Pair of Linear Equations in Two Variables · Class 10 Mathematics: 220 MCQs with answers
Showing 200 of 220 multiple-choice questions from this kit.
Warm-up · 61 questions
Q1. A linear equation in two variables has the form
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$ax + by + c = 0$ with a, b not both zero
Both variables appear to the first power, and at least one of a, b is non-zero.
Q2. A solution of a pair of linear equations is a pair (x, y) that
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satisfies both equations
It must work in both equations at the same time.
Q3. The graph of a linear equation in two variables is
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a straight line
That is why they are called linear.
Q4. If two lines cross at exactly one point, the pair of equations has
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exactly one solution
The crossing point is the only pair satisfying both.
Q5. If the two lines are parallel, the pair has
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no solution
Parallel lines never meet, so no point satisfies both.
Q6. If the two lines coincide, the number of solutions is
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infinitely many
Every point of the line satisfies both equations.
Q7. The point where the line $x + 3y = 6$ meets the y-axis is
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$(0, 2)$
On the y-axis $x = 0$, so $3y = 6$ and $y = 2$.
Q8. The point where $2x - 3y = 12$ meets the x-axis is
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$(6, 0)$
On the x-axis $y = 0$, so $2x = 12$ and $x = 6$.
Q9. A pair of equations that has at least one solution is called
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consistent
Consistent covers both the crossing and the coinciding cases.
Q10. A pair with no solution is called
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inconsistent
Its lines are parallel.
Q11. Which point lies on the line $2x + 3y = 12$?
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$(3, 2)$
$2(3) + 3(2) = 12$ ✓ The others give 13, 14 and 14.
Q12. Assertion (A): One linear equation in two variables has infinitely many solutions. Reason (R): Every point on its graph, which is a straight line, satisfies the equation.
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Both A and R are true, and R is the correct explanation of A
A line holds infinitely many points, and each is a solution — R explains A.
Q13. How many solutions does the single equation $x + y = 7$ have?
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Infinitely many
Every point on its line is a solution, and a line holds infinitely many points.
Q14. The line $y = 4$ is
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horizontal, through $(0, 4)$
Every point with height 4 satisfies it, so the line is horizontal.
Q15. Which equation is satisfied by the point $(0, 0)$?
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$3x - 5y = 0$
Putting both coordinates to 0 gives $0 = 0$ only in the first.
Q16. Form a pair of linear equations: the cost of 2 kg of wheat and 3 kg of rice is ₹140, and the cost of 4 kg of wheat and 5 kg of rice is ₹260.
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Q17. Find two solutions of the equation $2x + y = 8$ and use them to describe its line.
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Q18. The sum of two numbers is 20 and their difference is 4. Form a pair of equations and solve it.
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Q19. A pair of linear equations has exactly one solution when
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$\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$
Unequal a-to-b ratios mean different slopes, so the lines must cross once.
Q20. A pair has infinitely many solutions when
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$\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$
All three ratios equal means one equation is a multiple of the other.
Q21. A pair has no solution when
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$\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$
Matching slopes with different constants give parallel lines.
Q22. Coincident lines correspond to
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infinitely many solutions
Every point of the shared line satisfies both equations.
Q23. Parallel lines correspond to a pair that is
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inconsistent
No solution means inconsistent.
Q24. Written in standard form, $3x + 2y = 7$ has c equal to
BeginnerShow answer & explanation
−7
$3x + 2y - 7 = 0$, so $c = -7$.
Q25. For the pair $x + y - 5 = 0$ and $2x + 2y - 10 = 0$, the ratio $\frac{c_1}{c_2}$ is
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$\frac{1}{2}$
$\frac{-5}{-10} = \frac12$ — the minus signs cancel.
Q26. A dependent pair of linear equations is
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always consistent
Dependent means the equations are equivalent, so they have infinitely many solutions.
Q27. Which case does NOT need the ratio of the constants?
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one solution
If the a and b ratios already differ, the lines cross whatever the constants are.
Q28. Assertion (A): The pair $2x + 3y - 5 = 0$ and $4x + 6y - 10 = 0$ has infinitely many solutions. Reason (R): All three ratios of the coefficients are equal.
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Both A and R are true, and R is the correct explanation of A
$\frac24 = \frac36 = \frac{-5}{-10} = \frac12$, which is exactly the condition for coincident lines.
Q29. A pair of equations represents two lines that meet at exactly one point. The pair is
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consistent with a unique solution
One crossing point means one solution, so the pair is consistent.
Q30. Without drawing, say how many solutions $x - 2y = 0$ and $3x + 4y = 20$ have, and name the pair.
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Q31. Classify the pair $2x + 3y - 9 = 0$ and $4x + 6y - 18 = 0$, giving all three ratios.
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Q32. Show that $x + 2y - 4 = 0$ and $2x + 4y - 12 = 0$ is an inconsistent pair.
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Q33. State the conditions on the ratios for a pair to be (i) consistent with a unique solution (ii) inconsistent.
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Q34. The first step of the substitution method is to
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make one variable the subject in one equation
Substitution begins by expressing one variable in terms of the other.
Q35. Rearranging $x + 2y = 3$ for x gives
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$x = 3 - 2y$
The term $2y$ changes sign as it crosses the equals sign.
Q36. Substituting $x = 3 - 2y$ into $7x - 15y = 2$ gives
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$7(3 - 2y) - 15y = 2$
x is replaced by its expression, brackets included.
Q37. $7(3 - 2y)$ equals
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$21 - 14y$
Multiply both terms inside the bracket by 7.
Q38. You must substitute the expression into
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the other equation
The equation you rearranged would give an identity such as 3 = 3.
