Circles · Class 10 Mathematics: 114 MCQs with answers
All 114 multiple-choice questions from this kit, free and with no sign-up.
Warm-up · 21 questions
Q1. A line meeting a circle at two points is called a
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secant
It cuts through.
Q2. A line meeting a circle at exactly one point is called a
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tangent
It touches.
Q3. The single point a tangent shares with its circle is the
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point of contact
That is its name.
Q4. The greatest number of points a straight line can share with a circle is
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two
A secant is the extreme case.
Q5. The part of a secant lying inside the circle is a
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chord
It joins the two crossing points.
Q6. The tangent at a point of a circle is perpendicular to
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the radius through the point of contact
Theorem 1.
Q7. The right angle in a tangent figure is marked at the
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point of contact
Where the tangent touches.
Q8. A point 10 cm from the centre of a circle of radius 6 cm has a tangent of length
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8 cm
$\sqrt{100-36} = 8$.
Q9. How many tangents can be drawn through a point INSIDE a circle?
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none
Every line through it must leave the circle on both sides.
Q10. The single tangent at a point of a circle is the line through that point perpendicular to
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the radius drawn to it
The line perpendicular to the radius there.
Q11. Two tangents can be drawn to a circle from a point whose distance from the centre is
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greater than the radius
One on each side.
Q12. A tangent touches a circle at $P$ and the centre is $O$. The angle $\angle OPT$, with $T$ on the tangent, is
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90°
Theorem 1 gives it directly.
Q13. The word 'tangent' comes from a Latin verb meaning
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to touch
Tangere — the same root as 'tangible'.
Q14. A wheel resting on flat ground touches it along
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a tangent
One point of contact.
Q15. Distinguish between a secant and a tangent, and name the special point in each case.
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Q16. State Theorem 1 of this chapter precisely.
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Q17. Drawing two tangents to a circle from a single outside point, their lengths turn out to be
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equal
Theorem 2.
Q18. A circle of radius 20 cm has an external point 29 cm away. Each tangent length is
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21 cm
$\sqrt{841-400} = 21$.
Q19. If $PA$ and $PB$ are tangents from $P$ and $PA = 9$ cm, then $PB$ is
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9 cm
Theorem 2 makes them equal.
Q20. A circle touches all three sides of a triangle. That circle is called the
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incircle
It sits inside, touching each side.
Q21. State Theorem 2 of this chapter and name the congruence criterion used to prove it.
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Building up · 40 questions
Q22. In the proof of Theorem 1, every point of the tangent other than the point of contact lies
IntermediateShow answer & explanation
outside the circle
Otherwise the line would meet the circle more than once.
Q23. The proof concludes that $OP$ is perpendicular because
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the shortest distance from a point to a line is the perpendicular one
$OP$ was shown to be the shortest such distance.
Q24. In triangle $OAP$, where $PA$ is a tangent touching at $A$, the hypotenuse is
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$OP$
It faces the right angle at $A$.
Q25. The length of a tangent from a point at distance $d$ to a circle of radius $r$ is
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$\sqrt{d^2 - r^2}$
Pythagoras in the right triangle.
Q26. A point is 13 cm from the centre of a circle of radius 5 cm. The tangent length is
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12 cm
$\sqrt{169-25} = 12$.
Q27. A tangent 24 cm long is drawn to a circle of radius 7 cm. The point is
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25 cm from the centre
$\sqrt{49+576} = 25$.
Q28. A circle of radius 8 cm has a tangent of length 15 cm from a point. That point is
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17 cm from the centre
$\sqrt{64+225} = 17$.
Q29. The tangents at the two ends of a diameter are
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parallel
Both are perpendicular to the same straight line.
Q30. Which fact makes those two tangents parallel?
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two lines perpendicular to the same line are parallel
It is the standard parallel-lines result.
Q31. Assertion (A): The radius drawn to the point of contact is the shortest segment from the centre to the tangent line. Reason (R): The shortest distance from a point to a line is measured along the perpendicular.
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Both A and R are true, and R is the correct explanation of A
Theorem 1 says that radius IS the perpendicular, so R explains A exactly.
Q32. The converse of Theorem 1 states that a line through a point of a circle is a tangent if it is
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perpendicular to the radius at that point
That is how you prove a line is a tangent.
Q33. The 'length of the tangent' from a point means the distance from that point to
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the point of contact
The line itself is infinite; only this segment has a length.
Q34. Marking the right angle at the CENTRE instead of the point of contact would
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make the whole solution wrong
It changes which side is the hypotenuse.
