both sides in the same way, and keep them equal.

Concepts and terms

The balance as an equation

A level scale means equal weight, so three bags and four blocks against nineteen blocks becomes 3b + 4 = 19.

What an equation is

A statement that two expressions have the same value, with its two sides standing either side of the equals sign.

A solution

A value for the letter that makes the two sides agree. Five solves 3b + 4 = 19, while 6 gives 22 and fails.

Forming an equation

Situations give equations. A pattern needing 2n + 1 sticks at position n uses 41 sticks when 2n + 1 = 41.

Trial and error

Trying values until one makes the sides agree. It proves its own answer but is slow, and offers no hint about the next value.

Watch out

Common misconceptions

The matchstick pattern and the bag of blocks

Scenario:

A class is given two puzzles. In the first, a scale balances three identical bags and four loose blocks against nineteen loose blocks. One pupil guesses that each bag weighs 6 blocks. In the second, a pattern of matchsticks needs 2n + 1 sticks at position n, and the class must find the position using 41 sticks. A pupil tries n as 19, gets 39, and says that is close enough. A third pupil complains that trial and error is not real mathematics at all.

Analysis:

Three claims, and each one can be settled by substituting.

Activity:

Make up three equations of your own, swap them with a partner, and solve them by trying values.

A balance made of coins

Title:

A balance made of coins

Safety:

Balance the ruler low down so nothing falls far.

What You Notice:

The loose coins on the far side should come to 19 if each envelope holds 5, giving 3b + 4 = 19. Trying values should reach b as 5, and opening the envelope confirms it.

Did you know

The equals sign in an equation states a fact, unlike the one in a sum, where it means work this out.

Trial and error is the one method that proves its own answer at the moment it finds it.

Solving unknowns with letters was called bijaganita in ancient India, from the word for a seed.

Memory tricks

Balanced means equal, both sides the same.

Substitute, and let the two sides argue.

Practice MCQs with answers (25)

Q1 A weighing scale is loaded on both sides and its beam comes to rest exactly level. A level scale shows that its two pans are beginner
  • A equal in size
  • B equal in weight
  • C equal in number of items
  • D empty of loose blocks
Show answer
Answer: equal in weight
Why:

Balanced means equal.

Q2 Three identical bags and four loose blocks are placed in one pan, with b standing for one bag. That pan weighs beginner
  • A 3b + 4
  • B 3 + 4b
  • C 3b - 4
  • D 4b + 3
Show answer
Answer: 3b + 4
Why:

Three bags, then the loose four.

Q3 That pan is balanced against nineteen loose blocks in the other pan, and the balance is written down. That gives the equation beginner
  • A 3b + 4 = 23
  • B 3b - 4 = 19
  • C 4b + 3 = 19
  • D 3b + 4 = 19
Show answer
Answer: 3b + 4 = 19
Why:

Balanced means the sides are equal.

Q4 Two expressions are written with an equals sign between them, claiming that they come to the same number. Such a statement is called beginner
  • A an equation
  • B a formula
  • C an expression
  • D a solution
Show answer
Answer: an equation
Why:

Not an instruction to do anything.

Q5 Lying to the left and the right of the equals sign are the equation and its beginner
  • A two solutions
  • B two sides
  • C two letters
  • D two methods
Show answer
Answer: two sides
Why:

Each one an expression.

Q6 An equation on its own never tells you intermediate
  • A the value of the letter
  • B which two sides match
  • C where the equals sign is
  • D what the letter is called
Show answer
Answer: the value of the letter
Why:

It only makes a claim.

Q7 A value is put in place of the letter and the two sides of the equation then come to the same number. Such a value is beginner
  • A a formula
  • B a side
  • C a solution
  • D an expression
Show answer
Answer: a solution
Why:

And it can be checked.

Q8 The value 5 is put in place of b in the left side of 3b + 4 = 19, and the arithmetic is worked out. That gives beginner
  • A 19
  • B 17
  • C 22
  • D 15
Show answer
Answer: 19
Why:

Three fives, then four.

Q9 That result shows 5 to be intermediate
  • A a solution of the equation
  • B too small to be a solution
  • C too large to be a solution
  • D equal to the right side only by chance
Show answer
Answer: a solution of the equation
Why:

Both sides come to 19.

Q10 The value 6 is tried instead in the same left side, to see whether it too makes the sides agree. That gives beginner
  • A 22
  • B 19
  • C 21
  • D 20
Show answer
Answer: 22
Why:

Three sixes, then four.

Q11 That result shows 6 to be intermediate
  • A a second solution
  • B not a solution at all
  • C the only solution
  • D a solution of the right side
Show answer
Answer: not a solution at all
Why:

Twenty-two is not 19.

Q12 Testable against any value at all by substituting is intermediate
  • A a weighing scale
  • B a bag of blocks
  • C an equation
  • D a position number
Show answer
Answer: an equation
Why:

Which is one of its best features.

Q13 A stick pattern needs 2n + 1 sticks at position n, and one position uses 41 sticks altogether. That position is given by intermediate
  • A 2n + 1 = 40
  • B 2n + 1 = 41
  • C 2n = 41
  • D n + 1 = 41
Show answer
Answer: 2n + 1 = 41
Why:

Set the expression equal to 41.

Q14 Substituting 10 into 2n + 1 gives beginner
  • A 20
  • B 11
  • C 21
  • D 41
Show answer
Answer: 21
Why:

Two tens, then one.

Q15 Substituting 15 into 2n + 1 gives beginner
  • A 30
  • B 16
  • C 31
  • D 41
Show answer
Answer: 31
Why:

Two fifteens, then one.

Q16 Substituting 19 into 2n + 1 gives intermediate
  • A 38
  • B 41
  • C 39
  • D 40
Show answer
Answer: 39
Why:

Only two short of 41.

Q17 Values are tried in 2n + 1 = 41 until one of them makes both sides agree exactly. Solving it gives n as intermediate
  • A 19
  • B 21
  • C 40
  • D 20
Show answer
Answer: 20
Why:

Two twenties and one more.

Q18 An equation is solved by putting in one value after another until the sides agree. That way of working is called beginner
  • A the balancing method
  • B the substitution rule
  • C the inverse operation rule
  • D the trial and error method
Show answer
Answer: the trial and error method
Why:

An honest method, and a slow one.

Q19 Why does trial and error prove its own answer at the moment it succeeds? advanced
  • A The method tries every possible value before it reports one
  • B The value tried has made the two sides agree, which is the test
  • C A value that fails once can never succeed later in the search
  • D The number of tries needed is recorded alongside the answer
Show answer
Answer: The value tried has made the two sides agree, which is the test
Why:

A solution is defined as a value making the sides agree. The successful trial IS the substitution that checks it.

