Light — Reflection and Refraction · Class 10 Science: 264 MCQs with answers

Showing 200 of 264 multiple-choice questions from this kit.

Warm-up · 42 questions

Q1. The angle of incidence is the angle between the incident ray and the:

Beginner
A mirror surface B normal C reflected ray D horizontal
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normal

All angles in reflection are measured from the normal — the perpendicular at the point of incidence.

Q2. According to the first law of reflection:

Beginner
A ∠i = ∠r B ∠i > ∠r C ∠i < ∠r D ∠i + ∠r = 90°
Show answer & explanation

∠i = ∠r

The angle of incidence always equals the angle of reflection.

Q3. You stand 3 m in front of a plane mirror. Your image is formed:

Beginner
A 3 m in front of the mirror B on the mirror surface C 3 m behind the mirror D 6 m behind the mirror
Show answer & explanation

3 m behind the mirror

Image distance behind the mirror equals object distance in front: 3 m.

Q4. Lateral inversion means the interchange of:

Beginner
A top and bottom B front and back C up and down D left and right
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left and right

A plane mirror swaps left and right — never top and bottom.

Q5. The line perpendicular to a reflecting surface at the point of incidence is called the:

Beginner
A axis B normal C incident line D baseline
Show answer & explanation

normal

The normal is the reference line from which ∠i and ∠r are measured.

Q6. We can see a book lying on a table from any direction because the book's surface shows:

Beginner
A regular reflection B diffuse reflection C no reflection D total internal reflection
Show answer & explanation

diffuse reflection

Rough surfaces scatter light in all directions (diffuse reflection), making the object visible from everywhere.

Q7. The size of the image formed by a plane mirror is:

Beginner
A equal to the object B smaller than the object C larger than the object D depends on distance
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equal to the object

A plane mirror image is always exactly the same size as the object, at every distance.

Q8. A ray of light falls on a plane mirror along its normal. The angle of reflection is:

Beginner
A 45° B 0° C 90° D 180°
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0°

∠i = 0°, so ∠r = 0° — the ray retraces its own path.

Q9. Which of these is a luminous object?

Beginner
A the Moon B a mirror C a book D a burning candle
Show answer & explanation

a burning candle

A candle emits its own light; the others only reflect light.

Q10. The second law of reflection says the incident ray, reflected ray and normal:

Beginner
A are mutually perpendicular B lie in the same plane C make equal angles with the surface D meet at the centre of the mirror
Show answer & explanation

lie in the same plane

All three lie in one plane at the point of incidence.

Q11. An image that CAN be obtained on a screen is called:

Beginner
A virtual B real C erect D lateral
Show answer & explanation

real

Real images form where rays actually meet, so a screen placed there catches them.

Q12. State the two laws of reflection of light.

Beginner
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Q13. What is lateral inversion? Give one everyday consequence of it.

Beginner
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Q14. An object is placed 12 cm in front of a plane mirror. Where is the image, and what is the distance between object and image?

Beginner
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Q15. A ray of light is incident along the normal to a plane mirror. What are the angle of incidence and the angle of reflection?

Beginner
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Q16. A steel spoon is held with its HOLLOW side facing you, close to your face. Your face looks enlarged and the right way up. The hollow side is behaving as:

Beginner
A a plane mirror B a concave mirror C a convex mirror D a converging lens
Show answer & explanation

a concave mirror

The hollow side curves inwards, so it is a concave mirror. Held closer than the focus it gives a virtual, erect, magnified image — which is why a spoon is the easiest concave mirror to find at home.

Q17. Two concave mirrors have focal lengths 9 cm and 18 cm. Their radii of curvature are, respectively:

Beginner
A 4.5 cm and 9 cm B 9 cm and 18 cm C 18 cm and 36 cm D 36 cm and 72 cm
Show answer & explanation

18 cm and 36 cm

R = 2f, so the radii are twice the focal lengths: 18 cm and 36 cm.

Q18. A concave mirror gives a virtual, erect and magnified image when the object is:

Beginner
A between P and F B at C C beyond C D at F
Show answer & explanation

between P and F

Inside the focus is the one virtual case — the shaving-mirror position.

Q19. Define principal focus of a concave mirror.

Beginner
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Q20. Define principal focus of a convex mirror.

Beginner
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Q21. Give two uses each of concave and convex mirrors, with the reason for each.

Beginner
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Q22. Which mirror always gives a diminished, erect image? What advantage does this give in vehicles?

Beginner
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Q23. In the New Cartesian sign convention, all distances are measured from the:

Beginner
A pole B object C focus D centre of curvature
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pole

The pole acts as the origin of the coordinate system.

Q24. The object distance u for a mirror is always:

Beginner
A positive B zero C equal to f D negative
Show answer & explanation

negative

The object lies against the direction of incident light, so u < 0.

Q25. The focal length of a concave mirror is taken as:

Beginner
A negative B positive C zero D depends on the object
Show answer & explanation

negative

Its focus is in front of the mirror — the negative side.

Q26. The focal length of a convex mirror is taken as:

Beginner
A negative B positive C zero D imaginary
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positive

Its (virtual) focus lies behind the mirror — the positive side.

Q27. The mirror formula is:

Beginner
A 1/v − 1/u = 1/f B 1/u − 1/v = 1/f C 1/v + 1/u = 1/f D v + u = f
Show answer & explanation

1/v + 1/u = 1/f

Mirrors take the PLUS; the minus version is the lens formula.

Q28. Magnification of a mirror equals:

Beginner
A v/u B u/v C −u/v D −v/u
Show answer & explanation

−v/u

m = h′/h = −v/u.

Q29. A magnification of −1 means the image is:

Beginner
A virtual and same size B real, inverted, same size C erect and magnified D diminished
Show answer & explanation

real, inverted, same size

Negative → real & inverted; magnitude 1 → same size (object at C).

Q30. A positive magnification means the image is:

Beginner
A real and inverted B always magnified C virtual and erect D always diminished
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virtual and erect

Positive m goes with virtual, erect images.

Q31. Heights measured above the principal axis are taken as:

Beginner
A negative B zero C depends on mirror D positive
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positive

Upward = positive, downward = negative.

Q32. State the three rules of the New Cartesian sign convention.

Beginner
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Q33. The magnification produced by a mirror is +1. What does this tell you about the mirror and the image?

Beginner
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Q34. Light travelling from a rarer to a denser medium bends:

Beginner
A away from the normal B along the surface C towards the normal D not at all
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towards the normal

It slows down and bends towards the normal.

Q35. Light travelling from glass to air bends:

Beginner
A towards the normal B away from the normal C along the normal D backwards
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away from the normal

Denser → rarer: speeds up, bends away from the normal.

Q36. A ray incident normally (i = 0°) on a glass slab:

Beginner
A bends towards the normal B bends away C passes undeviated D is totally reflected
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passes undeviated

No oblique crossing → no bending; only the speed changes.

Q37. sin i / sin r = constant is known as:

Beginner
A law of reflection B Newton's law C Snell's law D lens formula
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Snell's law

The second law of refraction — Snell's law.

Q38. The absolute refractive index of a medium equals:

Beginner
A v/c B c/v C c × v D c − v
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c/v

n = c/v — vacuum speed over medium speed.

Q39. Which of these has the highest refractive index?

Beginner
A water B crown glass C diamond D air
Show answer & explanation

diamond

Diamond: n = 2.42, the highest among common materials.

Q40. Light travels slowest in:

Beginner
A vacuum B air C water D diamond
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diamond

Highest n → lowest speed.

Q41. The emergent ray from a rectangular glass slab is:

Beginner
A parallel to the incident ray B perpendicular to the incident ray C along the normal D divergent
Show answer & explanation

parallel to the incident ray

The equal-and-opposite bendings at the two parallel faces restore the direction.

