Light — Reflection and Refraction · Class 10 Science: 264 MCQs with answers
Showing 200 of 264 multiple-choice questions from this kit.
Warm-up · 42 questions
Q1. The angle of incidence is the angle between the incident ray and the:
BeginnerShow answer & explanation
normal
All angles in reflection are measured from the normal — the perpendicular at the point of incidence.
Q2. According to the first law of reflection:
BeginnerShow answer & explanation
∠i = ∠r
The angle of incidence always equals the angle of reflection.
Q3. You stand 3 m in front of a plane mirror. Your image is formed:
BeginnerShow answer & explanation
3 m behind the mirror
Image distance behind the mirror equals object distance in front: 3 m.
Q4. Lateral inversion means the interchange of:
BeginnerShow answer & explanation
left and right
A plane mirror swaps left and right — never top and bottom.
Q5. The line perpendicular to a reflecting surface at the point of incidence is called the:
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normal
The normal is the reference line from which ∠i and ∠r are measured.
Q6. We can see a book lying on a table from any direction because the book's surface shows:
BeginnerShow answer & explanation
diffuse reflection
Rough surfaces scatter light in all directions (diffuse reflection), making the object visible from everywhere.
Q7. The size of the image formed by a plane mirror is:
BeginnerShow answer & explanation
equal to the object
A plane mirror image is always exactly the same size as the object, at every distance.
Q8. A ray of light falls on a plane mirror along its normal. The angle of reflection is:
BeginnerShow answer & explanation
0°
∠i = 0°, so ∠r = 0° — the ray retraces its own path.
Q9. Which of these is a luminous object?
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a burning candle
A candle emits its own light; the others only reflect light.
Q10. The second law of reflection says the incident ray, reflected ray and normal:
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lie in the same plane
All three lie in one plane at the point of incidence.
Q11. An image that CAN be obtained on a screen is called:
BeginnerShow answer & explanation
real
Real images form where rays actually meet, so a screen placed there catches them.
Q12. State the two laws of reflection of light.
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Q13. What is lateral inversion? Give one everyday consequence of it.
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Q14. An object is placed 12 cm in front of a plane mirror. Where is the image, and what is the distance between object and image?
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Q15. A ray of light is incident along the normal to a plane mirror. What are the angle of incidence and the angle of reflection?
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Q16. A steel spoon is held with its HOLLOW side facing you, close to your face. Your face looks enlarged and the right way up. The hollow side is behaving as:
BeginnerShow answer & explanation
a concave mirror
The hollow side curves inwards, so it is a concave mirror. Held closer than the focus it gives a virtual, erect, magnified image — which is why a spoon is the easiest concave mirror to find at home.
Q17. Two concave mirrors have focal lengths 9 cm and 18 cm. Their radii of curvature are, respectively:
BeginnerShow answer & explanation
18 cm and 36 cm
R = 2f, so the radii are twice the focal lengths: 18 cm and 36 cm.
Q18. A concave mirror gives a virtual, erect and magnified image when the object is:
BeginnerShow answer & explanation
between P and F
Inside the focus is the one virtual case — the shaving-mirror position.
Q19. Define principal focus of a concave mirror.
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Q20. Define principal focus of a convex mirror.
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Q21. Give two uses each of concave and convex mirrors, with the reason for each.
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Q22. Which mirror always gives a diminished, erect image? What advantage does this give in vehicles?
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Q23. In the New Cartesian sign convention, all distances are measured from the:
BeginnerShow answer & explanation
pole
The pole acts as the origin of the coordinate system.
Q24. The object distance u for a mirror is always:
BeginnerShow answer & explanation
negative
The object lies against the direction of incident light, so u < 0.
Q25. The focal length of a concave mirror is taken as:
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negative
Its focus is in front of the mirror — the negative side.
Q26. The focal length of a convex mirror is taken as:
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positive
Its (virtual) focus lies behind the mirror — the positive side.
Q27. The mirror formula is:
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1/v + 1/u = 1/f
Mirrors take the PLUS; the minus version is the lens formula.
Q28. Magnification of a mirror equals:
BeginnerShow answer & explanation
−v/u
m = h′/h = −v/u.
Q29. A magnification of −1 means the image is:
BeginnerShow answer & explanation
real, inverted, same size
Negative → real & inverted; magnitude 1 → same size (object at C).
Q30. A positive magnification means the image is:
BeginnerShow answer & explanation
virtual and erect
Positive m goes with virtual, erect images.
Q31. Heights measured above the principal axis are taken as:
BeginnerShow answer & explanation
positive
Upward = positive, downward = negative.
Q32. State the three rules of the New Cartesian sign convention.
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Q33. The magnification produced by a mirror is +1. What does this tell you about the mirror and the image?
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Q34. Light travelling from a rarer to a denser medium bends:
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towards the normal
It slows down and bends towards the normal.
Q35. Light travelling from glass to air bends:
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away from the normal
Denser → rarer: speeds up, bends away from the normal.
Q36. A ray incident normally (i = 0°) on a glass slab:
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passes undeviated
No oblique crossing → no bending; only the speed changes.
Q37. sin i / sin r = constant is known as:
BeginnerShow answer & explanation
Snell's law
The second law of refraction — Snell's law.
Q38. The absolute refractive index of a medium equals:
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c/v
n = c/v — vacuum speed over medium speed.
Q39. Which of these has the highest refractive index?
BeginnerShow answer & explanation
diamond
Diamond: n = 2.42, the highest among common materials.
Q40. Light travels slowest in:
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diamond
Highest n → lowest speed.
Q41. The emergent ray from a rectangular glass slab is:
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parallel to the incident ray
The equal-and-opposite bendings at the two parallel faces restore the direction.
Q42. A coin in a water-filled bucket appears raised because of:
BeginnerShow answer & explanation
refraction
Light from the coin bends away from the normal on exiting the water.
