Coordinate Geometry · Class 10 Mathematics: 171 MCQs with answers
All 171 multiple-choice questions from this kit, free and with no sign-up.
Warm-up · 47 questions
Q1. The distance between $(x_1, y_1)$ and $(x_2, y_2)$ is
BeginnerShow answer & explanation
$\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$
The differences are squared, added, then rooted.
Q2. The distance formula comes from
BeginnerShow answer & explanation
Pythagoras' theorem
The two coordinate gaps are the legs of a right triangle.
Q3. The distance of $P(x, y)$ from the origin is
BeginnerShow answer & explanation
$\sqrt{x^2 + y^2}$
The origin is $(0, 0)$, so the differences are just x and y.
Q4. The distance between $(0, 0)$ and $(3, 4)$ is
BeginnerShow answer & explanation
5
$\sqrt{9 + 16} = 5$.
Q5. The distance between $(0, 0)$ and $(8, 15)$ is
BeginnerShow answer & explanation
17
$\sqrt{64 + 225} = \sqrt{289} = 17$.
Q6. The distance between $(2, 3)$ and $(2, 11)$ is
BeginnerShow answer & explanation
8
The x-coordinates match, so the distance is just the vertical gap.
Q7. The distance between $(1, 4)$ and $(7, 4)$ is
BeginnerShow answer & explanation
6
The y-coordinates match, so the distance is the horizontal gap.
Q8. Does the order of the two points change the distance?
BeginnerShow answer & explanation
no, because the differences are squared
$(a - b)^2 = (b - a)^2$.
Q9. A distance can never be
BeginnerShow answer & explanation
negative
It is a length, so the positive root is always taken.
Q10. Simplified, $\sqrt{50}$ equals
BeginnerShow answer & explanation
$5\sqrt2$
$\sqrt{25 \times 2}$.
Q11. The distance between $(1, 1)$ and $(9, 7)$ is
BeginnerShow answer & explanation
10
$\sqrt{64 + 36} = \sqrt{100} = 10$.
Q12. Assertion (A): The distance between $(2, 5)$ and $(5, 9)$ is 5. Reason (R): The horizontal gap is 4 and the vertical gap is 3, and $\sqrt{4^2 + 3^2} = 7$.
BeginnerShow answer & explanation
A is true but R is false
The gaps are 3 and 4 and the root is 5, not 7. The assertion is correct, the reason is not.
Q13. The squared distance between $(2, 1)$ and $(5, 5)$ is
BeginnerShow answer & explanation
25
$3^2 + 4^2 = 25$; the distance itself is 5.
Q14. Before squaring, the two differences between $(4, 9)$ and $(1, 5)$ are
BeginnerShow answer & explanation
−3 and −4
Taking the second point from the first: $1 - 4 = -3$ and $5 - 9 = -4$.
Q15. Two points have the same x-coordinate. The distance between them equals
BeginnerShow answer & explanation
the difference of their y-coordinates
The horizontal gap is zero, so only the vertical gap remains.
Q16. Find the distance between the points $(3, 1)$ and $(7, 4)$.
BeginnerShow answer & explanation
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Q17. Find the distance of the point $(-6, 8)$ from the origin.
BeginnerShow answer & explanation
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Q18. The section formula for the ratio $m : n$ from A to B gives the x-coordinate as
BeginnerShow answer & explanation
$\frac{mx_2 + nx_1}{m+n}$
The weights cross: m goes with the second point.
Q19. The midpoint of $(x_1, y_1)$ and $(x_2, y_2)$ is
BeginnerShow answer & explanation
$\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$
The average of each coordinate.
Q20. The midpoint formula is the section formula with
BeginnerShow answer & explanation
$m = n = 1$
Equal weights give an ordinary mean.
Q21. The midpoint of $(2, 4)$ and $(6, 8)$ is
BeginnerShow answer & explanation
$(4, 6)$
$\left(\frac{2+6}{2}, \frac{4+8}{2}\right)$.
Q22. The midpoint of $(-3, 5)$ and $(7, -1)$ is
BeginnerShow answer & explanation
$(2, 2)$
$\left(\frac{-3+7}{2}, \frac{5-1}{2}\right)$.
Q23. In the section formula, what must you divide by?
BeginnerShow answer & explanation
$m + n$
The total number of parts in the ratio.
Q24. The two points of trisection divide a segment in the ratios
BeginnerShow answer & explanation
$1 : 2$ and $2 : 1$
Three equal parts means the first point is one part out of three.
Q25. A point on the x-axis has
BeginnerShow answer & explanation
$y = 0$
Height zero, so the y-coordinate vanishes.
Q26. To find where a segment meets the y-axis you set which expression to zero?
BeginnerShow answer & explanation
the x-coordinate
Every point on the y-axis has x-coordinate zero.