Q20 Assertion: Trial and error is made easier when the answer is not a whole number. Reason: Nothing in the method says which value to try next. advanced
  • A Both true, and the reason explains the assertion
  • B Both true, but the reason does not explain it
  • C The assertion is true and the reason is false
  • D The assertion is false and the reason is true
Show answer
Answer: The assertion is false and the reason is true
Why:

The reason is true and the assertion is false: a fractional answer makes the search far harder, because there is no next value to reach for.

Q21 Solving 2n + 1 = 4001 by trying values would be intermediate
  • A quick and easy
  • B impossible in principle
  • C slow but possible
  • D wrong as a method
Show answer
Answer: slow but possible
Why:

The method does not fail, it just drags.

Q22 Removing four blocks from each pan of a balanced scale leaves it intermediate
  • A tipped to the left
  • B tipped to the right
  • C impossible to read
  • D still balanced
Show answer
Answer: still balanced
Why:

Equal amounts came off both.

Q23 The equation 5x - 4 = 26 is to be solved, so a value is wanted that makes both sides agree. Solving it gives x as intermediate
  • A 5
  • B 7
  • C 30
  • D 6
Show answer
Answer: 6
Why:

Five sixes less four.

Q24 Appearing twice in one equation, the same letter stands for advanced
  • A a different number each time
  • B any number at all
  • C the same number both times
  • D the number of sides
Show answer
Answer: the same number both times
Why:

One letter, one value.

Q25 Consider these statements about an equation. I. An equation also states what that value is. II. A solution is a value that makes the two sides agree. III. It states that two expressions have the same value. Which statements are correct? advanced
  • A I and II only
  • B II and III only
  • C I and III only
  • D I, II and III
Show answer
Answer: II and III only
Why:

II and III are true. The first fails: 3b + 4 = 19 claims the sides match and leaves the 5 to be found.

Important short questions (7)

Three bags and four blocks balance nineteen blocks. Write this as an equation, explaining your letter.

Let b stand for the weight of one bag, counted in blocks. The left pan weighs 3b + 4 and the right weighs 19, so 3b + 4 = 19.

What is an equation, and what are its two sides?

An equation is a statement that two expressions have the same value. Its two sides are the parts standing to the left and the right of the equals sign.

Explain why an equation is a claim rather than an answer.

It never states the value of the letter. It claims only that the two sides match for the right value, and finding that value is what solving means.

Check whether 5 and whether 6 solve 3b + 4 = 19.

At 5 the left side is 3 times 5 plus 4, which is 19, matching the right, so 5 is a solution. At 6 the left side is 22, which is not 19, so 6 is not.

A pattern uses 2n + 1 sticks at position n. Form and solve the equation for 41 sticks.

The equation is 2n + 1 = 41. Trying values, n as 19 gives 39 and n as 20 gives 41, so the solution is 20 and the position is the twentieth.

Give one strength and one weakness of trial and error.

Its strength is that it confirms its own answer, since the sides are seen to agree. Its weakness is that it is slow and gives no hint about what value to try next.

How does an equation differ from a formula?

A formula shows how to work something out and allows every value. An equation claims two expressions match, which only some values do, so only an equation can be solved.

Long answer questions (3)

A scale balances three bags and four blocks against nineteen blocks. Form the equation, find the bag weight, and prove your answer is right.

Start by naming the unknown. Let b be the weight of one bag, counted in blocks. The left pan then holds 3b + 4 blocks worth and the right pan holds 19. A level scale means the pans weigh the same, so the equation is 3b + 4 = 19. Now look for a value of b that makes the two sides agree. Trying 4 gives a left side of 16, which is short. Trying 5 gives 3 times 5 plus 4, which is 19, and the right side is 19 as well. So one bag weighs 5 blocks. The proof is the substitution itself. Putting 5 back in makes the left side 19 and the right side 19, so the claim the equation makes is true at that value. Trying 6 gives 22, which fails, so 5 is not a lucky guess among many.

Explain what a solution of an equation is, and why every claimed solution can be checked. Use 2n + 1 = 41.

An equation claims that two expressions have the same value. It does not say what the letter stands for. A solution is a value for the letter that makes the claim come true, which is to say it makes the two sides agree. Because the claim is about values, any proposal can be tested simply by putting it in. Take 2n + 1 = 41. Try n as 15. The left side becomes 31 and the right stays 41, so they disagree and 15 is not a solution. Try n as 19. The left side is 39, which is still not 41. Try n as 20. The left side is 41 and so is the right, so 20 is a solution. Nothing has been taken on trust at any point, which is what makes an equation such a useful kind of statement.

Describe the trial and error method, say honestly where it is weak, and explain what the weighing scale suggests instead.

Trial and error means trying values for the letter until one makes the two sides agree. Most people invent it for themselves. It also has a real virtue. The moment it succeeds it has already proved its own answer, because the two sides have been seen to match. Solving 2n + 1 = 41 that way gives 21 at n as 10, then 31 at 15, then 39 at 19, and finally 41 at 20. The weakness is speed. Solving 2n + 1 = 4001 that way would drag, and nothing tells you which value to try next. If the answer is not a whole number, the guessing may never land on it. The scale suggests better. Take four blocks off each pan, so the pans still match, and the problem has got smaller.

Flashcards (17)

What does a level weighing scale tell you?
The two pans weigh exactly the same.
Write three bags and four blocks against nineteen blocks as an equation.
Three b plus 4 equals 19, with b for one bag.
What is an equation?
A statement that two expressions have the same value.
What are the two sides of an equation?
The parts to the left and right of the equals sign.
What does an equation NOT tell you?
The value of the letter.
What is a solution of an equation?
A value for the letter that makes the two sides agree.
Check whether 5 solves 3b + 4 = 19.
Yes, since 3 times 5 plus 4 is 19, matching the right side.
Check whether 6 solves 3b + 4 = 19.
No, since the left side becomes 22 and the right stays 19.
A pattern needs 2n + 1 sticks at position n. Which position uses 41?
The twentieth, since 2 times 20 plus 1 is 41.
What does n as 15 give in 2n + 1?
Thirty-one.
What does n as 19 give in 2n + 1?
Thirty-nine, only 2 short.
What is the trial and error method?
Trying values until one makes the two sides agree.
What is the drawback of trial and error?
It is slow, and nothing says what to try next.
Solve 5x - 4 = 26.
Six, since 5 times 6 is 30 and 30 less 4 is 26.
What does the balance suggest instead of guessing?
Changing both sides in the same way, keeping them equal.
How does an equation differ from a formula?
A formula allows every value; an equation is satisfied by only some.
In one equation, what does a repeated letter stand for?
The same number every time it appears.

