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Physics Motion Exam Prep

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Physics Motion Exam Prep

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1 marks Short answer

A particle moving along x-axis has acceleration $f$, at time t, given by $f = f_0 [1 - (t/T)]$ where $f_0$ and $T$ are constants. The particle at $t = 0$ has zero velocity. In the time interval between $t = 0$ and the instant when $f = 0$ the particle's velocity ($v_x$) is ................

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$\frac{1}{2} f_0 T$

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1 marks Short answer

Velocity of a particle is given by $\vec{v} = (t^2 \hat{i} - 3t \hat{j})$ m/s. What is acceleration at time $t = 3$ s?

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$6 \hat{i} - 3 \hat{j}$ m/s$^2$

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1 marks Short answer

A particle starting from the origin of co-ordinate system with velocity $2 \hat{i}$ m/s moves in XY plane with constant acceleration of $\hat{i} + 3 \hat{j}$ m/s$^2$. Find its y co-ordinate when its x co-ordinate is 30 m?

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54 m

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1 marks Short answer

A particle starting from the origin of co-ordinate system with velocity $2 \hat{i}$ m/s moves in XY plane with constant acceleration of $\hat{i} + 3 \hat{j}$ m/s$^2$. Find magnitude of its velocity at that time.

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19.698 m/s

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1 marks Short answer

A particle starts its motion at time $t = 0$ from the origin with velocity $10 \hat{j}$ m/s and moves in the X-Y plane with constant acceleration of $8 \hat{i} + 2 \hat{j}$ m/s$^2$. At what time is its x co-ordinate become 16 m? And at this time what will be its y co-ordinate?

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2 sec, 12 m

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1 marks Short answer

A particle starts its motion at time $t = 0$ from the origin with velocity $10 \hat{j}$ m/s and moves in the X-Y plane with constant acceleration of $8 \hat{i} + 2 \hat{j}$ m/s$^2$. What will be the speed of this particle at this time?

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20.26 m/s

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1 marks Short answer

A particle starts its motion at time $t = 0$ from the origin with velocity $(10 \hat{i})$ m/s and moves in the X - Y plane with constant acceleration $(8 \hat{i} + 2 \hat{j})$ m/s$^2$. At what time is its Y co-ordinate become 16 m? And at this time what will be its X co-ordinate?

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t = 2 s X co-ordinate 24 m

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1 marks Short answer

A body initially at rest is moving with uniform acceleration "$a"$. It's velocity after $n$ seconds is $v$. The displacement of the body in last 2 seconds is ......

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$\frac{2v(n-1)}{n}$

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1 marks Short answer

A student is standing at a distance 50 metre from the bus. As soon as the bus begins its motion with acceleration of 1 m/s², the student starts running towards the bus with a uniform velocity u. Assuming the motion to be along a straight road, the minimum value of u, so that the student is able to catch the bus is :

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10 m/s

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1 marks Short answer

A car, starting from rest, accelerates at the rate $f$ through a distance S, then continues at constant speed for time t and than decelerates at the rate $f / 2$ to come to rest. If the total distance travelled is 15 S, then S = ............

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$\frac{1}{4} ft^2$

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