Q27. An unknown ratio is best written as
BeginnerShow answer & explanation
$k : 1$
It reduces two unknowns to one.
Q28. Is $3 : 2$ from A the same point as $2 : 3$ from A?
BeginnerShow answer & explanation
no — they are different points
The first is nearer B and the second nearer A.
Q29. Assertion (A): The midpoint formula does not need to be memorised separately. Reason (R): It is the section formula with the ratio $1 : 1$.
BeginnerShow answer & explanation
Both A and R are true, and R is the correct explanation of A
Setting both weights to 1 turns the section formula into the average, exactly as R says.
Q30. The midpoint of $(0, 0)$ and $(10, 6)$ is
BeginnerShow answer & explanation
$(5, 3)$
Average each coordinate.
Q31. In the ratio $m : n$ from A to B, the part nearer B is
BeginnerShow answer & explanation
$n$
m measures the piece from A to the point, so n is the remaining piece to B.
Q32. Assertion (A): The midpoint of a segment is equidistant from its two endpoints. Reason (R): The midpoint divides the segment in the ratio $1 : 1$.
BeginnerShow answer & explanation
Both A and R are true, and R is the correct explanation of A
Equal parts either side is exactly what a $1 : 1$ division means.
Q33. Find the midpoint of the line segment joining $(4, -3)$ and $(-2, 7)$.
BeginnerShow answer & explanation
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Q34. Three points are collinear when
BeginnerShow answer & explanation
the two shorter distances add to the longest
Equality leaves no room for a bend in the path.
Q35. To classify a quadrilateral from its vertices you compute
BeginnerShow answer & explanation
four sides and two diagonals
The sides and the diagonals each decide part of the answer.
Q36. In a quadrilateral PQRS taken in order, the diagonals are
BeginnerShow answer & explanation
PR and QS
Diagonals join opposite vertices — 1st to 3rd and 2nd to 4th.
Q37. A quadrilateral with all four sides equal and both diagonals equal is a
BeginnerShow answer & explanation
square
Equal sides give a rhombus; equal diagonals upgrade it to a square.
Q38. A quadrilateral with all four sides equal but unequal diagonals is a
BeginnerShow answer & explanation
rhombus
A squashed square keeps its side lengths.
Q39. A quadrilateral with opposite sides equal and equal diagonals is a
BeginnerShow answer & explanation
rectangle
Equal diagonals mean right angles at the corners.
Q40. Unequal diagonals distinguish a rectangle from a
BeginnerShow answer & explanation
parallelogram
Both have opposite sides equal; only the rectangle has equal diagonals.
Q41. Which single check rules out the whole parallelogram family at once?
BeginnerShow answer & explanation
the diagonals not sharing a midpoint
Bisecting diagonals are necessary for every parallelogram, rectangle, rhombus and square.
Q42. A point known to lie on the x-axis should be written as
BeginnerShow answer & explanation
$(x, 0)$
Writing it this way removes one unknown immediately.
Q43. For a question about a perimeter, the right tool is
BeginnerShow answer & explanation
the distance formula
A perimeter is a sum of lengths.
Q44. For a question about trisection, the right tool is
BeginnerShow answer & explanation
the section formula
Trisection is a division in a ratio.
Q45. Assertion (A): Every square is also a rectangle. Reason (R): A rectangle requires opposite sides equal and equal diagonals, both of which a square satisfies.
BeginnerShow answer & explanation
Both A and R are true, and R is the correct explanation of A
A square meets the rectangle's conditions and more, so the name still applies.
Q46. Which shape has four equal sides AND four right angles?
BeginnerShow answer & explanation
a square
It satisfies both the rhombus and the rectangle conditions at once.
Q47. Assertion (A): To find a missing vertex of a parallelogram you equate two midpoints. Reason (R): The diagonals of a parallelogram bisect each other, so they share a midpoint.
BeginnerShow answer & explanation
Both A and R are true, and R is the correct explanation of A
The shared midpoint is exactly what makes the two expressions equal.
Building up · 67 questions
Q48. The distance between $(-5, 7)$ and $(-1, 3)$ is
IntermediateShow answer & explanation
$4\sqrt2$
The gaps are 4 and $-4$, so $\sqrt{32} = 4\sqrt2$.
Q49. The distance between $(2, 3)$ and $(4, 1)$ is
IntermediateShow answer & explanation
$2\sqrt2$
$\sqrt{4 + 4} = \sqrt8 = 2\sqrt2$.
Q50. How far is the point $(-3, -4)$ from the origin?
IntermediateShow answer & explanation
5
$\sqrt{9 + 16} = 5$; the signs vanish on squaring.
Q51. Comparing $AB^2$ and $AC^2$ instead of $AB$ and $AC$ is valid because
IntermediateShow answer & explanation
distances are positive, so equal squares mean equal lengths
For non-negative numbers, $p^2 = q^2$ forces $p = q$.