Play this topic

  • Match each value to what it gives in 2n + 1
  • Solution, or not a solution?
  • Fact or myth
  • Order these steps for solving 2n + 1 = 41 by trying values
  • Match each term to its meaning

Solving an equation step by step

Do the same thing to both sides, and keep going until the letter stands alone. It is allowed because the two sides name one value. Each step is chosen by its inverse: subtract an added number, divide by a multiplier, multiply by a divisor. Gather letters on one side first, then check by substituting.

What you will be able to do

  • Solve an equation by doing the same thing to both sides.
  • Explain why changing both sides in the same way is allowed.
  • Choose each step using inverse operations.
  • Solve equations with a subtracted letter, a divisor, or letters twice.
  • Use an inverse operation to shortcut an arithmetic value.

Key points

  • Do exactly the same thing to both sides, every step.

  • It is allowed because the two sides name one and the same value.

  • All four operations may be used, but never dividing by zero.

  • Subtract an added number: 4a + 9 = 37 becomes 4a = 28.

  • Divide by a multiplier: 4a = 28 becomes a = 7.

  • Multiply by a divisor: c/4 = 4 becomes c = 16.

  • Take care with signs: 20 - 3b = 5 gives -3b = -15, so b = 5.

  • Gather letters first: 7d - 2 = 5d + 12 gives 2d - 2 = 12, so d = 7.

  • Always check by substituting into the original equation.

Full explanation

Back to the scale

Nobody solves a balance puzzle by guessing. If both pans hold four loose blocks, you take those four off each pan.

The scale is still level, and the puzzle is simpler. That single move is the whole method of this topic.

Doing the same to both sides

Here is the rule. Whatever you do to one side of an equation, do exactly the same to the other.

Then the two sides still have the same value, so the equation still says something true. The letter has not changed, so its solution has not changed either.

Why it is allowed

The reason is worth stating plainly. An equation says its two sides name one and the same value.

So one operation applied to that value gives one answer, however it is written. Both sides must still match.

A first equation

Take 4a + 9 = 37. The 9 is in the way, so subtract 9 from both sides.

The left side becomes 4a and the right becomes 28. So 4a = 28.

Finishing it

Now 4a is four copies of a. Divide both sides by 4.

The left side becomes a and the right becomes 7. So a = 7.

Always check

The check costs one line. Put 7 back into the original equation.

Four sevens are 28, and 28 plus 9 is 37, which is the right side. So 7 is correct, and nothing was taken on trust.

All four operations are allowed

Adding, subtracting, multiplying and dividing all work, as long as you do them to both sides. Dividing by zero is the one thing never allowed.

Usually you choose the operation that removes something. That is why subtracting 9 was the sensible first move above.

Inverse operations

Subtracting undoes adding, and dividing undoes multiplying. Pairs like that are called inverse operations.

So you remove an added 9 by subtracting 9, and remove a multiplier of 4 by dividing by 4. The inverse is how you choose the step.

A useful shortcut

Inverses also save work on plain arithmetic. Suppose you are told that 582 - 47 + 19 - 8 + 64 = 610.

To find 582 - 47 + 19 - 8, subtract 64 from both sides. The answer is 546, and nothing had to be worked out from scratch.

And with multiplication

The same trick works the other way round. Suppose 13 times 7 times 5 times 4 comes to 1820.

Then 13 times 7 times 5 is found by dividing both sides by 4, which gives 455.

When the letter is subtracted

Now 20 - 3b = 5. Here the letter is being taken away, which looks harder.

Subtract 20 from both sides, giving -3b = -15. Then divide both sides by -3, which gives b = 5. Checking, 20 less 15 is 5.

When the letter has a divisor

Try c/4 + 6 = 10. Subtract 6 from both sides, giving c/4 = 4.

Now multiply both sides by 4, since multiplying undoes dividing. That gives c = 16, and 16 divided by 4 plus 6 is indeed 10.

Letters on both sides

Sometimes the letter appears twice. Take 7d - 2 = 5d + 12.

The first job is to gather the letters on one side. Subtract 5d from both sides, which leaves 2d - 2 = 12.

Finishing that one

Now the equation looks like the first one. Add 2 to both sides, giving 2d = 14.

Divide both sides by 2, so d = 7. Checking, the left side is 47 and so is the right.

Nothing actually moves

One habit to drop. People often say a number moves across the equals sign and changes its sign on the way.

Nothing moves anywhere. You subtracted 9 from both sides, and that is the only reason the 9 turns up as a subtraction on the right.

A routine, not a trick

Notice the shape of all four solutions. Gather the letters, remove what is added or subtracted, then undo the multiplier or divisor.

Every step is the same change to both sides, and every answer is checked by substituting. There is nothing to remember beyond that.

What carries forward

To solve an equation, do the same thing to both sides, and keep doing it until the letter stands alone. This is allowed because the two sides name one value, so one operation on both leaves them equal.

Choose each step by its inverse: subtract an added number, divide by a multiplier, multiply by a divisor. Gather letters on one side first when the letter appears twice. And always finish by substituting the answer back into the original equation.

Concepts and terms

The rule

Whatever you do to one side of an equation, do exactly the same to the other, until the letter stands alone.

Why it is allowed

The two sides name one value, so one operation applied to both gives one answer and they still match.

Inverse operations

Subtracting undoes adding and dividing undoes multiplying, which is how each step is chosen.

Letters on both sides

Gather them onto one side first. Subtracting 5d from both sides of 7d - 2 = 5d + 12 leaves 2d - 2 = 12.

Checking the answer

Substitute the answer into the original equation and compare the two sides. It costs one line and proves the result.

Watch out

Common misconceptions

Four equations on a blackboard

Scenario:

A teacher writes four equations for the class. They are 4a + 9 = 37, then 20 - 3b = 5, then c/4 + 6 = 10, and finally 7d - 2 = 5d + 12. One pupil begins the first by dividing both sides by 4. Another begins the second by writing 3b = 5 + 20. A third looks at the fourth equation and says it cannot be done. Her reason is that the letter sits on both sides at once. So there is nothing left to work towards, and no side for the answer to end up on. The rest of the class is unsure whether she is right.

Analysis:

Three pupils, three different habits, and one rule that settles all of them.

Activity:

Write four equations of your own, one of each kind, and solve them with the steps and checks written out.

Undo it with a partner

Title:

Undo it with a partner

Safety:

No hazards here.

What You Notice:

Your partner should recover the secret number every time, because each step undoes exactly one operation. The subtracted-letter version is where signs usually go wrong.

Did you know

Nothing ever travels across the equals sign; the sign appears to flip only because the same operation was done to both sides.

Dividing by zero is the single operation barred from both sides, since no number results from it.

