Chemical Bonding: 19 MCQs with answers

All 19 multiple-choice questions from this kit, free and with no sign-up.

Warm-up · 5 questions

Q1. Which of the following pairs of atoms is most likely to form an ionic bond?

Beginner
A Nitrogen and oxygen B Carbon and hydrogen C Oxygen and hydrogen D Sodium and chlorine
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Sodium and chlorine

Ionic bonds form between a metal (low electronegativity) and a non-metal (high electronegativity). Sodium (metal) and chlorine (non-metal) have a large electronegativity difference, leading to electron transfer and ionic bond formation.

Q2. According to the octet rule, atoms tend to combine in order to achieve how many electrons in their valence shell?

Beginner
A 6 B 8 C 18 D 2
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8

The octet rule states that atoms are most stable when they have eight electrons in their outermost shell, resembling the electron configuration of a noble gas.

Q3. Which type of bond is formed by the overlap of atomic orbitals along the internuclear axis?

Beginner
A Ionic bond B σ bond C π bond D Hydrogen bond
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σ bond

A sigma (σ) bond is formed by the head-on overlap of atomic orbitals along the internuclear axis, while a pi (π) bond involves sidewise overlap.

Q4. Which of the following molecules has a bent (V-shaped) geometry?

Beginner
A H2O B CH4 C BF3 D CO2
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H2O

H2O has two bonding pairs and two lone pairs on the central oxygen, resulting in a bent shape with a bond angle of about 104.5°.

Q5. A sigma bond is stronger than a pi bond.

Beginner
A True B False
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True

Sigma bonds involve greater orbital overlap along the internuclear axis, making them stronger than pi bonds, which have sidewise overlap.

Building up · 10 questions

Q6. Which of the following molecules has a linear shape?

Intermediate
A H2O B NH3 C CO2 D CH4
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CO2

CO2 has two bonding pairs and no lone pairs on the central carbon atom, leading to a linear geometry with a bond angle of 180°.

Q7. What is the hybridization of the central atom in BF3?

Intermediate
A dsp2 B sp2 C sp3 D sp
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sp2

In BF3, boron has three bonding pairs and no lone pairs, requiring three equivalent orbitals, which corresponds to sp2 hybridization and a trigonal planar shape.

Q8. Which of the following bonds is the most polar?

Intermediate
A C-H B F-H C N-H D O-H
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O-H

Polarity depends on electronegativity difference. Fluorine is the most electronegative element, so the F-H bond has the largest electronegativity difference and is the most polar among the given options.

Q9. What is the bond order of the O2 molecule?

Intermediate
A 3 B 2.5 C 2 D 1
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2

O2 has a bond order of 2, calculated as (number of bonding electrons - number of antibonding electrons)/2 = (10-6)/2 = 2.

Q10. Which of the following molecules has a dipole moment of zero?

Intermediate
A H2O B NH3 C BF3 D HCl
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BF3

BF3 is trigonal planar and symmetrical, so the individual bond dipoles cancel out, resulting in a net dipole moment of zero.

Q11. Which of the following is an example of a molecule with a trigonal pyramidal shape?

Intermediate
A H2O B CO2 C NH3 D CH4
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NH3

NH3 has three bonding pairs and one lone pair on nitrogen, leading to a trigonal pyramidal shape due to lone pair repulsion.

Q12. What is the approximate bond angle in H2O?

Intermediate
A 120° B 107° C 104.5° D 90°
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104.5°

H2O has two lone pairs on oxygen, which compress the bond angle from the ideal tetrahedral angle (109.5°) to about 104.5°.

Q13. Which of the following molecules has a linear shape according to VSEPR theory?

Intermediate
A NH3 B BeCl2 C H2S D SO2
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BeCl2

BeCl2 has two bonding pairs and no lone pairs on beryllium, leading to a linear geometry with a bond angle of 180°.

Q14. Which of the following molecules has a non-zero dipole moment?

Intermediate
A BF3 B CO2 C H2O D CH4
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H2O

H2O is bent and has polar O-H bonds that do not cancel out, resulting in a net dipole moment. CO2, BF3, and CH4 are symmetrical and have zero dipole moments.

Q15. The shape of a molecule is determined solely by the number of bonding pairs of electrons.

Intermediate
A True B False
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False

According to VSEPR theory, the shape is determined by the total number of electron pairs (bonding and lone pairs) around the central atom, as lone pairs also influence geometry.

Topper level · 4 questions

Q16. Which of the following species does NOT follow the octet rule?

Advanced
A NH3 B CH4 C BF3 D H2O
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BF3

BF3 has only six electrons around boron, making it electron-deficient and an exception to the octet rule.

Q17. Which of the following is a correct statement about resonance?

Advanced
A Resonance structures differ in the position of atoms. B Resonance structures are in equilibrium with each other. C Resonance structures differ only in the distribution of electrons. D Resonance structures have different molecular formulas.
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Resonance structures differ only in the distribution of electrons.

Resonance structures represent the same molecule with the same arrangement of atoms but different distributions of electrons. The actual molecule is a hybrid of all resonance structures.

Q18. Which of the following is an example of a molecule that exhibits sp3d hybridization?

Advanced
A CH4 B PCl5 C SF6 D BF3
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PCl5

PCl5 has five bonding pairs around phosphorus, requiring sp3d hybridization to accommodate five electron pairs in a trigonal bipyramidal arrangement.

Q19. Which of the following is the correct order of bond lengths for C-C, C=C, and C≡C?

Advanced
A C-C > C=C > C≡C B C≡C > C=C > C-C C C=C > C-C > C≡C D C-C = C=C = C≡C
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C-C > C=C > C≡C

Bond length decreases as bond order increases. A triple bond is shorter than a double bond, which is shorter than a single bond.

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