Building up · 82 questions
Q43. Which of these statements about the image in a plane mirror are correct? I. It is virtual and erect. II. It is the same size as the object. III. It is laterally inverted. IV. It lies as far behind the mirror as the object stands in front. Which statements are correct?
IntermediateShow answer & explanation
All four
All four are genuine properties of a plane-mirror image, and together they describe it completely.
Q44. A plane-mirror image cannot be caught on a screen because:
IntermediateShow answer & explanation
the reflected rays never actually meet — they only appear to come from a point behind the mirror
That is precisely what makes an image virtual. No light really passes through the image position, so there is nothing at that place for a screen to catch.
Q45. Which group lists ONLY non-luminous objects?
IntermediateShow answer & explanation
the Moon, a mirror, a page of a book
A non-luminous object is seen only by the light it reflects. The Sun, a flame, a torch bulb and a firefly all make their own light, so any group containing them fails.
Q46. A ray strikes a plane mirror at 30° to the mirror SURFACE. The angle of incidence is:
IntermediateShow answer & explanation
60°
Angle with surface + angle of incidence = 90°, so ∠i = 90° − 30° = 60°. The classic trap!
Q47. A ray strikes a plane mirror with an angle of incidence of 35°. The angle between the incident ray and the reflected ray is:
IntermediateShow answer & explanation
70°
The two rays are each 35° from the normal, on opposite sides: 35° + 35° = 70°.
Q48. The angle between an incident ray and the mirror surface is 25°. The angle of reflection is:
IntermediateShow answer & explanation
65°
∠i = 90° − 25° = 65°, and ∠r = ∠i = 65°.
Q49. A man stands 4 m from a plane mirror and his friend stands 6 m from the same mirror beside him. How far is the man from his FRIEND'S image?
IntermediateShow answer & explanation
10 m
The friend's image is 6 m behind the mirror; the man is 4 m in front: 4 + 6 = 10 m.
Q50. You walk towards a plane mirror at 2 m/s. Your image approaches YOU at:
IntermediateShow answer & explanation
4 m/s
You close in at 2 m/s and the image closes in at 2 m/s from the other side — relative speed 4 m/s.
Q51. The angle between the incident ray and the reflected ray is 90°. The angle of incidence is:
IntermediateShow answer & explanation
45°
∠i + ∠r = 90° and ∠i = ∠r, so each is 45°.
Q52. A plane mirror is rotated by 10° keeping the incident ray fixed. The reflected ray rotates by:
IntermediateShow answer & explanation
20°
The reflected ray always turns by twice the mirror's rotation: 2 × 10° = 20°.
Q53. Which letter of the alphabet would appear UNCHANGED in a plane mirror?
IntermediateShow answer & explanation
A
'A' is symmetric about its vertical axis, so its lateral inversion looks identical. B, R and N are not.
Q54. A clock shows 4:00. In a plane mirror, it will appear to show:
IntermediateShow answer & explanation
8:00
Mirror time = 12:00 − 4:00 = 8:00 (lateral inversion of the dial).
Q55. Diffuse reflection occurs because on a rough surface:
IntermediateShow answer & explanation
normals at different points face different directions
Each point obeys ∠i = ∠r, but the surface — hence the normal — is tilted differently at each point, scattering rays.
Q56. In a periscope, the two plane mirrors are inclined to the tube's axis at:
IntermediateShow answer & explanation
45°
At 45° each, a horizontal ray turns exactly 90° at each mirror, entering and leaving the tube horizontally.
Q57. The final image seen through a periscope is:
IntermediateShow answer & explanation
erect and NOT laterally inverted
Two reflections cancel each other's lateral inversion, giving a normal, erect view.
Q58. Two plane mirrors are placed at 90° to each other. The number of images of an object between them is:
IntermediateShow answer & explanation
3
n = 360°/90° − 1 = 3 images.
Q59. Two plane mirrors face each other, parallel. The number of images formed is:
IntermediateShow answer & explanation
infinite
Each mirror reflects the other's reflections endlessly — an infinite series of images.
Q60. A ray reflected from a plane mirror retraces its path. The angle of incidence was:
IntermediateShow answer & explanation
0°
Only a ray along the normal (∠i = 0°) reflects straight back on itself.
Q61. An object moves 30 cm closer to a plane mirror. The distance between the object and its image decreases by:
IntermediateShow answer & explanation
60 cm
Object-image separation is twice the object distance, so it shrinks by 2 × 30 = 60 cm.
Q62. Why can a virtual image not be obtained on a screen?
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Q63. A ray of light strikes a plane mirror such that the angle between the incident ray and the reflected ray is 60°. Find the angle of incidence.
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Q64. Distinguish between regular and diffuse reflection. Do the laws of reflection hold in diffuse reflection?
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Q65. With the help of a labelled description, explain how the image of an object is formed by a plane mirror, and state all the characteristics of this image.
IntermediateShow answer & explanation
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Ray construction with ∠i = ∠r (1), backward extension meeting behind mirror (1), virtual + erect (1), same size + equal distance (1), lateral inversion (1).
Q66. A ray aimed at the centre of curvature of a concave mirror comes straight back along its own path because it:
IntermediateShow answer & explanation
strikes the mirror along the normal, so the angle of incidence is zero
The normal at any point of a spherical mirror is the radius through that point. A ray through C IS a radius, so it arrives at 0° to the normal and is reflected straight back.
Q67. Two rays leave the tip of an object in front of a concave mirror — one parallel to the axis, the other through F. After reflection the two rays:
IntermediateShow answer & explanation
meet at the tip of the image
Each ray obeys its own rule, and the point where they cross is where the tip of the image lies. That is the whole method of drawing a ray diagram.
Q68. A shopkeeper fixes a convex mirror high in a corner of the shop. The single property that makes it useful there is that it:
IntermediateShow answer & explanation
gives an erect, diminished image of a wide area for every position of the object
Diminished means more of the shop fits into the mirror; erect and always-virtual means it works whatever the distance. Between them they give the wide, reliable view the corner needs.
Q69. Which of these images could actually be caught on a screen?