An inverse operation tells you which step to take next, which is exactly what trial and error could not do.

Memory tricks

Same to both sides, every time.

Added, so subtract; times, so divide.

Practice MCQs with answers (25)

Q1 A scale is level and four loose blocks are lifted off each pan, leaving fewer blocks on both sides. Doing that leaves it beginner
  • A still level, and simpler
  • B tipped to the left
  • C tipped to the right
  • D impossible to read
Show answer
Answer: still level, and simpler
Why:

Equal amounts came off both.

Q2 Why must every step treat the two sides of an equation alike? advanced
  • A The two sides name one value, so both must change alike
  • B Each side needs whatever will make the letter stand alone
  • C Doing nothing at all would leave the equation unsolved
  • D Opposite things on the two sides cancel each other out
Show answer
Answer: The two sides name one value, so both must change alike
Why:

A level scale stays level only if the same weight leaves both pans. Treating the sides differently breaks the equality itself.

Q3 Both sides may be changed in the same way because they advanced
  • A contain the same letter
  • B are the same length
  • C have the same number of terms
  • D name one and the same value
Show answer
Answer: name one and the same value
Why:

So one operation gives one answer.

Q4 An equation can be worked on with addition, subtraction, multiplication and division alike, provided both sides are treated the same. Usable that way, the operations number intermediate
  • A two
  • B one
  • C four
  • D three
Show answer
Answer: four
Why:

Add, subtract, multiply, divide.

Q5 Assertion: Dividing both sides of an equation by zero is never allowed. Reason: A division by zero has no answer at all. advanced
  • A Both true, and the reason explains the assertion
  • B Both true, but the reason does not explain it
  • C The assertion is true and the reason is false
  • D The assertion is false and the reason is true
Show answer
Answer: Both true, and the reason explains the assertion
Why:

Both are true and the second explains the first. A step has to leave a statement that still means something.

Q6 The equation 4a + 9 = 37 is to be solved, and the added number has to go before the multiplier can. The sensible first step is to subtract beginner
  • A 9 from both sides
  • B 4 from both sides
  • C 37 from both sides
  • D 9 from the left side only
Show answer
Answer: 9 from both sides
Why:

The 9 is in the way.

Q7 Nine is taken from both sides of 4a + 9 = 37, which leaves a simpler equation behind. That step turns it into beginner
  • A 4a = 28
  • B 4a = 46
  • C 4a = 37
  • D a = 28
Show answer
Answer: 4a = 28
Why:

Thirty-seven less nine.

Q8 The equation has reached 4a = 28, so the multiplier has to be undone to leave a standing alone. Finishing needs both sides divided by beginner
  • A 28
  • B 4
  • C 7
  • D 2
Show answer
Answer: 4
Why:

Four a is four copies of a.

Q9 Solving 4a + 9 = 37 therefore gives a as beginner
  • A 28
  • B 4
  • C 7
  • D 9
Show answer
Answer: 7
Why:

Twenty-eight over four.

Q10 The answer 7 is substituted back into the original left side to see whether it rebuilds the right side. The left side comes to intermediate
  • A 28
  • B 34
  • C 40
  • D 37
Show answer
Answer: 37
Why:

Four sevens, then nine.

Q11 Consider these statements about solving an equation. I. The same thing must be done to both sides at every step. II. Dividing both sides by zero is allowed like any other division. III. That is allowed because the two sides name one and the same value. Which statements are correct? advanced
  • A I and II only
  • B II and III only
  • C I and III only
  • D I, II and III
Show answer
Answer: I and III only
Why:

I and III are true. The second fails: division by zero has no answer, so it is the one operation barred.

Q12 Removed from an equation by subtracting 9 from both sides is intermediate
  • A a multiplier of 9
  • B a divisor of 9
  • C an added 9
  • D a subtracted 9
Show answer
Answer: an added 9
Why:

Subtracting undoes adding.

Q13 Removed from an equation by dividing both sides by 4 is intermediate
  • A an added 4
  • B a divisor of 4
  • C a multiplier of 4
  • D a subtracted 4
Show answer
Answer: a multiplier of 4
Why:

Dividing undoes multiplying.

Q14 Removed from an equation by multiplying both sides by 4 is advanced
  • A a divisor of 4
  • B a multiplier of 4
  • C an added 4
  • D a subtracted 4
Show answer
Answer: a divisor of 4
Why:

Multiplying undoes dividing.

Q15 Given that 582 - 47 + 19 - 8 + 64 = 610, the value of 582 - 47 + 19 - 8 is advanced
  • A 674
  • B 546
  • C 610
  • D 528
Show answer
Answer: 546
Why:

Six hundred and ten less 64.

Q16 That answer was reached by subtracting 64 from intermediate
  • A the left side only
  • B both sides
  • C the right side only
  • D neither side
Show answer
Answer: both sides
Why:

Which keeps the equality.

Q17 Given that 13 times 7 times 5 times 4 is 1820, the value of 13 times 7 times 5 is advanced
  • A 1816
  • B 7280
  • C 455
  • D 364
Show answer
Answer: 455
Why:

One thousand eight hundred and twenty over four.

Q18 The equation 20 - 3b = 5 has 20 taken from both of its sides, and the sign in front of the 3b matters. That step gives advanced
  • A -3b = 25
  • B -3b = -15
  • C 3b = 15
  • D -3b = 15
Show answer
Answer: -3b = -15
Why:

Five less twenty.

Q19 Dividing both sides of that by -3 gives b as advanced
  • A -5
  • B 5
  • C 15
  • D -15
Show answer
Answer: 5
Why:

A negative divided by a negative.

Q20 Subtracting 6 from both sides of c/4 + 6 = 10 gives intermediate
  • A c/4 = 16
  • B c = 4
  • C c/4 = 10
  • D c/4 = 4
Show answer
Answer: c/4 = 4
Why:

Ten less six.

Q21 Both sides of c/4 = 4 must then be multiplied by intermediate
  • A 6
  • B 10
  • C 16
  • D 4
Show answer
Answer: 4
Why:

Multiplying undoes dividing.

Q22 The equation c/4 + 6 = 10 has the 6 subtracted and is then multiplied through by 4. Solving it gives c as intermediate
  • A 4
  • B 16
  • C 40
  • D 64
Show answer
Answer: 16
Why:

Four fours.

Q23 With the letter on both sides of 7d - 2 = 5d + 12, the first job is to advanced
  • A divide both sides by 7
  • B add the two letter terms together
  • C subtract 12 from both sides
  • D gather the letters on one side
Show answer
Answer: gather the letters on one side
Why:

Subtract the smaller letter term.