Q39. Solving $y = 2x$ and $x + y = 9$ by substitution gives
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$x = 3,\ y = 6$
$x + 2x = 9$ gives $3x = 9$, so $x = 3$ and $y = 6$.
Q40. Which variable is easiest to make the subject in $3x + 4y = 10$ and $x - 2y = 1$?
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x, from the second equation
Its coefficient is 1, so $x = 1 + 2y$ brings no fractions.
Q41. After substituting, the variables cancel and you are left with $5 = 5$. The pair has
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infinitely many solutions
A true statement means the equations are equivalent.
Q42. After substituting, you are left with $4 = 9$. The pair has
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no solution
A false statement means no values can satisfy both equations.
Q43. Where should the final answer be checked?
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in both original equations
The rearranged equation cannot fail, so it proves nothing.
Q44. Assertion (A): Substituting $x = 3 - 2y$ back into $x + 2y = 3$ is useless. Reason (R): It gives the identity $3 = 3$, which contains no new information.
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Both A and R are true, and R is the correct explanation of A
The rearranged equation is the same equation, so nothing new can come out of it.
Q45. Making y the subject of $5x - y = 12$ gives
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$y = 5x - 12$
Move y to the right and 12 to the left: $5x - 12 = y$.
Q46. Which line of working shows Step 2 of the method?
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replacing x by its expression in the second equation
Step 2 is the substitution itself; adding or subtracting belongs to elimination.
Q47. Solve by substitution: $x + y = 14$ and $x - y = 4$.
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Q48. The sum of two numbers is 45 and one is four times the other. Find them by substitution.
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Q49. The first step of the elimination method is to
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multiply so that one variable's coefficients become equal
Only matching coefficients allows a variable to cancel.
Q50. If the matched terms are $+5y$ and $+5y$, you should
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subtract the equations
Same Sign → Subtract: $5y - 5y = 0$.
Q51. If the matched terms are $+4x$ and $-4x$, you should
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add the equations
Opposite signs cancel on addition.
Q52. Multiplying $2x + 3y = 13$ by 3 gives
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$6x + 9y = 39$
Every term, including the constant, is multiplied.
Q53. Adding $x + y = 7$ and $x - y = 3$ gives
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$2x = 10$
The y-terms are $+y$ and $-y$, so they cancel on addition.
Q54. Solving $x + y = 7$ and $x - y = 3$ gives
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$x = 5,\ y = 2$
Adding gives $2x = 10$, so $x = 5$ and then $y = 2$.
Q55. To eliminate y from $2x + 3y = 13$ and $5x - 2y = 4$, the multipliers are
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2 and 3
The LCM of 3 and 2 is 6, so multiply the first by 2 and the second by 3.
Q56. Reversing the digits of the number $10x + y$ produces
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$10y + x$
After reversing, y sits in the tens place and x in the units place.
Q57. Elimination leaves $0 = 0$. The pair has
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infinitely many solutions
A true statement means the two equations are equivalent.
Q58. Elimination leaves $0 = 5$. The pair has
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no solution
A false statement can never be satisfied.
Q59. Assertion (A): An equation may be multiplied throughout by 3 during elimination. Reason (R): Multiplying every term by a non-zero number gives an equivalent equation with the same solutions.
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Both A and R are true, and R is the correct explanation of A
That equivalence is exactly what makes Step 1 legitimate.
Q60. Subtracting $x - y = 2$ from $x + y = 8$ gives
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$2y = 6$
The x-terms cancel and $8 - 2 = 6$ remains on the right.
Q61. Which is NOT a step of the elimination method?
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making one variable the subject of a formula
Making a variable the subject belongs to substitution; elimination matches coefficients instead.
Building up · 86 questions
Q62. Two pencils and three erasers cost ₹9. With ₹x per pencil and ₹y per eraser, the equation is
IntermediateShow answer & explanation
$2x + 3y = 9$
Two lots of x and three lots of y come to 9.
Q63. 'The number of skirts is two less than twice the number of pants' becomes
IntermediateShow answer & explanation
$y = 2x - 2$
Twice the pants is $2x$; two less is $2x - 2$.
Q64. The lines $y = 2x - 2$ and $y = 4x - 4$ meet at
IntermediateShow answer & explanation
$(1, 0)$
$2x - 2 = 4x - 4$ gives $2x = 2$, so $x = 1$ and $y = 0$.
Q65. The solution of $x + 3y = 6$ and $2x - 3y = 12$ is
IntermediateShow answer & explanation
$x = 6,\ y = 0$
Adding gives $3x = 18$, so $x = 6$ and then $y = 0$.
Q66. Which pair of points can be used to draw $3x + 4y = 12$?
IntermediateShow answer & explanation
$(0, 3)$ and $(4, 0)$
$x = 0$ gives $y = 3$; $y = 0$ gives $x = 4$.
Q67. A father is 30 years older than his daughter. With ages x and y, the equation is
IntermediateShow answer & explanation
$x - y = 30$
Taking x as the father's age, his age minus hers is 30.
Q68. If $(2, 3)$ is a solution of $ax + 3y = 13$, then a is
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2
$2a + 9 = 13$ gives $2a = 4$, so $a = 2$.
Q69. The pair $2x + 3y = 9$ and $4x + 6y = 18$ represents
IntermediateShow answer & explanation
the same line drawn twice
The second equation is twice the first, so both draw the same line.
Q70. Which of these pairs is inconsistent?
IntermediateShow answer & explanation
$x + 2y = 4$ and $2x + 4y = 12$
Doubling the first gives $2x + 4y = 8$, which contradicts 12 — parallel lines, no solution.
