Polynomials · Class 10 Mathematics: 170 MCQs with answers
All 170 multiple-choice questions from this kit, free and with no sign-up.
Warm-up · 47 questions
Q1. Which of these is a polynomial?
BeginnerShow answer & explanation
$x^2 - 3x + 2$
Only the first uses whole-number powers of x throughout.
Q2. The degree of $5x^3 - 4x^2 + x - 2$ is
BeginnerShow answer & explanation
3
The highest power of x is 3.
Q3. A polynomial of degree 2 is called
BeginnerShow answer & explanation
quadratic
Degree 1 is linear, 2 quadratic, 3 cubic.
Q4. The general form of a linear polynomial is
BeginnerShow answer & explanation
$ax + b,\ a \neq 0$
Degree 1 with a non-zero coefficient of x.
Q5. For $p(x) = x^2 - 3x - 4$, the value of $p(0)$ is
BeginnerShow answer & explanation
−4
$p(0) = 0 - 0 - 4 = -4$.
Q6. For $p(x) = 2x + 7$, $p(3)$ equals
BeginnerShow answer & explanation
13
$2(3) + 7 = 13$.
Q7. A real number k is a zero of p(x) when
BeginnerShow answer & explanation
$p(k) = 0$
That is the definition of a zero.
Q8. The zero of the polynomial $3x - 12$ is
BeginnerShow answer & explanation
4
$3x - 12 = 0$ gives $x = 4$.
Q9. The zero of $ax + b$ ($a \neq 0$) is
BeginnerShow answer & explanation
$-\frac{b}{a}$
Solving $ax + b = 0$ gives $x = -\frac{b}{a}$.
Q10. How many zeroes does a linear polynomial have?
BeginnerShow answer & explanation
Exactly one
$ax + b = 0$ has exactly one solution when $a \neq 0$.
Q11. The degree of the polynomial $3 - x^2 + x^3$ is
BeginnerShow answer & explanation
3
Read every term: the highest power is 3.
Q12. Which of these is a cubic polynomial?
BeginnerShow answer & explanation
$3x^3 - 2x^2 + x - 1$
A cubic has degree 3.
Q13. Assertion (A): $x^2 + \frac{1}{x}$ is not a polynomial. Reason (R): In a polynomial every power of the variable must be a whole number.
BeginnerShow answer & explanation
Both A and R are true, and R is the correct explanation of A
$\frac{1}{x} = x^{-1}$, and −1 is not a whole number. R is the rule that makes A true.
Q14. The coefficient of $x^2$ in $5 - 3x + 7x^2 - x^3$ is
BeginnerShow answer & explanation
7
Read the number multiplying $x^2$, keeping its sign: 7.
Q15. The constant term of $p(x) = 4x^3 - x + 6$ is
BeginnerShow answer & explanation
6
The constant term is the one with no x: 6. (It is also p(0).)
Q16. State which of these are polynomials in x, giving a reason: (i) $4x^2 - 3x + 7$ (ii) $\frac{2}{x} + 5$ (iii) $\sqrt{3}x^2 - 2x$ (iv) $x^{3/2} + 1$.
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Q17. For $p(x) = x^2 - 3x - 4$, find p(2), p(0) and p(−1), and say which of these numbers is a zero.
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Q18. Find the zero of each linear polynomial: (i) $2x + 3$ (ii) $5x - 20$ (iii) $-3x + 9$.
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Q19. Verify whether 2 and −1 are zeroes of $p(x) = x^2 - x - 2$.
BeginnerShow answer & explanation
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Q20. The zeroes of a polynomial are the x-coordinates of the points where its graph meets
BeginnerShow answer & explanation
the x-axis
On the x-axis, y = 0, which is exactly the condition $p(x) = 0$.
Q21. The graph of a linear polynomial is
BeginnerShow answer & explanation
a straight line
$y = ax + b$ is always a straight line.
Q22. The graph of $y = ax^2 + bx + c$ with $a > 0$
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opens upwards
A positive a gives a parabola opening upwards; whether it meets the axis depends on the other coefficients.
Q23. A graph meets the x-axis at exactly 2 points. The number of zeroes is
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2
Each meeting with the x-axis is one zero.
Q24. The graph of a quadratic polynomial touches the x-axis at exactly one point. The polynomial has
BeginnerShow answer & explanation
two equal zeroes
A touch is where two crossings have come together — one value, repeated.
Q25. A parabola lies entirely above the x-axis. The number of real zeroes is
BeginnerShow answer & explanation
0
It never meets the axis, so the polynomial has no real zero.
Q26. The graph of $y = 2x + 3$ cuts the x-axis at
BeginnerShow answer & explanation
$\left(-\frac{3}{2}, 0\right)$
Set $y = 0$: $2x + 3 = 0$ gives $x = -\frac{3}{2}$.
Q27. The point where a graph meets the y-axis gives
BeginnerShow answer & explanation
p(0)
At the y-axis $x = 0$, so the height there is p(0), the constant term.
Q28. How many times does the graph of a polynomial of degree 4 meet the x-axis, at most?
BeginnerShow answer & explanation
4
At most n times for degree n.