Q42. A coin in a water-filled bucket appears raised because of:

Beginner
A refraction B reflection C dispersion D lateral inversion
Show answer & explanation

refraction

Light from the coin bends away from the normal on exiting the water.

Building up · 82 questions

Q43. Which of these statements about the image in a plane mirror are correct? I. It is virtual and erect. II. It is the same size as the object. III. It is laterally inverted. IV. It lies as far behind the mirror as the object stands in front. Which statements are correct?

Intermediate
A All four B I and II only C II and III only D I, III and IV only
Show answer & explanation

All four

All four are genuine properties of a plane-mirror image, and together they describe it completely.

Q44. A plane-mirror image cannot be caught on a screen because:

Intermediate
A the reflected rays never actually meet — they only appear to come from a point behind the mirror B the mirror absorbs too much of the light falling on it C the image is always far too small to see on a screen D a screen reflects light instead of absorbing it
Show answer & explanation

the reflected rays never actually meet — they only appear to come from a point behind the mirror

That is precisely what makes an image virtual. No light really passes through the image position, so there is nothing at that place for a screen to catch.

Q45. Which group lists ONLY non-luminous objects?

Intermediate
A the Sun, a candle flame, a torch bulb B the Moon, a firefly, a mirror C a candle flame, a page of a book, the Moon D the Moon, a mirror, a page of a book
Show answer & explanation

the Moon, a mirror, a page of a book

A non-luminous object is seen only by the light it reflects. The Sun, a flame, a torch bulb and a firefly all make their own light, so any group containing them fails.

Q46. A ray strikes a plane mirror at 30° to the mirror SURFACE. The angle of incidence is:

Intermediate
A 30° B 90° C 60° D 15°
Show answer & explanation

60°

Angle with surface + angle of incidence = 90°, so ∠i = 90° − 30° = 60°. The classic trap!

Q47. A ray strikes a plane mirror with an angle of incidence of 35°. The angle between the incident ray and the reflected ray is:

Intermediate
A 35° B 55° C 110° D 70°
Show answer & explanation

70°

The two rays are each 35° from the normal, on opposite sides: 35° + 35° = 70°.

Q48. The angle between an incident ray and the mirror surface is 25°. The angle of reflection is:

Intermediate
A 25° B 50° C 90° D 65°
Show answer & explanation

65°

∠i = 90° − 25° = 65°, and ∠r = ∠i = 65°.

Q49. A man stands 4 m from a plane mirror and his friend stands 6 m from the same mirror beside him. How far is the man from his FRIEND'S image?

Intermediate
A 6 m B 10 m C 8 m D 12 m
Show answer & explanation

10 m

The friend's image is 6 m behind the mirror; the man is 4 m in front: 4 + 6 = 10 m.

Q50. You walk towards a plane mirror at 2 m/s. Your image approaches YOU at:

Intermediate
A 1 m/s B 2 m/s C 4 m/s D 0 m/s
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4 m/s

You close in at 2 m/s and the image closes in at 2 m/s from the other side — relative speed 4 m/s.

Q51. The angle between the incident ray and the reflected ray is 90°. The angle of incidence is:

Intermediate
A 90° B 60° C 30° D 45°
Show answer & explanation

45°

∠i + ∠r = 90° and ∠i = ∠r, so each is 45°.

Q52. A plane mirror is rotated by 10° keeping the incident ray fixed. The reflected ray rotates by:

Intermediate
A 20° B 5° C 10° D 40°
Show answer & explanation

20°

The reflected ray always turns by twice the mirror's rotation: 2 × 10° = 20°.

Q53. Which letter of the alphabet would appear UNCHANGED in a plane mirror?

Intermediate
A B B R C N D A
Show answer & explanation

A

'A' is symmetric about its vertical axis, so its lateral inversion looks identical. B, R and N are not.

Q54. A clock shows 4:00. In a plane mirror, it will appear to show:

Intermediate
A 4:00 B 6:00 C 10:00 D 8:00
Show answer & explanation

8:00

Mirror time = 12:00 − 4:00 = 8:00 (lateral inversion of the dial).

Q55. Diffuse reflection occurs because on a rough surface:

Intermediate
A normals at different points face different directions B the laws of reflection fail C light is absorbed completely D light changes speed
Show answer & explanation

normals at different points face different directions

Each point obeys ∠i = ∠r, but the surface — hence the normal — is tilted differently at each point, scattering rays.

Q56. In a periscope, the two plane mirrors are inclined to the tube's axis at:

Intermediate
A 30° B 60° C 45° D 90°
Show answer & explanation

45°

At 45° each, a horizontal ray turns exactly 90° at each mirror, entering and leaving the tube horizontally.

Q57. The final image seen through a periscope is:

Intermediate
A laterally inverted B upside down C smaller than the object D erect and NOT laterally inverted
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erect and NOT laterally inverted

Two reflections cancel each other's lateral inversion, giving a normal, erect view.

Q58. Two plane mirrors are placed at 90° to each other. The number of images of an object between them is:

Intermediate
A 2 B 4 C 3 D infinite
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3

n = 360°/90° − 1 = 3 images.

Q59. Two plane mirrors face each other, parallel. The number of images formed is:

Intermediate
A infinite B 2 C 4 D 8
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infinite

Each mirror reflects the other's reflections endlessly — an infinite series of images.

Q60. A ray reflected from a plane mirror retraces its path. The angle of incidence was:

Intermediate
A 45° B 60° C 0° D 90°
Show answer & explanation

0°

Only a ray along the normal (∠i = 0°) reflects straight back on itself.

Q61. An object moves 30 cm closer to a plane mirror. The distance between the object and its image decreases by:

Intermediate
A 15 cm B 30 cm C 90 cm D 60 cm
Show answer & explanation

60 cm

Object-image separation is twice the object distance, so it shrinks by 2 × 30 = 60 cm.

Q62. Why can a virtual image not be obtained on a screen?

Intermediate
Show answer & explanation

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Q63. A ray of light strikes a plane mirror such that the angle between the incident ray and the reflected ray is 60°. Find the angle of incidence.

Intermediate
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Q64. Distinguish between regular and diffuse reflection. Do the laws of reflection hold in diffuse reflection?

Intermediate
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Q65. With the help of a labelled description, explain how the image of an object is formed by a plane mirror, and state all the characteristics of this image.

Intermediate
Show answer & explanation

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Ray construction with ∠i = ∠r (1), backward extension meeting behind mirror (1), virtual + erect (1), same size + equal distance (1), lateral inversion (1).

Q66. A ray aimed at the centre of curvature of a concave mirror comes straight back along its own path because it:

Intermediate
A travels along the principal axis B is parallel to the principal axis C is reflected twice inside the mirror D strikes the mirror along the normal, so the angle of incidence is zero
Show answer & explanation

strikes the mirror along the normal, so the angle of incidence is zero

The normal at any point of a spherical mirror is the radius through that point. A ray through C IS a radius, so it arrives at 0° to the normal and is reflected straight back.

Q67. Two rays leave the tip of an object in front of a concave mirror — one parallel to the axis, the other through F. After reflection the two rays:

Intermediate
A meet at the tip of the image B travel parallel to each other C both return along their own paths D both pass through the centre of curvature
Show answer & explanation

meet at the tip of the image

Each ray obeys its own rule, and the point where they cross is where the tip of the image lies. That is the whole method of drawing a ray diagram.

