Basic Electrical and Electronics Engineering: 18 MCQs with answers

All 18 multiple-choice questions from this kit, free and with no sign-up.

Warm-up · 7 questions

Q1. A student says 'the battery pushes current through the wire.' Which statement correctly distinguishes voltage from current?

Beginner
A Voltage is the cause (potential difference); current is the effect (flow of charge). B Current is the cause; voltage is the effect produced by it. C Voltage and current are the same physical quantity with different units. D Voltage flows through wires; current is stored in the battery.
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Voltage is the cause (potential difference); current is the effect (flow of charge).

Voltage is the potential difference that drives charge, while current is the actual rate of flow of charge. A 12 V battery with nothing connected has voltage but zero current.

Q2. Which of the following is the correct statement of Ohm's law for a conductor at constant temperature?

Beginner
A $V = I^2R$ B $V = IR$ C $V = R/I$ D $V = I/R$
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$V = IR$

Ohm's law states $V = IR$ at constant temperature. The other forms are algebraic rearrangements or unrelated expressions.

Q3. A 12 V battery is connected across a $4\ \Omega$ resistor. What current flows?

Beginner
A $3\ \text{A}$ B $16\ \text{A}$ C $48\ \text{A}$ D $0.33\ \text{A}$
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$3\ \text{A}$

Using $I = V/R = 12/4 = 3\ \text{A}$.

Q4. Which unit is used to measure electrical resistance?

Beginner
A Volt (V) B Ohm ($\Omega$) C Watt (W) D Ampere (A)
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Ohm ($\Omega$)

Resistance is measured in ohms ($\Omega$). Volts measure voltage, amperes measure current, and watts measure power.

Q5. In a series circuit containing three resistors, which quantity is the same through every component?

Beginner
A Voltage B Resistance C Current D Power
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Current

In a series circuit, the same current flows through every component; the voltage splits across them.

Q6. A diode is best described as which of the following?

Beginner
A A one-way valve for current B A component that stores charge C A resistor whose value changes with light D A device that steps up AC voltage
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A one-way valve for current

A diode conducts in one direction only, acting like a one-way valve. This property is used for rectification.

Q7. **Ohm's law** ($V = IR$) holds only when the temperature of the conductor is constant; filament bulbs and diodes violate it under normal operating conditions.

Beginner
A True B False
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True

**Ohm's law** ($V = IR$) holds only when the temperature of the conductor is constant; filament bulbs and diodes violate it under normal operating conditions.

Building up · 6 questions

Q8. A 60 W bulb is left on for 10 hours. How much energy does it consume?

Intermediate
A $0.6\ \text{kWh}$ B $600\ \text{kWh}$ C $60\ \text{kWh}$ D $6\ \text{kWh}$
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$0.6\ \text{kWh}$

Energy $E = Pt = 60\ \text{W} \times 10\ \text{h} = 600\ \text{Wh} = 0.6\ \text{kWh}$.

Q9. Two resistors, $6\ \Omega$ and $3\ \Omega$, are connected in parallel. What is the equivalent resistance?

Intermediate
A $2\ \Omega$ B $9\ \Omega$ C $18\ \Omega$ D $4.5\ \Omega$
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$2\ \Omega$

$\frac{1}{R_{eq}} = \frac{1}{6} + \frac{1}{3} = \frac{1}{2}$, so $R_{eq} = 2\ \Omega$.

Q10. A wire of length $L$ and area $A$ is replaced by another wire of the same material but twice the length and half the area. What happens to its resistance?

Intermediate
A It becomes twice the original value. B It becomes half the original value. C It becomes four times the original value. D It stays the same.
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It becomes four times the original value.

$R = \rho L / A$. Doubling $L$ doubles $R$; halving $A$ doubles $R$ again. Combined effect: $R$ becomes $4\times$.

Q11. Why is house wiring done in parallel rather than series?

