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📚 Chapter Learning Kit

Combining Quantities · Class 9 Mathematics

English 3 topics 170 leveled MCQs 60 flashcards 4 games Free

Shared by a Veda teacher · Generated with Veda AI · Oct 2026

⚡ Veda Bites

The whole idea, one bite at a time

Veda Bites are swipeable micro-lessons — each one teaches exactly one idea. Here's a taste from this kit; the app has the full deck.

💡 Key Idea

Averaging averages

The shortcut everyone reaches for, and it is usually wrong.

Given two group averages, it is tempting to average them. That gives each group the same say — which is only fair when the groups are the same size.

↳ An average carries the weight of the group behind it.

➗ Formula

The weighted mean

One formula covers every question in this topic.

Multiply each value by its weight, add, and divide by the TOTAL WEIGHT: $\dfrac{w_1x_1 + w_2x_2 + \cdots}{w_1 + w_2 + \cdots}$.

↳ Divide by the sum of the weights, never by how many values there are.

🚫 Warning

The wrong divisor

The single commonest slip in this chapter.

Rehmat has three scores, so 3 looks like the divisor. It is not — the weights are $3 : 2 : 5$, so you divide by 10. Dividing by 3 gives 224.33, which is above every score she got.

↳ If your answer is bigger than every value, you divided by the wrong thing.

💡 Key Idea

Two ways to cluster

One table, and the chart you choose decides what is easy.

↳ Pick the chart from the question, not the other way round.

➗ Formula

The total is the height

What the height of a stack actually is.

A stacked column stands as tall as the sum of its parts: $1940 + 1700 + 1280 + 1200 + 1770 + 535 = 8425$ for Family A.

↳ Totals are what stacking shows at a glance.

🚫 Warning

Only the bottom starts at zero

The cost of stacking, in one sentence.

Every segment above the first begins wherever the one below ended, so its length is a difference, not a height.

↳ Read the top, read the bottom, subtract.

📖 Smart notes

What you'll study, topic by topic

1

Weighted Average: When the Average of Averages Works

Averaging a set of averages looks like the obvious shortcut, and it is wrong more often than it is right. It gives the correct answer only when every group is the same size; the moment the groups differ, each average has…

~45 min · full explanation, examples & memory tricks in the app

2

Stacked Columns: Comparing Totals Without Losing the Parts

The same table can be drawn as a chart in more than one way, and the choice decides which questions become easy. Clustering by family answers questions about one household; clustering by category compares the same cost a…

~45 min · full explanation, examples & memory tricks in the app

3

The 100% Stacked Bar: Comparing Shares Instead of Totals

Asking which family spends the smallest SHARE on healthcare is awkward on an ordinary stacked chart, because the columns are different heights and a share has to be judged against each one separately. Three pie charts fi…

~45 min · full explanation, examples & memory tricks in the app

❓ Leveled MCQ practice

Try the smart MCQs from this kit

170 questions laddered from warm-up to topper-level, each with an explanation. A taste:

A badminton group has 8 seniors averaging $165.5$ cm and 3 juniors averaging $149.33$ cm. What is the average height of all 11 trainees?

Beginner
A 149.33 cm B 157.42 cm C 161.09 cm D 165.5 cm
Show answer & explanation

161.09 cm

Weight each average by its group size: $\dfrac{(165.5 \times 8) + (149.33 \times 3)}{11} = \dfrac{1772}{11} = 161.09$ cm. The value $157.42$ is what you get by averaging the two averages, which ignores that there are nearly three times as many seniors.

Why does averaging the two group averages give the wrong height for the badminton group?

Beginner
A Heights cannot be averaged at all unless every single value in both of the groups is a whole number B The junior average of $149.33$ has been rounded to two decimal places, so the whole discrepancy between the two methods comes from that rounding C It uses division where it should have used multiplication at the very last step of the working D It treats the seniors' average and the juniors' average as equally important, when there are 8 seniors and only 3 juniors
Show answer & explanation

It treats the seniors' average and the juniors' average as equally important, when there are 8 seniors and only 3 juniors

Each average carries the weight of the group behind it. Averaging the averages silently gives the 3 juniors the same say as the 8 seniors.

Jaspreet cycles 5 days a week for 3 weeks, averaging $12.8$, $15.8$ and $18$ minutes. What is her average over the 15 days?

Beginner
A 15.53 minutes B 15.33 minutes C 18 minutes D 46.60 minutes
Show answer & explanation

15.53 minutes

All three weeks have the same number of cycling days, so the sizes cancel and the plain average is correct: $\dfrac{12.8 + 15.8 + 18}{3} = \dfrac{46.6}{3} = 15.53$ minutes.

Averaging a set of averages gives the correct overall average in exactly which case?

Beginner
A When every group contains the same number of values B When there are exactly three groups being combined C When every group average is a whole number D Never — it is always an incorrect method
Show answer & explanation

When every group contains the same number of values

Putting $p = q = r$ into $\dfrac{ap + bq + cr}{p + q + r}$ gives $\dfrac{(a + b + c)p}{3p} = \dfrac{a + b + c}{3}$. The sizes cancel only when they are equal.

🃏 Flashcards

Tap a card to flip it

60 flashcards in this kit — the app reviews them with spaced repetition so the right card returns on the right day.

🎮 Learning games

Play your way through this kit

Every game is built from this kit's own content — scores feed your mastery, so playing counts as studying.

Word Match True False Fill Blank Word Scramble Playable in the app

Study it properly — free, in the app

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