Q68. A shopkeeper fixes a convex mirror high in a corner of the shop. The single property that makes it useful there is that it:

Intermediate
A magnifies everything, so faces can be recognised B forms a real image that can be projected onto a wall C gives an erect, diminished image of a wide area for every position of the object D reflects light without any loss
Show answer & explanation

gives an erect, diminished image of a wide area for every position of the object

Diminished means more of the shop fits into the mirror; erect and always-virtual means it works whatever the distance. Between them they give the wide, reliable view the corner needs.

Q69. Which of these images could actually be caught on a screen?

Intermediate
A your face in a plane mirror B a shop aisle in a convex security mirror C your face in the BACK of a spoon D the Sun, formed by a concave mirror
Show answer & explanation

the Sun, formed by a concave mirror

Only a real image can be caught on a screen, and of these only the concave mirror forms one. The other three are virtual — the rays only appear to come from them.

Q70. The bulb of a torch sits at the focus of its concave reflector so that the light:

Intermediate
A leaves as a parallel beam, which travels far without spreading and dimming B spreads out in every direction C forms a real image of the bulb on the front glass D is prevented from heating the case
Show answer & explanation

leaves as a parallel beam, which travels far without spreading and dimming

Rays leaving the focus are reflected parallel to the axis. A parallel beam keeps its brightness over distance, which is exactly what a torch needs.

Q71. A dentist holds a small concave mirror very close to a tooth — nearer than its focus. The image seen is:

Intermediate
A real, inverted and magnified B virtual, erect and magnified C virtual, erect and diminished D real, erect and the same size
Show answer & explanation

virtual, erect and magnified

Inside the focus, a concave mirror gives a virtual, erect, magnified image — the one position in which it magnifies without turning the view upside down.

Q72. Parallel rays from a distant tower fall on a concave mirror of focal length 25 cm. A screen catches a sharp image at:

Intermediate
A 12.5 cm from the mirror B 25 cm from the mirror C 50 cm from the mirror D no screen position at all — the image is virtual
Show answer & explanation

25 cm from the mirror

Rays from a very distant object arrive parallel and converge at the focus, so the sharp image forms 25 cm from the mirror and is real, inverted and highly diminished.

Q73. An object is at C of a concave mirror. The image is:

Intermediate
A at F, diminished B at C, same size C beyond C, magnified D behind the mirror
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at C, same size

At C the image is also at C — real, inverted, equal in size.

Q74. An object is placed between C and F of a concave mirror. The image is:

Intermediate
A between F and C, diminished B at infinity C behind the mirror, magnified D beyond C, magnified
Show answer & explanation

beyond C, magnified

Real, inverted and magnified, formed beyond C.

Q75. To get a real image of the SAME size, the object in front of a concave mirror must be at:

Intermediate
A F B C C between P and F D infinity
Show answer & explanation

C

Only at C is the real image equal in size.

Q76. To burn a paper using a concave mirror and sunlight, the paper must be held at:

Intermediate
A the pole B the focus C the centre of curvature D anywhere
Show answer & explanation

the focus

Sunlight is parallel; it converges (with its heat) at the focus.

Q77. The image formed by a convex mirror lies:

Intermediate
A between P and F behind the mirror B in front of the mirror C beyond C behind the mirror D on the mirror
Show answer & explanation

between P and F behind the mirror

Always virtual, between P and F behind the mirror.

Q78. An object moves from infinity towards the focus of a concave mirror. Its real image:

Intermediate
A moves towards the mirror and shrinks B stays at F C moves away from the mirror and grows D moves behind the mirror
Show answer & explanation

moves away from the mirror and grows

The image travels F → C → beyond C → infinity, growing throughout.

Q79. Rule 4: a ray incident AT the pole of a concave mirror reflects:

Intermediate
A through F B through C C symmetrically about the principal axis D parallel to axis
Show answer & explanation

symmetrically about the principal axis

At P the principal axis serves as the normal, so ∠i = ∠r about it.

Q80. Which single mirror can show BOTH a magnified and a diminished image (at different object distances)?

Intermediate
A plane B convex C concave D none
Show answer & explanation

concave

Concave: diminished beyond C, magnified between C and F (and inside F).

Q81. Street lights use convex reflecting surfaces because they:

Intermediate
A converge light onto the road B form real images C spread light over a large area D save electricity
Show answer & explanation

spread light over a large area

Diverging spreads the light widely — exactly what a street lamp needs.

Q82. A student sees her erect image become inverted as she slowly moves AWAY from a mirror. The mirror is:

Intermediate
A plane B convex C concave D cannot say
Show answer & explanation

concave

Inside F: erect (virtual). Crossing F flips it to inverted (real). Only concave behaves this way.

Q83. A convex mirror is called a DIVERGING mirror because it:

Intermediate
A makes every image larger than the object B spreads a parallel beam, so the reflected rays appear to come from a focus behind the mirror C reflects only part of the light that falls on it D forms images of distant objects only
Show answer & explanation

spreads a parallel beam, so the reflected rays appear to come from a focus behind the mirror

The reflected rays actually spread apart. They never meet, so the focus is the point BEHIND the mirror from which they appear to diverge — which is also why the image is always virtual.

Q84. Assertion (A): A concave mirror is used in a solar cooker. Reason (R): A concave mirror is also used as a shaving mirror and by dentists to examine teeth.

Intermediate
A Both A and R are true, and R is the correct explanation of A B Both A and R are true, but R is not the correct explanation of A C A is true but R is false D A is false but R is true
Show answer & explanation

Both A and R are true, but R is not the correct explanation of A

Both are true, but the other uses of a concave mirror do not explain what it does in a solar cooker.

Q85. Four concave mirrors have radii of curvature 10 cm, 20 cm, 30 cm and 40 cm. Sunlight converges NEAREST the pole for the mirror of radius:

Intermediate
A 20 cm B 10 cm C 30 cm D 40 cm
Show answer & explanation

10 cm

Sunlight converges at the focus, and f = R/2. The smallest radius gives the shortest focal length, so the 10 cm mirror brings the light to a point just 5 cm away.

Q86. A concave mirror forms a sharp image of the Sun 8 cm from its pole. Its radius of curvature is:

Intermediate
A 4 cm B 16 cm C 8 cm D 32 cm
Show answer & explanation

16 cm

The Sun is effectively at infinity, so its image forms at the focus: f = 8 cm. R = 2f = 16 cm.

Q87. Which group lists ONLY uses of a CONCAVE mirror?

Intermediate
A rear-view mirror, shaving mirror, solar cooker B headlight reflector, shop security mirror, dentist's mirror C solar cooker, rear-view mirror, street-light reflector D shaving mirror, headlight reflector, solar cooker
Show answer & explanation

shaving mirror, headlight reflector, solar cooker

All three converge light or magnify. The other groups each contain a convex mirror — rear-view, security and street-light reflectors all diverge light to widen the view.

Q88. The focal length of a concave mirror is 12 cm. Where must an object be placed to get (a) a real, same-size image, (b) a virtual, magnified image?

Intermediate
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Q89. Why does a ray of light passing through the centre of curvature of a concave mirror retrace its path?

Intermediate
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Q90. An object is placed at the focus of a concave mirror. Describe the image.

Intermediate
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Q91. The image of a candle flame formed by a concave mirror is caught sharply on a screen. What TWO properties of the image can you state immediately?

Intermediate
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Q92. How would you quickly find the approximate focal length of a concave mirror on a sunny day?

Intermediate
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Q93. With the six standard cases, describe image formation by a concave mirror as an object is moved from infinity to the pole, and connect each case to one practical use where possible.

Intermediate
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All six positions with image position/size/nature (3), correct trend noted (1), at least two uses tied correctly to cases (1).

Q94. Describe an activity to distinguish a plane mirror, a concave mirror and a convex mirror WITHOUT touching their surfaces.

Intermediate
Show answer & explanation

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Close-up observation method (1), correct plane behaviour (1), concave magnify-then-invert behaviour (1.5), convex always-diminished conclusion (1.5).

