Thermal Physics: 15 MCQs with answers
All 15 multiple-choice questions from this kit, free and with no sign-up.
Warm-up · 5 questions
Q1. What is a black body?
BeginnerShow answer & explanation
An object that absorbs all incident radiation and emits it perfectly
A black body is an idealized object that absorbs all incident electromagnetic radiation and emits radiation perfectly at all wavelengths.
Q2. Which of the following is a real-world approximation of a black body?
BeginnerShow answer & explanation
A small hole in a cavity
A small hole in a cavity acts as a near-perfect black body because any radiation entering is absorbed after multiple reflections.
Q3. Which scientist proposed that energy is emitted or absorbed in discrete quanta to explain black body radiation?
BeginnerShow answer & explanation
Max Planck
Max Planck introduced the quantum hypothesis in 1900 to explain the black body spectrum.
Q4. A black body emits radiation only at a single wavelength.
BeginnerShow answer & explanation
False
A black body emits a continuous spectrum of radiation across all wavelengths, with a peak that depends on temperature.
Q5. The total energy radiated by a black body is proportional to the fourth power of its absolute temperature.
BeginnerShow answer & explanation
True
This is the Stefan-Boltzmann law: $E = \sigma T^4$.
Building up · 10 questions
Q6. Which law describes how the wavelength of peak emission from a black body shifts with temperature?
IntermediateShow answer & explanation
Wien's displacement law
Wien's displacement law states that the peak wavelength is inversely proportional to temperature: $\lambda_{\text{max}} T = b$.
Q7. According to the Stefan-Boltzmann law, the total power radiated per unit area of a black body is proportional to:
IntermediateShow answer & explanation
$T^4$
The Stefan-Boltzmann law states that the power radiated per unit area is $P = \sigma T^4$, where $\sigma$ is the Stefan-Boltzmann constant.
Q8. What does Planck's radiation law describe?
IntermediateShow answer & explanation
The spectral energy density of black body radiation
Planck's law gives the spectral radiance of a black body as a function of wavelength and temperature, resolving the ultraviolet catastrophe.
Q9. The ultraviolet catastrophe refers to:
IntermediateShow answer & explanation
The failure of classical physics to explain the black body spectrum at short wavelengths
Classical Rayleigh-Jeans law predicted infinite energy at short wavelengths, which was resolved by Planck's quantum hypothesis.
Q10. What is the value of Wien's displacement constant $b$ approximately?
IntermediateShow answer & explanation
$2.898 \times 10^{-3} \, \text{m·K}$
Wien's displacement constant $b$ is approximately $2.898 \times 10^{-3} \, \text{m·K}$.
Q11. If the temperature of a black body is doubled, the total radiated power per unit area increases by a factor of:
IntermediateShow answer & explanation
16
Since $P \propto T^4$, doubling $T$ gives $2^4 = 16$ times the power.
Q12. The emissive power of a black body depends on:
IntermediateShow answer & explanation
Its temperature only
For a black body, emissive power depends solely on temperature, as described by Planck's law and Stefan-Boltzmann law.
Q13. What is the shape of the black body radiation spectrum at a given temperature?
IntermediateShow answer & explanation
A curve with a single peak
The spectrum is a continuous curve that rises to a peak at a certain wavelength and then falls off, with the peak shifting with temperature.
Q14. Which law states that the ratio of emissive power to absorptive power is constant for all bodies at the same temperature?
IntermediateShow answer & explanation
Kirchhoff's law
Kirchhoff's law of thermal radiation states that good absorbers are good emitters, and the ratio is the same for all bodies at a given temperature.
Q15. The Sun's spectrum approximates that of a black body at about 5800 K. What is the peak wavelength of its radiation?
IntermediateShow answer & explanation
500 nm
Using Wien's law: $\lambda_{\text{max}} = b/T = (2.898 \times 10^{-3})/5800 \approx 5 \times 10^{-7} \, \text{m} = 500 \, \text{nm}$.
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