Q24 Subtracting 5d from both sides of 7d - 2 = 5d + 12 gives advanced
  • A 2d = 12
  • B 12d - 2 = 12
  • C 2d - 2 = 10
  • D 2d - 2 = 12
Show answer
Answer: 2d - 2 = 12
Why:

Seven d less five d.

Q25 Solving 7d - 2 = 5d + 12 therefore gives d as advanced
  • A 5
  • B 14
  • C 12
  • D 7
Show answer
Answer: 7
Why:

Fourteen halved.

Important short questions (7)

State the rule for solving an equation, and why it is allowed.

Do exactly the same thing to both sides, until the letter stands alone. It is allowed because the two sides name one value, so one operation on both leaves them equal.

Solve 4a + 9 = 37, showing each step.

Subtract 9 from both sides, giving 4a = 28. Divide both sides by 4, giving a = 7. Checking, four sevens are 28 and 28 plus 9 is 37.

What are inverse operations, and how do they choose a step?

They are pairs that undo each other, such as adding and subtracting, or multiplying and dividing. You remove an added number by subtracting it, and a multiplier by dividing.

Given that 582 - 47 + 19 - 8 + 64 = 610, find 582 - 47 + 19 - 8 without working it out.

Subtract 64 from both sides, which removes the 64 on the left. So the expression equals 610 less 64, which is 546.

Solve 20 - 3b = 5, showing each step.

Subtract 20 from both sides, giving -3b = -15. Divide both sides by -3, giving b = 5. Checking, 20 less three fives is 5.

Solve c/4 + 6 = 10, showing each step.

Subtract 6 from both sides, giving c/4 = 4. Multiply both sides by 4, giving c = 16. Checking, 16 divided by 4 is 4, and 4 plus 6 is 10.

Solve 7d - 2 = 5d + 12, showing each step.

Subtract 5d from both sides, giving 2d - 2 = 12. Add 2 to both sides, giving 2d = 14. Divide by 2, so d = 7, and both sides come to 47.

Long answer questions (3)

Solve 4a + 9 = 37 step by step, saying why each step is allowed, and check the answer.

The aim is to leave the letter alone on one side. Begin with the 9, which is added on the left. Subtract 9 from both sides. That is allowed because the two sides name one value, so taking 9 off that value leaves the two still equal. The left becomes 4a and the right becomes 28, so 4a = 28. Now 4a means four copies of a, so divide both sides by 4. Again both sides are treated the same, so they stay equal. The left becomes a and the right becomes 7, so a = 7. Finally check the answer in the original equation. Four sevens are 28, and 28 plus 9 is 37, which is exactly the right side. So 7 is correct, and no step was taken on trust.

Explain what inverse operations are, and use them on three different kinds of step.

Two operations are inverse when each undoes the other. Adding and subtracting are a pair, and so are multiplying and dividing. Inverses matter because they choose your next step: to get rid of something, apply its inverse to both sides. Here are three kinds. First an added number. In 4a + 9 = 37 the 9 is added, so subtract 9 from both sides and 4a = 28 remains. Second a multiplier. In that result a is multiplied by 4, so divide both sides by 4, leaving a = 7. Third a divisor. In c/4 + 6 = 10, clear the 6 first to get c/4 = 4, where c is divided by 4, so multiply both sides by 4 and c = 16. Each time the inverse removed exactly one obstacle.

Solve 7d - 2 = 5d + 12 and 20 - 3b = 5, explaining the extra care each one needs.

The first has the letter on both sides, so the letters must be gathered before anything else. Subtract 5d from both sides. The left becomes 2d - 2 and the right becomes 12. Now add 2 to both sides, giving 2d = 14, and divide both sides by 2, so d = 7. Checking, the left side is 47 and so is the right. The second has the letter being subtracted, which is where signs go wrong. Subtract 20 from both sides. The left becomes -3b and the right becomes -15. Now divide both sides by -3. A negative divided by a negative is positive, so b = 5. Checking, three fives are 15, and 20 less 15 is 5. Both answers are confirmed.

Flashcards (17)

What is the rule for solving an equation?
Do exactly the same thing to both sides.
Why may both sides be changed in the same way?
They name one and the same value, so one operation gives one answer.
Which operations may be used on both sides?
Adding, subtracting, multiplying and dividing.
What is the first step in solving 4a + 9 = 37?
Subtract 9 from both sides, giving 4a = 28.
Finish solving 4a = 28.
Divide both sides by 4, so a = 7.
Check that 7 solves 4a + 9 = 37.
Four sevens are 28, and 28 plus 9 is 37, matching the right side.
What are inverse operations?
Pairs that undo each other, like adding and subtracting.
How do you remove a multiplier of 4?
Divide both sides by 4.
How do you remove a divisor of 4?
Multiply both sides by 4.
Given 582 - 47 + 19 - 8 + 64 = 610, find 582 - 47 + 19 - 8.
Five hundred and forty-six, by subtracting 64 from both sides.
Given 13 times 7 times 5 times 4 is 1820, find 13 times 7 times 5.
Four hundred and fifty-five, by dividing both sides by 4.
Solve 20 - 3b = 5.
Subtract 20 to get -3b = -15, then divide by -3, so b = 5.
Solve c/4 + 6 = 10.
Subtract 6 to get c/4 = 4, then multiply by 4, so c = 16.
What is the first job when the letter appears on both sides?
Gather the letters onto one side.
Solve 7d - 2 = 5d + 12.
Subtract 5d to get 2d - 2 = 12, then add 2 and halve, so d = 7.
What is the general shape of every solution here?
Gather letters, remove what is added, then undo the multiplier.
What is the one operation never allowed on both sides?
Dividing by zero.

Play this topic

  • Match each obstacle to the step that removes it
  • Allowed on both sides, or never allowed?
  • Fact or myth
  • Order these steps for solving 7d - 2 = 5d + 12
  • Match each term to its meaning

Checking a solution, and mending mistakes

Substituting an answer into the original equation takes one line. It is the only part of the work that proves anything. Five common mistakes all come from using a real rule in the wrong place. So the working looks tidy, and all five are caught by that one check.

What you will be able to do

  • Check a solution by substituting it into the original equation.
  • Say why the check must use the original and not a later line.
  • Name and mend five common mistakes in solving an equation.
  • Recompute what a faulty line gives, and show its check fails.
  • Describe how to hunt for a mistake once a check has failed.

Key points

  • Checking takes one line and is the only part that proves anything.

  • Substitute into the ORIGINAL equation, never a later line.

  • A wrong line always agrees with the wrong answer it produced.

  • An added 5 must be subtracted from both sides, not carried over.

  • In 12 - 5y = 2 the minus before the 5y must not be dropped.

  • A letter on the right is removed by subtracting it from both sides.