Q29. Assertion (A): The graph of a linear polynomial cuts the x-axis at exactly one point. Reason (R): A linear polynomial has exactly one zero.
BeginnerShow answer & explanation
Both A and R are true, and R is the correct explanation of A
Both are true and they say the same thing in two languages — the crossing IS the zero.
Q30. Which curve can meet the x-axis three times?
BeginnerShow answer & explanation
$y = x^3 - 4x$
Only the cubic can have three zeroes; it meets the axis at −2, 0 and 2.
Q31. Where does $y = x^2$ meet the x-axis?
BeginnerShow answer & explanation
at exactly one point
$x^2 = 0$ only at $x = 0$, so the parabola touches the axis at the origin.
Q32. What is the geometrical meaning of a zero of a polynomial? Illustrate with $p(x) = 2x + 3$.
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Q33. Describe the three ways in which the graph of a quadratic polynomial can meet the x-axis, and give the number of zeroes in each case.
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Q34. For the zeroes α and β of $ax^2 + bx + c$, the value of $\alpha + \beta$ equals
BeginnerShow answer & explanation
$-\frac{b}{a}$
The sum is minus the coefficient of x divided by the coefficient of $x^2$.
Q35. For the same polynomial, $\alpha\beta$ equals
BeginnerShow answer & explanation
$\frac{c}{a}$
The product is the constant term over the coefficient of $x^2$, with no minus sign.
Q36. The sum of the zeroes of $x^2 - 7x + 12$ is
BeginnerShow answer & explanation
7
$-\frac{b}{a} = -\frac{-7}{1} = 7$.
Q37. The product of the zeroes of $x^2 - 7x + 12$ is
BeginnerShow answer & explanation
12
$\frac{c}{a} = \frac{12}{1} = 12$.
Q38. The sum of the zeroes of $2x^2 - 8x + 6$ is
BeginnerShow answer & explanation
4
$-\frac{-8}{2} = 4$. Dividing by a is the step that is often missed.
Q39. A quadratic polynomial whose zeroes have sum 5 and product 6 is
BeginnerShow answer & explanation
$x^2 - 5x + 6$
Use $x^2 - Sx + P$ with $S = 5$ and $P = 6$.
Q40. A quadratic polynomial whose zeroes have sum −3 and product 2 is
BeginnerShow answer & explanation
$x^2 + 3x + 2$
$x^2 - (-3)x + 2 = x^2 + 3x + 2$.
Q41. The zeroes of $x^2 + 7x + 10$ are
BeginnerShow answer & explanation
−2 and −5
$(x + 2)(x + 5)$, so the zeroes are −2 and −5. Their sum is −7 and product 10 ✓
Q42. In splitting the middle term of $ax^2 + bx + c$, the two numbers chosen must have product
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ac
Product ac and sum b — using factors of b instead is the usual slip.
Q43. The product of the zeroes of $4x^2 + 8x$ is
BeginnerShow answer & explanation
0
The constant term is 0, so the product is $\frac{0}{4} = 0$.
Q44. Assertion (A): For $x^2 - 3$, the sum of the zeroes is 0. Reason (R): The sum of the zeroes equals $-\frac{b}{a}$, and here $b = 0$.
BeginnerShow answer & explanation
Both A and R are true, and R is the correct explanation of A
There is no x term, so $b = 0$ and the sum is 0. The zeroes $\pm\sqrt3$ confirm it.
Q45. The zeroes of $x^2 - 15$ are
BeginnerShow answer & explanation
$\sqrt{15}$ and $-\sqrt{15}$
$x^2 = 15$ gives $x = \pm\sqrt{15}$. Sum 0 ✓ product −15 ✓
Q46. Find the zeroes of $x^2 - 2x - 8$ and verify the relationship between the zeroes and the coefficients.
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Q47. Find a quadratic polynomial whose zeroes have sum $\frac{1}{4}$ and product −1.
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Building up · 78 questions
Q48. For $p(x) = x^2 - 3x - 4$, which number is a zero?
IntermediateShow answer & explanation
4
$p(4) = 16 - 12 - 4 = 0$. $p(0) = -4$, $p(2) = -6$ and $p(-4) = 24$.
Q49. If $p(x) = 5x^2 - 4x + 2$, then $p(1)$ is
IntermediateShow answer & explanation
3
$5 - 4 + 2 = 3$.
Q50. If $p(y) = y^3 - 3y + 5$, then $p(-2)$ is
IntermediateShow answer & explanation
3
$(-2)^3 - 3(-2) + 5 = -8 + 6 + 5 = 3$.
Q51. Which of these has 2 as a zero?
IntermediateShow answer & explanation
$x^2 - 5x + 6$
$4 - 10 + 6 = 0$. The others give 20, 8 and 8 at $x = 2$.
Q52. If $(k - 2)x^2 + 3x + 5$ is a linear polynomial, then k is
IntermediateShow answer & explanation
2
A linear polynomial has no $x^2$ term, so $k - 2 = 0$.
