Triangles · Class 10 Mathematics: 171 MCQs with answers
All 171 multiple-choice questions from this kit, free and with no sign-up.
Warm-up · 52 questions
Q1. Two figures are similar when they have
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the same shape, whatever their size
Similarity is about shape alone.
Q2. Two figures are congruent when they have
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the same shape and the same size
Congruence is the stricter idea.
Q3. Which statement is true?
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all congruent figures are similar
Congruence is similarity with scale factor 1; the converse fails.
Q4. The symbol $\sim$ means
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is similar to
Congruence uses a different symbol.
Q5. Any two circles are
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similar
A circle's shape is completely fixed.
Q6. Any two squares are
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similar
All squares have the same shape.
Q7. Any two equilateral triangles are
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similar
All their angles are 60°, and all sides are in one ratio.
Q8. For two polygons to be similar, their corresponding angles must be
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equal
Angles must match exactly; it is the SIDES that are in a ratio.
Q9. Which quantity is compared by a RATIO in the definition of similar polygons?
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the sides
Angles must be equal; it is the sides that share a common ratio.
Q10. The common ratio of corresponding sides is called the
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scale factor
It is one number for the whole figure.
Q11. A scale factor of 1 means the figures are
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congruent
Every side equals its match, so the sizes agree too.
Q12. Assertion (A): Every square is similar to every other square. Reason (R): Every angle of a square is a right angle.
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Both A and R are true, but R is not the correct explanation of A
Both are true, but equal angles alone do not give similarity; the sides must be in one ratio as well, which for squares they always are.
Q13. Similarity compares two figures' shapes; congruence compares
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their shapes and their sizes
Congruent figures must match in size as well as shape.
Q14. A figure and its enlargement are
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similar but not congruent
The shape is unchanged but the size is not.
Q15. Explain the difference between similar figures and congruent figures.
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Q16. State the two conditions for two polygons of the same number of sides to be similar.
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Q17. The Basic Proportionality Theorem says that a line parallel to one side of a triangle
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divides the other two sides in the same ratio
Equal ratios, not equal halves — unless the ratio happens to be 1 : 1.
Q18. The BPT is also known as
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Thales' Theorem
Thales is said to have used it on a pyramid's shadow.
Q19. If $DE \parallel BC$ in $\triangle ABC$, then
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$\frac{AD}{DB} = \frac{AE}{EC}$
Both fractions take the piece nearer A on top.
Q20. The part-over-whole form of the BPT is
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$\frac{AD}{AB} = \frac{AE}{AC}$
Both fractions use a part over its whole side.
Q21. In the BPT proof, the construction is to
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join BE and CD, and draw $DM \perp AC$, $EN \perp AB$
The perpendiculars supply the heights for the areas.
Q22. When proving the BPT, the area of a triangle is written as
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$\frac12 \times \text{base} \times \text{height}$
Halving the product of base and height.
Q23. Triangles on the same base and between the same parallels are equal in
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area
This Class IX fact is the key step of the proof.
Q24. Which two areas are equal in the proof of the BPT?
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$ar(DEC)$
Both stand on DE between the parallels DE and BC.
Q25. The converse of the BPT says that if a line divides two sides in the same ratio, then it is
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parallel to the third side
The converse is what proves parallelism.
Q26. In the statement of the BPT, the line must cut the other two sides in
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distinct points
A line through a vertex divides nothing.
Q27. In a triangle with a line parallel to BC, $AD = 2$, $DB = 4$ and $AE = 3$. Then EC is
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6
$\frac24 = \frac3{EC}$ gives $2 \cdot EC = 12$.
Q28. Assertion (A): The BPT proof does not use similar triangles. Reason (R): The similarity criteria are themselves proved using the BPT.
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Both A and R are true, and R is the correct explanation of A
Using similarity in the proof would make the argument circular, which is exactly R's point.
Q29. Which theorem number is the Basic Proportionality Theorem in the textbook?
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Theorem 6.1
Theorem 6.2 is its converse; 6.3 onwards are the similarity criteria.
Q30. A parallel line gives $AD = 6$, $DB = 9$ and $AE = 8$. Then EC is
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12
$\frac69 = \frac8{EC}$ gives $6 \cdot EC = 72$.
Q31. The heights EN and DM exist in the proof in order to
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write the areas of the triangles
Area needs a height, and these two supply it.
Q32. State the Basic Proportionality Theorem.
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Q33. State the converse of the Basic Proportionality Theorem.
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Q34. The AA similarity criterion requires
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two pairs of equal angles
The third angle pair then follows from the angle sum.
Q35. The SSS similarity criterion requires
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all three pairs of sides in the same ratio
Proportional, not equal — equal sides would give congruence.