Q71. The solution of $x + y = 5$ and $x - y = 1$ is
IntermediateShow answer & explanation
$x = 3,\ y = 2$
Adding gives $2x = 6$, so $x = 3$ and $y = 2$.
Q72. A line passes through $(0, 5)$ and $(5, 0)$. Its equation is
IntermediateShow answer & explanation
$x + y = 5$
Both points satisfy $x + y = 5$.
Q73. If a pair of lines coincides, the pair of equations is
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dependent and consistent
Equivalent equations give infinitely many solutions, and a dependent pair is always consistent.
Q74. Which situation needs a PAIR of equations?
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Finding the cost of a pencil and of an eraser from two bills
Two unknown prices need two facts about them.
Q75. Assertion (A): The pair $x + y = 5$ and $2x + 2y = 10$ has exactly one solution. Reason (R): The second equation is twice the first, so both represent the same line.
IntermediateShow answer & explanation
A is false but R is true
There are infinitely many, so the assertion is false. The reason explains why: the two equations describe the same line.
Q76. Assertion (A): The point $(2, 3)$ is a solution of the pair $x + y = 5$ and $x - y = 1$. Reason (R): A solution of a pair must satisfy both equations.
IntermediateShow answer & explanation
A is false but R is true
R is true. A is false: $2 + 3 = 5$ ✓ but $2 - 3 = -1 \neq 1$. The solution is $(3, 2)$.
Q77. The equations $x + y = 6$ and $x + y = 9$ represent
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two parallel lines
The same expression cannot equal both 6 and 9, so the lines never meet.
Q78. A pair of equations is formed from two facts about a situation. If the second fact repeats the first, the pair will have
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infinitely many solutions
A repeated fact gives an equivalent equation, so both lines coincide.
Q79. A two-digit number has tens digit x and units digit y. The number is
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$10x + y$
The tens digit is worth ten times its face value.
Q80. Solve graphically (describing the two lines): $x + y = 7$ and $x - y = 1$.
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Q81. Champa buys two fewer skirts than twice the number of pairs of trousers, and also four fewer than four times that number. Form the equations and solve them.
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Q82. Show that the pair $2x + 3y = 9$ and $4x + 6y = 18$ has infinitely many solutions.
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Q83. Show that the pair $x + 2y = 4$ and $2x + 4y = 12$ has no solution.
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Q84. Explain why the graphical method is unsuitable for $7x - 15y = 2$ and $x + 2y = 3$.
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Q85. (a) Write the general form of a pair of linear equations in two variables and say what a solution of the pair means. (b) Solve graphically (describing the lines): $x + 3y = 6$ and $2x - 3y = 12$. (c) Verify the solution in both equations and state whether the pair is consistent.
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1 mark — (a) general form. 1 mark — (a) meaning of a solution. 1 mark — (b) the two tables of points. 1 mark — (b) crossing point (6, 0). 1 mark — (c) verification and 'consistent'.
Q86. A shopkeeper sells 2 pens and 3 notebooks for ₹80, and 3 pens and 5 notebooks for ₹130. (a) Form a pair of linear equations, stating clearly what your letters mean. (b) Solve the pair. (c) Find the cost of 1 pen and 2 notebooks together.
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1½ marks — (a) letters named and both equations. 2 marks — (b) solving to x = 10, y = 20. 1½ marks — (c) ₹50.
Q87. The pair $x - 2y = 0$ and $3x + 4y - 20 = 0$ has
IntermediateShow answer & explanation
exactly one solution
$\frac13 \neq \frac{-2}{4}$, so the lines intersect once.
Q88. The pair $x + 2y - 4 = 0$ and $2x + 4y - 12 = 0$ has
IntermediateShow answer & explanation
no solution
$\frac12 = \frac24$ but $\frac{-4}{-12} = \frac13$ — parallel lines.
Q89. For $3x + 2y = 5$ and $6x + 4y = 11$, the number of solutions is
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0
$\frac36 = \frac24 = \frac12$ but $\frac{-5}{-11} \neq \frac12$ — no solution.
Q90. For $2x + 3y - 8 = 0$ and $4x + 6y - 16 = 0$, the lines are
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coincident
All three ratios equal ½, so the two equations describe the same line.
Q91. For which value of k does $2x + ky = 5$ and $4x + 6y = 11$ have a unique solution?
IntermediateShow answer & explanation
$k \neq 3$
A unique solution needs $\frac24 \neq \frac{k}{6}$, i.e. $k \neq 3$.
Q92. For which k does $x + 2y = 3$ and $5x + ky + 7 = 0$ have no solution?
IntermediateShow answer & explanation
10
Need $\frac15 = \frac{2}{k}$, so $k = 10$; then $\frac{-3}{7} \neq \frac15$ ✓ no solution.
Q93. If a pair of equations is consistent with a unique solution, then
IntermediateShow answer & explanation
$a_1b_2 \neq a_2b_1$
Cross-multiplying $\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$ gives exactly this.
Q94. The pair $5x - 8y + 1 = 0$ and $3x - \frac{24}{5}y + \frac{3}{5} = 0$ has
IntermediateShow answer & explanation
infinitely many solutions
Multiplying the second by $\frac53$ gives the first, so all three ratios agree.
Q95. Two lines have the same slope but different intercepts. The pair is
IntermediateShow answer & explanation
inconsistent
Same slope and different position means parallel, so there is no solution.
Q96. For $9x - 4y = 2000$ and $7x - 3y = 2000$, the number of solutions is
IntermediateShow answer & explanation
1
$\frac97 \neq \frac{-4}{-3}$, so the lines cross exactly once.
Q97. Which pair represents intersecting lines?