Q52. To show three points form an isosceles triangle, you show that
IntermediateShow answer & explanation
two of the squared distances are equal
Two equal sides is the definition.
Q53. Which comparison proves a right angle without any square root?
IntermediateShow answer & explanation
the largest squared distance equals the sum of the other two
That is the converse of Pythagoras, applied to squares.
Q54. For $A(1, 7)$, $B(4, 2)$ and $C(-1, -1)$, the value of $AB^2$ is
IntermediateShow answer & explanation
34
$3^2 + (-5)^2 = 9 + 25 = 34$.
Q55. The triangle with vertices $A(1, 7)$, $B(4, 2)$ and $C(-1, -1)$ is
IntermediateShow answer & explanation
isosceles and right-angled
$AB^2 = BC^2 = 34$ and $34 + 34 = 68 = CA^2$.
Q56. If the distance between $P(x, 2)$ and $Q(3, 6)$ is 5, then x is
IntermediateShow answer & explanation
0 or 6
$(3-x)^2 = 9$ gives $3 - x = \pm3$.
Q57. A general point on the x-axis is written as
IntermediateShow answer & explanation
$(x, 0)$
Every point on the x-axis has zero height.
Q58. Which coordinate is zero for every point on the y-axis?
IntermediateShow answer & explanation
the x-coordinate
Points on the y-axis sit directly above or below the origin.
Q59. Assertion (A): The distance between $(4, 0)$ and $(0, 3)$ is 5. Reason (R): Both points lie on the axes, so the distance is the sum $4 + 3$.
IntermediateShow answer & explanation
A is true but R is false
A is true — $\sqrt{16 + 9} = 5$ — but R is false, because the distance is the hypotenuse, not the sum of the legs.
Q60. Assertion (A): Two points with the same y-coordinate are separated by the difference of their x-coordinates. Reason (R): The vertical gap is then zero, so the formula reduces to $\sqrt{(x_2-x_1)^2} = |x_2 - x_1|$.
IntermediateShow answer & explanation
Both A and R are true, and R is the correct explanation of A
With one gap zero the formula collapses to the other gap, exactly as R shows.
Q61. The squared distance between $(0, 5)$ and $(12, 0)$ is
IntermediateShow answer & explanation
169
$144 + 25 = 169$.
Q62. For $A(0, 0)$, $B(4, 0)$ and $C(0, 3)$, the longest side is
IntermediateShow answer & explanation
BC
$BC^2 = 25$, while $AB^2 = 16$ and $CA^2 = 9$.
Q63. If $PQ^2 = 45$, then PQ in simplest surd form is
IntermediateShow answer & explanation
$3\sqrt5$
$\sqrt{45} = \sqrt{9 \times 5} = 3\sqrt5$.
Q64. Find the distance between $(-4, 6)$ and $(2, -2)$.
IntermediateShow answer & explanation
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Q65. Find the distance between $(5, 2)$ and $(3, 4)$, leaving your answer as a surd.
IntermediateShow answer & explanation
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Q66. Show that the points $A(1, 7)$, $B(4, 2)$ and $C(-1, -1)$ are the vertices of an isosceles triangle.
IntermediateShow answer & explanation
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Q67. Find the value of x if the distance between $P(x, 2)$ and $Q(3, 6)$ is 5.
IntermediateShow answer & explanation
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Q68. Explain why comparing squared distances is usually better than comparing the distances themselves.
IntermediateShow answer & explanation
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Q69. Find the perimeter of the triangle with vertices $(0, 0)$, $(4, 0)$ and $(0, 3)$.
IntermediateShow answer & explanation
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Q70. (a) Derive the distance formula from Pythagoras' theorem, explaining each step. (b) Use it to find the distance between $(-3, 5)$ and $(2, -7)$. (c) State two properties of the formula that follow from the differences being squared.
IntermediateShow answer & explanation
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2 marks — (a) the construction, the right angle and Pythagoras applied. 1½ marks — (b) both gaps and d = 13. 1½ marks — (c) both properties.
Q71. The point dividing $(-1, 7)$ and $(4, -3)$ in the ratio $2 : 3$ is
IntermediateShow answer & explanation
$(1, 3)$
$x = \frac{8-3}{5} = 1$ and $y = \frac{-6+21}{5} = 3$.
Q72. The point dividing $(1, 2)$ and $(7, 8)$ in the ratio $1 : 2$ is
IntermediateShow answer & explanation
$(3, 4)$
$x = \frac{7 + 2}{3} = 3$ and $y = \frac{8 + 4}{3} = 4$.