Q36. The SAS similarity criterion requires the equal angle to be
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included between the two proportional sides
The letters S-A-S record the order side, angle, side.
Q37. Two angles of one triangle equal two angles of another. The triangles are
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similar
This is exactly the AA criterion.
Q38. Why does knowing two pairs of equal angles settle the third?
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the angles of a triangle add to 180°
Subtracting the two known angles from 180° gives the same value in both triangles.
Q39. If $\angle A = \angle P = 50°$ and $\angle B = \angle Q = 60°$, then $\angle C$ equals
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70°
$180 - 50 - 60 = 70$.
Q40. Triangles with sides $3, 4, 5$ and $6, 8, 10$ are
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similar by SSS
Every ratio is $\frac12$.
Q41. In $\triangle ABC \sim \triangle PQR$, the angle equal to $\angle B$ is
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$\angle Q$
B is the second letter and Q is the second letter.
Q42. In $\triangle ABC \sim \triangle PQR$, the side corresponding to $CA$ is
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$RP$
C matches R and A matches P.
Q43. Similar triangles have sides that are
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in the same ratio
Equal sides would make them congruent.
Q44. The similarity criteria are proved from
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the Basic Proportionality Theorem
That is why the BPT comes first in the chapter.
Q45. Assertion (A): The AAA and AA criteria say effectively the same thing. Reason (R): Once two pairs of angles match, the third pair must match because the angles of a triangle sum to 180°.
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Both A and R are true, and R is the correct explanation of A
The third angle carries no new information, exactly as R states.
Q46. Which letters name the criterion that uses one angle and two sides?
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SAS
Side, angle, side — with the angle between the two sides.
Q47. In similar triangles, corresponding angles are
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equal
It is the SIDES that are in a ratio, never the angles.
Q48. Triangles with sides $9, 12, 15$ and $15, 20, 25$ are
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similar by SSS
Every ratio is $\frac35$.
Q49. Assertion (A): Two triangles with three pairs of equal angles must have proportional sides. Reason (R): This is exactly what the AAA similarity criterion states.
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Both A and R are true, and R is the correct explanation of A
Theorem 6.3 says equal angles force the sides into one ratio, which is R's point.
Q50. State the AA similarity criterion, and explain why two pairs of angles are enough.
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Q51. State the SSS similarity criterion.
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Q52. Determine whether triangles with sides 3, 4, 5 cm and 6, 8, 10 cm are similar, showing your working.
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Building up · 69 questions
Q53. A square and a rectangle 4 by 7 are NOT similar because
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their sides are not in the same ratio
All angles are 90° in both, but $\frac44 \ne \frac47$.
Q54. A square and a rhombus of the same side length are NOT similar because
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their angles are not equal
Every side ratio is 1, but the rhombus's angles are not 90°.
Q55. Are all rectangles similar?
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no — their side ratios can differ
A 2 × 3 and a 2 × 9 rectangle have equal angles but different shapes.
Q56. In $ABCD \sim PQRS$, the side $BC$ corresponds to
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$QR$
B matches Q and C matches R, so BC matches QR.
Q57. In $ABCD \sim PQRS$, the angle equal to $\angle C$ is
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$\angle R$
C is the third letter and R is the third letter.
Q58. If $\triangle ABC \sim \triangle PQR$ with $AB = 6$, $PQ = 9$ and $BC = 8$, then $QR$ is
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12
$\frac69 = \frac8{QR}$ gives $6 \cdot QR = 72$.
Q59. Two similar quadrilaterals have sides $4, 6, 8, 10$ and $6, 9, 12, x$. The value of x is
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15
The scale factor is $\frac23$, so $\frac{10}{x} = \frac23$.
Q60. Two similar polygons have a scale factor of 3. Each side of the first is
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three times its match in the second
The scale factor multiplies every length of the second figure.
Q61. Which pair of figures is definitely similar?
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two equilateral triangles
Only the equilateral triangle has its shape completely determined.
Q62. If two polygons have equal corresponding angles but different side ratios, they are
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not similar
Both conditions are required.
Q63. Two figures with the same shape but different sizes are
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similar but not congruent
Different sizes rule out congruence, but the shape is unchanged.
Q64. Assertion (A): All rectangles are similar. Reason (R): All rectangles have four right angles.
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A is false but R is true
A is false — the side ratios can differ — while R is a true statement about rectangles.
Q65. Assertion (A): Two polygons whose corresponding sides are in the same ratio must be similar. Reason (R): Similarity of polygons requires equal angles as well as proportional sides.
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A is false but R is true
A is false — a square and a rhombus are the counterexample — and R names the missing condition.
Q66. In $ABCD \sim PQRS$, the side that corresponds to $DA$ is
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$SP$
D matches S and A matches P.