Q53. If 4 is a zero of $p(x) = x^2 - 6x + k$, then k is
IntermediateShow answer & explanation
8
$p(4) = 16 - 24 + k = 0$, so $k = 8$.
Q54. If $-2$ is a zero of $p(x) = 2x^2 + 3x + m$, then m is
IntermediateShow answer & explanation
−2
$2(4) + 3(-2) + m = 8 - 6 + m = 0$, so $m = -2$.
Q55. The number of zeroes a cubic polynomial can have at most is
IntermediateShow answer & explanation
3
A polynomial of degree n has at most n zeroes.
Q56. Which quadratic polynomial has NO real zero?
IntermediateShow answer & explanation
$x^2 + 4$
$x^2 + 4 \ge 4$ for every real x. The others have zeroes ±2, {0, 4} and 2.
Q57. The zero of $p(x) = 7x$ is
IntermediateShow answer & explanation
0
$7x = 0$ gives $x = 0$.
Q58. If $p(x) = x^2 - 1$, then $p(1) + p(-1)$ equals
IntermediateShow answer & explanation
0
$p(1) = 0$ and $p(-1) = 0$, so the sum is 0.
Q59. A polynomial whose value is 0 for x = 5 must have
IntermediateShow answer & explanation
$(x - 5)$ as a factor
If $p(5) = 0$ then $x - 5$ divides p(x).
Q60. Assertion (A): $x^2 + 1$ has no real zero. Reason (R): $x^2 + 1$ is a quadratic polynomial.
IntermediateShow answer & explanation
Both A and R are true, but R is not the correct explanation of A
Both are true, but being quadratic does not rule out real zeroes - plenty of quadratics have them.
Q61. Assertion (A): Every quadratic polynomial has exactly two zeroes. Reason (R): A polynomial of degree n has at most n zeroes.
IntermediateShow answer & explanation
A is false but R is true
R is true. A is false — 'at most two', and $x^2 + 1$ has none.
Q62. Which is NOT a polynomial in x?
IntermediateShow answer & explanation
$3x^2 + 2\sqrt{x} - 1$
A surd COEFFICIENT is fine; a variable under a root is not.
Q63. The value of $p(x) = x^3 - 2x^2 + x$ at $x = 2$ is
IntermediateShow answer & explanation
2
$8 - 8 + 2 = 2$.
Q64. Which polynomial has 0 as one of its zeroes?
IntermediateShow answer & explanation
$x^2 - 4x$
$p(0) = 0$ happens exactly when the constant term is 0, as in $x^2 - 4x = x(x - 4)$.
Q65. A polynomial p(x) has $p(3) = 0$. Which statement must be true?
IntermediateShow answer & explanation
3 is a zero of p(x)
A zero is a number at which the value is 0 — that is exactly what $p(3) = 0$ says.
Q66. If $p(x) = x^2 - 9$, then the zeroes of p(x) are
IntermediateShow answer & explanation
3 and −3
$x^2 - 9 = (x - 3)(x + 3)$, so the value is 0 at 3 and at −3.
Q67. If 3 is a zero of $p(x) = x^2 - 4x + k$, find k and then the other zero.
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Q68. If $p(x) = (k - 3)x^2 + 5x - 2$ is a linear polynomial, find k and the zero of the resulting polynomial.
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Q69. Give one example each of a quadratic polynomial with (i) two zeroes (ii) exactly one zero (iii) no real zero, and state the zeroes where they exist.
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Q70. If $p(x) = 2x^3 - 3x^2 + 4x - 5$, find $p(1)$ and $p(-1)$.
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Q71. (a) Define the degree of a polynomial and name the polynomials of degree 1, 2 and 3. (b) For $p(x) = x^3 - 2x^2 - x + 2$, find p(1), p(2) and p(−1). (c) Write down the zeroes of p(x) from your answers in (b), and say how you know there are no others.
IntermediateShow answer & explanation
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1 mark — (a) definition. ½ mark — (a) the three names. 1½ marks — (b) the three values. 1 mark — (c) the zeroes listed. 1 mark — (c) 'a cubic has at most 3 zeroes'.
Q72. A shopkeeper's daily profit, in rupees, on selling x kites is $P(x) = x^2 - 12x + 20$. (a) Find the profit when 5 kites and when 10 kites are sold. (b) For which numbers of kites is the profit zero? (c) What does a negative value of P(x) mean, and give one value of x where it happens?
IntermediateShow answer & explanation
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1 mark — (a) P(5). 1 mark — (a) P(10). 1½ marks — (b) 2 and 10 with the factorisation. 1½ marks — (c) loss explained with a value.
Q73. A graph cuts the x-axis at 1 point and has no turning point. The polynomial is most likely
IntermediateShow answer & explanation
linear
A straight line meets the axis once and never turns.
Q74. A parabola opens downwards and cuts the x-axis at two points. Which is true?
IntermediateShow answer & explanation
$a < 0$ and there are two zeroes
Downwards means $a < 0$; two crossings mean two zeroes.
Q75. Which of these points lies on the curve $y = x^2 - 3x - 4$?
IntermediateShow answer & explanation
$(0, -4)$
$p(0) = -4$, so the curve passes through $(0, -4)$. Its x-axis points are $(-1, 0)$ and $(4, 0)$.