Q73. The first point of trisection of $(4, -1)$ and $(-2, -3)$ is
IntermediateShow answer & explanation
$\left(2, -\frac53\right)$
Ratio $1 : 2$ gives $x = \frac{-2 + 8}{3} = 2$ and $y = \frac{-3 - 2}{3} = -\frac53$.
Q74. The second point of trisection of $(4, -1)$ and $(-2, -3)$ is
IntermediateShow answer & explanation
$\left(0, -\frac73\right)$
Ratio $2 : 1$ gives $x = \frac{-4 + 4}{3} = 0$ and $y = \frac{-6 - 1}{3} = -\frac73$.
Q75. If $P$ divides $A(2, 1)$ and $B(8, 7)$ in the ratio $1 : 2$, then P is
IntermediateShow answer & explanation
$(4, 3)$
$x = \frac{8 + 4}{3} = 4$ and $y = \frac{7 + 2}{3} = 3$.
Q76. Setting the y-coordinate of the section formula to zero finds where a segment
IntermediateShow answer & explanation
crosses the x-axis
On the x-axis every point has $y = 0$.
Q77. The x-axis divides the join of $(1, -5)$ and $(-4, 5)$ in the ratio
IntermediateShow answer & explanation
$1 : 1$
$\frac{5k - 5}{k+1} = 0$ gives $k = 1$.
Q78. The point where the x-axis cuts the join of $(1, -5)$ and $(-4, 5)$ is
IntermediateShow answer & explanation
$\left(-\frac32, 0\right)$
The ratio is $1 : 1$, so it is the midpoint $\left(\frac{1-4}{2}, 0\right)$.
Q79. If the midpoint of $(a, 4)$ and $(6, b)$ is $(5, 7)$, then a and b are
IntermediateShow answer & explanation
$a = 4$, $b = 10$
$\frac{a+6}{2} = 5$ gives $a = 4$, and $\frac{4+b}{2} = 7$ gives $b = 10$.
Q80. Why is an unknown ratio written as $k : 1$?
IntermediateShow answer & explanation
it reduces two unknowns to one
Any ratio $m : n$ equals $\frac mn : 1$.
Q81. After finding a ratio from the x-coordinates, you should
IntermediateShow answer & explanation
verify it using the y-coordinates
The check costs one line and catches nearly every slip.
Q82. Assertion (A): The points of trisection divide a segment in the ratios $1 : 3$ and $3 : 1$. Reason (R): Trisection cuts a segment into three equal parts.
IntermediateShow answer & explanation
A is false but R is true
R is true, but the ratios are $1 : 2$ and $2 : 1$ — one part against the remaining two — so A is false.
Q83. Assertion (A): To find where a segment meets the y-axis, set the section formula's y-coordinate to zero. Reason (R): Every point on the y-axis has x-coordinate zero.
IntermediateShow answer & explanation
A is false but R is true
It is the x-coordinate that vanishes on the y-axis, so the assertion is false. The reason states the property correctly.
Q84. The point dividing $(1, 1)$ and $(5, 9)$ in the ratio $3 : 1$ is
IntermediateShow answer & explanation
$(4, 7)$
$x = \frac{15 + 1}{4} = 4$ and $y = \frac{27 + 1}{4} = 7$.
Q85. A point that is one-quarter of the way from A to B divides AB in the ratio
IntermediateShow answer & explanation
$1 : 3$
One part travelled and three remaining.
Q86. If the midpoint of $(2, p)$ and $(q, 8)$ is $(5, 6)$, then p and q are
IntermediateShow answer & explanation
$p = 4$, $q = 8$
$\frac{p+8}{2} = 6$ gives $p = 4$, and $\frac{2+q}{2} = 5$ gives $q = 8$.
Q87. Locate the point that splits the segment from $(-1, 7)$ to $(4, -3)$ in the ratio $2 : 3$, and give its coordinates.
IntermediateShow answer & explanation
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Q88. Explain why the section formula has the weights crossed over.
IntermediateShow answer & explanation
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Q89. If the midpoint of the segment joining $(a, 4)$ and $(6, b)$ is $(5, 7)$, find a and b.
IntermediateShow answer & explanation
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Q90. Find the point which divides the join of $(1, 2)$ and $(7, 10)$ in the ratio $3 : 1$.
IntermediateShow answer & explanation
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Q91. Why is it wrong to use the ratio $1 : 3$ for a point of trisection?
IntermediateShow answer & explanation
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Q92. (a) State the section formula and explain what each letter means. (b) Derive the midpoint formula from it. (c) Find the midpoint and the two trisection points of the segment joining $A(2, 1)$ and $B(8, 7)$.
IntermediateShow answer & explanation
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1½ marks — (a) the formula with every letter explained. 1 mark — (b) the substitution $m = n = 1$. 2½ marks — (c) the midpoint and both trisection points.
