Kit Library / Mathematics / Algebra

⚡ Topic Learning Kit

Quadratic Equations

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Quadratic Equations

Quadratic equations are second-degree polynomial equations of the form $ax^2 + bx + c = 0$ with $a \neq 0$. They model parabolic relationships and can be solved by factoring, completing the square, or the quadratic formu…

  • A quadratic equation is any equation of the form $ax^2 + bx + c = 0$ with $a \neq 0$.
  • Three common solving methods: factoring, completing the square, and the quadratic formula.
  • The quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ works for all quadratics.

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15 questions laddered from warm-up to topper-level, each with an explanation. A taste:

Which of the following is a quadratic equation?

Beginner
A $\frac{1}{x} + x = 2$ B $2x + 3 = 0$ C $x^3 - 2x + 1 = 0$ D $x^2 - 5x + 6 = 0$
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$x^2 - 5x + 6 = 0$

A quadratic equation is of the form $ax^2 + bx + c = 0$ with $a \neq 0$. Only $x^2 - 5x + 6 = 0$ fits this form.

What is the standard form of a quadratic equation?

Beginner
A $ax^2 + by^2 = c$ B $ax + b = 0$ C $ax^3 + bx^2 + cx + d = 0$ D $ax^2 + bx + c = 0$
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$ax^2 + bx + c = 0$

The standard form of a quadratic equation in variable $x$ is $ax^2 + bx + c = 0$, where $a, b, c$ are real numbers and $a \neq 0$.

The roots of the quadratic equation $x^2 - 7x + 12 = 0$ are:

Intermediate
A $2$ and $6$ B $3$ and $4$ C $1$ and $12$ D $-3$ and $-4$
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$3$ and $4$

Factorising: $x^2 - 7x + 12 = (x-3)(x-4) = 0$, so $x = 3$ or $x = 4$.

The discriminant of the quadratic equation $ax^2 + bx + c = 0$ is:

Beginner
A $4ac - b^2$ B $b^2 - 4ac$ C $b^2 + 4ac$ D $\sqrt{b^2 - 4ac}$
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$b^2 - 4ac$

The discriminant, denoted by $D$ or $\Delta$, is $b^2 - 4ac$. It determines the nature of the roots.

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