IntermediateShow answer & explanation
$x + y = 5$ and $x - y = 1$
Only the first has different a-to-b ratios: $\frac11 \neq \frac{1}{-1}$.
Q98. Assertion (A): The pair $x + y = 3$ and $2x + 2y = 7$ is inconsistent. Reason (R): All three of the coefficient ratios are equal.
IntermediateShow answer & explanation
A is true but R is false
The third ratio differs, which is exactly what makes the pair inconsistent rather than coincident. The assertion stands, the reason is false.
Q99. Assertion (A): If $\frac{a_1}{a_2} = \frac{b_1}{b_2}$, the pair has infinitely many solutions. Reason (R): Equal ratios of a and b mean the lines have the same slope.
IntermediateShow answer & explanation
A is false but R is true
R is true, but A is false: with the same slope the lines may also be parallel. The c ratio decides.
Q100. A pair of equations that is consistent may have
IntermediateShow answer & explanation
one or infinitely many solutions
Consistent means at least one solution, which covers both cases.
Q101. Which pair of lines is coincident?
IntermediateShow answer & explanation
$x - y = 2$ and $3x - 3y = 6$
Tripling the first gives $3x - 3y = 6$ exactly, so both equations describe the same line.
Q102. If both equations of a pair are multiplied by 3, the number of solutions
IntermediateShow answer & explanation
does not change
Multiplying an equation by a non-zero number gives an equivalent equation, so the ratios and the lines are unchanged.
Q103. For $x + y = 5$ and $3x + 3y = 15$, the value of $\frac{c_1}{c_2}$ is
IntermediateShow answer & explanation
$\frac13$
In standard form the constants are −5 and −15, so the ratio is $\frac{-5}{-15} = \frac13$, matching the other two ratios.
Q104. Assertion (A): For $4x + 6y = 12$ and $2x + 3y = 6$ the lines coincide. Reason (R): Dividing the first equation by 2 gives the second.
IntermediateShow answer & explanation
Both A and R are true, and R is the correct explanation of A
The two equations are equivalent, so they draw the same line and the pair is dependent.
Q105. Find the value of k for which $2x + ky = 5$ and $4x + 6y = 11$ have no solution.
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Q106. The pair $3x + 2y = 5$ and $6x + 4y = 11$ is given. Decide the number of solutions and explain what the graph looks like.
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Q107. Why is it not enough to check only $\frac{a_1}{a_2} = \frac{b_1}{b_2}$ before answering 'infinitely many solutions'?
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Q108. Find a value of c for which $2x + 3y = 7$ and $4x + 6y = c$ has (i) infinitely many solutions (ii) no solution.
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Q109. (a) State the three conditions on the ratios of coefficients, with the picture and the number of solutions in each case. (b) Apply them to: (i) $x - 2y = 0$, $3x + 4y = 20$ (ii) $2x + 3y = 9$, $4x + 6y = 18$ (iii) $x + 2y = 4$, $2x + 4y = 12$.
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1½ marks — (a) the three conditions. ½ mark — (a) the pictures and names. 1 mark each — (b) (i), (ii), (iii) with the ratios shown.
Q110. Two friends compare mobile plans. Plan A costs ₹x fixed plus ₹y per GB and Plan B is described by the equation $2x + 6y = 700$; Plan A's bill for 3 GB is given by $x + 3y = 350$. (a) Write both equations in standard form and find the three ratios. (b) How many solutions does the pair have, and what does that mean about the two descriptions? (c) Give one change to the second equation that would make the pair inconsistent, and say what that would mean.
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1½ marks — (a) standard form and ratios. 1½ marks — (b) infinitely many, with the meaning. 2 marks — (c) a valid change and its meaning.
Q111. Solving $x + y = 14$ and $x - y = 4$ by substitution gives
IntermediateShow answer & explanation
$x = 9,\ y = 5$
$x = 14 - y$, so $14 - 2y = 4$, giving $y = 5$ and $x = 9$.
Q112. The solution of $s - t = 3$ and $\frac{s}{3} + \frac{t}{2} = 6$ is
IntermediateShow answer & explanation
$s = 9,\ t = 6$
$s = 3 + t$, so $\frac{3+t}{3} + \frac{t}{2} = 6$; multiplying by 6: $2(3+t) + 3t = 36$, giving $5t = 30$, $t = 6$ and $s = 9$.
Q113. Solving $0.2x + 0.3y = 1.3$ and $0.4x + 0.5y = 2.3$ gives
IntermediateShow answer & explanation
$x = 2,\ y = 3$
Multiplying by 10: $2x + 3y = 13$ and $4x + 5y = 23$. Then $x = \frac{13 - 3y}{2}$ leads to $y = 3$, $x = 2$.
Q114. For $2x + 3y = 9$ and $4x + 6y = 18$, substitution ends with
IntermediateShow answer & explanation
a true statement, so infinitely many solutions
The second equation is twice the first, so both variables cancel and $18 = 18$ remains.
Q115. For $2x + 3y = 9$ and $4x + 6y = 20$, substitution ends with
IntermediateShow answer & explanation
a false statement, so no solution
The working leaves $18 = 20$, which is never true.
Q116. Aftab's ages give $x - 7y = -42$ and $x - 3y = 6$. His present age is
IntermediateShow answer & explanation
42
$x = 6 + 3y$ gives $-4y = -48$, so $y = 12$ and $x = 42$.
Q117. A two-digit number has digits adding to 9, and it stands 27 above the number its digits make in reverse. The number is
IntermediateShow answer & explanation
63
$x + y = 9$ and $x - y = 3$ give $x = 6$, $y = 3$, so the number is 63.