  • A letter term cannot be dropped mid-line: 10w - 4w is simply 6w.

  • Dividing a side means dividing all of it, not one term.

  • A failed check proves a mistake exists, though not where it is.

Full explanation

The cheapest step in algebra

Solving an equation takes several lines. Checking the answer takes one.

That one line is the only part of the work that proves anything. It is also the part most often skipped.

How to check

Take your answer and put it into the original equation, not into any of your own later lines. Work out the left side and the right side separately.

If the two agree, the answer is right. If they do not, something earlier was wrong.

A check that passes

Solve 6x + 5 = 29. Subtracting 5 from both sides gives 6x = 24, and dividing by 6 gives x = 4.

Now check. Six fours are 24, and 24 plus 5 is 29, which is the right side. So 4 is correct.

A check that fails

Suppose someone solving the same equation wrote 6x = 29 + 5 instead. That gives 6x = 34, and then x = 17/3.

Check it. Six times 17/3 is 34, and 34 plus 5 is 39, not 29. The check exposes the slip at once.

Mistake one: the sign

Look at what went wrong there. The 5 was added on the left, so it must be subtracted from both sides.

Writing 29 + 5 treats the 5 as though it hopped over the equals sign and kept its sign. It should have become a subtraction.

Mistake two: a subtracted letter

Now 12 - 5y = 2. A common line here is 5y = 12 + 2, giving 5y = 14 and then y = 14/5.

Check it: 12 less 14 is -2, not 2. Done properly, subtract 12 from both sides for -5y = -10, so y = 2. And 12 less 10 is 2.

Mistake three: gathering with the wrong sign

Try 3z + 4 = z + 16. A tempting line is 3z + z = 16 - 4, giving 4z = 12 and z = 3.

But the z on the right must be SUBTRACTED from both sides, not added. The right line is 3z - z = 16 - 4, so 2z = 12 and z = 6.

Checking that one

Test the wrong answer first. At z as 3 the left side is 13 and the right side is 19, which disagree.

Now the right answer. At z as 6 the left side is 22 and so is the right. The check settles which is which.

Mistake four: a letter term read as a number

Here is 10w - 4w = 30. Someone writes 10w = 30 + 4w and then 10w = 30, giving w = 3.

The 4w cannot be dropped halfway through a line. There is no need to move it at all: 10w - 4w is just 6w, so 6w = 30 and w = 5. And 50 less 20 is 30.

Mistake five: dividing only one term

Last, 2v + 3 = -9. Someone divides the left side by 2 and writes v + 3 = -9/2.

Dividing a side by 2 means dividing all of it, so the 3 must be halved too. Better still, subtract 3 from both sides first: 2v = -12, so v = -6.

What the five have in common

Not one of these is careless arithmetic. Each is a rule applied in the wrong place, which is why the working looks so tidy.

That is exactly why a check is needed. Tidy working is not evidence of a right answer.

The check catches all five

Run the substitution on each wrong answer and all five fail. The checks give 39 against 29, then -2 against 2, then 13 against 19, then 18 against 30, and then -12 against -9.

One method catches every kind of slip. You do not have to remember the list.

When the check fails

A failed check does not tell you where the mistake is. It tells you that there is one, which is already worth a great deal.

Then read your working back line by line, asking of each step what was done to both sides. The line where the answer stops being honest is the line to mend.

Where this all comes from

Solving for unknowns with letters has a long history in India. The subject was called bijaganita, from the word bija, meaning a seed.

The idea is that an answer lies hidden inside a problem as a tree lies hidden in a seed. Brahmagupta set out rules for working with unknown numbers in his book of 628 CE.

What carries forward

Check every answer by substituting it into the original equation and comparing the two sides. It is one line, it is the only part that proves anything, and it catches every kind of mistake.

The five slips in this topic all come from applying a rule in the wrong place: keeping a sign when a term should change, adding a letter term that should be subtracted, dropping a letter term, or dividing only part of a side. Ask of every line what was done to both sides, and these cannot survive.

Concepts and terms

How to check

Put the answer into the original equation, work out the two sides separately, and compare them.

Why the original

A faulty line agrees with the wrong answer it produced, so only the original equation is a real test.

Mistakes of sign

Writing 29 + 5 keeps the sign of an added 5, and 5y = 12 + 2 also loses the minus in front of the letter term.

Mistakes with terms

Adding a letter term that should be subtracted, or dropping one mid-line, both give tidy working and a wrong answer.

Dividing a whole side

Halving 2v + 3 means halving the 3 as well. Clearing the 3 first is simpler, giving 2v = -12.

Watch out

Common misconceptions

Marking a page of homework

Scenario:

A teacher collects four answers and marks none of them yet. The first pupil solved 6x + 5 = 29 and wrote 6x = 29 + 5, reaching 17/3. The second solved 3z + 4 = z + 16 by writing 3z + z = 16 - 4, reaching 3. The third solved 10w - 4w = 30 by writing 10w = 30 + 4w and then 10w = 30, reaching 3. The fourth solved 2v + 3 = -9 by dividing the left side by 2, reaching -9/2 less 3. Every page looks neat, and every pupil says the steps felt right.

Analysis:

Four tidy pages, four wrong answers, and one method that finds them all.

Activity:

Swap your own solutions with a partner and check each other by substituting into the original equations only.

Plant a mistake

Title:

Plant a mistake

Safety:

No hazards here.

What You Notice:

The check should find the planted mistake every time, even though both pages look equally neat. Naming the exact line is harder, and needs the working read back.

Did you know

None of the five common mistakes is careless arithmetic; each is a real rule applied in the wrong place.

A failed check is still useful, because knowing a mistake exists is most of the work of finding it.

Solving for unknowns with letters was called bijaganita in India, from bija, meaning a seed.

Memory tricks

One line proves it: substitute and compare.

Neat is not right.

Practice MCQs with answers (25)

Q1 An answer to an equation has been found and now has to be shown to be right rather than merely likely. Proving it takes lines numbering beginner
  • A two
  • B three
  • C four
  • D one
Show answer
Answer: one
Why:

A single substitution.

Q2 Why must an answer be substituted into the original equation? advanced
  • A A wrong line agrees with the answer it gave, so it proves nothing
  • B The original equation is shorter than the later lines of working
  • C Substituting into a later line takes longer than into the first
  • D The original equation is the only one with a letter still in it
Show answer
Answer: A wrong line agrees with the answer it gave, so it proves nothing
Why:

6x = 34 and x = 17/3 agree perfectly with each other. Only the original 6x + 5 = 29 can expose the faulty step.

