Quadratic Basics: 17 flashcards

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1. What is the standard form of a quadratic equation in one variable?

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$ax^2 + bx + c = 0$, where $a \neq 0$ and $a, b, c$ are real numbers.

2. Which of the following is a quadratic equation? (i) $x^2 + 2x + 1 = 0$ (ii) $x^3 + x = 0$ (iii) $2x + 5 = 0$

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Only (i) is quadratic because its highest power of the variable is 2.

3. Define the root (or solution) of a quadratic equation.

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A root is a value of the variable that satisfies the equation, i.e., makes the left-hand side equal to zero.

4. How many roots does a quadratic equation have?

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A quadratic equation has at most two roots (real or complex).

5. What does it mean to factorize a quadratic expression like $x^2 + 5x + 6$?

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It means writing it as a product of two linear factors: $(x + 2)(x + 3)$.

6. Factorize: $x^2 - 5x + 6$.

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$(x - 2)(x - 3)$

7. Solve by factorization: $x^2 - 9 = 0$.

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$x = 3$ or $x = -3$ (since $(x - 3)(x + 3) = 0$).

8. What is the zero-product property used in solving quadratic equations by factorization?

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If $ab = 0$, then either $a = 0$ or $b = 0$ (or both).

9. Solve: $x^2 - 4x = 0$.

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$x = 0$ or $x = 4$ (factor out $x$: $x(x - 4) = 0$).

10. Write the quadratic equation whose roots are 2 and 3.

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$x^2 - 5x + 6 = 0$ (since $(x - 2)(x - 3) = 0$).

11. What is the condition for a quadratic equation to have real and equal roots?

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The discriminant $b^2 - 4ac = 0$.

12. For the equation $x^2 + 4x + 4 = 0$, find the discriminant and the nature of roots.

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Discriminant = $4^2 - 4(1)(4) = 0$, so roots are real and equal (both -2).

13. Solve by factorization: $2x^2 - 5x + 2 = 0$.

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$x = 2$ or $x = \frac{1}{2}$ (factor as $(2x - 1)(x - 2) = 0$).

14. What is the quadratic formula for solving $ax^2 + bx + c = 0$?

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$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

15. Using the quadratic formula, solve $x^2 - 2x - 3 = 0$.

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$x = 3$ or $x = -1$ (since $x = \frac{2 \pm \sqrt{4 + 12}}{2} = \frac{2 \pm 4}{2}$).

16. For a quadratic equation, what does the discriminant $b^2 - 4ac$ tell you?

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It indicates the nature of roots: positive → two distinct real roots, zero → one real repeated root, negative → no real roots (complex).

17. Find the value of $k$ for which $x^2 + kx + 9 = 0$ has real and equal roots.

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$k = \pm 6$ (since discriminant $k^2 - 36 = 0$).

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