Q118. If $x = 2y$ and $3x - y = 10$, then y is
IntermediateShow answer & explanation
2
$3(2y) - y = 10$ gives $5y = 10$, so $y = 2$ (and $x = 4$).
Q119. A number is three times another and their sum is 48. The smaller number is
IntermediateShow answer & explanation
12
With $x = 3y$ and $x + y = 48$: $4y = 48$, so $y = 12$.
Q120. Which pair is best suited to substitution?
IntermediateShow answer & explanation
$y = 3x - 2$ and $2x + y = 8$
y is already the subject in the first equation, so substitution costs nothing.
Q121. Solving $y = 3x - 2$ and $2x + y = 8$ gives
IntermediateShow answer & explanation
$x = 2,\ y = 4$
$2x + 3x - 2 = 8$ gives $5x = 10$, so $x = 2$ and $y = 4$.
Q122. Assertion (A): A fractional answer such as $x = \frac{49}{29}$ means a mistake has been made. Reason (R): The solution of a pair of linear equations is always a whole number.
IntermediateShow answer & explanation
A is false but R is true
Both are false as stated; the correct choice is that A is false — fractional solutions are perfectly normal, as NCERT's own Example 4 shows.
Q123. Assertion (A): In the substitution method, the expression must be put into the equation that was NOT rearranged. Reason (R): Substituting into the rearranged equation gives an identity.
IntermediateShow answer & explanation
Both A and R are true, and R is the correct explanation of A
R explains A exactly: the rearranged equation cannot produce new information.
Q124. Solving $x - y = 1$ and $2x + y = 8$ by substitution gives
IntermediateShow answer & explanation
$x = 3,\ y = 2$
$x = 1 + y$, so $2(1 + y) + y = 8$ gives $3y = 6$, $y = 2$ and $x = 3$.
Q125. For $x + y = 6$ and $2x + 2y = k$, the pair has NO solution when k is
IntermediateShow answer & explanation
8
$k = 12$ would make the equations identical; any other value, such as 8, leaves a false statement.
Q126. Five pens and three pencils cost ₹44, and one pen costs ₹4 more than one pencil. The cost of a pen is
IntermediateShow answer & explanation
₹7
Let a pencil cost ₹y, so a pen costs ₹(y + 4). Then $5(y + 4) + 3y = 44$ gives $8y = 24$, so $y = 3$ and a pen costs ₹7.
Q127. The sum of two numbers is 35 and their difference is 13. The larger number is
IntermediateShow answer & explanation
24
$x = 35 - y$, so $35 - 2y = 13$ gives $y = 11$ and $x = 24$.
Q128. Solve by substitution: $3x - y = 3$ and $9x - 3y = 9$.
IntermediateShow answer & explanation
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Q129. Solve by substitution: $x + 2y = 5$ and $2x + 4y = 15$.
IntermediateShow answer & explanation
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Q130. Solve by substitution: $7x - 15y = 2$ and $x + 2y = 3$.
IntermediateShow answer & explanation
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Q131. Solve by substitution: $s - t = 3$ and $\frac{s}{3} + \frac{t}{2} = 6$.
IntermediateShow answer & explanation
—
Q132. The larger of two supplementary angles exceeds the smaller by 18°. Find both angles by substitution.
IntermediateShow answer & explanation
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Q133. Explain what it means if, while solving by substitution, both variables disappear and you are left with $0 = 0$.
IntermediateShow answer & explanation
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Q134. (a) Write the three steps of the substitution method. (b) Use it to solve $2x + 3y = 11$ and $2x - 4y = -24$. (c) Verify your answer in both original equations.
IntermediateShow answer & explanation
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1½ marks — (a) the three steps. 2½ marks — (b) working to x = −2, y = 5. 1 mark — (c) both checks.
Q135. (a) Solve by substitution: $3x - y = 3$, $9x - 3y = 9$, and say what your result means. (b) Solve by substitution: $x + 2y = 5$, $2x + 4y = 15$, and say what your result means. (c) What picture do the lines make in each case?
IntermediateShow answer & explanation
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2 marks — (a) working and meaning. 2 marks — (b) working and meaning. 1 mark — (c) both pictures.
Q136. Solving $x + y = 5$ and $2x - 3y = 4$ by elimination gives
IntermediateShow answer & explanation
$x = \frac{19}{5},\ y = \frac{6}{5}$
Multiplying the first by 3 and adding gives $5x = 19$, so $x = \frac{19}{5}$ and $y = \frac{6}{5}$.
Q137. Solving $3x + 4y = 10$ and $2x - 2y = 2$ gives
IntermediateShow answer & explanation
$x = 2,\ y = 1$
Doubling the second gives $4x - 4y = 4$; adding removes y and leaves $7x = 14$.
Q138. Solving $3x - 5y = 4$ and $9x = 2y + 7$ gives
IntermediateShow answer & explanation
$x = \frac{9}{13},\ y = -\frac{5}{13}$
Writing the second as $9x - 2y = 7$ and tripling the first gives $9x - 15y = 12$; subtracting leaves $13y = -5$.
Q139. Two people's incomes are in the ratio 9 : 7 and their spendings in the ratio 4 : 3, each saving ₹2000 a month. Their incomes are
IntermediateShow answer & explanation
₹18,000 and ₹14,000
$9x - 4y = 2000$ and $7x - 3y = 2000$ give $x = 2000$, so the incomes are $9x$ and $7x$.
Q140. Adding a two-digit number to the number its digits make in reverse gives 66, and the two digits are 2 apart. One such number is
IntermediateShow answer & explanation
24
$11(x + y) = 66$ gives $x + y = 6$, and with $y - x = 2$ the digits are 2 and 4.
