Kit Library / Engineering / Materials Science

⚡ Topic Learning Kit

Semiconductor Materials: Properties, Carriers & Doping

English 17 leveled MCQs 30 flashcards 9 games Free

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💡 Key Idea

What Makes a Semiconductor Special

Not quite metal, not quite insulator.

A semiconductor's conductivity sits between that of a conductor and an insulator — and crucially, it can be tuned by orders of magnitude.

↳ The tunable conductivity of semiconductors is why they power virtually all modern electronics.

📖 Definition

Three Ways to Control Conductivity

Doping, heat, or light — pick your lever.

↳ These three factors make semiconductors uniquely controllable for device engineering.

⭐ Important Fact

Key Properties of Semiconductors

Nine properties that define every semiconductor.

↳ The negative temperature coefficient and non-ohmic behaviour distinguish semiconductors from metals.

💡 Key Idea

Group IV Elements: The Covalent Lattice

Four valence electrons build the entire crystal.

Silicon ($1s^2 2s^2 2p^6 3s^2 3p^2$), Germanium, and Tin each have 4 valence electrons that form covalent bonds with four neighbours, completing an octet.

↳ The covalent bonding of Group IV elements is the foundation of all elemental semiconductor behaviour.

📖 Definition

What Exactly Is a Hole?

It's not a particle — but it acts like one.

↳ Holes are conceptual entities representing electron vacancies, not physical positive particles.

⚙️ Process

How Two Types of Current Flow

Electrons and holes move in opposite directions.

↳ In pure semiconductors, conduction is due to both free electrons and the motion of bound electrons (described as hole movement).

⚖️ Comparison

Intrinsic vs Extrinsic Semiconductors

Pure vs doped — the game changes completely.

↳ Doping converts low-conductivity intrinsic semiconductors into device-ready extrinsic ones.

💡 Key Idea

n-Type Semiconductors: Donor Doping

Add a pentavalent atom, get a free electron.

Adding a pentavalent atom (As, Sb, Bi, P) to silicon: four electrons form covalent bonds, the fifth is loosely bound and easily promoted to the conduction band.

↳ n-type = negative majority carriers (electrons) from donor impurities.

💡 Key Idea

p-Type Semiconductors: Acceptor Doping

Add a trivalent atom, create a hole.

Adding a trivalent atom (In, B, Al, Ga) to silicon: only three covalent bonds form, leaving the fourth bond with a hole.

↳ p-type = positive majority carriers (holes) from acceptor impurities.

⚠️ Common Mistake

Holes Are Not Positive Particles

The most common misconception in semiconductors.

↳ Hole conduction = bound electron conduction described in reverse. No real positive particle exists.

⭐ Important Fact

Compound Semiconductors: Beyond Group IV

Mix two groups, get a semiconductor.

↳ Binary/compound semiconductors expand the range of band gaps and properties beyond elemental Group IV materials.

⭐ Important Fact

Band Gap Comparison: Diamond vs Glass

Why diamond and glass are insulators.

↳ Large band gaps (>3 eV) make materials insulators — electrons cannot easily jump to the conduction band.

🎯 Exam Tip

Exam Favourites from This Topic

These questions appear again and again.

↳ Focus on band diagrams and the donor/acceptor distinction — they carry the most marks.

🧠 Memory Trick

Remembering n-type vs p-type

n = negative, p = positive. Simple.

↳ n-type = pentavalent donor, p-type = trivalent acceptor. The first letter tells you the majority carrier.

🌍 Real World

Where Semiconductors Power Your World

From your phone to solar panels.

↳ Doping and carrier control are the foundation of diodes, transistors, solar cells, and photodetectors.

Smart notes

What you'll study, topic by topic

1

Semiconductor Materials: Properties, Carriers & Doping

18 min

Semiconductors are materials whose conductivity lies between conductors and insulators and can be tuned by doping, temperature, and illumination. This topic covers Group IV elements, intrinsic conduction via electrons an…

  • A semiconductor has conductivity between that of a conductor and an insulator, roughly $10^{-6}$ to $10^3$ S/cm.
  • Semiconductor conductivity can be tuned by doping, temperature change, and illumination.
  • Group IV elements (Si, Ge, Sn) are the most common elemental semiconductors.

Full explanation, worked examples & memory tricks in the app

Leveled MCQ practice

Try the smart MCQs from this kit

All 17 questions, laddered from warm-up to topper-level, each with its answer and the reasoning behind it.