Q93. For collinear points with $AB^2 = 10$, $BC^2 = 40$ and $AC^2 = 90$, the sum $10 + 40$ is
IntermediateShow answer & explanation
not equal to 90, which is why squares must not be used
Squaring does not respect addition, so collinearity needs the distances themselves.
Q94. The points $(-2, 3)$, $(1, 2)$ and $(7, 0)$ are
IntermediateShow answer & explanation
collinear
$\sqrt{10} + 2\sqrt{10} = 3\sqrt{10}$.
Q95. The quadrilateral with vertices $(1,1)$, $(5,1)$, $(5,5)$, $(1,5)$ is a
IntermediateShow answer & explanation
square
All four sides are 16 and both diagonals are 32.
Q96. The quadrilateral with vertices $(0,0)$, $(4,3)$, $(0,6)$, $(-4,3)$ is a
IntermediateShow answer & explanation
rhombus
Sides all 25, diagonals 36 and 64 — equal sides but unequal diagonals.
Q97. The quadrilateral with vertices $(0,0)$, $(6,0)$, $(6,3)$, $(0,3)$ is a
IntermediateShow answer & explanation
rectangle
Opposite sides equal (36 and 9) and both diagonals 45.
Q98. Three vertices of a parallelogram in order are $(1,2)$, $(4,3)$ and $(6,6)$. The fourth is
IntermediateShow answer & explanation
$(3, 5)$
Equating the midpoints of AC and BD gives $4 + x = 7$ and $3 + y = 8$.
Q99. Why must the vertices be taken in order?
IntermediateShow answer & explanation
otherwise the 'diagonals' would actually be sides
The order is what identifies which vertices are opposite.
Q100. If a shape satisfies the conditions for both a rectangle and a rhombus, it is a
IntermediateShow answer & explanation
square
Equal sides and equal diagonals together define a square.
Q101. To find a point equidistant from two given points, you
IntermediateShow answer & explanation
set the two squared distances equal
The $x^2$ terms then cancel and a linear equation remains.
Q102. A question asks what kind of triangle three points form. The right tool is
IntermediateShow answer & explanation
the distance formula
Classifying a triangle compares side lengths.
Q103. A question asks for the fourth vertex of a parallelogram. The right tool is
IntermediateShow answer & explanation
the section formula, via equal midpoints
The diagonals bisect each other.
Q104. Assertion (A): Four equal sides prove a quadrilateral is a square. Reason (R): A rhombus also has four equal sides.
IntermediateShow answer & explanation
A is false but R is true
R is true and is exactly the counterexample that makes A false — the diagonals must be checked too.
Q105. Assertion (A): Collinearity can be tested using squared distances. Reason (R): Comparing squared distances is valid whenever lengths are being compared for equality.
IntermediateShow answer & explanation
A is false but R is true
R is true for EQUALITY, but collinearity needs a SUM, and squaring does not respect addition — so A is false.
Q106. The quadrilateral $(4,0)$, $(8,0)$, $(8,4)$, $(4,4)$ is a
IntermediateShow answer & explanation
square
All four squared sides are 16 and both squared diagonals are 32.
Q107. Three collinear points enclose a region of area
IntermediateShow answer & explanation
zero
Points on a single line cannot enclose anything.
Q108. If $AB = 3\sqrt2$, $BC = 2\sqrt2$ and $AC = 5\sqrt2$, the points are
IntermediateShow answer & explanation
collinear, with B between A and C
$3\sqrt2 + 2\sqrt2 = 5\sqrt2$, so the two shorter lengths add to the longest.
Q109. Writing each distance as a multiple of the same surd helps because
IntermediateShow answer & explanation
the addition becomes obvious and stays exact
Comparing $\sqrt{10} + 2\sqrt{10}$ with $3\sqrt{10}$ needs no approximation at all.
Q110. Show that the points $A(-2, 3)$, $B(1, 2)$ and $C(7, 0)$ are collinear.
IntermediateShow answer & explanation
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Q111. Show that $(1,1)$, $(5,1)$, $(5,5)$ and $(1,5)$ are the vertices of a square.
IntermediateShow answer & explanation
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Q112. Explain why four equal sides do not prove that a quadrilateral is a square.
IntermediateShow answer & explanation
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Q113. State which formula you would use for each: (i) the perimeter of a triangle, (ii) the midpoint of a segment, (iii) whether three points are collinear.
IntermediateShow answer & explanation
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Q114. Why does a question say 'taken in order' when listing the vertices of a quadrilateral?
IntermediateShow answer & explanation
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Topper level · 57 questions
Q115. The point on the x-axis equidistant from $(2, -5)$ and $(-2, 9)$ is
AdvancedShow answer & explanation
$(-7, 0)$
Setting $PA^2 = PB^2$ with $P(x, 0)$ gives $29 - 4x = 85 + 4x$, so $x = -7$.
Q116. Why does setting two squared distances equal give a LINEAR equation?