Q67. Two similar triangles have sides in the ratio 3 : 7. The larger triangle's side matching a side of 12 is
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28
$\frac{12}{x} = \frac37$ gives $3x = 84$.
Q68. A scale drawing of 1 : 500 means 1 cm on the drawing represents
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500 cm on the ground
The scale factor multiplies the drawing's lengths to give the real ones.
Q69. Which is NOT required for two polygons to be similar?
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equal areas
Equal areas would force the figures to be congruent, which similarity does not demand.
Q70. Show, with an example, that equal angles alone do not make two polygons similar.
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Q71. Show, with an example, that proportional sides alone do not make two polygons similar.
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Q72. Are all rectangles similar? Justify your answer.
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Q73. $\triangle ABC \sim \triangle PQR$ with $AB = 6$ cm, $PQ = 9$ cm and $BC = 8$ cm. Find $QR$.
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Q74. Two similar quadrilaterals have sides 4, 6, 8, 10 and 6, 9, 12, x. Find the scale factor and x.
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Q75. Explain why the order of the letters in $ABCD \sim PQRS$ matters.
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Q76. (a) Define similar figures, and state the relationship between similarity and congruence. (b) State the two conditions for two polygons to be similar. (c) Show by a separate example that each condition on its own is insufficient.
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1½ marks — (a) the definition and the congruence relationship. 1½ marks — (b) both conditions. 2 marks — (c) one valid counterexample for each condition.
Q77. (a) Explain what the correspondence $\triangle ABC \sim \triangle PQR$ tells you, listing the equal angles and the equal ratios. (b) Given $AB = 5$ cm, $BC = 7$ cm, $CA = 9$ cm and $PQ = 10$ cm, find $QR$ and $RP$. (c) State whether the two triangles could ever be congruent, and under what condition.
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2 marks — (a) all three angle pairs and the ratio statement. 2 marks — (b) both sides. 1 mark — (c) the scale-factor-1 condition.
Q78. A parallel line gives $AD = 4$ cm, $DB = 6$ cm and $AE = 6$ cm. Then EC is
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9 cm
$\frac46 = \frac6{EC}$ gives $4 \cdot EC = 36$.
Q79. In $\triangle ABC$, $AD = 3$, $DB = 5$, $AE = 6$ and $EC = 10$. Then $DE$ is
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parallel to BC, by the converse of the BPT
$\frac35 = \frac6{10}$, so the ratios match.
Q80. In $\triangle ABC$, $AD = 2$, $DB = 3$, $AE = 4$ and $EC = 5$. Then $DE$ is
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not parallel to BC
$\frac23 \ne \frac45$, so the converse does not apply.
Q81. Which is a valid way to write the BPT?
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$\frac{AD}{AB} = \frac{AE}{AC}$
Only the first keeps the same form — part over whole — on both sides.
Q82. To prove that a line is parallel to a side, you should use
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the converse of the BPT
Using the BPT would assume what is to be proved.
Q83. With a parallel line, $AD = 4$, $AB = 10$ and $AE = 6$. Then AC is
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15
Using the part-over-whole form: $\frac{4}{10} = \frac{6}{AC}$, so $4 \cdot AC = 60$.
Q84. Given a parallel line with $AD = 4$, $DB = 6$ and $AE = 6$, the length AC is
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15
$EC = 9$ from the BPT, and $AC = AE + EC = 6 + 9$.
Q85. The ratio $\frac{ar(ADE)}{ar(BDE)}$ simplifies to $\frac{AD}{DB}$ because
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the two triangles share the height EN
The common height and the $\frac12$ cancel from the ratio.
Q86. A line through a vertex of a triangle
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is not covered by the BPT, which needs distinct points on two sides
It meets only one of the other two sides, so it divides nothing in a ratio.
Q87. If $D$ and $E$ are the midpoints of $AB$ and $AC$, then $DE$ is parallel to BC because
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both ratios are 1 : 1, so the converse of the BPT applies
Equal ratios of 1 : 1 satisfy the converse's condition.
Q88. The BPT holds
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whichever of the two sides you start from, if you stay consistent
The theorem is symmetric in the two sides it cuts.
Q89. Assertion (A): $\frac{AD}{DB} = \frac{AE}{AC}$ follows from $DE \parallel BC$. Reason (R): The BPT may be written either as part : part or as part : whole.
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A is false but R is true
R is true, but A mixes the two forms — a part over a part equated to a part over a whole — so A is false.
Q90. Assertion (A): The converse of the BPT can be used to prove two lines parallel. Reason (R): If a line cuts two sides of a triangle in unequal proportion, it runs parallel to the remaining side.
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A is true but R is false
The converse needs the proportions to be equal, not unequal. The assertion stands, the reason is false.