IntermediateShow answer & explanation
the Sun, formed by a concave mirror
Only a real image can be caught on a screen, and of these only the concave mirror forms one. The other three are virtual — the rays only appear to come from them.
Q70. The bulb of a torch sits at the focus of its concave reflector so that the light:
IntermediateShow answer & explanation
leaves as a parallel beam, which travels far without spreading and dimming
Rays leaving the focus are reflected parallel to the axis. A parallel beam keeps its brightness over distance, which is exactly what a torch needs.
Q71. A dentist holds a small concave mirror very close to a tooth — nearer than its focus. The image seen is:
IntermediateShow answer & explanation
virtual, erect and magnified
Inside the focus, a concave mirror gives a virtual, erect, magnified image — the one position in which it magnifies without turning the view upside down.
Q72. Parallel rays from a distant tower fall on a concave mirror of focal length 25 cm. A screen catches a sharp image at:
IntermediateShow answer & explanation
25 cm from the mirror
Rays from a very distant object arrive parallel and converge at the focus, so the sharp image forms 25 cm from the mirror and is real, inverted and highly diminished.
Q73. An object is at C of a concave mirror. The image is:
IntermediateShow answer & explanation
at C, same size
At C the image is also at C — real, inverted, equal in size.
Q74. An object is placed between C and F of a concave mirror. The image is:
IntermediateShow answer & explanation
beyond C, magnified
Real, inverted and magnified, formed beyond C.
Q75. To get a real image of the SAME size, the object in front of a concave mirror must be at:
IntermediateShow answer & explanation
C
Only at C is the real image equal in size.
Q76. To burn a paper using a concave mirror and sunlight, the paper must be held at:
IntermediateShow answer & explanation
the focus
Sunlight is parallel; it converges (with its heat) at the focus.
Q77. The image formed by a convex mirror lies:
IntermediateShow answer & explanation
between P and F behind the mirror
Always virtual, between P and F behind the mirror.
Q78. An object moves from infinity towards the focus of a concave mirror. Its real image:
IntermediateShow answer & explanation
moves away from the mirror and grows
The image travels F → C → beyond C → infinity, growing throughout.
Q79. Rule 4: a ray incident AT the pole of a concave mirror reflects:
IntermediateShow answer & explanation
symmetrically about the principal axis
At P the principal axis serves as the normal, so ∠i = ∠r about it.
Q80. Which single mirror can show BOTH a magnified and a diminished image (at different object distances)?
IntermediateShow answer & explanation
concave
Concave: diminished beyond C, magnified between C and F (and inside F).
Q81. Street lights use convex reflecting surfaces because they:
IntermediateShow answer & explanation
spread light over a large area
Diverging spreads the light widely — exactly what a street lamp needs.
Q82. A student sees her erect image become inverted as she slowly moves AWAY from a mirror. The mirror is:
IntermediateShow answer & explanation
concave
Inside F: erect (virtual). Crossing F flips it to inverted (real). Only concave behaves this way.
Q83. A convex mirror is called a DIVERGING mirror because it:
IntermediateShow answer & explanation
spreads a parallel beam, so the reflected rays appear to come from a focus behind the mirror
The reflected rays actually spread apart. They never meet, so the focus is the point BEHIND the mirror from which they appear to diverge — which is also why the image is always virtual.
Q84. Assertion (A): A concave mirror is used in a solar cooker. Reason (R): A concave mirror is also used as a shaving mirror and by dentists to examine teeth.
IntermediateShow answer & explanation
Both A and R are true, but R is not the correct explanation of A
Both are true, but the other uses of a concave mirror do not explain what it does in a solar cooker.
Q85. Four concave mirrors have radii of curvature 10 cm, 20 cm, 30 cm and 40 cm. Sunlight converges NEAREST the pole for the mirror of radius:
IntermediateShow answer & explanation
10 cm
Sunlight converges at the focus, and f = R/2. The smallest radius gives the shortest focal length, so the 10 cm mirror brings the light to a point just 5 cm away.
Q86. A concave mirror forms a sharp image of the Sun 8 cm from its pole. Its radius of curvature is:
IntermediateShow answer & explanation
16 cm
The Sun is effectively at infinity, so its image forms at the focus: f = 8 cm. R = 2f = 16 cm.
Q87. Which group lists ONLY uses of a CONCAVE mirror?
IntermediateShow answer & explanation
shaving mirror, headlight reflector, solar cooker
All three converge light or magnify. The other groups each contain a convex mirror — rear-view, security and street-light reflectors all diverge light to widen the view.
Q88. The focal length of a concave mirror is 12 cm. Where must an object be placed to get (a) a real, same-size image, (b) a virtual, magnified image?
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Q89. Why does a ray of light passing through the centre of curvature of a concave mirror retrace its path?
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Q90. An object is placed at the focus of a concave mirror. Describe the image.
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Q91. The image of a candle flame formed by a concave mirror is caught sharply on a screen. What TWO properties of the image can you state immediately?
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Q92. How would you quickly find the approximate focal length of a concave mirror on a sunny day?
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Q93. With the six standard cases, describe image formation by a concave mirror as an object is moved from infinity to the pole, and connect each case to one practical use where possible.
IntermediateShow answer & explanation
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All six positions with image position/size/nature (3), correct trend noted (1), at least two uses tied correctly to cases (1).
Q94. Describe an activity to distinguish a plane mirror, a concave mirror and a convex mirror WITHOUT touching their surfaces.
IntermediateShow answer & explanation
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Close-up observation method (1), correct plane behaviour (1), concave magnify-then-invert behaviour (1.5), convex always-diminished conclusion (1.5).
Q95. For a real image formed by a mirror, the image distance v is:
IntermediateShow answer & explanation
negative
Real images form in front of the mirror — the negative side.
Q96. An object is 30 cm in front of a concave mirror with f = 15 cm. The image distance is:
IntermediateShow answer & explanation
−30 cm
u = −30, f = −15: 1/v = −1/15 + 1/30 = −1/30 → v = −30 cm (at C).