Q3 The equation 6x + 5 = 29 has 5 subtracted from both of its sides as the first step. That step gives beginner
  • A 6x = 24
  • B 6x = 34
  • C x = 24
  • D 6x = 29
Show answer
Answer: 6x = 24
Why:

Twenty-nine less five.

Q4 From 6x = 24 both sides are divided by 6, leaving the letter standing alone at last. Solving 6x + 5 = 29 gives x as beginner
  • A 6
  • B 4
  • C 24
  • D 34
Show answer
Answer: 4
Why:

Twenty-four over six.

Q5 Checking that answer, the left side of 6x + 5 comes to beginner
  • A 29
  • B 24
  • C 34
  • D 39
Show answer
Answer: 29
Why:

Six fours, then five.

Q6 The faulty line 6x = 29 + 5 leads to x as advanced
  • A 4
  • B 6
  • C 17/3
  • D 34
Show answer
Answer: 17/3
Why:

Thirty-four over six.

Q7 Substituting that faulty answer gives a left side of advanced
  • A 29
  • B 34
  • C 39
  • D 24
Show answer
Answer: 39
Why:

Which does not match 29.

Q8 Writing 29 + 5 treats the added 5 as though it had intermediate
  • A been halved somewhere along the way
  • B hopped over and kept its sign
  • C been doubled somewhere along the way
  • D belonged with the letter all along
Show answer
Answer: hopped over and kept its sign
Why:

It should become a subtraction.

Q9 The equation 12 - 5y = 2 has 12 taken from both sides, and the minus before the 5y has to be kept. That step gives advanced
  • A 5y = 14
  • B -5y = 10
  • C 5y = -10
  • D -5y = -10
Show answer
Answer: -5y = -10
Why:

Two less twelve.

Q10 Solving 12 - 5y = 2 therefore gives y as intermediate
  • A 14/5
  • B 10
  • C 2
  • D -2
Show answer
Answer: 2
Why:

Minus ten over minus five.

Q11 Substituting the faulty answer 14/5 into 12 - 5y gives advanced
  • A -2
  • B 2
  • C 14
  • D 12
Show answer
Answer: -2
Why:

Twelve less fourteen.

Q12 In 3z + 4 = z + 16 a letter stands on the right as well as the left, and the two have to be gathered. The z on the right must be intermediate
  • A added to both sides
  • B left exactly where it is
  • C multiplied by both sides
  • D subtracted from both sides
Show answer
Answer: subtracted from both sides
Why:

Which is where the sign goes wrong.

Q13 Subtracting z from both sides of 3z + 4 = z + 16 leaves the letters on one side only. Doing that correctly gives advanced
  • A 2z = 12
  • B 4z = 12
  • C 2z = 20
  • D 4z = 20
Show answer
Answer: 2z = 12
Why:

Three z less z.

Q14 Solving 3z + 4 = z + 16 therefore gives z as intermediate
  • A 3
  • B 12
  • C 6
  • D 4
Show answer
Answer: 6
Why:

Twelve halved.

Q15 At the faulty answer 3, the two sides of 3z + 4 = z + 16 come to advanced
  • A 19 and 13
  • B 22 and 22
  • C 13 and 13
  • D 13 and 19
Show answer
Answer: 13 and 19
Why:

Which disagree.

Q16 At the right answer, both sides of 3z + 4 = z + 16 come to intermediate
  • A 19
  • B 13
  • C 16
  • D 22
Show answer
Answer: 22
Why:

Three sixes plus four.

Q17 The expression 10w - 4w has two like terms that can be collected without moving anything across. Collected together, it is beginner
  • A 6w
  • B 14w
  • C 10w
  • D 6
Show answer
Answer: 6w
Why:

Ten lots less four lots.

Q18 Solving 10w - 4w = 30 therefore gives w as beginner
  • A 3
  • B 5
  • C 6
  • D 30
Show answer
Answer: 5
Why:

Thirty over six.

Q19 The faulty pair of lines 10w = 30 + 4w and then 10w = 30 has advanced
  • A halved the 4w
  • B dropped the 4w entirely
  • C doubled the 30
  • D changed the sign of the 30
Show answer
Answer: dropped the 4w entirely
Why:

A term cannot vanish mid-line.

Q20 Writing v + 3 = -9/2 from 2v + 3 = -9 has divided advanced
  • A the whole of the left side
  • B the right side twice
  • C only part of the left side
  • D neither side at all
Show answer
Answer: only part of the left side
Why:

The 3 must be halved too.

Q21 The equation 2v + 3 = -9 has 3 subtracted from both of its sides, negative right-hand side and all. That step gives intermediate
  • A 2v = -12
  • B 2v = -6
  • C 2v = 12
  • D v = -12
Show answer
Answer: 2v = -12
Why:

Minus nine less three.

Q22 Solving 2v + 3 = -9 therefore gives v as intermediate
  • A -12
  • B 6
  • C -6
  • D -3
Show answer
Answer: -6
Why:

Minus twelve halved.

Q23 Consider these statements about checking an answer. I. The answer must be substituted into the original equation. II. A wrong line always agrees with the wrong answer it produced. III. A failed check does not show which line the mistake is in Which statements are correct? advanced
  • A I and II only
  • B II and III only
  • C I and III only
  • D I, II and III
Show answer
Answer: I, II and III
Why:

All three are true. The check proves that a mistake exists and leaves the hunt for it to you.

Q24 Assertion: A failed check proves that a mistake exists somewhere earlier. Reason: Checking takes one line and is the only part that proves anything. advanced
  • A Both true, and the reason explains the assertion
  • B Both true, but the reason does not explain it
  • C The assertion is true and the reason is false
  • D The assertion is false and the reason is true
Show answer
Answer: Both true, but the reason does not explain it
Why:

Both statements are true, but the reason does not explain the assertion. The failure is evidence because the original equation is the thing being tested.

Q25 In ancient India the study of unknown quantities written as letters had a name of its own. Called bijaganita was the study of advanced
  • A shapes drawn with a compass
  • B unknowns written as letters
  • C numbers counted in tallies
  • D angles measured in degrees
Show answer
Answer: unknowns written as letters
Why:

From bija, meaning a seed.

Important short questions (7)

How is an answer checked, and why into the original equation?

Substitute the answer and work out the two sides separately, then compare them. It must be the original equation, because a later line of your own working may already be wrong.

Solve 6x + 5 = 29 and check your answer.

Subtract 5 from both sides for 6x = 24, then divide by 6, so x = 4. Checking, six fours are 24 and 24 plus 5 is 29, which is the right side.

Explain the mistake in writing 6x = 29 + 5, and what its check gives.

The 5 is added on the left, so it must be subtracted from both sides, not carried over unchanged. That line gives x as 17/3, and checking it gives 39 instead of 29.

Solve 12 - 5y = 2, and say why 5y = 12 + 2 is wrong.