Q76. For $y = x^2 - 3x - 4$, the value of y at $x = 1$ is
IntermediateShow answer & explanation
−6
$1 - 3 - 4 = -6$: the curve is below the axis there.
Q77. A graph meets the x-axis at 3 points and the y-axis at 1 point. How many zeroes does the polynomial have?
IntermediateShow answer & explanation
3
Only x-axis meetings are zeroes; every graph of $y = p(x)$ meets the y-axis exactly once.
Q78. Which polynomial's graph TOUCHES the x-axis without crossing it?
IntermediateShow answer & explanation
$y = x^2 - 4x + 4$
$x^2 - 4x + 4 = (x - 2)^2$ is never negative and is 0 only at $x = 2$.
Q79. A cubic polynomial's graph meets the x-axis at exactly 1 point. Its number of zeroes is
IntermediateShow answer & explanation
1
A cubic may have fewer zeroes than its degree: $y = x^3$ meets the axis only at 0.
Q80. If the graph of a quadratic polynomial does not meet the x-axis at all, then
IntermediateShow answer & explanation
it has no real zero
No crossing means no real zero, as for $y = x^2 + 2$.
Q81. The zeroes of the polynomial whose graph cuts the x-axis at $(-3, 0)$ and $(5, 0)$ are
IntermediateShow answer & explanation
−3 and 5
Read the x-coordinates of the crossings.
Q82. Which of these could NOT be the number of zeroes of a quadratic polynomial?
IntermediateShow answer & explanation
3
A parabola meets the x-axis at most twice.
Q83. Assertion (A): A graph that meets the x-axis at four points belongs to a polynomial of degree at least 4. Reason (R): A polynomial of degree $n$ has at least $n$ zeroes.
IntermediateShow answer & explanation
A is true but R is false
It has at most $n$, which is what forces the degree up to 4 here. The assertion stands, the reason is false.
Q84. Assertion (A): The point $(0, 5)$ on the graph of $y = p(x)$ means 5 is a zero of p(x). Reason (R): The zeroes of p(x) are the x-coordinates of the points where the graph meets the x-axis.
IntermediateShow answer & explanation
A is false but R is true
R is true. A is false: $(0, 5)$ is on the y-axis, so it gives $p(0) = 5$, not a zero.
Q85. A parabola passes through $(2, 0)$ and $(6, 0)$ and opens upwards. Between $x = 2$ and $x = 6$ the curve is
IntermediateShow answer & explanation
below the x-axis
An upward parabola dips below the axis between its two zeroes.
Q86. How many zeroes does the polynomial have if its graph is a straight line lying ALONG the x-axis?
IntermediateShow answer & explanation
Infinitely many
That graph is $y = 0$, the zero polynomial: every x gives the value 0.
Q87. For which polynomial does the graph meet the x-axis at exactly one point and lie above it everywhere else?
IntermediateShow answer & explanation
$y = (x + 3)^2$
$(x + 3)^2 \ge 0$, and it is 0 only at $x = -3$.
Q88. Which of these graphs must cross the x-axis at least once?
IntermediateShow answer & explanation
a cubic
A cubic runs from below the axis to above it, so it must cross. The others may miss it.
Q89. At which points does $y = -x^2 + 9$ cross the x-axis?
IntermediateShow answer & explanation
$(-3, 0)$ and $(3, 0)$
$-x^2 + 9 = 0$ gives $x^2 = 9$, so $x = \pm 3$.
Q90. A graph passes through $(0, 0)$. Which statement is certain?
IntermediateShow answer & explanation
0 is a zero of the polynomial
$(0, 0)$ lies on the x-axis, so $p(0) = 0$ and 0 is a zero. Nothing about the degree follows.
Q91. The number of turning points of a parabola is
IntermediateShow answer & explanation
1
A parabola turns exactly once, whether it has two zeroes, one or none.
Q92. A graph of $y = p(x)$ meets the x-axis at 3 points and has 2 turning points. How many zeroes has p(x), and what can you say about its degree?
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Q93. For $p(x) = x^2 - 3x - 4$, complete the values at $x = -2, -1, 0, 1, 2, 3, 4$ and state the zeroes from the table.
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Q94. The graph of a quadratic polynomial passes through $(0, 6)$ and lies completely above the x-axis. How many zeroes does it have, and what is the constant term?
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Q95. Explain why the graph of a quadratic polynomial can never meet the x-axis at three points.
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Q96. State whether each graph could belong to a quadratic polynomial: (i) a curve cutting the x-axis at 2 points (ii) a straight line (iii) a curve meeting the x-axis at 3 points.
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Q97. (a) State the geometrical meaning of the zeroes of a polynomial. (b) Draw a rough sketch, described in words, of a quadratic polynomial with (i) two distinct zeroes (ii) two equal zeroes (iii) no real zero. (c) In each case state how many times the curve meets the x-axis.
IntermediateShow answer & explanation
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1 mark — (a). 1 mark each — (b) the three descriptions. 1 mark — (c) the three counts.