Q95. For a real image formed by a mirror, the image distance v is:

Intermediate
A positive B zero C negative D equal to u
Show answer & explanation

negative

Real images form in front of the mirror — the negative side.

Q96. An object is 30 cm in front of a concave mirror with f = 15 cm. The image distance is:

Intermediate
A −10 cm B −30 cm C +30 cm D −15 cm
Show answer & explanation

−30 cm

u = −30, f = −15: 1/v = −1/15 + 1/30 = −1/30 → v = −30 cm (at C).

Q97. For the same case (u = −30, f = −15), the magnification is:

Intermediate
A +1 B +2 C −1 D −0.5
Show answer & explanation

−1

m = −v/u = −(−30)/(−30) = −1: real, inverted, same size.

Q98. An object is 20 cm in front of a convex mirror with f = +10 cm. The image forms:

Intermediate
A 20 cm in front B 10 cm behind C 6.7 cm behind D at infinity
Show answer & explanation

6.7 cm behind

1/v = 1/10 + 1/20 = 3/20 → v = +20/3 ≈ +6.7 cm (virtual, behind).

Q99. An object placed at the focus of a concave mirror gives 1/v = 0. This means the image is at:

Intermediate
A the pole B the focus C infinity D the centre of curvature
Show answer & explanation

infinity

1/v = 0 ⇔ v → infinity: the reflected rays are parallel.

Q100. A mirror produces m = +1/2 for all reasonable object positions. The mirror is:

Intermediate
A plane B concave C cannot say D convex
Show answer & explanation

convex

Virtual (positive) AND diminished (

Q101. A concave mirror forms a real image 3 times the object's size. The magnification is:

Intermediate
A +3 B +1/3 C −1/3 D −3
Show answer & explanation

−3

Real → negative sign; 3× → magnitude 3: m = −3.

Q102. If m = −0.5 for a mirror, the object lies:

Intermediate
A between P and F of a concave mirror B beyond C of a concave mirror C at C D in front of a convex mirror
Show answer & explanation

beyond C of a concave mirror

Real (negative), diminished (|m|

Q103. Assertion (A): For a convex mirror the image distance v is always positive. Reason (R): A convex mirror always forms its image behind the mirror.

Intermediate
A Both A and R are true, and R is the correct explanation of A B Both A and R are true, but R is not the correct explanation of A C A is true but R is false D A is false but R is true
Show answer & explanation

Both A and R are true, and R is the correct explanation of A

Distances behind the mirror run along the direction of the incident light and are counted positive, so forming the image behind the mirror is exactly why v comes out positive.

Q104. A student writes u = +25 cm for an object standing in front of a mirror. The mistake is that:

Intermediate
A the object lies against the direction of the incident light, so u must be negative B all distances are counted positive in the New Cartesian convention C u should be measured from the focus rather than the pole D u is negative only for convex mirrors
Show answer & explanation

the object lies against the direction of the incident light, so u must be negative

Light travels from the object towards the mirror, and distances measured against that direction are negative. The object distance is therefore negative for every mirror, always.

Q105. Why is the focal length of a concave mirror negative but that of a convex mirror positive?

Intermediate
Show answer & explanation

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Q106. An object is placed 24 cm in front of a concave mirror of focal length 16 cm. Find the position of the image.

Intermediate
Show answer & explanation

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Q107. For the numerical above (u = −24, v = −48), find the magnification and describe the image fully.

Intermediate
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Q108. A convex mirror of focal length 20 cm forms an image of an object placed 30 cm away. Find v and m.

Intermediate
Show answer & explanation

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Q109. Refraction happens at the boundary between two media because:

Intermediate
A some of the light is absorbed as it crosses the boundary B the boundary reflects part of the light back into the first medium C the speed of light differs in the two media, so a wavefront arriving obliquely is swung round D the colour of the light changes as it crosses the boundary
Show answer & explanation

the speed of light differs in the two media, so a wavefront arriving obliquely is swung round

One edge of the wavefront crosses first and changes speed before the other, which turns the ray. Change of speed is the cause; change of direction is the effect.

Q110. If the speed of light in a medium is 1.5 × 10⁸ m/s, its refractive index is:

Intermediate
A 0.5 B 1.5 C 2.0 D 3.0
Show answer & explanation

2.0

n = (3 × 10⁸)/(1.5 × 10⁸) = 2.0.

Q111. The refractive index of glass is 1.5. The speed of light in glass is:

Intermediate
A 2 × 10⁸ m/s B 3 × 10⁸ m/s C 1.5 × 10⁸ m/s D 4.5 × 10⁸ m/s
Show answer & explanation

2 × 10⁸ m/s

v = c/n = (3 × 10⁸)/1.5 = 2 × 10⁸ m/s.

Q112. n(water) = 1.33 and n(glass) = 1.52. Light going from glass INTO water bends:

Intermediate
A towards the normal B undeviated C back into glass D away from the normal
Show answer & explanation

away from the normal

Glass is denser (higher n) than water — going to the rarer medium bends away.

Q113. The refractive index of water with respect to glass (n glass→water) equals:

Intermediate
A 1.52/1.33 B 1.33 × 1.52 C 1.52 − 1.33 D 1.33/1.52
Show answer & explanation

1.33/1.52

n₂₁ = n₂/n₁ = n(water)/n(glass) = 1.33/1.52 ≈ 0.87.

Q114. In the glass-slab experiment, the angle of emergence is:

Intermediate
A greater than i B less than i C always 90° D equal to i
Show answer & explanation

equal to i

Parallel faces make the exit bending undo the entry bending: e = i.

Q115. Lateral displacement does NOT depend on:

Intermediate
A colour of the slab's frame B slab thickness C angle of incidence D refractive index
Show answer & explanation

colour of the slab's frame

Thickness, incidence angle and n are the three real factors.

Q116. Which quantity is unchanged when light enters glass from air?

Intermediate
A speed B wavelength C frequency D direction
Show answer & explanation

frequency

Frequency is fixed by the source; v and λ shrink together.

Q117. Kerosene (n = 1.44) floats on water (n = 1.33). Which statement is TRUE?

Intermediate
A Kerosene is optically denser B Water is optically denser C Both are equally dense optically D Floating decides optical density
Show answer & explanation

Kerosene is optically denser

Higher n = optically denser — regardless of who floats.

Q118. n₂₁ = 4/3 for water w.r.t. air. Then n₁₂ (air w.r.t. water) is:

Intermediate
A 4/3 B 1 C 16/9 D 3/4
Show answer & explanation

3/4

Reciprocal pair: n₁₂ = 1/n₂₁ = 3/4.

Q119. Light travels at 2.25 × 10⁸ m/s in water. Taking c = 3 × 10⁸ m/s, the refractive index of water is:

Intermediate
A 1.5 B 0.75 C 2.25 D 1.33
Show answer & explanation

1.33

n = c/v = (3 × 10⁸)/(2.25 × 10⁸) = 1.33.

Q120. Four media P, Q, R and S have refractive indices 1.31, 1.44, 1.50 and 2.42. A ray entering from air bends MOST on entering:

Intermediate
A P B S C Q D R
Show answer & explanation

S

The greater the refractive index, the greater the bending for the same angle of incidence. S, with 2.42, bends the ray most — it is diamond.

Q121. The refractive index of a medium is 1.6. The speed of light inside it is about:

Intermediate
A 1.88 × 10⁸ m/s B 4.80 × 10⁸ m/s C 1.60 × 10⁸ m/s D 3.00 × 10⁸ m/s
Show answer & explanation

1.88 × 10⁸ m/s

v = c/n = (3 × 10⁸)/1.6 = 1.88 × 10⁸ m/s. Nothing travels faster than light in vacuum, which rules out the second option immediately.