Q97. For the same case (u = −30, f = −15), the magnification is:
IntermediateShow answer & explanation
−1
m = −v/u = −(−30)/(−30) = −1: real, inverted, same size.
Q98. An object is 20 cm in front of a convex mirror with f = +10 cm. The image forms:
IntermediateShow answer & explanation
6.7 cm behind
1/v = 1/10 + 1/20 = 3/20 → v = +20/3 ≈ +6.7 cm (virtual, behind).
Q99. An object placed at the focus of a concave mirror gives 1/v = 0. This means the image is at:
IntermediateShow answer & explanation
infinity
1/v = 0 ⇔ v → infinity: the reflected rays are parallel.
Q100. A mirror produces m = +1/2 for all reasonable object positions. The mirror is:
IntermediateShow answer & explanation
convex
Virtual (positive) AND diminished (
Q101. A concave mirror forms a real image 3 times the object's size. The magnification is:
IntermediateShow answer & explanation
−3
Real → negative sign; 3× → magnitude 3: m = −3.
Q102. If m = −0.5 for a mirror, the object lies:
IntermediateShow answer & explanation
beyond C of a concave mirror
Real (negative), diminished (|m|
Q103. Assertion (A): For a convex mirror the image distance v is always positive. Reason (R): A convex mirror always forms its image behind the mirror.
IntermediateShow answer & explanation
Both A and R are true, and R is the correct explanation of A
Distances behind the mirror run along the direction of the incident light and are counted positive, so forming the image behind the mirror is exactly why v comes out positive.
Q104. A student writes u = +25 cm for an object standing in front of a mirror. The mistake is that:
IntermediateShow answer & explanation
the object lies against the direction of the incident light, so u must be negative
Light travels from the object towards the mirror, and distances measured against that direction are negative. The object distance is therefore negative for every mirror, always.
Q105. Why is the focal length of a concave mirror negative but that of a convex mirror positive?
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Q106. An object is placed 24 cm in front of a concave mirror of focal length 16 cm. Find the position of the image.
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Q107. For the numerical above (u = −24, v = −48), find the magnification and describe the image fully.
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Q108. A convex mirror of focal length 20 cm forms an image of an object placed 30 cm away. Find v and m.
IntermediateShow answer & explanation
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Q109. Refraction happens at the boundary between two media because:
IntermediateShow answer & explanation
the speed of light differs in the two media, so a wavefront arriving obliquely is swung round
One edge of the wavefront crosses first and changes speed before the other, which turns the ray. Change of speed is the cause; change of direction is the effect.
Q110. If the speed of light in a medium is 1.5 × 10⁸ m/s, its refractive index is:
IntermediateShow answer & explanation
2.0
n = (3 × 10⁸)/(1.5 × 10⁸) = 2.0.
Q111. The refractive index of glass is 1.5. The speed of light in glass is:
IntermediateShow answer & explanation
2 × 10⁸ m/s
v = c/n = (3 × 10⁸)/1.5 = 2 × 10⁸ m/s.
Q112. n(water) = 1.33 and n(glass) = 1.52. Light going from glass INTO water bends:
IntermediateShow answer & explanation
away from the normal
Glass is denser (higher n) than water — going to the rarer medium bends away.
Q113. The refractive index of water with respect to glass (n glass→water) equals:
IntermediateShow answer & explanation
1.33/1.52
n₂₁ = n₂/n₁ = n(water)/n(glass) = 1.33/1.52 ≈ 0.87.
Q114. In the glass-slab experiment, the angle of emergence is:
IntermediateShow answer & explanation
equal to i
Parallel faces make the exit bending undo the entry bending: e = i.
Q115. Lateral displacement does NOT depend on:
IntermediateShow answer & explanation
colour of the slab's frame
Thickness, incidence angle and n are the three real factors.
Q116. Which quantity is unchanged when light enters glass from air?
IntermediateShow answer & explanation
frequency
Frequency is fixed by the source; v and λ shrink together.
Q117. Kerosene (n = 1.44) floats on water (n = 1.33). Which statement is TRUE?
IntermediateShow answer & explanation
Kerosene is optically denser
Higher n = optically denser — regardless of who floats.
Q118. n₂₁ = 4/3 for water w.r.t. air. Then n₁₂ (air w.r.t. water) is:
IntermediateShow answer & explanation
3/4
Reciprocal pair: n₁₂ = 1/n₂₁ = 3/4.
Q119. Light travels at 2.25 × 10⁸ m/s in water. Taking c = 3 × 10⁸ m/s, the refractive index of water is:
IntermediateShow answer & explanation
1.33
n = c/v = (3 × 10⁸)/(2.25 × 10⁸) = 1.33.
Q120. Four media P, Q, R and S have refractive indices 1.31, 1.44, 1.50 and 2.42. A ray entering from air bends MOST on entering:
IntermediateShow answer & explanation
S
The greater the refractive index, the greater the bending for the same angle of incidence. S, with 2.42, bends the ray most — it is diamond.
Q121. The refractive index of a medium is 1.6. The speed of light inside it is about:
IntermediateShow answer & explanation
1.88 × 10⁸ m/s
v = c/n = (3 × 10⁸)/1.6 = 1.88 × 10⁸ m/s. Nothing travels faster than light in vacuum, which rules out the second option immediately.
Q122. The refractive index of glass with respect to air is 1.5. The refractive index of air with respect to glass is:
IntermediateShow answer & explanation
0.67
Relative refractive indices are reciprocals of one another: 1/1.5 = 0.67.
Q123. Which group lists ONLY effects of REFRACTION?
IntermediateShow answer & explanation
a bent-looking pencil in water, a raised coin, a shallow-looking pool
All three in the first group come from light bending at a boundary. The blue sky, the red sunset and the white of clouds are all scattering effects, not refraction.