Q98. A stone is thrown upwards from a cliff. Its height above the sea, in metres, after t seconds is $h(t) = -5t^2 + 10t + 40$, and the graph of h against t is a parabola. (a) Which way does the parabola open, and why? (b) What is the height at $t = 0$, and what does the point $(0, 40)$ mean? (c) Show that $t = 4$ is a zero of h(t) and say what it means. Why is $t = -2$, the other zero, of no use here?
IntermediateShow answer & explanation
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1 mark — (a) with the reason. 1½ marks — (b) 40 m and its meaning. 1½ marks — (c) the substitution and meaning. 1 mark — (c) rejecting the negative time.
Q99. The zeroes of $6x^2 - 7x - 3$ are
IntermediateShow answer & explanation
$\frac{3}{2}$ and $-\frac{1}{3}$
$6x^2 - 9x + 2x - 3 = 3x(2x - 3) + 1(2x - 3) = (3x + 1)(2x - 3)$.
Q100. If the sum of the zeroes of $kx^2 - 3x + 5$ is 1, then k is
IntermediateShow answer & explanation
3
Sum $= \frac{3}{k} = 1$, so $k = 3$.
Q101. If the product of the zeroes of $2x^2 + 5x + k$ is 3, then k is
IntermediateShow answer & explanation
6
Product $= \frac{k}{2} = 3$, so $k = 6$.
Q102. Let α and β be the zeroes of $x^2 - 5x + 6$. Then $\alpha^2 + \beta^2$ is
IntermediateShow answer & explanation
13
$(\alpha+\beta)^2 - 2\alpha\beta = 25 - 12 = 13$.
Q103. Given the zeroes α and β of $x^2 - 6x + 8$, the value of $\frac{1}{\alpha} + \frac{1}{\beta}$ is
IntermediateShow answer & explanation
$\frac{3}{4}$
$\frac{\alpha+\beta}{\alpha\beta} = \frac{6}{8} = \frac{3}{4}$.
Q104. A quadratic polynomial whose zeroes are 3 and −5 is
IntermediateShow answer & explanation
$x^2 + 2x - 15$
Sum $-2$, product $-15$, so $x^2 - (-2)x + (-15) = x^2 + 2x - 15$.
Q105. Which quadratic polynomial has zeroes whose sum is 0 and product is −9?
IntermediateShow answer & explanation
$x^2 - 9$
$x^2 - 0x + (-9) = x^2 - 9$, whose zeroes are 3 and −3.
Q106. The zeroes of $x^2 - 2x - 8$ are
IntermediateShow answer & explanation
4 and −2
$(x - 4)(x + 2)$. Sum 2 ✓ and product −8 ✓
Q107. For $4x^2 - 4x + 1$, the zeroes are
IntermediateShow answer & explanation
$\frac{1}{2}$ and $\frac{1}{2}$
$(2x - 1)^2$, so both zeroes are $\frac12$. Sum 1 ✓ product $\frac14$ ✓
Q108. If one zero of $x^2 - 4x + k$ is 3, the other zero is
IntermediateShow answer & explanation
1
The sum of the zeroes is 4, so the other is $4 - 3 = 1$. (Then $k = 3$.)
Q109. If the zeroes of a quadratic are equal, then
IntermediateShow answer & explanation
both relations still hold with α = β
Equal zeroes are still zeroes: sum $2\alpha = -\frac{b}{a}$ and product $\alpha^2 = \frac{c}{a}$.
Q110. How many quadratic polynomials have zeroes 2 and 3?
IntermediateShow answer & explanation
Infinitely many
Every $k(x^2 - 5x + 6)$ with $k \neq 0$ has these zeroes.
Q111. Assertion (A): $2x^2 - 10x + 12$ and $x^2 - 5x + 6$ have different zeroes. Reason (R): Multiplying a polynomial by a non-zero constant does not change its zeroes.
IntermediateShow answer & explanation
A is false but R is true
They have the same zeroes, so the assertion is false. The reason explains why the factor of 2 makes no difference.
Q112. Assertion (A): The sum of the zeroes of $3x^2 - 6x + 2$ is 6. Reason (R): The sum of the zeroes of $ax^2 + bx + c$ is $-\frac{b}{a}$.
IntermediateShow answer & explanation
A is false but R is true
R is correct, but A forgets to divide by a: the sum is $\frac{6}{3} = 2$.
Q113. Two numbers have sum 27 and product 182. The numbers are
IntermediateShow answer & explanation
13 and 14
They are the zeroes of $x^2 - 27x + 182 = (x - 13)(x - 14)$.
Q114. For $3x^2 - x - 4$, the sum and product of the zeroes are
IntermediateShow answer & explanation
$\frac{1}{3}$ and $-\frac{4}{3}$
$-\frac{b}{a} = \frac{1}{3}$ and $\frac{c}{a} = -\frac{4}{3}$.
Q115. If the zeroes of a quadratic are 1 and 1, the polynomial could be
IntermediateShow answer & explanation
$x^2 - 2x + 1$
Sum 2 and product 1 give $x^2 - 2x + 1 = (x-1)^2$.