Q35. A line drawn through a point inside a circle must be
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a secant
It has to leave the circle on both sides.
Q36. In a tangent figure, which theorem allows Pythagoras to be used at all?
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the tangent is perpendicular to the radius
Pythagoras needs a right angle, and Theorem 1 supplies it.
Q37. If a line is at a distance from the centre EQUAL to the radius, the line is
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a tangent
Exactly one point of it is at distance $r$.
Q38. A circle has radius 6 cm and a straight line runs 7 cm from its centre. Their number of common points is
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zero
Every point of it is further than $r$.
Q39. If a line is at a distance from the centre LESS than the radius, it is
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a secant
It cuts the circle twice.
Q40. A point is 17 cm from the centre of a circle of radius 8 cm. Find the length of the tangent from that point.
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Q41. A tangent of length 12 cm is drawn to a circle of radius 5 cm. How far is the external point from the centre?
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Q42. State how many tangents can be drawn to a circle through a point in each of the three possible positions, with a reason for each.
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Q43. Explain why the line from the centre to an external point, and not the radius, is the hypotenuse of the tangent triangle.
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Q44. State the converse of Theorem 1 and say when it is used.
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Q45. The congruence criterion used to prove Theorem 2 is
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RHS
Two right triangles with equal hypotenuses and one equal leg.
Q46. In that proof, the equal legs of the two right triangles are
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the two radii
$OA = OB$, radii of the same circle.
Q47. In that proof, the common hypotenuse is
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$OP$
It belongs to both triangles.
Q48. The right angles used in the proof come from
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Theorem 1
The tangent is perpendicular to the radius at the point of contact.
Q49. The step that turns the congruence into $PA = PB$ is
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CPCT
Corresponding parts of congruent triangles are equal.
Q50. The segment $OP$ bisects
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both the angle between the tangents and the angle between the radii
Both follow by CPCT from the same congruence.
Q51. A circle of radius 7 cm has an external point 25 cm from its centre. Each tangent length is
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24 cm
$\sqrt{625-49} = 24$.
Q52. In a quadrilateral $ABCD$ circumscribing a circle, which equation holds?
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$AB + CD = BC + DA$
Opposite sides have equal sums.
Q53. A triangle has sides 14, 10 and 12 cm. Its semiperimeter is
IntermediateShow answer & explanation
18 cm
Half of $14+10+12 = 36$.
Q54. Assertion (A): The tangents drawn from an external point to a circle are equal in length. Reason (R): The two right triangles formed are congruent by RHS, having equal radii and a common hypotenuse.
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Both A and R are true, and R is the correct explanation of A
R sets out exactly the congruence from which A follows by CPCT.
Q55. The first practical step in a tangent-figure question is to
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give equal tangent lengths from each vertex the same letter
The labelling is what turns the figure into equations.
Q56. The two tangents from an external point, together with the chord of contact, form a triangle that is always
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isosceles
The two tangents are equal.
Q57. A circle of radius 9 cm has tangents of length 12 cm from a point. That point is
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15 cm from the centre
$\sqrt{81+144} = 15$.
Q58. In the kite $OAPB$, the two right angles are at
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$A$ and $B$
They are the points of contact.
Q59. Name three results, besides $PA = PB$, that follow from the same congruence.
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Q60. A circle has radius 7 cm and a point $P$ lies 25 cm from its centre. Find the length of each tangent from $P$.
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Q61. A quadrilateral circumscribes a circle. Three consecutive sides are 6 cm, 7 cm and 4 cm. Find the fourth side.
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Topper level · 53 questions
Q62. Assertion (A): A tangent can be drawn to a circle from any point of the plane. Reason (R): A point outside a circle has exactly two tangents through it.
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Both A and R are true, but R is not the correct explanation of A
R is true, but A is false — a point inside the circle has no tangent at all.
Q63. To PROVE that a given line touching a circle at $P$ is a tangent, you would use
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the converse of Theorem 1
The theorem uses tangency; the converse establishes it.
Q64. A tangent is best described as the limiting position of
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a secant whose two points of intersection coincide
Slide the secant outwards until the two points merge.
Q65. Which point of a tangent line is nearest to the centre of the circle?
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the point of contact
The perpendicular distance is the shortest, and it lands at the contact point.
Q66. A circle has radius 9 cm. A tangent is drawn from a point 41 cm from the centre. Its length is
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40 cm
$\sqrt{1681 - 81} = 40$.