Warm-up · 6 questions

Q1. Which range best describes the conductivity of a semiconductor?

Beginner
A $10^{-6}$ to $10^3$ S/cm
B $10^{-12}$ to $10^{-18}$ S/cm
C $10^{8}$ to $10^{12}$ S/cm
D $10^4$ to $10^7$ S/cm
Show the answer

A · $10^{-6}$ to $10^3$ S/cm

Semiconductors sit between conductors ($10^4$ to $10^7$ S/cm) and insulators ($10^{-12}$ to $10^{-18}$ S/cm), in the range $10^{-6}$ to $10^3$ S/cm.

Q2. A silicon crystal is cooled to absolute zero. What is its electrical behaviour?

Beginner
A It behaves as a perfect conductor
B It behaves as an insulator
C It behaves as a p-type semiconductor
D It behaves as a superconductor
Show the answer

B · It behaves as an insulator

At absolute zero, all valence electrons are locked in covalent bonds, so no free carriers exist and the crystal behaves as an insulator.

Q3. Which particle is responsible for the second type of current in a pure semiconductor, alongside free electrons?

Beginner
A The phonon
B The neutron
C The proton
D The hole
Show the answer

D · The hole

Thermal breaking of a covalent bond frees an electron and leaves a hole, which behaves as a positive carrier and contributes to current.

Q4. Which of the following is a pentavalent donor dopant used to make n-type silicon?

Beginner
A Phosphorus (P)
B Boron (B)
C Aluminium (Al)
D Gallium (Ga)
Show the answer

A · Phosphorus (P)

Phosphorus is pentavalent (Group V) and acts as a donor. Boron, aluminium, and gallium are trivalent acceptors.

Q5. In an n-type semiconductor, which carriers are the majority carriers?

Beginner
A Positive ions
B Electrons
C Protons
D Holes
Show the answer

B · Electrons

Donor atoms contribute free electrons, so electrons outnumber holes and are the majority carriers in n-type material.

Q6. Semiconductors have a negative temperature coefficient of resistivity, meaning resistivity decreases as temperature rises — the opposite of metals.

Beginner
A True
B False
Show the answer

A · True

Semiconductors have a negative temperature coefficient of resistivity, meaning resistivity decreases as temperature rises — the opposite of metals.

Building up · 6 questions

Q7. A student claims that a hole is a real positively charged particle moving through the crystal. Why is this claim wrong?

Intermediate
A A hole only exists in insulators, never in semiconductors
B A hole carries a negative charge just like an electron
C A hole is a proton that has escaped from the nucleus
D A hole is the absence of an electron at a bond site, so no positive particle actually moves
Show the answer

D · A hole is the absence of an electron at a bond site, so no positive particle actually moves

A hole is a vacancy left by a freed electron. Because an electron is negative, its absence looks positive, but no real positive particle is moving — bound electrons hop between bonds instead.

Q8. A silicon sample is heated from room temperature to a much higher temperature. What happens to its resistivity?

Intermediate
A It increases, because atoms vibrate more and block carriers
B It decreases, because more covalent bonds break and free more carriers
C It stays exactly the same, because doping is unchanged
D It first increases, then decreases sharply
Show the answer

B · It decreases, because more covalent bonds break and free more carriers

Semiconductors have a negative temperature coefficient of resistivity. Heating breaks more covalent bonds, creating more electron-hole pairs and lowering resistivity.

Q9. Which dopant would you choose to make a p-type semiconductor?

Intermediate
A Phosphorus, because it is pentavalent and donates an electron
B Arsenic, because it is pentavalent and donates an electron
C Antimony, because it is pentavalent and donates an electron
D Boron, because it is trivalent and accepts an electron
Show the answer

D · Boron, because it is trivalent and accepts an electron

Trivalent dopants such as boron, indium, aluminium, and gallium act as acceptors and produce p-type material. Arsenic, antimony, and phosphorus are donors.

Q10. Assertion (A): In a p-type semiconductor, the acceptor level $E_a$ lies just above the valence band $E_v$. Reason (R): Trivalent dopants create holes that are easily promoted into the valence band.

Intermediate
A Both A and R are true, and R correctly explains A
B Both A and R are true, but R does not explain A
C A is true but R is false
D A is false but R is true
Show the answer

A · Both A and R are true, and R correctly explains A

The acceptor level sits just above $E_v$ precisely because the hole it creates is only weakly bound and easily released into the valence band, so R is the correct reason for A.