Q116. For $x^2 + 4x + 4$, the sum and product of the zeroes are
IntermediateShow answer & explanation
−4 and 4
$-\frac{4}{1} = -4$ and $\frac{4}{1} = 4$. (Both zeroes are −2.)
Q117. If α and β are the zeroes of $x^2 - 2x - 15$, then $\alpha\beta + \alpha + \beta$ equals
IntermediateShow answer & explanation
−13
Product $-15$ plus sum 2 gives $-13$.
Q118. Find the zeroes of $6x^2 - 3 - 7x$ and verify both relations.
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Q119. Find a quadratic polynomial whose zeroes are $\sqrt{2}$ and $-\sqrt{2}$.
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Q120. If α and β are the zeroes of $x^2 - 5x + 4$, find $\alpha^2 + \beta^2$ without finding the zeroes.
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Q121. If α and β are the zeroes of $2x^2 - 7x + 3$, find $\frac{1}{\alpha} + \frac{1}{\beta}$.
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Q122. One zero of $x^2 - 9x + k$ is 4. Find the other zero and k.
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Q123. Two numbers have a sum of 17 and a product of 60. Form a quadratic polynomial with these numbers as zeroes and find them.
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Q124. (a) State the relationship between the zeroes and the coefficients of $ax^2 + bx + c$. (b) Find the zeroes of $4x^2 + 8x$ and verify both relations. (c) Write a quadratic polynomial whose zeroes are the squares of the zeroes found in (b).
IntermediateShow answer & explanation
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1 mark — (a) both relations. 1 mark — (b) zeroes 0 and −2. 1 mark — (b) both verifications. 2 marks — (c) new sum and product, and the polynomial.
Q125. (a) Find a quadratic polynomial whose zeroes have sum −3 and product 2, and find its zeroes. (b) Show that $2x^2 + 6x + 4$ has the same zeroes, and explain why. (c) How many quadratic polynomials have these zeroes? Justify your answer.
IntermediateShow answer & explanation
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1½ marks — (a) polynomial and zeroes. 1½ marks — (b) factorisation and reason. 2 marks — (c) infinitely many with justification.
Topper level · 45 questions
Q126. If 2 and −3 are both zeroes of $p(x) = x^2 + ax + b$, then a and b are
AdvancedShow answer & explanation
$a = 1,\ b = -6$
$p(x) = (x - 2)(x + 3) = x^2 + x - 6$, so $a = 1$ and $b = -6$.
Q127. For which value of k does $p(x) = kx^2 - 3x + k$ have 1 as a zero?
AdvancedShow answer & explanation
$\frac{3}{2}$
$k - 3 + k = 0$ gives $2k = 3$, so $k = \frac{3}{2}$.
Q128. If $p(x) = ax + b$ has zero 4 and $p(0) = -8$, then a is
AdvancedShow answer & explanation
2
$p(0) = b = -8$, and $4a - 8 = 0$ gives $a = 2$.
Q129. A polynomial p(x) satisfies $p(2) = 0$ and $p(-5) = 0$. Its lowest possible degree is
AdvancedShow answer & explanation
2
Two different zeroes need at least degree 2, and $(x-2)(x+5)$ achieves it.
Q130. If the value of $x^2 - kx + 6$ at $x = 2$ is 0, then the other zero is
AdvancedShow answer & explanation
3
$4 - 2k + 6 = 0$ gives $k = 5$, so $x^2 - 5x + 6 = (x-2)(x-3)$ and the other zero is 3.
Q131. $p(x) = x^2 + 2x - 3$. How many of the numbers −3, −1, 1 and 3 are zeroes of p(x)?
AdvancedShow answer & explanation
2
$p(-3) = 0$ and $p(1) = 0$; $p(-1) = -4$ and $p(3) = 12$.
Q132. If $p(x) = x^{2} - x$, which statement is true?
AdvancedShow answer & explanation
Both 0 and 1 are zeroes
$x^2 - x = x(x - 1)$, so both 0 and 1 give the value 0.
Q133. Assertion (A): If $p(x) = (x - 1)(x - 2)(x - 3)$, then p(x) has three zeroes. Reason (R): A cubic polynomial has at most three zeroes.
AdvancedShow answer & explanation
Both A and R are true, but R is not the correct explanation of A
Both are true: the zeroes are 1, 2 and 3. But R only sets a limit — what makes A true is the factorisation, not the limit.
Q134. The degree of the product of a quadratic and a cubic polynomial is
AdvancedShow answer & explanation
5
Degrees add when polynomials are multiplied: $2 + 3 = 5$.
Q135. If $p(x) = 2x^3 - 3x^2 + 4x - 5$, then $p(1) - p(0)$ equals
AdvancedShow answer & explanation
3
$p(1) = 2 - 3 + 4 - 5 = -2$ and $p(0) = -5$, so $p(1) - p(0) = -2 - (-5) = 3$.
Q136. The polynomial $p(x) = ax + b$ has $p(2) = 7$ and $p(-1) = -2$. Find a and b, and hence the zero of p(x).