Q67. If the radius is 5 cm and a point is 5 cm from the centre, the tangent length from it is
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0, since the point lies on the circle
The point of contact IS the point, so the distance between them is zero.
Q68. Can a tangent be drawn from a point 3 cm from the centre of a circle of radius 5 cm?
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no, the point is inside the circle
$3 < 5$, so the point is inside.
Q69. Two circles of the same centre are drawn. A tangent to the smaller one is, for the larger one,
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a secant
Its distance from the centre equals the smaller radius, which is less than the larger.
Q70. A ball whirled on a string flies off, when released, along
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the tangent at that point
Its velocity at that instant points along the tangent.
Q71. Assertion (A): A line meeting a circle at exactly one point is perpendicular to the radius at that point. Reason (R): Every other point of such a line lies inside the circle.
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A is true but R is false
The other points lie outside the circle, which is what makes the contact point the nearest one. The assertion holds, the reason is false.
Q72. Assertion (A): The radius is the hypotenuse of the right triangle formed by a tangent, the radius and the line to an external point. Reason (R): The right angle in that triangle is at the point of contact.
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A is false but R is true
R is true, and it is exactly why A is false — the hypotenuse faces the right angle, so it is the line from the centre to the external point.
Q73. Prove that the tangent meets the radius at its point of contact squarely, at 90°.
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Q74. Prove that the two tangents drawn where a diameter meets the circle run parallel.
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Q75. A line lies at a distance $p$ from the centre of a circle of radius $r$. Describe the three cases.
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Q76. (a) Explain, with reasons, the three ways in which a line and a circle can be related. (b) Prove that the tangent meets the radius at its point of contact squarely, at 90°. (c) Explain which step of your proof would fail if the line were a secant instead.
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Q77. (a) Explain how Theorem 1 makes Pythagoras' theorem available in circle problems, naming the right angle and the hypotenuse. (b) A point $P$ is 25 cm from the centre $O$ of a circle of radius 7 cm, and $PA$ is a tangent touching at $A$. Find $PA$. (c) A second circle, concentric with the first, has radius 24 cm. Show that $PA$ is itself the radius of a circle centred at $P$ that touches the first circle, and state the connection with (b).
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Q78. (a) State and prove that the tangents at the ends of a diameter are parallel. (b) State the converse of Theorem 1. (c) A line $l$ meets a circle of centre $O$ at a single point $T$, and it is given that $\angle OTl = 90°$. Explain which result is being used and what may be concluded.
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Q79. (a) Describe how many tangents pass through a point in each position relative to a circle, justifying each count. (b) A circle has radius 6 cm. Decide, with reasons, how many tangents pass through a point 4 cm from the centre, and how many through a point 10 cm from the centre, giving the tangent length where one exists. (c) Explain what happens to the tangent length as the external point moves towards the circle.
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Q80. The quadrilateral $OAPB$ formed by the two radii and the two tangents is a
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kite
$OA = OB$ and $PA = PB$, in adjacent pairs.
Q81. $OP$ is, with respect to the chord of contact $AB$,
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its perpendicular bisector
It is the axis of symmetry of the kite $OAPB$.
Q82. That quadrilateral result is proved by applying Theorem 2
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once at each of the four vertices
Each vertex is an external point.
Q83. A quadrilateral circumscribes a circle and three of its sides are 6, 7 and 4 cm in that order. The fourth side is
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3 cm
$6 + 4 = 7 + x$ gives $x = 3$.
Q84. A parallelogram circumscribing a circle must be a
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rhombus
Equal opposite sides plus equal opposite sums force all four to be equal.
Q85. Can a rectangle measuring 3 cm by 5 cm circumscribe a circle?
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no, because $3+3 \ne 5+5$
The opposite-sides condition fails.
Q86. For a triangle with sides $a$, $b$, $c$ and semiperimeter $s$, the incircle tangent length from the vertex opposite $a$ is
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$s - a$
Subtract the opposite side from the semiperimeter.
Q87. For that triangle, the tangent length from the vertex opposite the 14 cm side is
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4 cm
$s - a = 18 - 14 = 4$.
Q88. Assertion (A): Theorem 2 can be proved using the SSS criterion. Reason (R): The two triangles share the segment $OP$ and have equal radii.
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A is true but R is false
R is true but A is false: only two pairs of sides are known equal at the start, so SSS is unavailable and RHS is required.
Q89. The angle at the external point and the angle between the two radii are
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supplementary
The kite has two right angles, leaving $180°$ for the other two.
Q90. If two tangents from an external point meet at 70°, the angle between the radii is
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110°
$180° - 70°$.