Intermediate
A So the fuse can be placed in any branch. B So each appliance gets the full supply voltage and can be switched independently. C So the current through every appliance is the same. D So the total resistance of the circuit increases.
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So each appliance gets the full supply voltage and can be switched independently.

Parallel connection gives each appliance the full supply voltage and allows independent switching. In series, one failed component breaks the whole circuit.

Q12. A p-n junction diode is forward biased when:

Intermediate
A The diode is connected in reverse across the supply. B The positive terminal of the supply is connected to the p-side. C The positive terminal of the supply is connected to the n-side. D No external voltage is applied across it.
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The positive terminal of the supply is connected to the p-side.

Forward bias means the p-side is connected to the positive terminal and the n-side to the negative terminal, allowing current to flow.

Q13. A fuse blows in a circuit. Which physical effect of current is directly responsible?

Intermediate
A Chemical effect, since the wire reacts with air. B Magnetic effect, since the current creates a field. C Heating effect, since $P = I^2R$ melts the fuse wire. D Electrostatic effect, since charge builds up.
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Heating effect, since $P = I^2R$ melts the fuse wire.

A fuse relies on the heating effect of current. When current exceeds a safe value, $P = I^2R$ generates enough heat to melt the fuse wire.

Topper level · 5 questions

Q14. A filament bulb's resistance when cold is roughly one-tenth of its resistance when glowing. What is the main reason?

Advanced
A Ohm's law fails for all conductors when they heat up. B The filament's length changes significantly when hot. C The bulb's supply voltage drops when it is switched on. D For metals, resistance increases with temperature, so the hot filament has higher resistance.
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For metals, resistance increases with temperature, so the hot filament has higher resistance.

Ohm's law holds only at constant temperature. For most metals, resistance rises with temperature, so the glowing filament has much higher resistance than the cold one.

Q15. A bridge rectifier uses four diodes instead of one. What is the practical advantage?

Advanced
A It rectifies both halves of the AC cycle, giving full-wave output. B It converts DC back into AC for transmission. C It steps up the AC voltage before rectification. D It eliminates the need for a transformer in the circuit.
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It rectifies both halves of the AC cycle, giving full-wave output.

A single diode gives half-wave rectification (one half of the cycle is blocked). Four diodes in a bridge configuration rectify both halves, producing full-wave DC.

Q16. A transistor has a small base current controlling a much larger collector current. Which application does this property directly enable?

Advanced
A Storage of electrical energy B Rectification of AC to DC C Amplification of weak signals D Stepping up of AC voltage
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Amplification of weak signals

A small base current controlling a large collector current is the principle of amplification. Rectification is done by diodes; voltage stepping is done by transformers.

Q17. A circuit consists of a 12 V battery connected to a resistor of unknown resistance, and the current flowing through the circuit is measured to be 3 A. If the resistance is doubled, what will be the new current flowing through the circuit when the same voltage is applied?

Advanced
A 12 A B 1.5 A C 3 A D 6 A
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1.5 A

Using Ohm's law, the initial resistance can be calculated as $R = \frac{V}{I} = \frac{12 V}{3 A} = 4 \Omega$. If the resistance is doubled, the new resistance becomes $8 \Omega$. The new current can be calculated as $I = \frac{V}{R} = \frac{12 V}{8 \Omega} = 1.5 A$.

Q18. In a parallel circuit with three resistors of values $R_1 = 4 \Omega$, $R_2 = 6 \Omega$, and $R_3 = 12 \Omega$, what is the total equivalent resistance of the circuit?

Advanced
A 2 \Omega B 3 \Omega C 6 \Omega D 4 \Omega
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3 \Omega

The equivalent resistance for resistors in parallel is given by the formula: $$\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$$. Substituting the values, we get: $$\frac{1}{R_{eq}} = \frac{1}{4} + \frac{1}{6} + \frac{1}{12} = \frac{3}{12} + \frac{2}{12} + \frac{1}{12} = \frac{6}{12} = \frac{1}{2}$$. T…

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