Q124. A ray bends AWAY from the normal as it leaves glass and enters air because:
IntermediateShow answer & explanation
the light speeds up on entering the rarer medium, and that swings the ray away from the normal
Going from denser to rarer the speed rises, so the ray turns away from the normal — the exact reverse of what happens on the way in.
Topper level · 76 questions
Q125. You can see your face in a polished marble floor but not in a sheet of newspaper, even though both reflect light. The reason is that:
AdvancedShow answer & explanation
the marble is smooth, so parallel rays stay parallel after reflection, while the rough paper scatters them in all directions
Both obey the laws of reflection at every point. The difference is the surface: smooth gives regular reflection and an image, rough gives diffuse reflection and none.
Q126. To see his FULL image, a 1.8 m tall man needs a plane mirror of minimum height:
AdvancedShow answer & explanation
0.9 m
A plane mirror of half the person's height suffices, positioned correctly: 1.8/2 = 0.9 m — independent of how far he stands.
Q127. The angle between the incident ray and the mirror is θ. The angle between the incident and reflected rays is:
AdvancedShow answer & explanation
180° − 2θ
∠i = 90° − θ, and the rays are separated by 2∠i = 180° − 2θ.
Q128. A ray falls on one of two mirrors placed at 90°, parallel to the second mirror. After both reflections, the outgoing ray is:
AdvancedShow answer & explanation
anti-parallel (parallel but opposite) to the incident ray
Perpendicular mirrors reverse a ray's direction: the final ray travels back anti-parallel to the incident ray — the principle of retroreflectors.
Q129. Assertion: A rough wall forms no image. Reason: The laws of reflection are not obeyed on rough surfaces. Choose:
AdvancedShow answer & explanation
Assertion true, reason false
No image forms (true) — but the laws ARE obeyed at each point; scattered normals cause the diffusion. The reason is false.
Q130. A mirror is rotated by θ and the reflected ray is found to rotate by 50°. θ is:
AdvancedShow answer & explanation
25°
Reflected-ray rotation = 2θ, so θ = 50°/2 = 25°.
Q131. A boy runs at 1.5 m/s AWAY from a plane mirror. The distance between him and his image increases at:
AdvancedShow answer & explanation
3 m/s
Both he and his image move 1.5 m/s in opposite directions relative to the mirror: separation grows at 3 m/s.
Q132. At what angle should two plane mirrors be inclined so that exactly 11 images of an object are formed?
AdvancedShow answer & explanation
30°
n = 360°/θ − 1 = 11 gives 360°/θ = 12, so θ = 30°.
Q133. A person sees the image of a candle in a plane mirror 5 m away from him; the candle is 2 m in front of the mirror on his side. How far is the PERSON from the mirror?
AdvancedShow answer & explanation
3 m
Image is 2 m behind the mirror. Person-to-image = person-to-mirror + 2 = 5, so person-to-mirror = 3 m.
Q134. Light takes about 1.3 s to reach Earth from the Moon. This light originally came from:
AdvancedShow answer & explanation
the Sun
Moonlight is reflected sunlight — the Moon is non-luminous.
Q135. Two plane mirrors are placed at right angles to each other. A ray strikes the first mirror, reflects onto the second, and leaves it. The emerging ray is:
AdvancedShow answer & explanation
parallel to the original ray but travelling in the opposite direction
Two reflections at 90° reverse the ray's direction whatever the angle of incidence. This is why a bicycle reflector sends light straight back at the driver who lit it.
Q136. A person 1.5 m tall wishes to see a full-length image of themselves in a plane mirror fixed to a wall. The shortest mirror that will do is:
AdvancedShow answer & explanation
0.75 m tall, since a plane mirror needs only half the height of the object
Light from the top of the head meets the mirror halfway between eye and crown, and from the feet halfway between eye and floor. Half the height suffices, and moving back does not change it.
Q137. A wet road at night looks darker to a driver than a dry road. Explain using reflection.
AdvancedShow answer & explanation
—
Q138. State the laws of reflection. Describe an activity (as in the NCERT textbook) to verify the first law of reflection.
AdvancedShow answer & explanation
—
Both laws stated (2), activity setup described (1), method of sighting images with pins (1), measurement conclusion ∠i = ∠r (1).
Q139. Explain, with reasons: (a) why we can see our face in a mirror but not in a newspaper; (b) why the word AMBULANCE is painted laterally inverted on ambulances; (c) why a periscope shows an erect, un-reversed view.
AdvancedShow answer & explanation
—
(a) regular vs diffuse with reasoning (2), (b) double-inversion logic (1.5), (c) two mirrors cancelling inversion (1.5).
Q140. A ray of light strikes a plane mirror at an angle of 40° to the mirror surface. (a) Find the angle of incidence and the angle of reflection. (b) Find the angle through which the ray is deviated from its original path. (c) If the mirror is now rotated by 5°, keeping the incident ray fixed, through what additional angle does the reflected ray turn?
AdvancedShow answer & explanation
—
Surface-to-normal conversion (1), ∠i = ∠r = 50° (1), deviation 80° with working (1.5), 2θ rule applied for 10° (1.5).
Q141. A concave mirror has a radius of curvature of 30 cm. An object is placed exactly 30 cm in front of it. The image is:
AdvancedShow answer & explanation
30 cm from the mirror, real, inverted and the same size
The object is at the centre of curvature. With u = −30 cm and f = −15 cm, 1/v = 1/f − 1/u = −1/15 + 1/30 = −1/30, so v = −30 cm — the image returns to C, real, inverted and the same size.
Q142. A car's rear-view mirror makes following traffic look smaller, and therefore further away, than it really is. This happens because:
AdvancedShow answer & explanation
a convex mirror always forms a diminished virtual image, and the brain reads a smaller image as a more distant object
This is why such mirrors carry the warning that objects are closer than they appear — the diminished image is the price paid for the wide field of view.