Q141. Five years ago a father was seven times as old as his son; in five years he will be three times as old. The son's present age is
IntermediateShow answer & explanation
10 years
$x - 5 = 7(y - 5)$ and $x + 5 = 3(y + 5)$ give $y = 10$ and $x = 40$.
Q142. Which pair is better suited to elimination than to substitution?
IntermediateShow answer & explanation
$7x + 9y = 11$ and $4x - 5y = 3$
No coefficient is 1, so making a variable the subject would bring fractions immediately.
Q143. Half the perimeter of a rectangular garden is 36 m and its length is 4 m more than its width. Its dimensions are
IntermediateShow answer & explanation
20 m by 16 m
$x + y = 36$ and $x - y = 4$ give $x = 20$ and $y = 16$.
Q144. Subtracting $(5x + 3y = 13)$ from $(5x - 2y = 4)$ gives
IntermediateShow answer & explanation
$-5y = -9$
$(-2y) - (3y) = -5y$ and $4 - 13 = -9$; the constant's sign changes too.
Q145. Two kilograms of apples and one of grapes cost ₹160, while four kilograms of apples and two of grapes cost ₹300. The pair has
IntermediateShow answer & explanation
no solution
Doubling the first bill gives ₹320, not ₹300, so elimination leaves a false statement.
Q146. Assertion (A): In elimination you add the equations when the matched coefficients have the same sign. Reason (R): Adding two equal positive terms gives zero.
IntermediateShow answer & explanation
A is false but R is true
Both statements are false: with the same sign you SUBTRACT, and adding equal positive terms doubles them rather than cancelling.
Q147. Assertion (A): Elimination and substitution give the same solution for any pair. Reason (R): Both methods only ever replace an equation by an equivalent one.
IntermediateShow answer & explanation
Both A and R are true, and R is the correct explanation of A
Each step preserves the solution set, so the two routes must end in the same place.
Topper level · 53 questions
Q148. For what value of k do the lines $x + 2y = 3$ and $2x + ky = 6$ coincide?
AdvancedShow answer & explanation
4
Doubling the first gives $2x + 4y = 6$, so $k = 4$ makes the equations identical.
Q149. The lines $x = 3$ and $y = -2$ meet at
AdvancedShow answer & explanation
$(3, -2)$
$x = 3$ is a vertical line and $y = -2$ a horizontal one; they cross at $(3, -2)$.
Q150. A pair of equations has the solution $(4, 1)$. Which pair could it be?
AdvancedShow answer & explanation
$x + y = 5$ and $x - y = 3$
$4 + 1 = 5$ ✓ and $4 - 1 = 3$ ✓ Only the first pair holds for both.
Q151. The cost of 3 kg apples and 2 kg grapes is ₹180, and of 2 kg apples and 4 kg grapes is ₹200. Taking prices x and y per kg, the pair is
AdvancedShow answer & explanation
$3x + 2y = 180$, $2x + 4y = 200$
Each bill is one equation, with the quantities as coefficients.
Q152. Two lines meet at $(2, 5)$. How many pairs of linear equations have this solution?
AdvancedShow answer & explanation
Infinitely many
Any two different lines through $(2, 5)$ give such a pair, and there are infinitely many lines through a point.
Q153. If a pair of lines has exactly one common point, which is NOT possible?
AdvancedShow answer & explanation
The equations are equivalent
Equivalent equations draw the same line, which shares every point, not one.
Q154. Assertion (A): Two distinct straight lines can meet at exactly two points. Reason (R): Two points determine a unique straight line.
AdvancedShow answer & explanation
A is false but R is true
R is true, and it is precisely why A is false: lines sharing two points must be the same line.
Q155. A boat's speed downstream and upstream gives the pair $x + y = 10$ and $x - y = 6$, where x is the boat's speed and y the stream's. The stream's speed is
AdvancedShow answer & explanation
2 km/h
Subtracting gives $2y = 4$, so $y = 2$ (and $x = 8$).
Q156. Which pair of equations is NOT a pair of linear equations in two variables?
AdvancedShow answer & explanation
$xy = 6$ and $x + y = 5$
$xy = 6$ multiplies the variables, so it is not linear.
Q157. If $(3, 2)$ is a solution of $2x + ky = 12$, find k and write one more solution of that equation.
AdvancedShow answer & explanation
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Q158. A father is three times as old as his son. Five years later he will be two and a half times as old. Form the pair of equations (do not solve).
AdvancedShow answer & explanation
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Q159. (a) Describe the three ways in which the lines of a pair of linear equations can be placed, and give the number of solutions in each case. (b) For each case, give one example of a pair of equations. (c) Which of your three pairs are consistent?
AdvancedShow answer & explanation
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1½ marks — (a) three cases with counts. 2 marks — (b) one valid example each. 1½ marks — (c) the two consistent pairs, with the reason.
Q160. The coach of a cricket team buys 3 bats and 6 balls for ₹3900. Later she buys another bat and 3 more balls of the same kind for ₹1300. (a) Represent this situation algebraically. (b) Find the cost of one bat and one ball by any method. (c) If she now buys 2 bats and 5 balls, what will she pay?
AdvancedShow answer & explanation
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1½ marks — (a) both equations with the letters named. 2 marks — (b) the solution, with the comment on the data. 1½ marks — (c) ₹2600.
Q161. For what value of k do $2x + 3y - 7 = 0$ and $(k-1)x + (k+2)y - 3k = 0$ have infinitely many solutions?
AdvancedShow answer & explanation
7
$2(k+2) = 3(k-1)$ gives $k = 7$, and then $\frac{2}{6} = \frac{-7}{-21}$ ✓
Q162. For which value of k does $kx + 2y = 5$ and $3x + y = 1$ have a unique solution?