AdvancedShow answer & explanation
the $x^2$ terms on both sides cancel
Expanding both sides produces the same $x^2$, which subtracts out.
Q117. The points $(1, 5)$, $(2, 3)$ and $(-2, -11)$ are
AdvancedShow answer & explanation
not collinear
$AB = \sqrt5$ and $BC = \sqrt{212}$, while $AC = \sqrt{265}$; since $\sqrt5 + \sqrt{212} \ne \sqrt{265}$, they are not collinear.
Q118. If $(a, 0)$ is equidistant from $(3, 4)$ and $(-1, 2)$, then a is
AdvancedShow answer & explanation
2.5
$(3-a)^2 + 16 = (-1-a)^2 + 4$ gives $25 - 6a = 5 + 2a$, so $8a = 20$.
Q119. A point equidistant from all three vertices of a triangle is
AdvancedShow answer & explanation
the circumcentre
Equal distances to all three vertices is the defining property of the circumcentre.
Q120. The triangle with vertices $(0, 0)$, $(4, 0)$ and $(0, 3)$ has perimeter
AdvancedShow answer & explanation
12
The sides are 4, 3 and $\sqrt{16+9} = 5$, so $4 + 3 + 5 = 12$.
Q121. If the distance between $(2, -3)$ and $(10, y)$ is 10, then y is
AdvancedShow answer & explanation
3 or −9
$64 + (y+3)^2 = 100$ gives $(y+3)^2 = 36$, so $y + 3 = \pm6$.
Q122. The points $(3, 0)$, $(6, 4)$ and $(-1, 3)$ form
AdvancedShow answer & explanation
an isosceles right triangle
The squared sides are 25, 50 and 25, and $25 + 25 = 50$.
Q123. Assertion (A): Three points can be tested for a right angle without finding any square root. Reason (R): The converse of Pythagoras can be applied to the squared distances directly.
AdvancedShow answer & explanation
Both A and R are true, and R is the correct explanation of A
Comparing squares is exactly the test, and it never needs a root.
Q124. Any point at distance 13 from the origin satisfies
AdvancedShow answer & explanation
$x^2 + y^2 = 169$
Squaring $\sqrt{x^2+y^2} = 13$ gives the equation of that circle.
Q125. Assertion (A): The distance between $(a, b)$ and $(b, a)$ is zero when $a = b$. Reason (R): The distance between two points is zero exactly when the points coincide.
AdvancedShow answer & explanation
Both A and R are true, and R is the correct explanation of A
If $a = b$ the two points are the same, and R states the general rule behind that.
Q126. Show that the triangle in the previous question is also right-angled, and name the right angle.
AdvancedShow answer & explanation
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Q127. Which point of the x-axis stands the same distance from $(2, -5)$ as it does from $(-2, 9)$?
AdvancedShow answer & explanation
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Q128. Find the values of y for which the distance between $(2, -3)$ and $(10, y)$ is 10.
AdvancedShow answer & explanation
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Q129. The points $A(3, 0)$, $B(6, 4)$ and $C(-1, 3)$ are plotted. (a) Find $AB^2$, $BC^2$ and $CA^2$. (b) Determine what kind of triangle ABC is, justifying every claim. (c) Find the perimeter of the triangle, leaving surds in exact form.
AdvancedShow answer & explanation
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1½ marks — (a) all three squared distances. 2 marks — (b) isosceles and right-angled, each justified, with the right angle located. 1½ marks — (c) the exact perimeter.
Q130. (a) Find the point on the y-axis which is equidistant from $A(6, 5)$ and $B(-4, 3)$. (b) Explain why setting the two squared distances equal leaves a linear equation. (c) Verify your answer by computing both distances.
AdvancedShow answer & explanation
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2 marks — (a) the setup and y = 9. 1½ marks — (b) the cancellation explained. 1½ marks — (c) both squared distances computed and shown equal.
Q131. A surveyor plots three markers on a field at $P(0, 0)$, $Q(8, 0)$ and $R(0, 6)$, with all coordinates in metres. (a) Find the distances PQ, PR and QR. (b) Show that the markers form a right-angled triangle and state where the right angle is. (c) A fourth marker S is to be placed so that PQSR is a rectangle. Give its coordinates, and find the distance from P to S.
AdvancedShow answer & explanation
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1½ marks — (a) all three distances. 1½ marks — (b) the Pythagoras check and the location of the right angle. 2 marks — (c) S = (8, 6) and PS = 10 with the diagonal comment.
Q132. The point $(-1, 6)$ divides the join of $(-3, 10)$ and $(6, -8)$ in the ratio
AdvancedShow answer & explanation
$2 : 7$
With ratio $k : 1$: $\frac{6k - 3}{k + 1} = -1$ gives $7k = 2$.
