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Chemistry Exam Preparation

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7 marks Long answer

Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 L water at 25 °C, assuming that K2SO4 is completely dissociated.

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Osmotic pressure = 0.0067 atm.

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5 marks Long answer

Write the reaction for the Williamson ether synthesis of 2-ethoxy-3-methyl pentane, starting from ethanol and 3-methylpentan-2-ol.

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Ethanol reacts with 3-methylpentan-2-ol in the presence of NaH to form 2-ethoxy-3-methylpentane.

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5 marks Long answer

How will you convert benzaldehyde into benzophenone?

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Benzaldehyde can be converted to benzophenone via a Friedel-Crafts acylation reaction.

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5 marks Long answer

Explain why the complex ion [Ti(H2O)6]^{3+} is coloured, based on Crystal Field Theory.

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The color arises from d-d transitions of electrons in the split d-orbitals due to ligand field.

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5 marks Long answer

How is potassium permanganate prepared commercially? Also, give the structures of chromate and dichromate ions.

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Potassium permanganate is prepared by the oxidation of MnO2 with KMnO4; chromate is CrO4^{2-} and dichromate is Cr2O7^{2-}.

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5 marks Long answer

Give equation for the preparation of phenol from cumene.

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Cumene is oxidized to cumene hydroperoxide, which decomposes to phenol and acetone.

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4 marks Medium answer

Using Valence Bond Theory, explain the following in relation to the paramagnetic complex [NiCl4]^{2-}: c) Type of complex—whether inner orbital or outer orbital. Justify your answer.

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It is an outer orbital complex due to dsp^2 hybridization.

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4 marks Medium answer

Calculate the mass of the compound (molar mass = 256 g mol^{-1}) to be dissolved in 75 g of benzene to lower its freezing point by 0.48 K. (Given: Kf of C6H6 = 5.12 K kg mol^{-1})

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Mass = 19.2 g.

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4 marks Medium answer

Complete and balance the following equations: 1. Fe^{2+} + MnO4^{-} + H^{+} →

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The balanced equation is: 5Fe^{2+} + MnO4^{-} + 8H^{+} → 5Fe^{3+} + Mn^{2+} + 4H2O.

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4 marks Medium answer

Complete and balance the following equations: 2. MnO4^{-} + H2O + I^{-} →

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The balanced equation is: MnO4^{-} + 8H2O + 5I^{-} → Mn^{2+} + 8OH^{-} + 5I2.

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4 marks Medium answer

Explain the following named reactions: Swartz reaction.

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Swartz reaction involves the conversion of aryl halides to aryl fluorides using silver fluoride.

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4 marks Medium answer

Explain the following named reactions: Sandmeyer's reaction.

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Sandmeyer's reaction involves the substitution of an aryl diazonium salt with halides using copper salts.

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4 marks Medium answer

Explain the following named reactions: Reimer-Tiemann reaction.

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Reimer-Tiemann reaction involves the ortho-formylation of phenols using chloroform and a base.

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4 marks Medium answer

What is meant by hydroboration-oxidation reaction? Illustrate with an example.

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Hydroboration-oxidation converts alkenes to alcohols; e.g., ethene to ethanol.

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4 marks Medium answer

Account for the following: Zn^{2+} salts are colourless while Ni^{2+} salts are coloured.

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Zn^{2+} has a full d-orbital, while Ni^{2+} has unpaired electrons causing color.

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4 marks Medium answer

Write the ionic equation for the oxidizing action of MnO4^- in acidic medium with: Fe^{2+} ion.

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The equation is: MnO4^{-} + 8H^{+} + 5Fe^{2+} → Mn^{2+} + 4H2O + 5Fe^{3+}.

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4 marks Medium answer

Complete the following equations: MnO2 + KOH + O2 →

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The balanced equation is: 2MnO2 + 4KOH + O2 → 2K2MnO4 + 2H2O.

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4 marks Medium answer

Complete the following equations: Cr2O7^{2-} + 14H^{+} + 6I^{-} →

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The balanced equation is: Cr2O7^{2-} + 14H^{+} + 6I^{-} → 2Cr^{3+} + 7H2O + 3I2.

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3 marks Medium answer

Using Valence Bond Theory, explain the following in relation to the paramagnetic complex [NiCl4]^{2-}: a) Type of hybridization.

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The hybridization is dsp^2.

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3 marks Medium answer

Using Valence Bond Theory, explain the following in relation to the paramagnetic complex [NiCl4]^{2-}: b) Magnetic moment value.

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The magnetic moment value is 2.83 BM.

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3 marks Medium answer

Illustrate the following reaction with a suitable chemical equation: a) Cannizzaro reaction.

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The reaction is: 2RCHO → RCOO^- + RCH2OH.

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3 marks Medium answer

In 3d series, Mn exhibits highest oxidation state while in 4d and 5d, Ru and Os have highest oxidation state. What is the highest oxidation state shown among the given elements?

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The highest oxidation state is +7.

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3 marks Medium answer

Vanadium has the ability to exhibit various oxidation states. How do you explain this?

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Vanadium can exhibit various oxidation states due to its ability to lose different numbers of electrons.

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3 marks Medium answer

Account for the following: Propanol has a higher boiling point than that of the hydrocarbon butane.

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Propanol has hydrogen bonding, which increases its boiling point compared to butane.

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3 marks Medium answer

Account for the following: o-Nitrophenol is more acidic than o-methoxyphenol.

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o-Nitrophenol is more acidic due to the electron-withdrawing effect of the nitro group.

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3 marks Medium answer

Account for the following: The dipole moment of chlorobenzene is lower than that of cyclohexyl chloride.

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Chlorobenzene has a planar structure, while cyclohexyl chloride has a non-planar structure leading to a higher dipole moment.

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3 marks Medium answer

Write the equation involved in the preparation of KMnO4 from pyrolusite ore.

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The reaction is: 4MnO2 + 4KOH + O2 → 4KMnO4 + 2H2O.

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2 marks Short answer

What happens when n-butyl chloride is treated with alcoholic KOH?

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n-butyl chloride undergoes elimination to form butene.

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2 marks Short answer

Give the products of the following reaction: C6H5CH2OC6H5 + HI → ?

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The products are C6H5I and CH3I.

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2 marks Short answer

Give a chemical test to distinguish between benzaldehyde and acetophenone.

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Use 2,4-DNP test; benzaldehyde gives a yellow precipitate, while acetophenone gives a red precipitate.

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2 marks Short answer

What happens when methyl bromide is treated with sodium in the presence of dry ether?

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A Wurtz reaction occurs, forming butane.

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2 marks Short answer

What happens when ethyl chloride is treated with aqueous KOH?

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Ethyl chloride undergoes hydrolysis to form ethanol.

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2 marks Short answer

Cr^{2+} is a strong reducing agent.

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Cr^{2+} readily loses electrons to form Cr^{3+}.

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2 marks Short answer

Transition metals form complex compounds.

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Transition metals have vacant d-orbitals that can accept electron pairs from ligands.

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1 marks Short answer

State Henry's law.

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At a constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure of the gas above the liquid.

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