Trigonometry Exam Prep
Full explanation, worked examples & memory tricks in the app
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Full explanation, worked examples & memory tricks in the app
Every question in the paper gets a full exam-length answer in the app — organised by marks, the way a topper writes it.
If $m = \tan\theta + \sin\theta$ and $n = \tan\theta - \sin\theta$ then prove that $m^2 - n^2 = 4\sqrt{mn}$.
Use the identity $m^2 - n^2 = (m+n)(m-n)$ and simplify.
The full exam-length answer is in the app.
If $\tan A = \sqrt{2} - 1$, show that $\sin A \cdot \cos A = \frac{\sqrt{2}}{4}$.
Use the identity $\sin A \cos A = \frac{1}{2} \sin 2A$.
The full exam-length answer is in the app.
If $x = p \sec\theta + q \tan\theta$ and $y = p \tan\theta + q \sec\theta$, then prove that $x^2 - y^2 = p^2 - q^2$.
Use the difference of squares formula and simplify.
The full exam-length answer is in the app.
If $\sec\theta = x + \frac{1}{4x}$, prove that $\sec\theta + \tan\theta = 2x$ or $\frac{1}{2x}$.
Substitute $\sec\theta$ and simplify to show both cases.
The full exam-length answer is in the app.
If $\tan(A+B) = \sqrt{3}$ and $\tan(A-B) = \frac{1}{\sqrt{3}}$ where $0 < A+B < 90^\circ$, $A > B$, find A and B.
Use the tangent addition and subtraction formulas.
The full exam-length answer is in the app.
Prove that $\frac{\tan\theta+\sec\theta-1}{\tan\theta-\sec\theta+1} = \frac{1+\sin\theta}{\cos\theta}$.
Manipulate the left-hand side using identities to match the right-hand side.
The full exam-length answer is in the app.
Prove that $\frac{1+\cos\theta+\sin\theta}{1+\cos\theta-\sin\theta} = \frac{1+\sin\theta}{\cos\theta}$
Simplify both sides using trigonometric identities.
The full exam-length answer is in the app.
If $\operatorname{cosec}\theta + \cot\theta = p$, then prove that $\cos\theta = \frac{p^2-1}{p^2+1}$.
Use the identities for cosecant and cotangent to derive the result.
The full exam-length answer is in the app.
Identify the step in which Jyoti has made error(s), if any. Rectify the same and find the correct answer.
Step 2 is incorrect; correct it and simplify to find the answer.
The full exam-length answer is in the app.
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