Q122. The refractive index of glass with respect to air is 1.5. The refractive index of air with respect to glass is:

Intermediate
A 1.50 B 0.67 C 2.25 D 1.00
Show answer & explanation

0.67

Relative refractive indices are reciprocals of one another: 1/1.5 = 0.67.

Q123. Which group lists ONLY effects of REFRACTION?

Intermediate
A a bent-looking pencil in water, a raised coin, a shallow-looking pool B a bent-looking pencil in water, the blue sky, a red sunset C a raised coin, the blue sky, a shallow-looking pool D the blue sky, a red sunset, the whiteness of clouds
Show answer & explanation

a bent-looking pencil in water, a raised coin, a shallow-looking pool

All three in the first group come from light bending at a boundary. The blue sky, the red sunset and the white of clouds are all scattering effects, not refraction.

Q124. A ray bends AWAY from the normal as it leaves glass and enters air because:

Intermediate
A air is optically denser than glass B the light speeds up on entering the rarer medium, and that swings the ray away from the normal C the glass absorbs part of the ray on the way out D the frequency of the light increases once it reaches the air
Show answer & explanation

the light speeds up on entering the rarer medium, and that swings the ray away from the normal

Going from denser to rarer the speed rises, so the ray turns away from the normal — the exact reverse of what happens on the way in.

Topper level · 76 questions

Q125. You can see your face in a polished marble floor but not in a sheet of newspaper, even though both reflect light. The reason is that:

Advanced
A the marble is smooth, so parallel rays stay parallel after reflection, while the rough paper scatters them in all directions B newspaper absorbs all the light that falls on it C newspaper reflects only invisible light D marble is a source of light of its own
Show answer & explanation

the marble is smooth, so parallel rays stay parallel after reflection, while the rough paper scatters them in all directions

Both obey the laws of reflection at every point. The difference is the surface: smooth gives regular reflection and an image, rough gives diffuse reflection and none.

Q126. To see his FULL image, a 1.8 m tall man needs a plane mirror of minimum height:

Advanced
A 1.8 m B 1.2 m C 0.6 m D 0.9 m
Show answer & explanation

0.9 m

A plane mirror of half the person's height suffices, positioned correctly: 1.8/2 = 0.9 m — independent of how far he stands.

Q127. The angle between the incident ray and the mirror is θ. The angle between the incident and reflected rays is:

Advanced
A θ B 180° − 2θ C 2θ D 90° − θ
Show answer & explanation

180° − 2θ

∠i = 90° − θ, and the rays are separated by 2∠i = 180° − 2θ.

Q128. A ray falls on one of two mirrors placed at 90°, parallel to the second mirror. After both reflections, the outgoing ray is:

Advanced
A perpendicular to the incident ray B parallel to the incident ray, same direction C anti-parallel (parallel but opposite) to the incident ray D along the normal
Show answer & explanation

anti-parallel (parallel but opposite) to the incident ray

Perpendicular mirrors reverse a ray's direction: the final ray travels back anti-parallel to the incident ray — the principle of retroreflectors.

Q129. Assertion: A rough wall forms no image. Reason: The laws of reflection are not obeyed on rough surfaces. Choose:

Advanced
A Both true, reason explains assertion B Both true, reason does NOT explain assertion C Assertion true, reason false D Both false
Show answer & explanation

Assertion true, reason false

No image forms (true) — but the laws ARE obeyed at each point; scattered normals cause the diffusion. The reason is false.

Q130. A mirror is rotated by θ and the reflected ray is found to rotate by 50°. θ is:

Advanced
A 100° B 50° C 25° D 12.5°
Show answer & explanation

25°

Reflected-ray rotation = 2θ, so θ = 50°/2 = 25°.

Q131. A boy runs at 1.5 m/s AWAY from a plane mirror. The distance between him and his image increases at:

Advanced
A 3 m/s B 1.5 m/s C 0.75 m/s D 6 m/s
Show answer & explanation

3 m/s

Both he and his image move 1.5 m/s in opposite directions relative to the mirror: separation grows at 3 m/s.

Q132. At what angle should two plane mirrors be inclined so that exactly 11 images of an object are formed?

Advanced
A 45° B 30° C 36° D 24°
Show answer & explanation

30°

n = 360°/θ − 1 = 11 gives 360°/θ = 12, so θ = 30°.

Q133. A person sees the image of a candle in a plane mirror 5 m away from him; the candle is 2 m in front of the mirror on his side. How far is the PERSON from the mirror?

Advanced
A 3 m B 2 m C 5 m D 7 m
Show answer & explanation

3 m

Image is 2 m behind the mirror. Person-to-image = person-to-mirror + 2 = 5, so person-to-mirror = 3 m.

Q134. Light takes about 1.3 s to reach Earth from the Moon. This light originally came from:

Advanced
A the Moon's core B Earth's atmosphere C the Sun D the stars
Show answer & explanation

the Sun

Moonlight is reflected sunlight — the Moon is non-luminous.

Q135. Two plane mirrors are placed at right angles to each other. A ray strikes the first mirror, reflects onto the second, and leaves it. The emerging ray is:

Advanced
A perpendicular to the original ray B along the same line and in the same direction as the original ray C parallel to the original ray but travelling in the opposite direction D at 45° to the original ray whatever the angle of incidence
Show answer & explanation

parallel to the original ray but travelling in the opposite direction

Two reflections at 90° reverse the ray's direction whatever the angle of incidence. This is why a bicycle reflector sends light straight back at the driver who lit it.

Q136. A person 1.5 m tall wishes to see a full-length image of themselves in a plane mirror fixed to a wall. The shortest mirror that will do is:

Advanced
A 1.5 m tall, since the mirror must match the person's height B 0.75 m tall, since a plane mirror needs only half the height of the object C 3.0 m tall, since the image is as far behind as the person is in front D of any height, since the distance from the mirror can be adjusted instead
Show answer & explanation

0.75 m tall, since a plane mirror needs only half the height of the object

Light from the top of the head meets the mirror halfway between eye and crown, and from the feet halfway between eye and floor. Half the height suffices, and moving back does not change it.

Q137. A wet road at night looks darker to a driver than a dry road. Explain using reflection.

Advanced
Show answer & explanation

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Q138. State the laws of reflection. Describe an activity (as in the NCERT textbook) to verify the first law of reflection.

Advanced
Show answer & explanation

—

Both laws stated (2), activity setup described (1), method of sighting images with pins (1), measurement conclusion ∠i = ∠r (1).

Q139. Explain, with reasons: (a) why we can see our face in a mirror but not in a newspaper; (b) why the word AMBULANCE is painted laterally inverted on ambulances; (c) why a periscope shows an erect, un-reversed view.

Advanced
Show answer & explanation

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(a) regular vs diffuse with reasoning (2), (b) double-inversion logic (1.5), (c) two mirrors cancelling inversion (1.5).

Q140. A ray of light strikes a plane mirror at an angle of 40° to the mirror surface. (a) Find the angle of incidence and the angle of reflection. (b) Find the angle through which the ray is deviated from its original path. (c) If the mirror is now rotated by 5°, keeping the incident ray fixed, through what additional angle does the reflected ray turn?

Advanced
Show answer & explanation

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Surface-to-normal conversion (1), ∠i = ∠r = 50° (1), deviation 80° with working (1.5), 2θ rule applied for 10° (1.5).