AdvancedShow answer & explanation
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Q137. Show that $x = -\frac{b}{a}$ is the only zero of the linear polynomial $ax + b$, $a \neq 0$.
AdvancedShow answer & explanation
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Q138. (a) If 2 is a zero of $p(x) = x^2 + kx - 6$, find k. (b) Find the other zero. (c) Write a quadratic polynomial whose zeroes are the same two numbers but which is not equal to p(x).
AdvancedShow answer & explanation
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1½ marks — (a) k = 1. 1½ marks — (b) −3, with the factorisation. 2 marks — (c) a correct multiple, with a reason.
Q139. (a) Explain, with an example each, why $\frac{1}{x} + 2$ and $\sqrt{x} - 1$ are not polynomials while $\sqrt{5}x^2 - x$ is. (b) Find the degree of $(x^2 + 1)(x^3 - x)$ without multiplying it out, and give a reason. (c) Find p(0) and p(2) for $p(x) = (x^2 + 1)(x - 2)$, and name one zero of p(x).
AdvancedShow answer & explanation
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2 marks — (a) both rejections and the acceptance, with reasons. 1½ marks — (b) degree 5 with the reason. 1½ marks — (c) the two values and the zero.
Q140. The graph of a polynomial meets the x-axis at 3 points and the curve rises at both ends. The least possible degree is
AdvancedShow answer & explanation
4
Rising at both ends needs an even degree, and three zeroes need degree at least 3; the least even degree that works is 4.
Q141. A quadratic polynomial has exactly one zero. Which statement must be true?
AdvancedShow answer & explanation
Its graph touches the x-axis
One zero for a quadratic means the two zeroes are equal — a touch.
Q142. $y = p(x)$ lies entirely below the x-axis. Which is true about p(x)?
AdvancedShow answer & explanation
It has no real zero and p(0) < 0
No crossing means no real zero; the y-intercept is below the axis, so $p(0) < 0$.
Q143. A parabola cuts the x-axis at $(-2, 0)$ and $(3, 0)$ and passes through $(0, -6)$. A polynomial that fits is
AdvancedShow answer & explanation
$y = x^2 - x - 6$
$(x + 2)(x - 3) = x^2 - x - 6$, and at $x = 0$ it gives −6 ✓
Q144. Which pair of graphs has the SAME number of zeroes?
AdvancedShow answer & explanation
$y = x^3$ and $y = 2x + 1$
$y = x^3$ has one zero (0) and a line has one zero. The others pair 2 with 0, 3 with 1 and 1 with 2.
Q145. Assertion (A): A cubic polynomial always has three zeroes. Reason (R): The graph of a cubic polynomial always meets the x-axis.
AdvancedShow answer & explanation
A is false but R is true
R is true — a cubic must cross the axis somewhere. A is false: $y = x^3$ meets it only once.
Q146. A graph touches the x-axis at $x = 1$ and cuts it at $x = -2$. The least possible degree is
AdvancedShow answer & explanation
3
A touch counts as two equal zeroes, and the cut is a third: degree at least 3, for example $(x-1)^2(x+2)$.
Q147. The graph of $y = p(x)$ is a parabola with its lowest point at $(2, 0)$. Then p(x) has
AdvancedShow answer & explanation
one zero, x = 2
The lowest point sits on the axis, so the curve touches there: a repeated zero at 2.
Q148. For a quadratic whose graph opens downwards and touches the x-axis, the value of p(x) is
AdvancedShow answer & explanation
never positive
A downward parabola touching the axis has its highest point on the axis, so every value is 0 or below.
Q149. A curve meets the x-axis at 5 points. The polynomial's degree is at least
AdvancedShow answer & explanation
5
Five zeroes need degree at least 5.
Q150. Assertion (A): The graph of $y = x^2 + 1$ has no point on the x-axis. Reason (R): $x^2 + 1 \ge 1$ for every real number x.
AdvancedShow answer & explanation
Both A and R are true, and R is the correct explanation of A
The value never reaches 0, so the curve never touches the axis — R is the reason.
Q151. The lowest point of a parabola is $(3, 0)$. How many zeroes does the polynomial have, and what are they?
AdvancedShow answer & explanation
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Q152. Sketch in words the shape of $y = x^3 - 4x$ and give its zeroes.
AdvancedShow answer & explanation
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Q153. Two parabolas have the same shape, but one meets the x-axis twice and the other not at all. Give an example of each and explain the difference.
AdvancedShow answer & explanation
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Q154. For each description, state the number of zeroes and give the least possible degree, with a reason: (a) a straight line crossing the x-axis once (b) a curve touching the x-axis at one point and lying above it elsewhere (c) a curve cutting the x-axis at −1, 1 and 4 (d) a curve lying entirely below the x-axis (e) a curve touching the axis at 2 and cutting it at −3.
AdvancedShow answer & explanation
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1 mark each for (a)–(e): number of zeroes and degree with a reason.
Q155. A parabola cuts the x-axis at $(-2, 0)$ and $(3, 0)$ and passes through $(0, -6)$. (a) Write down the zeroes of the polynomial. (b) Find a quadratic polynomial with these zeroes whose graph passes through $(0, -6)$. (c) Does the parabola open upwards or downwards? Give a reason.