Q143. A concave mirror and a convex mirror both have a radius of curvature of 40 cm. In the New Cartesian convention their focal lengths are:
AdvancedShow answer & explanation
−20 cm for the concave and +20 cm for the convex
f = R/2 gives 20 cm for both. The sign separates them: a concave mirror's focus lies in front of it, against the incident light, so f is negative; a convex mirror's focus lies behind it, so f is positive.
Q144. The minimum distance between an object and its REAL image formed by a concave mirror is:
AdvancedShow answer & explanation
zero
At C, object and image coincide in position — separation zero.
Q145. A concave mirror produces a magnified REAL image. The object lies:
AdvancedShow answer & explanation
between C and F
Real + magnified happens only between C and F. (Inside F is magnified but virtual.)
Q146. Sunlight converges to a bright spot 12 cm from a concave mirror. Its radius of curvature is:
AdvancedShow answer & explanation
24 cm
The spot is the focus, so f = 12 cm and R = 2f = 24 cm.
Q147. A driver's mirror shows a bus as a small erect image. As the bus approaches, its image will:
AdvancedShow answer & explanation
grow but stay erect and virtual
Convex images stay virtual and erect but grow (while remaining smaller than the object) as the object nears.
Q148. In a ray diagram, a ray from the object's tip through F reflects parallel, and another through C retraces. They meet 20 cm in front of the mirror. The image is:
AdvancedShow answer & explanation
real, 20 cm in front
Reflected rays ACTUALLY meeting in front of the mirror = a real image there.
Q149. Assertion: A convex mirror can never focus sunlight to burn paper. Reason: Its focus is virtual — rays never actually pass through it.
AdvancedShow answer & explanation
Both true, reason explains assertion
Diverged rays only appear to come from F behind the mirror; no real concentration of energy occurs.
Q150. A concave mirror of focal length 15 cm forms an image at infinity. The object distance is:
AdvancedShow answer & explanation
15 cm
Image at infinity ⇔ object exactly at the focus (15 cm).
Q151. Consider these statements about a concave mirror. I. It converges a parallel beam to a real focus in front of it. II. It forms a virtual image only when the object lies between the pole and the focus. III. Its focal length is negative in the New Cartesian convention. IV. It always forms a diminished image. Which statements are correct?
AdvancedShow answer & explanation
I, II and III only
I, II and III are correct. IV is false — a concave mirror magnifies whenever the object is nearer than the centre of curvature, and only diminishes beyond it.
Q152. An object is placed at four positions in front of a concave mirror of focal length 10 cm. Which row pairs the position with the image CORRECTLY?
AdvancedShow answer & explanation
u = 20 cm → real, inverted and the same size
20 cm is 2f, the centre of curvature, where the image returns the same size, real and inverted. At 5 cm the object is inside the focus, so the image is virtual and erect; at 15 cm and 30 cm it is real and inverted, magnified and diminished respectively.
Q153. A convex mirror gives a wider field of view than a plane mirror of the same size because:
AdvancedShow answer & explanation
its outward curve spreads the reflected rays, so light from a wider region can reach the eye
The curvature is doing the work. Each part of the surface faces a slightly different direction, so between them they gather light from a much wider cone than a flat surface of the same size.
Q154. Which of these ray rules for a concave mirror are correct? I. A ray through F reflects parallel to the principal axis. II. A ray through C retraces its own path. III. A ray parallel to the axis reflects through C. IV. A ray striking the pole reflects making equal angles with the axis. Which statements are correct?
AdvancedShow answer & explanation
I, II and IV only
I, II and IV are the true rules. III is the common slip: a ray parallel to the axis reflects through the FOCUS, not through the centre of curvature.
Q155. A concave mirror has a focal length of 12 cm. For the image to be real, inverted and exactly the same size as the object, the object must be placed:
AdvancedShow answer & explanation
24 cm from the mirror
An image of the same size is formed only when the object is at the centre of curvature, and R = 2f = 24 cm.
Q156. State what happens to the size and position of the image as an object approaches a convex mirror from far away.
AdvancedShow answer & explanation
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Q157. Explain, with the ray rules involved, (a) why the bulb of a torch is placed at the focus of its concave reflector, and (b) why a concave mirror is used by dentists. Draw the reasoning for both (describe the rays in words).
AdvancedShow answer & explanation
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Rule 2/reversibility for torch (1.5), parallel beam consequence (1), object-inside-F setup for dentist (1), virtual-erect-magnified outcome (1.5).
Q158. A concave mirror and a convex mirror each have a radius of curvature of 30 cm. An object is placed 10 cm in front of each mirror. Using the mirror tables (no formula needed), compare the two images formed.
AdvancedShow answer & explanation
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f = 15 cm from R = 2f (1), concave case identified as inside-F with correct nature (1.5), convex nature stated (1), explicit comparison of size and similarity (1.5).
Q159. u = −10 cm for a concave mirror of f = −15 cm. The image is:
AdvancedShow answer & explanation
virtual, behind, magnified
|u| < |f| → inside focus: 1/v = −1/15 + 1/10 = +1/30 → v = +30 cm, m = +3 — virtual, erect, 3× magnified.
Q160. For a convex mirror, which is IMPOSSIBLE?
AdvancedShow answer & explanation
v negative
A convex mirror never forms an image in front (v < 0 impossible) — its images are always virtual.
Q161. A concave mirror (f = −12 cm) must form a real image of magnification −2. The object distance is:
AdvancedShow answer & explanation
−18 cm
m = −v/u = −2 → v = 2u. Substituting: 1/(2u) + 1/u = −1/12 → 3/(2u) = −1/12 → u = −18 cm.
Q162. The image in a mirror is erect and exactly half the object's height. The mirror and m are:
AdvancedShow answer & explanation
convex, m = +1/2
Erect → +; half → 1/2; erect-diminished only happens in a convex mirror.
Q163. An object 2 cm tall gives a real image 6 cm tall at 45 cm from a concave mirror. The object distance is:
AdvancedShow answer & explanation
−15 cm
Real → v = −45, m = h′/h = −6/2 = −3 = −v/u → −3 = −(−45)/u → u = −15 cm.