Q91. If two tangents from an external point meet at 60°, the triangle formed by the two tangents and the chord of contact is
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equilateral
$PA = PB$ makes it isosceles, and a 60° apex forces the base angles to 60° too.
Q92. A quadrilateral circumscribes a circle with sides 8, 9, 10 in order. The fourth side is
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9 cm
$8 + 10 = 9 + x$ gives $x = 9$.
Q93. A triangle with sides 5, 12 and 13 cm has incircle tangent lengths
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10, 3 and 2 cm
$s = 15$, so $15-5 = 10$, $15-12 = 3$, $15-13 = 2$.
Q94. The three incircle tangent lengths of a triangle always add up to
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the semiperimeter
$x + y + z = s$, which is how the formulas are derived.
Q95. Two tangents from $P$ touch a circle at $A$ and $B$. If $\angle APB = 90°$ and the radius is 5 cm, then $PA$ is
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5 cm
$OAPB$ then has four right angles and $OA = PA$, so it is a square of side 5.
Q96. Which fact is NOT a consequence of the congruence in Theorem 2's proof?
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the tangents are perpendicular to each other
The angle between the tangents depends on how far $P$ is from the centre.
Q97. As the external point moves further from the circle, the angle between the two tangents
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gets smaller
From very far away the two tangents are almost parallel.
Q98. Every triangle has an incircle, but a quadrilateral has one only if
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the sums of its opposite sides are equal
That is the tangential condition.
Q99. The point where the two tangents meet lies on
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the perpendicular bisector of the chord of contact
$OP$ is that perpendicular bisector, and $P$ is on it.
Q100. Which theorem supplies the right angles in the circumscribing-quadrilateral proof?
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neither — only Theorem 2 is needed
That proof adds four tangent-length equalities and never uses a right angle.
Q101. In a tangential quadrilateral with sides 12, 15, 18 in order, the fourth side is
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15 cm
$12 + 18 = 15 + x$ gives $x = 15$.
Q102. Assertion (A): A rectangle that is not a square can still have a circle touching all four of its sides. Reason (R): In a quadrilateral circumscribing a circle the sums of opposite sides are equal.
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A is false but R is true
Its opposite sides give unequal sums, so no such circle exists and the assertion is false. The reason states the condition.
Q103. Assertion (A): In the figure of two tangents from an external point, the chord of contact is bisected by $OP$. Reason (R): $OAPB$ is a square, and the diagonals of a square bisect each other.
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A is true but R is false
$OAPB$ is a kite, not a square - two sides are radii and two are tangents. The assertion stands, the reason is false.
Q104. A circle of radius 6 cm has an external point 10 cm from its centre. The total length of both tangents together is
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16 cm
Each is $\sqrt{100-36} = 8$, and there are two of them.
Q105. Prove that the two tangents drawn to a circle from one outside point have equal length.
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Q106. Prove that in a quadrilateral $ABCD$ circumscribing a circle, $AB + CD = BC + DA$.
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Q107. Prove that a parallelogram circumscribing a circle is a rhombus.
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Q108. A triangle has sides 14 cm, 10 cm and 12 cm. Find the three tangent lengths of its incircle.
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Q109. Explain why the angle between two tangents from an external point and the angle between the corresponding radii are supplementary.
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Q110. Why can Theorem 2 not be proved by the SAS criterion?
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Q111. (a) Prove that the two tangents drawn to a circle from one outside point have equal length. (b) List the other results that follow from the same congruence. (c) A circle of radius 9 cm has an external point 41 cm from its centre. Find each tangent length, and state the angle between each tangent and its radius.
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Q112. (a) Prove that a quadrilateral circumscribing a circle has equal sums of opposite sides. (b) Use it to prove that a parallelogram circumscribing a circle is a rhombus. (c) A quadrilateral circumscribes a circle and has consecutive sides 8 cm, 9 cm and 10 cm. Find the fourth side, and decide whether a 3 cm by 5 cm rectangle could circumscribe a circle.
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Q113. (a) Derive the formulas for the three tangent lengths of a triangle's incircle. (b) Apply them to a triangle with sides 13 cm, 14 cm and 15 cm. (c) Explain how to check your three answers.
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Q114. (a) Explain why the angle at the external point and the angle at the centre are supplementary. (b) Two tangents are drawn from a point $P$ to a circle of centre $O$ and radius 5 cm, and they meet at 90°. Find the tangent length and the distance $OP$. (c) Describe what happens to the angle between the tangents as $P$ moves further from the circle, and why.
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