Q141. A concave mirror has a radius of curvature of 30 cm. An object is placed exactly 30 cm in front of it. The image is:

Advanced
A 15 cm from the mirror and virtual B at infinity C 7.5 cm from the mirror and magnified D 30 cm from the mirror, real, inverted and the same size
Show answer & explanation

30 cm from the mirror, real, inverted and the same size

The object is at the centre of curvature. With u = −30 cm and f = −15 cm, 1/v = 1/f − 1/u = −1/15 + 1/30 = −1/30, so v = −30 cm — the image returns to C, real, inverted and the same size.

Q142. A car's rear-view mirror makes following traffic look smaller, and therefore further away, than it really is. This happens because:

Advanced
A a convex mirror always forms a diminished virtual image, and the brain reads a smaller image as a more distant object B the mirror is tilted away from the driver C the glass is thicker at its edges than at its centre D the image formed is real and inverted
Show answer & explanation

a convex mirror always forms a diminished virtual image, and the brain reads a smaller image as a more distant object

This is why such mirrors carry the warning that objects are closer than they appear — the diminished image is the price paid for the wide field of view.

Q143. A concave mirror and a convex mirror both have a radius of curvature of 40 cm. In the New Cartesian convention their focal lengths are:

Advanced
A both +20 cm B both −20 cm C −40 cm for the concave and +40 cm for the convex D −20 cm for the concave and +20 cm for the convex
Show answer & explanation

−20 cm for the concave and +20 cm for the convex

f = R/2 gives 20 cm for both. The sign separates them: a concave mirror's focus lies in front of it, against the incident light, so f is negative; a convex mirror's focus lies behind it, so f is positive.

Q144. The minimum distance between an object and its REAL image formed by a concave mirror is:

Advanced
A f B 2f C 4f D zero
Show answer & explanation

zero

At C, object and image coincide in position — separation zero.

Q145. A concave mirror produces a magnified REAL image. The object lies:

Advanced
A beyond C B at C C between P and F D between C and F
Show answer & explanation

between C and F

Real + magnified happens only between C and F. (Inside F is magnified but virtual.)

Q146. Sunlight converges to a bright spot 12 cm from a concave mirror. Its radius of curvature is:

Advanced
A 24 cm B 6 cm C 12 cm D 48 cm
Show answer & explanation

24 cm

The spot is the focus, so f = 12 cm and R = 2f = 24 cm.

Q147. A driver's mirror shows a bus as a small erect image. As the bus approaches, its image will:

Advanced
A stay the same size B become real C grow but stay erect and virtual D invert
Show answer & explanation

grow but stay erect and virtual

Convex images stay virtual and erect but grow (while remaining smaller than the object) as the object nears.

Q148. In a ray diagram, a ray from the object's tip through F reflects parallel, and another through C retraces. They meet 20 cm in front of the mirror. The image is:

Advanced
A real, 20 cm in front B virtual, 20 cm behind C at infinity D at the pole
Show answer & explanation

real, 20 cm in front

Reflected rays ACTUALLY meeting in front of the mirror = a real image there.

Q149. Assertion: A convex mirror can never focus sunlight to burn paper. Reason: Its focus is virtual — rays never actually pass through it.

Advanced
A Both true, reason explains assertion B Both true, reason irrelevant C Assertion true, reason false D Both false
Show answer & explanation

Both true, reason explains assertion

Diverged rays only appear to come from F behind the mirror; no real concentration of energy occurs.

Q150. A concave mirror of focal length 15 cm forms an image at infinity. The object distance is:

Advanced
A 7.5 cm B 30 cm C 15 cm D infinity
Show answer & explanation

15 cm

Image at infinity ⇔ object exactly at the focus (15 cm).

Q151. Consider these statements about a concave mirror. I. It converges a parallel beam to a real focus in front of it. II. It forms a virtual image only when the object lies between the pole and the focus. III. Its focal length is negative in the New Cartesian convention. IV. It always forms a diminished image. Which statements are correct?

Advanced
A I, II and III only B I and IV only C II and III only D All four
Show answer & explanation

I, II and III only

I, II and III are correct. IV is false — a concave mirror magnifies whenever the object is nearer than the centre of curvature, and only diminishes beyond it.

Q152. An object is placed at four positions in front of a concave mirror of focal length 10 cm. Which row pairs the position with the image CORRECTLY?

Advanced
A u = 5 cm → real and inverted B u = 15 cm → virtual and erect C u = 30 cm → virtual and magnified D u = 20 cm → real, inverted and the same size
Show answer & explanation

u = 20 cm → real, inverted and the same size

20 cm is 2f, the centre of curvature, where the image returns the same size, real and inverted. At 5 cm the object is inside the focus, so the image is virtual and erect; at 15 cm and 30 cm it is real and inverted, magnified and diminished respectively.

Q153. A convex mirror gives a wider field of view than a plane mirror of the same size because:

Advanced
A it reflects a greater fraction of the light falling on it B it forms a real image instead of a virtual one C its outward curve spreads the reflected rays, so light from a wider region can reach the eye D its surface area is greater than it appears
Show answer & explanation

its outward curve spreads the reflected rays, so light from a wider region can reach the eye

The curvature is doing the work. Each part of the surface faces a slightly different direction, so between them they gather light from a much wider cone than a flat surface of the same size.

Q154. Which of these ray rules for a concave mirror are correct? I. A ray through F reflects parallel to the principal axis. II. A ray through C retraces its own path. III. A ray parallel to the axis reflects through C. IV. A ray striking the pole reflects making equal angles with the axis. Which statements are correct?

Advanced
A I, II and IV only B I and III only C II, III and IV only D All four
Show answer & explanation

I, II and IV only

I, II and IV are the true rules. III is the common slip: a ray parallel to the axis reflects through the FOCUS, not through the centre of curvature.

Q155. A concave mirror has a focal length of 12 cm. For the image to be real, inverted and exactly the same size as the object, the object must be placed:

Advanced
A 6 cm from the mirror B 12 cm from the mirror C 48 cm from the mirror D 24 cm from the mirror
Show answer & explanation

24 cm from the mirror

An image of the same size is formed only when the object is at the centre of curvature, and R = 2f = 24 cm.

Q156. State what happens to the size and position of the image as an object approaches a convex mirror from far away.

Advanced
Show answer & explanation

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Q157. Explain, with the ray rules involved, (a) why the bulb of a torch is placed at the focus of its concave reflector, and (b) why a concave mirror is used by dentists. Draw the reasoning for both (describe the rays in words).

Advanced
Show answer & explanation

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Rule 2/reversibility for torch (1.5), parallel beam consequence (1), object-inside-F setup for dentist (1), virtual-erect-magnified outcome (1.5).

Q158. A concave mirror and a convex mirror each have a radius of curvature of 30 cm. An object is placed 10 cm in front of each mirror. Using the mirror tables (no formula needed), compare the two images formed.

Advanced
Show answer & explanation

—

f = 15 cm from R = 2f (1), concave case identified as inside-F with correct nature (1.5), convex nature stated (1), explicit comparison of size and similarity (1.5).

Q159. u = −10 cm for a concave mirror of f = −15 cm. The image is:

Advanced
A real, in front B at infinity C real, at C D virtual, behind, magnified
Show answer & explanation

virtual, behind, magnified

|u| < |f| → inside focus: 1/v = −1/15 + 1/10 = +1/30 → v = +30 cm, m = +3 — virtual, erect, 3× magnified.

Q160. For a convex mirror, which is IMPOSSIBLE?

Advanced
A v negative B v positive C m = +0.6 D image between P and F
Show answer & explanation

v negative

A convex mirror never forms an image in front (v < 0 impossible) — its images are always virtual.

Q161. A concave mirror (f = −12 cm) must form a real image of magnification −2. The object distance is:

Advanced
A −6 cm B −12 cm C −24 cm D −18 cm
Show answer & explanation

−18 cm

m = −v/u = −2 → v = 2u. Substituting: 1/(2u) + 1/u = −1/12 → 3/(2u) = −1/12 → u = −18 cm.