Q11. Which statement about the direction of hole motion is correct?

Intermediate
A Hole motion is opposite in direction to the bound electron motion that creates it
B Hole motion is always in the same direction as the bound electron motion
C Holes move perpendicular to the applied field
D Holes do not move at all; only free electrons move
Show the answer

A · Hole motion is opposite in direction to the bound electron motion that creates it

When a bound electron fills a neighbouring hole, a new hole appears where that electron came from. The hole therefore appears to move opposite to the electron that filled it.

Q12. Which of the following is NOT a property of semiconductors?

Intermediate
A They have a band gap between $0.1$ and $3$ eV
B Their conductivity responds to illumination
C Their resistivity decreases as temperature rises
D They obey Ohm's law exactly at all voltages
Show the answer

D · They obey Ohm's law exactly at all voltages

Semiconductors are nonlinear conductors and do not obey Ohm's law. The other three statements are all standard semiconductor properties.

Topper level · 5 questions

Q13. A silicon crystal is doped with arsenic. Which energy-level description matches the result?

Advanced
A An acceptor level $E_a$ appears just above the valence band $E_v$
B An acceptor level $E_a$ appears just below the conduction band $E_c$
C A donor level $E_d$ appears just below the conduction band $E_c$
D A donor level $E_d$ appears just above the valence band $E_v$
Show the answer

C · A donor level $E_d$ appears just below the conduction band $E_c$

Arsenic is pentavalent and acts as a donor. Its loosely held fifth electron creates a donor level $E_d$ just below the conduction band $E_c$, giving n-type behaviour.

Q14. A student says that doping a silicon crystal with boron makes the crystal negatively charged because holes are removed. Why is this reasoning flawed?

Advanced
A Boron is pentavalent and adds extra electrons to the crystal
B Doping changes the dominant carrier type but leaves the crystal electrically neutral overall
C Doping always makes a crystal positively charged regardless of dopant
D Holes carry negative charge, so removing them makes the crystal positive
Show the answer

B · Doping changes the dominant carrier type but leaves the crystal electrically neutral overall

Each dopant atom substitutes for a silicon atom and contributes the same number of nuclear charges as the atom it replaces, so the crystal remains neutral. Only the balance of carrier types changes.

Q15. Which pair correctly matches a compound semiconductor family with its constituent groups?

Advanced
A III-V semiconductors combine one Group III element with one Group VI element
B III-V semiconductors combine one Group III element with one Group V element
C II-VI semiconductors combine one Group II element with one Group V element
D II-VI semiconductors combine two Group IV elements
Show the answer

B · III-V semiconductors combine one Group III element with one Group V element

III-V compounds pair a Group III element with a Group V element, while II-VI compounds pair a Group II element with a Group VI element.

Q16. A designer needs a semiconductor whose dominant carrier type can be switched from electrons to holes without changing the host crystal. Which approach achieves this?

Advanced
A Raise the temperature until all bonds break
B Illuminate the crystal with light of any wavelength
C Cool the crystal to absolute zero
D Replace a pentavalent dopant with a trivalent dopant
Show the answer

D · Replace a pentavalent dopant with a trivalent dopant

Pentavalent donors give electron-majority n-type material; trivalent acceptors give hole-majority p-type material. Switching the dopant type switches the dominant carrier.

Q17. A silicon crystal is doped with a trivalent atom, creating a p-type semiconductor. If the concentration of holes is measured to be $1.5 \times 10^{16} \text{ cm}^{-3}$, what is the expected concentration of electrons in the crystal, assuming intrinsic carrier concentration is $n_i = 1.5 \times 10^{10} \text{ cm}^{-3}$? Use the mass action law, which states that for a semiconductor, the product of the concentrations of electrons and holes is constant: $n \cdot p = n_i^2$.

Advanced
A $1.5 \times 10^{2} \text{ cm}^{-3}$
B $1.0 \times 10^{6} \text{ cm}^{-3}$
C $1.5 \times 10^{10} \text{ cm}^{-3}$
D $1.0 \times 10^{4} \text{ cm}^{-3}$
Show the answer

A · $1.5 \times 10^{2} \text{ cm}^{-3}$

Using the mass action law, we have \( n \cdot p = n_i^2 \). Given \( p = 1.5 \times 10^{16} \text{ cm}^{-3} \) and \( n_i = 1.5 \times 10^{10} \text{ cm}^{-3} \), we can calculate \( n \):…

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