Q164. Assertion: For mirrors, v and u of a real image are both negative. Reason: Real images form in front of the mirror, on the same side as the object.
AdvancedShow answer & explanation
Both true, reason explains assertion
Both quantities lie against the incident-light direction — both negative; the reason is the correct explanation.
Q165. A concave mirror of f = −10 cm forms an image on the object itself. The object distance is:
AdvancedShow answer & explanation
−20 cm
Image coincides with object only at C: u = 2f = −20 cm (and m = −1).
Q166. A concave mirror forms a REAL image. Which of these are true? I. The object distance u is negative. II. The image distance v is negative. III. The magnification m is negative. IV. The focal length f is positive. Which statements are correct?
AdvancedShow answer & explanation
I, II and III only
A real image forms in front of the mirror, so v is negative like u, and m = −v/u comes out negative. IV is wrong — a concave mirror's focus lies in front of it, so f is negative.
Q167. The magnification of a mirror is written m = −v/u rather than v/u because:
AdvancedShow answer & explanation
the minus sign makes m negative for a real inverted image and positive for a virtual erect one
Both u and v are negative for a real image, so v/u alone would be positive and would wrongly suggest an erect image. The minus sign is what makes the sign of m carry the nature of the image.
Q168. A concave mirror of focal length 20 cm forms an image 60 cm in front of it. The object distance is:
AdvancedShow answer & explanation
30 cm
With f = −20 cm and v = −60 cm, 1/u = 1/f − 1/v = −1/20 + 1/60 = −1/30, so u = −30 cm.
Q169. An object 3 cm tall stands 24 cm from a concave mirror of focal length 8 cm. The height of the image is:
AdvancedShow answer & explanation
1.5 cm
f = −8 cm, u = −24 cm give 1/v = −1/8 + 1/24 = −1/12, so v = −12 cm. m = −v/u = −0.5, so the image is 1.5 cm tall and inverted.
Q170. A concave mirror gives a virtual image twice the size of an object placed 5 cm in front of it. The focal length of the mirror is:
AdvancedShow answer & explanation
10 cm
A virtual erect image means m = +2, so +2 = −v/u = −v/(−5), giving v = +10 cm. Then 1/f = 1/v + 1/u = 1/10 − 1/5 = −1/10, so f = −10 cm — a focal length of 10 cm.
Q171. A convex mirror has a focal length of 15 cm. An object 30 cm in front of it forms an image at:
AdvancedShow answer & explanation
+10 cm
f = +15 cm and u = −30 cm give 1/v = 1/f − 1/u = 1/15 + 1/30 = 1/10, so v = +10 cm — 10 cm behind the mirror, virtual and erect.
Q172. A mirror produces a magnification of −2. Which statements are true? I. The image is real. II. The image is inverted. III. The image is twice as tall as the object. IV. The mirror is convex. Which statements are correct?
AdvancedShow answer & explanation
I, II and III only
A negative m means real and inverted, and the size 2 means twice as tall. IV is wrong — a convex mirror can never magnify, so only a concave mirror can give m = −2.
Q173. An object and its real image formed by a concave mirror are both 36 cm from the mirror. The focal length is:
AdvancedShow answer & explanation
18 cm
Object and image coincide only at the centre of curvature, so R = 36 cm and f = R/2 = 18 cm. The mirror formula agrees: 1/f = −1/36 − 1/36 = −1/18.
Q174. Four concave mirrors of focal length 10 cm, 15 cm, 20 cm and 25 cm each have an object placed 30 cm away. The image forms FURTHEST from the mirror for the one of focal length:
AdvancedShow answer & explanation
25 cm
The image distances work out as 15 cm, 30 cm, 60 cm and 150 cm. As the focal length approaches the object distance, the image runs away towards infinity — at f = 25 cm the object is closest to the focus.
Q175. A candle stands between the pole and the focus of a concave mirror. The mirror is moved slowly away until the candle is exactly at the focus. At that moment the image:
AdvancedShow answer & explanation
runs off to infinity and cannot be caught on a screen at all
At the focus 1/v = 1/f − 1/u = 0, so v is infinite. The reflected rays emerge parallel and never meet, which is why no screen anywhere catches an image.
Q176. A convex mirror of radius of curvature 24 cm has an object 12 cm in front of it. The magnification is:
AdvancedShow answer & explanation
+0.5
f = +12 cm and u = −12 cm give 1/v = 1/12 + 1/12 = 1/6, so v = +6 cm. m = −v/u = −6/(−12) = +0.5 — virtual, erect and half the size, as a convex mirror always gives.
Q177. A real image formed by a mirror always has a negative magnification because:
AdvancedShow answer & explanation
a real image forms on the same side as the object, so v and u are both negative and −v/u comes out negative
The sign follows straight from the convention, and it is what encodes the inversion: every real image formed by a mirror is inverted.
Q178. A concave mirror forms a real, inverted image. Which group lists quantities that are ALL negative?
AdvancedShow answer & explanation
u, v, f and m
For a real image from a concave mirror all four are negative. The object height is measured upwards from the axis and is positive, and a convex mirror's focal length is positive.
Q179. An object stands 15 cm from a concave mirror of focal length 10 cm, and the image is caught on a screen. The screen must be placed:
AdvancedShow answer & explanation
30 cm in front of the mirror
1/v = −1/10 + 1/15 = −1/30, so v = −30 cm. The negative sign puts the image in FRONT of the mirror, which is where a screen can catch it.
Q180. Can the magnification of a convex mirror ever exceed 1? Justify.
AdvancedShow answer & explanation
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Q181. A student gets v = +15 cm for a concave mirror problem. What kind of image is this, and what must have been true about the object's position?
AdvancedShow answer & explanation
—
Q182. An object 4 cm tall is placed 18 cm in front of a concave mirror of radius of curvature 24 cm. Find the position, size and nature of the image.
AdvancedShow answer & explanation
—
f from R with sign (1), correct substitution and v = −36 (1.5), m = −2 and h′ = −8 (1.5), full verbal interpretation + table consistency (1).