Q133. Taking $(1, 2)$, $(4, y)$, $(x, 6)$ and $(3, 5)$ as the corners of a parallelogram, named in order, x and y come to
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$x = 6$, $y = 3$
The diagonals of a parallelogram bisect each other, so the midpoints of the two diagonals coincide.
Q134. The diagonals of a parallelogram
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bisect each other
That is what makes the midpoint method work for parallelogram problems.
Q135. If $A(1, 2)$ and $B(7, 10)$, the point three-quarters of the way from A to B divides AB in the ratio
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$3 : 1$
Three parts travelled and one remaining gives $3 : 1$.
Q136. The point three-quarters of the way from $A(1, 2)$ to $B(7, 10)$ is
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$\left(\frac{11}{2}, 8\right)$
Ratio $3 : 1$ gives $x = \frac{21 + 1}{4} = \frac{11}{2}$ and $y = \frac{30 + 2}{4} = 8$.
Q137. A negative value of k when solving for a ratio means
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the point lies outside the segment
It indicates external division, on the extension of the line.
Q138. The y-axis divides the join of $(-4, -6)$ and $(2, 3)$ in the ratio
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$2 : 1$
$\frac{2k - 4}{k+1} = 0$ gives $2k = 4$, so $k = 2$.
Q139. If the midpoint of the join of $(2a, 4)$ and $(-2, 3b)$ is $(1, 5)$, then a and b are
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$a = 2$, $b = 2$
$\frac{2a - 2}{2} = 1$ gives $a = 2$, and $\frac{4 + 3b}{2} = 5$ gives $b = 2$.
Q140. Assertion (A): Finding a ratio needs only one of the two coordinate equations. Reason (R): The other coordinate provides an independent check on the answer.
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Both A and R are true, but R is not the correct explanation of A
Both statements are true — one equation does determine k — but R describes a check rather than explaining why one equation suffices.
Q141. The centroid of a triangle divides each median in the ratio
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$2 : 1$ from the vertex
It sits two-thirds of the way along each median from the vertex.
Q142. The section formula gives a point BETWEEN A and B when
AdvancedShow answer & explanation
both m and n are positive
Internal division needs both parts of the ratio positive.
Q143. Split the segment from $(4, -1)$ to $(-2, -3)$ into three equal parts, and name the two points where the cuts fall.
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Q144. In what ratio does the point $(-1, 6)$ divide the join of $(-3, 10)$ and $(6, -8)$?
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Q145. In what ratio does the x-axis divide the line segment joining $A(1, -5)$ and $B(-4, 5)$? Find the point of division.
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Q146. The points $(1, 2)$, $(4, y)$, $(x, 6)$ and $(3, 5)$ are the corners of a parallelogram, named in order. Work out x and y.
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Q147. In what ratio does the y-axis divide the join of $(-4, -6)$ and $(2, 3)$?
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Q148. (a) Explain the advantage of writing an unknown ratio as $k : 1$. (b) Find the ratio in which $P(-1, 6)$ divides the join of $A(-3, 10)$ and $B(6, -8)$. (c) Verify your answer using the other coordinate.
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1½ marks — (a) the reason one unknown suffices. 2 marks — (b) the equation and $k = \frac27$. 1½ marks — (c) the verification.
Q149. (a) Explain how to find the ratio in which the x-axis divides a segment. (b) Find the ratio in which the x-axis divides the join of $A(1, -5)$ and $B(-4, 5)$, and the point of division. (c) Find the ratio in which the y-axis divides the join of $C(-4, -6)$ and $D(2, 3)$.
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1½ marks — (a) the method with the y = 0 reason. 2 marks — (b) the ratio and the point. 1½ marks — (c) the ratio for the y-axis.
Q150. During Sports Day on a rectangular ground, flower pots are placed 1 m apart along one edge. Niharika posts a green flag at $(2, 25)$ and Preet posts a red flag at $(8, 20)$, distances in metres. (a) Find the distance between the two flags. (b) Rashmi must post a blue flag exactly halfway between them. Where should she post it? (c) A fourth flag is to go one-third of the way from the green flag to the red flag. Find its position.
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1½ marks — (a) the distance in surd form. 1½ marks — (b) the midpoint. 2 marks — (c) recognising the ratio 1 : 2 and both coordinates.
Q151. The points $(0, 1)$, $(2, 4)$ and $(5, 7)$ are
AdvancedShow answer & explanation
not collinear
$AB = \sqrt{13}$ and $BC = \sqrt{18}$, but $AC = \sqrt{61}$, and $\sqrt{13} + \sqrt{18} e \sqrt{61}$.
Q152. The quadrilateral $(0,0)$, $(5,0)$, $(7,3)$, $(2,3)$ is a
AdvancedShow answer & explanation
parallelogram
Opposite sides are equal (25 and 13) but the diagonals are 58 and 18 — unequal.