AdvancedShow answer & explanation
$k \neq 6$
A unique solution needs $\frac{k}{3} \neq \frac21$, i.e. $k \neq 6$.
Q163. The pair $2x + 3y = 7$ and $(a - b)x + (a + b)y = 3a + b - 2$ has infinitely many solutions. Then
AdvancedShow answer & explanation
$a = 5,\ b = 1$
From $\frac{2}{a-b} = \frac{3}{a+b}$: $2a + 2b = 3a - 3b$, so $a = 5b$. The constant ratio then gives $b = 1$, $a = 5$; checking, the second equation becomes $4x + 6y = 14$ ✓
Q164. If the lines $3x + 2ky = 2$ and $2x + 5y + 1 = 0$ are parallel, then k is
AdvancedShow answer & explanation
$\frac{15}{4}$
Parallel needs $\frac32 = \frac{2k}{5}$, so $4k = 15$ and $k = \frac{15}{4}$. (The constants then differ, as required.)
Q165. A pair with $a_1b_2 - a_2b_1 = 0$ and $b_1c_2 - b_2c_1 \neq 0$ has
AdvancedShow answer & explanation
no solution
The first says the slopes match; the second says the constants do not — parallel lines.
Q166. Assertion (A): A pair of linear equations can have exactly two solutions. Reason (R): Two straight lines can cross at no point, one point, or infinitely many.
AdvancedShow answer & explanation
A is false but R is true
R is true and rules A out: exactly two crossings is impossible for straight lines.
Q167. For $x + 2y = 3$ and $2x + 4y = k$, the pair has infinitely many solutions when k is
AdvancedShow answer & explanation
6
All three ratios must agree: $\frac12 = \frac24 = \frac{-3}{-k}$ needs $k = 6$.
Q168. Which change to $x + y = 4$ and $2x + 2y = 8$ would make the pair inconsistent?
AdvancedShow answer & explanation
Change 8 to 9
With 9 the a and b ratios still match while the c ratio does not, giving parallel lines.
Q169. If $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} = \frac{1}{2}$, then the second equation is
AdvancedShow answer & explanation
twice the first
Each coefficient of the second is twice the matching one in the first.
Q170. Two equations with $a_1 = 2$, $b_1 = -3$, $a_2 = -4$, $b_2 = 6$ represent lines that are
AdvancedShow answer & explanation
parallel or coincident
$\frac{2}{-4} = \frac{-3}{6} = -\frac12$, so the slopes match; only the constants can tell parallel from coincident.
Q171. Which of these pairs is consistent?
AdvancedShow answer & explanation
$2x + y = 5$ and $3x - y = 5$
Only the first has unequal a-to-b ratios, so its lines cross; the other three are parallel pairs.
Q172. For what value of k does $kx + 3y = k - 3$ and $12x + ky = k$ have infinitely many solutions?
AdvancedShow answer & explanation
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Q173. Two lines are given by $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ with $a_2 = 0$. Explain how to test for a unique solution without dividing by zero.
AdvancedShow answer & explanation
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Q174. (a) Find the value of k for which the pair $3x + y = 1$ and $(2k - 1)x + (k - 1)y = 2k + 1$ has no solution. (b) Show that for this k the lines are parallel and not coincident. (c) For what values of k does the pair have a unique solution?
AdvancedShow answer & explanation
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2 marks — (a) the condition and k = 2. 1½ marks — (b) the ratios shown for k = 2. 1½ marks — (c) k ≠ 2, with the reasoning.
Q175. (a) For what value of k does $x + 2y = 3$ and $5x + ky + 7 = 0$ have no solution? (b) For that k, write both equations in standard form and give all three ratios. (c) Is there any value of k for which this pair has infinitely many solutions? Justify your answer.
AdvancedShow answer & explanation
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1½ marks — (a) k = 10. 1½ marks — (b) the three ratios. 2 marks — (c) 'no', with the reason that c is fixed.
Q176. If $2x + 3y = 11$ and $2x - 4y = -24$, then the value of $y$ is
AdvancedShow answer & explanation
5
Subtracting the equations gives $7y = 35$, so $y = 5$; by substitution $2x = 11 - 15$, giving $x = -2$.
Q177. For the pair $x + y = 5$ and $2x + 2y = k$, substitution leaves a true statement when k is
AdvancedShow answer & explanation
10
The second equation must be exactly twice the first, so $k = 10$.
Q178. If (x, y) is the solution of $3x + 2y = 11$ and $2x + 3y = 4$, then $x - y$ equals
AdvancedShow answer & explanation
7
Solving the pair gives $x = 5$ and $y = -2$, so $x - y = 5 - (-2) = 7$.
Q179. A fraction becomes $\frac{4}{5}$ if 1 is added to both numerator and denominator, and $\frac{1}{2}$ if 5 is subtracted from both. The fraction is
AdvancedShow answer & explanation
$\frac{7}{9}$
With numerator x and denominator y: $5(x+1) = 4(y+1)$ and $2(x-5) = y-5$. Solving gives $x = 7$, $y = 9$.
Q180. Two numbers differ by 26 and one is three times the other. The larger number is
AdvancedShow answer & explanation
39
With $x = 3y$ and $x - y = 26$: $2y = 26$, so $y = 13$ and $x = 39$.
Q181. The larger of two supplementary angles exceeds the smaller by 18°. The larger angle is
AdvancedShow answer & explanation
99°
$x + y = 180$ and $x - y = 18$ give $x = 99$, $y = 81$.