AdvancedShow answer & explanation
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1 mark — (a). 1 mark — (b) the factor form. 2 marks — (b) using $(0, -6)$ to fix k and writing p(x). 1 mark — (c) with the reason.
Q156. Suppose α and β are the zeroes of $x^2 - 7x + 10$. Then $(\alpha - \beta)^2$ is
AdvancedShow answer & explanation
9
$(\alpha+\beta)^2 - 4\alpha\beta = 49 - 40 = 9$. (The zeroes are 2 and 5.)
Q157. For the zeroes α and β of $x^2 + 5x + 6$, a quadratic whose zeroes are $2\alpha$ and $2\beta$ is
AdvancedShow answer & explanation
$x^2 + 10x + 24$
New sum $= 2(-5) = -10$, new product $= 4 \times 6 = 24$, giving $x^2 + 10x + 24$.
Q158. If one zero of $2x^2 - 8x + k$ is three times the other, then k is
AdvancedShow answer & explanation
6
Zeroes α and 3α: sum $4\alpha = 4$ so $\alpha = 1$; product $3\alpha^2 = \frac{k}{2}$ gives $k = 6$.
Q159. If the zeroes of $x^2 + px + q$ are equal in magnitude but opposite in sign, then
AdvancedShow answer & explanation
p = 0
Zeroes α and −α have sum 0, and the sum is $-p$, so $p = 0$.
Q160. If α and β are the zeroes of $x^2 - 4x + 3$, then $\alpha^3 + \beta^3$ is
AdvancedShow answer & explanation
28
$(\alpha+\beta)^3 - 3\alpha\beta(\alpha+\beta) = 64 - 36 = 28$. (Zeroes 1 and 3: $1 + 27 = 28$ ✓)
Q161. A quadratic polynomial whose zeroes are the reciprocals of the zeroes of $2x^2 - 5x + 3$ is
AdvancedShow answer & explanation
$3x^2 - 5x + 2$
Reversing the coefficients swaps sum and product appropriately: the zeroes of $2x^2 - 5x + 3$ are 1 and $\frac32$, whose reciprocals 1 and $\frac23$ are the zeroes of $3x^2 - 5x + 2$.
Q162. If the sum and product of the zeroes of a quadratic are both 6, the polynomial is
AdvancedShow answer & explanation
$x^2 - 6x + 6$
$x^2 - Sx + P$ with $S = P = 6$.
Q163. Assertion (A): A quadratic polynomial with zeroes $\sqrt2$ and $-\sqrt2$ is $x^2 - 2$. Reason (R): The sum of the zeroes is 0 and their product is 2.
AdvancedShow answer & explanation
A is true but R is false
The product is $-2$, which is what puts $-2$ in the polynomial. The assertion holds, the reason is false.
Q164. The zeroes of $x^2 - 6x + 8$ are α and β with $\alpha > \beta$, then $\alpha - \beta$ is
AdvancedShow answer & explanation
2
$(\alpha-\beta)^2 = 36 - 32 = 4$, so $\alpha - \beta = 2$. (Zeroes 4 and 2.)
Q165. For which value of m are the zeroes of $x^2 - mx + 9$ equal?
AdvancedShow answer & explanation
6 or −6
Equal zeroes α, α give $\alpha^2 = 9$ so $\alpha = \pm3$, and $m = 2\alpha = \pm6$.
Q166. A quadratic polynomial with zeroes $\frac{1}{2}$ and $-\frac{3}{2}$ is
AdvancedShow answer & explanation
$4x^2 + 4x - 3$
Sum $-1$ and product $-\frac34$ give $x^2 + x - \frac34$; multiplying by 4 gives $4x^2 + 4x - 3$.
Q167. If the sum of the zeroes of $kx^2 + 2x + 3k$ is equal to their product, find k.
AdvancedShow answer & explanation
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Q168. Prove that the sum of the zeroes of $ax^2 + bx + c$ is $-\frac{b}{a}$.
AdvancedShow answer & explanation
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Q169. (a) Find the zeroes of $3x^2 - x - 4$ and verify the relations between the zeroes and the coefficients. (b) If α and β are those zeroes, find $\alpha^2 + \beta^2$. (c) Write a quadratic polynomial whose zeroes are $\alpha + 1$ and $\beta + 1$.
AdvancedShow answer & explanation
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1 mark — (a) zeroes. 1 mark — (a) verification. 1½ marks — (b). 1½ marks — (c) new sum, new product and the polynomial.
Q170. A rectangular kitchen garden has a perimeter of 34 m and an area of 60 m². (a) Taking the sides as α and β, write down their sum and product. (b) Form a quadratic polynomial with α and β as zeroes, and find the sides. (c) The gardener now wants a perimeter of 34 m and an area of 80 m². Show that this is not possible.
AdvancedShow answer & explanation
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1 mark — (a) 17 and 60. 1 mark — (b) the polynomial. 1 mark — (b) sides 5 m and 12 m. 2 marks — (c) the negative value of $(\alpha-\beta)^2$ and the conclusion.
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