Q153. Three vertices of a rectangle in order are $(0,0)$, $(8,0)$ and $(8,6)$. The fourth is
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$(0, 6)$
Equating the midpoints of the diagonals gives $(0, 6)$.
Q154. A point on the y-axis equidistant from $(6, 5)$ and $(-4, 3)$ is
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$(0, 9)$
$36 + (5-y)^2 = 16 + (3-y)^2$ gives $61 - 10y = 25 - 6y$, so $y = 9$.
Q155. For the quadrilateral $(1,1),(5,1),(5,5),(1,5)$, the squared diagonals are
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both 32
$(1,1)$ to $(5,5)$ gives $16 + 16 = 32$, and $(5,1)$ to $(1,5)$ gives the same.
Q156. If three points are collinear, the triangle they 'form' has
AdvancedShow answer & explanation
zero area, so it is not a triangle
Collinear points cannot enclose a region.
Q157. Which pair of checks distinguishes a rectangle from a general parallelogram?
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the two diagonals
Both have opposite sides equal; only a rectangle has equal diagonals.
Q158. The fourth vertex D of a parallelogram ABCD with $A(-2,1)$, $B(1,0)$ and $C(4,3)$ is
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$(1, 4)$
Midpoint of AC is $(1, 2)$; setting the midpoint of BD equal gives $1 + x = 2$ and $0 + y = 4$.
Q159. Assertion (A): A classification answer should give the most specific shape name. Reason (R): A square also satisfies the definitions of a rectangle, a rhombus and a parallelogram.
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Both A and R are true, and R is the correct explanation of A
Because looser names are also true, only the most specific one distinguishes the shape.
Q160. A quadrilateral whose diagonals do NOT have the same midpoint is
AdvancedShow answer & explanation
not a parallelogram at all
Bisecting diagonals are necessary for a parallelogram, so the test fails at the first step.
Q161. The point on the x-axis equidistant from $(7, 6)$ and $(-3, 4)$ is
AdvancedShow answer & explanation
$(3, 0)$
$85 - 14x = 25 + 6x$ gives $20x = 60$.
Q162. Explain why collinearity must not be tested using squared distances.
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Q163. Do $(1, 5)$, $(2, 3)$ and $(-2, -11)$ all lie along one straight line? Justify your answer.
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Q164. Show that $(0,0)$, $(4,3)$, $(0,6)$ and $(-4,3)$ form a rhombus but not a square.
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Q165. Three vertices of a parallelogram taken in order are $(1, 2)$, $(4, 3)$ and $(6, 6)$. Find the fourth vertex.
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Q166. Find the point on the y-axis which is equidistant from $(6, 5)$ and $(-4, 3)$.
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Q167. Classify the quadrilateral with vertices $(0,0)$, $(5,0)$, $(7,3)$ and $(2,3)$, justifying your answer.
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Q168. (a) State the test for three points to be collinear, and explain why squared distances must not be used. (b) Determine whether $A(3, 1)$, $B(6, 4)$ and $C(8, 6)$ are collinear. (c) Determine whether $P(1, 5)$, $Q(2, 3)$ and $R(-2, -11)$ are collinear.
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1½ marks — (a) the test and the reason squares fail. 2 marks — (b) all three distances and the conclusion. 1½ marks — (c) the distances and the conclusion.
Q169. (a) List the four classifications of a quadrilateral in terms of its sides and diagonals. (b) Classify $(1,1)$, $(5,1)$, $(5,5)$, $(1,5)$, showing all six squared lengths. (c) Classify $(0,0)$, $(4,3)$, $(0,6)$, $(-4,3)$, and explain what distinguishes it from your answer to (b).
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1½ marks — (a) all four classifications. 2 marks — (b) six lengths and the name. 1½ marks — (c) the name and the distinguishing comparison.
Q170. (a) State the property of a parallelogram used to find a missing vertex. (b) Three vertices of parallelogram ABCD taken in order are $A(-2, 1)$, $B(1, 0)$ and $C(4, 3)$. Find D. (c) Verify your answer by checking that the opposite sides are equal.
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1 mark — (a) the bisecting-diagonals property. 2 marks — (b) both midpoints equated and D found. 2 marks — (c) both pairs of opposite sides checked.
Q171. A town planner marks four corners of a proposed park at $P(0, 0)$, $Q(6, 0)$, $R(6, 3)$ and $S(0, 3)$, in metres, taken in order. (a) Find the four squared side lengths and the two squared diagonals. (b) Classify the park, justifying your answer fully. (c) Find the point where the two diagonals cross, and explain how you know they cross there.
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1½ marks — (a) all six squared lengths. 2 marks — (b) the classification with both comparisons stated. 1½ marks — (c) the crossing point and the bisecting reason.
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