Subtract 12 from both sides for -5y = -10, so y = 2. The faulty line both adds the 2 and loses the minus sign, giving 14/5, which checks to -2.

Solve 3z + 4 = z + 16, naming the sign slip to avoid.

The z on the right must be subtracted from both sides, not added. That gives 2z = 12, so z = 6, and both sides come to 22. Adding instead would give 3.

Solve 10w - 4w = 30, and say what is wrong with writing 10w = 30.

Ten w less 4w is simply 6w, so 6w = 30 and w = 5. Writing 10w = 30 has dropped the 4w from the line altogether, and it gives 3.

Solve 2v + 3 = -9, and explain the mistake in v + 3 = -9/2.

Subtract 3 from both sides for 2v = -12, so v = -6. The faulty line divided only the 2v by 2 and left the 3 alone, but dividing a side divides all of it.

Long answer questions (3)

Two pupils solve 6x + 5 = 29. One writes 6x = 24, the other 6x = 34. Finish both, use checks to decide, and name the mistake.

Take the first. From 6x = 24, dividing both sides by 6 gives x = 4. Now the second. From 6x = 34, dividing by 6 gives x = 17/3. The checks settle it. Put 4 into the original: six fours are 24, and 24 plus 5 is 29, which is the right side exactly. Now put 17/3 in: six times 17/3 is 34, and 34 plus 5 is 39, which is not 29. So the first pupil is right and the second is wrong. The mistake is in how the 5 was treated. It is added on the left, so the step is to subtract 5 from both sides, which leaves 24 on the right. The second pupil wrote 29 + 5 instead, as though the 5 crossed the equals sign and kept its sign.

Mend these two lines of working: 5y = 12 + 2 from 12 - 5y = 2, and 3z + z = 16 - 4 from 3z + 4 = z + 16.

Both lines mishandle a sign. Take the first. In 12 - 5y = 2 the letter term is being subtracted, and the 12 is added. So subtract 12 from both sides. That leaves -5y on the left and -10 on the right. Dividing both sides by -5 gives y = 2, and checking, 12 less ten is 2. The faulty line added the 2 to the 12 and quietly dropped the minus, giving 14/5, which checks to -2. Now the second. The z on the right must be removed by subtracting z from both sides, not by adding it. The correct line is 3z - z = 16 - 4, so 2z = 12 and z = 6. Both sides then come to 22. Adding instead gives 4z = 12 and z = 3, where the sides are 13 and 19.

Explain why a check is worth one line, what the five mistakes in this topic have in common, and what to do when a check fails.

A check is worth it because it is the only part of the work that proves anything. Solving takes several lines, and any one of them could be wrong. Substituting the answer into the original equation tests the whole chain at once. The five mistakes here have something important in common. Not one is careless arithmetic. Each is a rule applied in the wrong place, so the working looks perfectly tidy on the page. That is why tidy working is no evidence of a right answer. When a check fails, it does not say where the mistake is. It says there is one, which is already worth a great deal. Then read the working back line by line and ask of each step what was done to both sides. The first line that cannot answer is the line to mend.

Flashcards (17)

How many lines does checking an answer take?
One, and it is the only part that proves anything.
Where should an answer be substituted?
Into the original equation, not a later line of your working.
Solve 6x + 5 = 29 and check it.
Six x = 24, so x = 4. Six fours plus 5 is 29.
What does the wrong line 6x = 29 + 5 give, and what does its check show?
It gives x = 17/3, and the check gives 39 instead of 29.
Why must the 5 in 6x + 5 = 29 become a subtraction?
It is added on the left, so 5 is subtracted from both sides.
Solve 12 - 5y = 2.
Subtract 12 from both sides for -5y = -10, so y = 2.
What does the wrong line 5y = 12 + 2 give?
It gives y = 14/5, and 12 less 14 is -2, not 2.
Solve 3z + 4 = z + 16.
Subtract z from both sides for 2z = 12, so z = 6.
Why is 3z + z = 16 - 4 wrong?
The z on the right must be subtracted from both sides, not added.
Solve 10w - 4w = 30.
Ten w less 4w is 6w, so 6w = 30 and w = 5.
What is wrong with writing 10w = 30 + 4w and then 10w = 30?
The 4w has simply been dropped from the line.
Solve 2v + 3 = -9.
Subtract 3 from both sides for 2v = -12, so v = -6.
What is wrong with writing v + 3 = -9/2?
Only part of the left side was divided; the 3 must be halved too.
What do all five mistakes have in common?
Each applies a rule in the wrong place, so the working looks tidy.
What does a failed check tell you?
That there is a mistake somewhere, though not where it is.
What question should be asked of every line of working?
What was done to both sides here?
What was the study of unknowns called in ancient India?
Bijaganita, from bija, meaning a seed.

Play this topic

  • Match each faulty line to what its check gives
  • Right answer, or wrong answer?
  • Fact or myth
  • Order these steps for checking an answer
  • Match each mistake to its description

Class 7 Mathematics Chapter 15 — frequently asked questions

Three bags and four blocks balance nineteen blocks. Write this as an equation, explaining your letter.

Let b stand for the weight of one bag, counted in blocks. The left pan weighs 3b + 4 and the right weighs 19, so 3b + 4 = 19.

What is an equation, and what are its two sides?

An equation is a statement that two expressions have the same value. Its two sides are the parts standing to the left and the right of the equals sign.

Explain why an equation is a claim rather than an answer.

It never states the value of the letter. It claims only that the two sides match for the right value, and finding that value is what solving means.

State the rule for solving an equation, and why it is allowed.

Do exactly the same thing to both sides, until the letter stands alone. It is allowed because the two sides name one value, so one operation on both leaves them equal.

Solve 4a + 9 = 37, showing each step.

Subtract 9 from both sides, giving 4a = 28. Divide both sides by 4, giving a = 7. Checking, four sevens are 28 and 28 plus 9 is 37.

What are inverse operations, and how do they choose a step?

They are pairs that undo each other, such as adding and subtracting, or multiplying and dividing. You remove an added number by subtracting it, and a multiplier by dividing.

How is an answer checked, and why into the original equation?

Substitute the answer and work out the two sides separately, then compare them. It must be the original equation, because a later line of your own working may already be wrong.

Solve 6x + 5 = 29 and check your answer.

Subtract 5 from both sides for 6x = 24, then divide by 6, so x = 4. Checking, six fours are 24 and 24 plus 5 is 29, which is the right side.

Explain the mistake in writing 6x = 29 + 5, and what its check gives.

The 5 is added on the left, so it must be subtracted from both sides, not carried over unchanged. That line gives x as 17/3, and checking it gives 39 instead of 29.

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