Q162. The image in a mirror is erect and exactly half the object's height. The mirror and m are:

Advanced
A concave, m = −1/2 B plane, m = 1/2 C convex, m = +1/2 D concave, m = +1/2
Show answer & explanation

convex, m = +1/2

Erect → +; half → 1/2; erect-diminished only happens in a convex mirror.

Q163. An object 2 cm tall gives a real image 6 cm tall at 45 cm from a concave mirror. The object distance is:

Advanced
A −15 cm B −45 cm C −7.5 cm D −135 cm
Show answer & explanation

−15 cm

Real → v = −45, m = h′/h = −6/2 = −3 = −v/u → −3 = −(−45)/u → u = −15 cm.

Q164. Assertion: For mirrors, v and u of a real image are both negative. Reason: Real images form in front of the mirror, on the same side as the object.

Advanced
A Both true, reason explains assertion B Both true, reason irrelevant C Assertion true, reason false D Both false
Show answer & explanation

Both true, reason explains assertion

Both quantities lie against the incident-light direction — both negative; the reason is the correct explanation.

Q165. A concave mirror of f = −10 cm forms an image on the object itself. The object distance is:

Advanced
A −5 cm B −10 cm C −20 cm D −40 cm
Show answer & explanation

−20 cm

Image coincides with object only at C: u = 2f = −20 cm (and m = −1).

Q166. A concave mirror forms a REAL image. Which of these are true? I. The object distance u is negative. II. The image distance v is negative. III. The magnification m is negative. IV. The focal length f is positive. Which statements are correct?

Advanced
A I, II and III only B I and IV only C II and IV only D All four
Show answer & explanation

I, II and III only

A real image forms in front of the mirror, so v is negative like u, and m = −v/u comes out negative. IV is wrong — a concave mirror's focus lies in front of it, so f is negative.

Q167. The magnification of a mirror is written m = −v/u rather than v/u because:

Advanced
A mirrors always interchange the left and right sides of an object B the focal length of a mirror is always taken to be negative C the object distance for a mirror is measured from behind the mirror D the minus sign makes m negative for a real inverted image and positive for a virtual erect one
Show answer & explanation

the minus sign makes m negative for a real inverted image and positive for a virtual erect one

Both u and v are negative for a real image, so v/u alone would be positive and would wrongly suggest an erect image. The minus sign is what makes the sign of m carry the nature of the image.

Q168. A concave mirror of focal length 20 cm forms an image 60 cm in front of it. The object distance is:

Advanced
A 15 cm B 45 cm C 30 cm D 90 cm
Show answer & explanation

30 cm

With f = −20 cm and v = −60 cm, 1/u = 1/f − 1/v = −1/20 + 1/60 = −1/30, so u = −30 cm.

Q169. An object 3 cm tall stands 24 cm from a concave mirror of focal length 8 cm. The height of the image is:

Advanced
A 0.5 cm B 1.5 cm C 3 cm D 6 cm
Show answer & explanation

1.5 cm

f = −8 cm, u = −24 cm give 1/v = −1/8 + 1/24 = −1/12, so v = −12 cm. m = −v/u = −0.5, so the image is 1.5 cm tall and inverted.

Q170. A concave mirror gives a virtual image twice the size of an object placed 5 cm in front of it. The focal length of the mirror is:

Advanced
A 5 cm B 15 cm C 20 cm D 10 cm
Show answer & explanation

10 cm

A virtual erect image means m = +2, so +2 = −v/u = −v/(−5), giving v = +10 cm. Then 1/f = 1/v + 1/u = 1/10 − 1/5 = −1/10, so f = −10 cm — a focal length of 10 cm.

Q171. A convex mirror has a focal length of 15 cm. An object 30 cm in front of it forms an image at:

Advanced
A +15 cm B −10 cm C +10 cm D +30 cm
Show answer & explanation

+10 cm

f = +15 cm and u = −30 cm give 1/v = 1/f − 1/u = 1/15 + 1/30 = 1/10, so v = +10 cm — 10 cm behind the mirror, virtual and erect.

Q172. A mirror produces a magnification of −2. Which statements are true? I. The image is real. II. The image is inverted. III. The image is twice as tall as the object. IV. The mirror is convex. Which statements are correct?

Advanced
A I, II and III only B I and IV only C II and III only D All four
Show answer & explanation

I, II and III only

A negative m means real and inverted, and the size 2 means twice as tall. IV is wrong — a convex mirror can never magnify, so only a concave mirror can give m = −2.

Q173. An object and its real image formed by a concave mirror are both 36 cm from the mirror. The focal length is:

Advanced
A 9 cm B 36 cm C 72 cm D 18 cm
Show answer & explanation

18 cm

Object and image coincide only at the centre of curvature, so R = 36 cm and f = R/2 = 18 cm. The mirror formula agrees: 1/f = −1/36 − 1/36 = −1/18.

Q174. Four concave mirrors of focal length 10 cm, 15 cm, 20 cm and 25 cm each have an object placed 30 cm away. The image forms FURTHEST from the mirror for the one of focal length:

Advanced
A 10 cm B 25 cm C 15 cm D 20 cm
Show answer & explanation

25 cm

The image distances work out as 15 cm, 30 cm, 60 cm and 150 cm. As the focal length approaches the object distance, the image runs away towards infinity — at f = 25 cm the object is closest to the focus.

Q175. A candle stands between the pole and the focus of a concave mirror. The mirror is moved slowly away until the candle is exactly at the focus. At that moment the image:

Advanced
A becomes real and very small B runs off to infinity and cannot be caught on a screen at all C becomes exactly the same size as the candle D disappears completely
Show answer & explanation

runs off to infinity and cannot be caught on a screen at all

At the focus 1/v = 1/f − 1/u = 0, so v is infinite. The reflected rays emerge parallel and never meet, which is why no screen anywhere catches an image.

Q176. A convex mirror of radius of curvature 24 cm has an object 12 cm in front of it. The magnification is:

Advanced
A −0.5 B +0.5 C +2 D −2
Show answer & explanation

+0.5

f = +12 cm and u = −12 cm give 1/v = 1/12 + 1/12 = 1/6, so v = +6 cm. m = −v/u = −6/(−12) = +0.5 — virtual, erect and half the size, as a convex mirror always gives.

Q177. A real image formed by a mirror always has a negative magnification because:

Advanced
A real images are always smaller than the object that made them B a real image forms on the same side as the object, so v and u are both negative and −v/u comes out negative C the mirror formula only works when the numbers are negative D real images can only be formed by convex mirrors
Show answer & explanation

a real image forms on the same side as the object, so v and u are both negative and −v/u comes out negative

The sign follows straight from the convention, and it is what encodes the inversion: every real image formed by a mirror is inverted.

Q178. A concave mirror forms a real, inverted image. Which group lists quantities that are ALL negative?

Advanced
A u, v and the height of the object B u, v, f and m C f, m and the height of the object D v, m and the focal length of a convex mirror
Show answer & explanation

u, v, f and m

For a real image from a concave mirror all four are negative. The object height is measured upwards from the axis and is positive, and a convex mirror's focal length is positive.

Q179. An object stands 15 cm from a concave mirror of focal length 10 cm, and the image is caught on a screen. The screen must be placed:

Advanced
A 30 cm in front of the mirror B 10 cm in front of the mirror C 30 cm behind the mirror D nowhere — the image is virtual
Show answer & explanation

30 cm in front of the mirror

1/v = −1/10 + 1/15 = −1/30, so v = −30 cm. The negative sign puts the image in FRONT of the mirror, which is where a screen can catch it.