Q182. Assertion (A): The pair $y = 2x + 1$ and $y = 2x + 5$ has no solution. Reason (R): Substituting gives $2x + 1 = 2x + 5$, i.e. $1 = 5$, which is false.
AdvancedShow answer & explanation
Both A and R are true, and R is the correct explanation of A
The false statement is exactly the sign of parallel lines and no solution.
Q183. For which value of m does $y = mx + 3$ and $y = 2x + 3$ have infinitely many solutions?
AdvancedShow answer & explanation
2
The two right-hand sides must be identical, so $m = 2$.
Q184. The cost of 2 kg of apples and 1 kg of grapes is ₹160, and of 4 kg of apples and 2 kg of grapes is ₹300. The pair has
AdvancedShow answer & explanation
no solution
Doubling the first gives ₹320, not ₹300, so the two statements contradict each other.
Q185. Assertion (A): Substitution works on any pair of linear equations in two variables. Reason (R): One variable can always be written in terms of the other when its coefficient is not zero.
AdvancedShow answer & explanation
Both A and R are true, and R is the correct explanation of A
In every linear equation at least one coefficient is non-zero, so a variable can always be made the subject; R is exactly why A holds.
Q186. In solving $3x + y = 10$ and $x + y = 6$ by substitution, the cleanest first move is
AdvancedShow answer & explanation
$y = 6 - x$ from the second equation
Both y-coefficients are 1, and taking $y = 6 - x$ keeps the arithmetic whole-numbered; substituting a rearranged equation back into itself does nothing.
Q187. Aftab is seven times as old as his daughter was seven years ago, and three times as old as she will be in three years. Find their present ages.
AdvancedShow answer & explanation
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Q188. A fraction becomes $\frac{4}{5}$ when 1 is added to both its numerator and denominator, and $\frac{1}{2}$ when 5 is subtracted from both. Find the fraction.
AdvancedShow answer & explanation
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Q189. A two-digit number is such that the sum of its digits is 9, and the number is 27 more than the number obtained by reversing its digits. (a) Taking the tens digit as x and the units digit as y, write both equations. (b) Solve them by substitution. (c) State the number and verify both conditions.
AdvancedShow answer & explanation
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1½ marks — (a) both equations, with the simplification. 2 marks — (b) substitution and both digits. 1½ marks — (c) the number and both verifications.
Q190. A lending library charges a fixed amount for the first three days and an extra charge for each further day. Saritha paid ₹27 for a book kept for seven days, and Susy paid ₹21 for a book kept for five days. (a) Taking the fixed charge as ₹x and the charge per extra day as ₹y, write the two equations. (b) Solve them by substitution. (c) What would a book kept for ten days cost?
AdvancedShow answer & explanation
—
1½ marks — (a) both equations with the 'extra days' counted correctly. 2 marks — (b) x = 15, y = 3. 1½ marks — (c) ₹36.
Q191. Twice a number added to three times a second gives 92, while four times the first minus the second gives 16. The first number is
AdvancedShow answer & explanation
10
$2x + 3y = 92$ and $4x - y = 16$. Tripling the second and adding removes y: $14x = 140$.
Q192. A boat covers 30 km upstream and 44 km downstream in 10 hours, and 40 km upstream and 55 km downstream in 13 hours. The boat's speed in still water is
AdvancedShow answer & explanation
8 km/h
With $p = \frac{1}{u-v}$ and $q = \frac{1}{u+v}$ the times give $p = \frac15$, $q = \frac1{11}$, so $u - v = 5$ and $u + v = 11$.
Q193. For what value of k do $2x + 3y = 7$ and $4x + 6y = k$ have infinitely many solutions?
AdvancedShow answer & explanation
14
The second equation must be exactly twice the first, so $k = 14$.
Q194. Eliminating x from $ax + by = c$ and $a'x + b'y = c'$ requires multiplying by
AdvancedShow answer & explanation
$a'$ and $a$ respectively
Multiplying the first by $a'$ and the second by $a$ makes both x-coefficients $aa'$.
Q195. Two complementary angles differ by 20°. Eliminating gives the larger angle as
AdvancedShow answer & explanation
55°
Complementary angles sum to 90°, so $x + y = 90$ and $x - y = 20$; adding gives $2x = 110$.
Q196. Five books and seven pens together cost ₹79, while seven books and five pens cost ₹77. The cost of one book is
AdvancedShow answer & explanation
₹6
Adding gives $12(x + y) = 156$, and subtracting gives $2(x - y) = -2$; so $x + y = 13$ and $y - x = 1$, making a book ₹6.
Q197. A two-digit number is four times the sum of its digits, and twice the product of its digits. The number is
AdvancedShow answer & explanation
36
$10x + y = 4(x + y)$ gives $2x = y$, and $10x + y = 2xy$ then gives $x = 3$, $y = 6$.
Q198. Assertion (A): For $3x + 2y = 8$ and $6x + 4y = 16$, elimination leaves $0 = 0$. Reason (R): The two equations represent parallel lines that never meet.
AdvancedShow answer & explanation
A is true but R is false
They represent the same line, which is why elimination collapses to $0 = 0$ instead of a contradiction. The assertion holds, the reason is false.
Q199. In a 3-mark word problem, the mark most often lost is for
AdvancedShow answer & explanation
not answering in a sentence with units
The final statement carries its own mark, and 'x = 42' does not earn it.
Q200. The coach of a team buys 7 bats and 6 balls for ₹3800, and later 3 bats and 5 balls for ₹1750. The cost of one bat is
AdvancedShow answer & explanation
₹500
$7x + 6y = 3800$ and $3x + 5y = 1750$; eliminating y gives $17x = 8500$.
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