Q183. Explain the complete method of solving mirror numericals, and show why interpreting the SIGNS of v and m is as important as computing them, using u = −10 cm, f = −15 cm as your example.
AdvancedShow answer & explanation
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5-step method (2), correct v = +30 with sign meaning (1.5), m = +3 with meaning (1), explicit point that signs encode nature (0.5).
Q184. A convex mirror used on a bus has a radius of curvature of 3 m. A car is 5 m behind the bus. Find the position and nature of the car's image, and explain why such mirrors carry the warning 'objects in mirror are closer than they appear'.
AdvancedShow answer & explanation
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f = +1.5 (0.5), v ≈ +1.15 m with working (2), m ≈ +0.23 and nature (1.5), size-distance perception explanation (1).
Q185. Using the magnification formula alone, explain how you can identify which mirror formed an image, given only the value of m. Cover all the important ranges of m with one example situation each.
AdvancedShow answer & explanation
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plane m=+1 (1), convex 0
Q186. A pond appears 1.5 m deep. If n(water) = 4/3, its REAL depth is:
AdvancedShow answer & explanation
2.0 m
Apparent = real/n → real = 1.5 × 4/3 = 2.0 m.
Q187. Light's speed in medium A is 2 × 10⁸ m/s and in B is 2.5 × 10⁸ m/s. The refractive index of A with respect to B is:
AdvancedShow answer & explanation
1.25
n(A wrt B) = v_B/v_A = 2.5/2 = 1.25.
Q188. A ray hits a glass slab at i = 45° and refracts at r = 28°. When it exits the far side, the angle inside the glass at that surface is:
AdvancedShow answer & explanation
28°
The internal ray meets the parallel exit face at the same 28° (alternate angles) — then exits at 45°.
Q189. Assertion: The Sun is visible about two minutes before actual sunrise. Reason: Light bends away from the normal as it leaves the vacuum of space into denser air layers.
AdvancedShow answer & explanation
Assertion true, reason false
The effect is real, but entering DENSER air bends light TOWARDS the normal — curving rays around the horizon; the stated reason has the direction wrong.
Q190. Two slabs, A (thick, n = 1.4) and B (thin, n = 1.4), refract the same ray at the same angle. Compared to B, slab A produces:
AdvancedShow answer & explanation
greater lateral displacement
Displacement grows with thickness; parallelism holds for both.
Q191. Consider these statements about light passing from air into glass. I. The ray bends towards the normal. II. The speed of the light decreases. III. The frequency of the light changes. IV. A ray along the normal is not deviated at all. Which statements are correct?
AdvancedShow answer & explanation
I, II and IV only
I, II and IV are correct. III is the common slip — the frequency is set by the source and never changes on refraction; it is the speed and the wavelength that change.
Q192. A swimming pool always looks shallower than it really is because:
AdvancedShow answer & explanation
light from the bottom bends away from the normal on leaving the water, and the eye traces it back in a straight line to a higher point
The eye assumes light has travelled in a straight line all the way, so it locates the bottom along the emergent direction — above where the bottom really is.
Q193. Assertion (A): A rectangular glass slab does not split white light into colours. Reason (R): Its two refracting faces are inclined to each other, as the faces of a prism are.
AdvancedShow answer & explanation
A is true but R is false
They are parallel, and that is why the colours recombine. The assertion holds, the reason is false.
Q194. A ray enters a transparent medium with an angle of incidence of 60° and an angle of refraction of 30°. The refractive index of the medium is about:
AdvancedShow answer & explanation
1.73
n = sin 60° / sin 30° = 0.866/0.5 ≈ 1.73.
Q195. A tank of water of refractive index 4/3 is 2.4 m deep. To someone looking straight down into it, the water appears:
AdvancedShow answer & explanation
1.8 m deep
Apparent depth = real depth ÷ n = 2.4 ÷ (4/3) = 1.8 m. The bottom looks raised by 0.6 m.
Q196. A glass rod becomes almost invisible when it is dipped into a certain liquid. This tells us that:
AdvancedShow answer & explanation
the liquid and the glass have nearly the same refractive index, so almost no refraction happens at their boundary
We see the rod only because light bends and reflects at its surface. Match the refractive indices and there is nothing at the boundary to bend the light, so the rod stops being visible.
Q197. For a ray passing obliquely through a rectangular glass slab, consider these statements. I. The emergent ray is parallel to the incident ray. II. The lateral displacement grows as the slab is made thicker. III. The lateral displacement grows as the angle of incidence is increased. IV. The emergent ray lies along the same straight line as the incident ray. Which statements are correct?
AdvancedShow answer & explanation
I, II and III only
I, II and III are correct. IV contradicts I in practice — the emergent ray is parallel to the incident ray but shifted sideways, and that shift is the lateral displacement.
Q198. A student shines a laser straight down onto the surface of a beaker of water and is surprised that the beam does not bend. The correct explanation is that:
AdvancedShow answer & explanation
the beam strikes along the normal, so the angle of incidence is 0° and there is no change of direction
By Snell's law an angle of incidence of 0° gives an angle of refraction of 0°. The light does slow down in the water — only its direction is unaffected.
Q199. Light takes the same time to cover 3 m in vacuum as it does to cover x metres in a medium of refractive index 1.5. The value of x is:
AdvancedShow answer & explanation
2 m
The speed in the medium is c/1.5. In the time 3/c that light needs for 3 m in vacuum, it covers (c/1.5) × (3/c) = 2 m in the medium.
Q200. A coin lies at the bottom of an empty opaque mug, just out of sight over the rim. Water is poured in without moving the coin, and the coin becomes visible. This happens because:
AdvancedShow answer & explanation
light from the coin bends away from the normal at the water surface, so rays that would have missed the eye now reach it
This is the classic coin-and-bowl demonstration. Refraction at the surface redirects rays that were previously blocked by the rim, and the eye traces them back to an apparently raised coin.
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