Q180. Can the magnification of a convex mirror ever exceed 1? Justify.

Advanced
Show answer & explanation

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Q181. A student gets v = +15 cm for a concave mirror problem. What kind of image is this, and what must have been true about the object's position?

Advanced
Show answer & explanation

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Q182. An object 4 cm tall is placed 18 cm in front of a concave mirror of radius of curvature 24 cm. Find the position, size and nature of the image.

Advanced
Show answer & explanation

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f from R with sign (1), correct substitution and v = −36 (1.5), m = −2 and h′ = −8 (1.5), full verbal interpretation + table consistency (1).

Q183. Explain the complete method of solving mirror numericals, and show why interpreting the SIGNS of v and m is as important as computing them, using u = −10 cm, f = −15 cm as your example.

Advanced
Show answer & explanation

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5-step method (2), correct v = +30 with sign meaning (1.5), m = +3 with meaning (1), explicit point that signs encode nature (0.5).

Q184. A convex mirror used on a bus has a radius of curvature of 3 m. A car is 5 m behind the bus. Find the position and nature of the car's image, and explain why such mirrors carry the warning 'objects in mirror are closer than they appear'.

Advanced
Show answer & explanation

—

f = +1.5 (0.5), v ≈ +1.15 m with working (2), m ≈ +0.23 and nature (1.5), size-distance perception explanation (1).

Q185. Using the magnification formula alone, explain how you can identify which mirror formed an image, given only the value of m. Cover all the important ranges of m with one example situation each.

Advanced
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—

plane m=+1 (1), convex 0

Q186. A pond appears 1.5 m deep. If n(water) = 4/3, its REAL depth is:

Advanced
A 2.0 m B 1.125 m C 1.5 m D 2.5 m
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2.0 m

Apparent = real/n → real = 1.5 × 4/3 = 2.0 m.

Q187. Light's speed in medium A is 2 × 10⁸ m/s and in B is 2.5 × 10⁸ m/s. The refractive index of A with respect to B is:

Advanced
A 0.8 B 1.25 C 1.5 D 2.0
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1.25

n(A wrt B) = v_B/v_A = 2.5/2 = 1.25.

Q188. A ray hits a glass slab at i = 45° and refracts at r = 28°. When it exits the far side, the angle inside the glass at that surface is:

Advanced
A 45° B 17° C 62° D 28°
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28°

The internal ray meets the parallel exit face at the same 28° (alternate angles) — then exits at 45°.

Q189. Assertion: The Sun is visible about two minutes before actual sunrise. Reason: Light bends away from the normal as it leaves the vacuum of space into denser air layers.

Advanced
A Both true, reason correct B Assertion true, reason false C Both false D Assertion false, reason true
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Assertion true, reason false

The effect is real, but entering DENSER air bends light TOWARDS the normal — curving rays around the horizon; the stated reason has the direction wrong.

Q190. Two slabs, A (thick, n = 1.4) and B (thin, n = 1.4), refract the same ray at the same angle. Compared to B, slab A produces:

Advanced
A less lateral displacement B greater lateral displacement C equal displacement D an emergent ray not parallel to incident
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greater lateral displacement

Displacement grows with thickness; parallelism holds for both.

Q191. Consider these statements about light passing from air into glass. I. The ray bends towards the normal. II. The speed of the light decreases. III. The frequency of the light changes. IV. A ray along the normal is not deviated at all. Which statements are correct?

Advanced
A I, II and IV only B I and III only C II and III only D All four
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I, II and IV only

I, II and IV are correct. III is the common slip — the frequency is set by the source and never changes on refraction; it is the speed and the wavelength that change.

Q192. A swimming pool always looks shallower than it really is because:

Advanced
A water absorbs some of the light coming from the bottom B water magnifies every object placed inside it C light travels faster in water than it does in air D light from the bottom bends away from the normal on leaving the water, and the eye traces it back in a straight line to a higher point
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light from the bottom bends away from the normal on leaving the water, and the eye traces it back in a straight line to a higher point

The eye assumes light has travelled in a straight line all the way, so it locates the bottom along the emergent direction — above where the bottom really is.

Q193. Assertion (A): A rectangular glass slab does not split white light into colours. Reason (R): Its two refracting faces are inclined to each other, as the faces of a prism are.

Advanced
A Both A and R are true, and R is the correct explanation of A B Both A and R are true, but R is not the correct explanation of A C A is true but R is false D A is false but R is true
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A is true but R is false

They are parallel, and that is why the colours recombine. The assertion holds, the reason is false.

Q194. A ray enters a transparent medium with an angle of incidence of 60° and an angle of refraction of 30°. The refractive index of the medium is about:

Advanced
A 0.58 B 2.00 C 0.50 D 1.73
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1.73

n = sin 60° / sin 30° = 0.866/0.5 ≈ 1.73.

Q195. A tank of water of refractive index 4/3 is 2.4 m deep. To someone looking straight down into it, the water appears:

Advanced
A 3.2 m deep B 2.4 m deep C 1.8 m deep D 0.6 m deep
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1.8 m deep

Apparent depth = real depth ÷ n = 2.4 ÷ (4/3) = 1.8 m. The bottom looks raised by 0.6 m.

Q196. A glass rod becomes almost invisible when it is dipped into a certain liquid. This tells us that:

Advanced
A the liquid has dissolved the surface of the glass B the liquid and the glass have nearly the same refractive index, so almost no refraction happens at their boundary C the liquid is very much denser than the glass D light has stopped passing through the rod altogether
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the liquid and the glass have nearly the same refractive index, so almost no refraction happens at their boundary

We see the rod only because light bends and reflects at its surface. Match the refractive indices and there is nothing at the boundary to bend the light, so the rod stops being visible.

Q197. For a ray passing obliquely through a rectangular glass slab, consider these statements. I. The emergent ray is parallel to the incident ray. II. The lateral displacement grows as the slab is made thicker. III. The lateral displacement grows as the angle of incidence is increased. IV. The emergent ray lies along the same straight line as the incident ray. Which statements are correct?

Advanced
A I, II and III only B I and IV only C II and III only D All four
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I, II and III only

I, II and III are correct. IV contradicts I in practice — the emergent ray is parallel to the incident ray but shifted sideways, and that shift is the lateral displacement.

Q198. A student shines a laser straight down onto the surface of a beaker of water and is surprised that the beam does not bend. The correct explanation is that:

Advanced
A water does not refract laser light B the laser beam is too narrow for the bending to occur C the beam strikes along the normal, so the angle of incidence is 0° and there is no change of direction D the beam does bend, but far too little to be seen
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the beam strikes along the normal, so the angle of incidence is 0° and there is no change of direction

By Snell's law an angle of incidence of 0° gives an angle of refraction of 0°. The light does slow down in the water — only its direction is unaffected.

Q199. Light takes the same time to cover 3 m in vacuum as it does to cover x metres in a medium of refractive index 1.5. The value of x is:

Advanced
A 1.5 m B 2 m C 4.5 m D 3 m
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2 m

The speed in the medium is c/1.5. In the time 3/c that light needs for 3 m in vacuum, it covers (c/1.5) × (3/c) = 2 m in the medium.

Q200. A coin lies at the bottom of an empty opaque mug, just out of sight over the rim. Water is poured in without moving the coin, and the coin becomes visible. This happens because:

Advanced
A the water pushes the coin upwards B the water makes the coin larger C light travels in curves inside water D light from the coin bends away from the normal at the water surface, so rays that would have missed the eye now reach it
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light from the coin bends away from the normal at the water surface, so rays that would have missed the eye now reach it

This is the classic coin-and-bowl demonstration. Refraction at the surface redirects rays that were previously blocked by the rim, and the eye traces them back to an apparently raised coin.

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