Q91. In $\triangle ABC$, $AD = 4$, $AB = 12$, $AE = 5$ and $AC = 15$. Then DE is
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parallel to BC
$\frac4{12} = \frac13$ and $\frac5{15} = \frac13$, so the converse applies.
Q92. If $\frac{AD}{DB} = \frac{5}{3}$ and $DE \parallel BC$, then $\frac{DB}{AB}$ is
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$\frac38$
AD and DB are 5 and 3 parts, so AB is 8 parts.
Q93. A line cuts AB at D with $AD : DB = 3 : 7$, and cuts AC at E with $AE : EC = 3 : 7$. This line is
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parallel to BC, by the converse of the BPT
The two ratios match, which is the converse's exact condition.
Q94. Assertion (A): A line through the midpoints of a triangle's two sides runs parallel to its third side. Reason (R): Both ratios are then 1 : 1, so the converse of the BPT applies.
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Both A and R are true, and R is the correct explanation of A
Equal ratios of 1 : 1 satisfy the converse, which is precisely R's reasoning.
Q95. In $\triangle ABC$, $DE \parallel BC$ with $AD = 4$ cm, $DB = 6$ cm and $AE = 6$ cm. Find EC.
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Q96. In $\triangle ABC$, $D$ is on $AB$ and $E$ on $AC$ with $AD = 3$ cm, $DB = 5$ cm, $AE = 6$ cm and $EC = 10$ cm. Is $DE \parallel BC$?
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Q97. In $\triangle ABC$, $AD = 2$ cm, $DB = 3$ cm, $AE = 4$ cm and $EC = 5$ cm. Determine whether $DE \parallel BC$.
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Q98. In $\triangle ABC$, $DE \parallel BC$ with $AD = 4$ cm, $AB = 10$ cm and $AE = 6$ cm. Find AC.
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Q99. Explain why $\frac{AD}{DB} = \frac{AE}{AC}$ is an incorrect statement of the BPT.
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Q100. In $\triangle ABC$, D and E are the midpoints of AB and AC. Show that $DE \parallel BC$.
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Q101. Triangles with sides $3, 4, 5$ and $6, 8, 11$ are
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not similar — the third ratio differs
$\frac36 = \frac48 = \frac12$ but $\frac5{11} \ne \frac12$.
Q102. In $\triangle ABC$ and $\triangle PQR$, $\angle A = \angle P$, $AB = 4$, $AC = 6$, $PQ = 6$ and $PR = 9$. The triangles are
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similar by SAS
$\frac46 = \frac69 = \frac23$ and $\angle A$ is included between AB and AC.
Q103. In two triangles, $\angle B = \angle Q$ and $\frac{AB}{PQ} = \frac{AC}{PR}$. Does SAS apply?
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no — the equal angle is not the included one
$\angle B$ does not lie between AB and AC, so the 'including' condition fails.
Q104. $\triangle ABC \sim \triangle PQR$ with $AB = 6$, $BC = 9$ and $PQ = 4$. Then QR is
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6
$\frac64 = \frac9{QR}$ gives $6 \cdot QR = 36$.
Q105. If $\angle A = \angle Q$, $\angle B = \angle R$ and $\angle C = \angle P$, the correct statement is
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$\triangle ABC \sim \triangle QRP$
The letters must follow the matching, not the alphabet.
Q106. Which criterion applies when three pairs of sides are proportional?
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SSS
No angle information is needed.
Q107. Which criterion applies when two pairs of angles are equal?
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AA
No side information is needed.
Q108. A tree and its shadow, and a stick and its shadow, form similar triangles by
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AA, since the sun's rays make equal angles
Both have a right angle at the ground and the same angle of elevation.
Q109. Two isosceles triangles with equal vertical angles are
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similar
The base angles are each $\frac{180° - \text{vertical angle}}{2}$, so two angle pairs match and AA applies.
Q110. The similarity criteria differ from the congruence criteria in that
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sides must be proportional rather than equal
The letters are the same; the side condition is relaxed.
Q111. Two triangles have $\frac{AB}{PQ} = \frac{BC}{QR} = \frac{2}{3}$ but nothing is known about CA and RP. The triangles are
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not yet shown to be similar
SSS needs all three ratios, and no included angle has been given for SAS.
Q112. Assertion (A): Two triangles with one equal angle and two proportional sides must be similar. Reason (R): The SAS criterion requires the equal angle to be included between the proportional sides.
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A is false but R is true
A is false because the angle may not be the included one, and R names exactly that missing condition.
Q113. Assertion (A): All equilateral triangles are similar to one another. Reason (R): An equilateral triangle has three equal sides.
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Both A and R are true, but R is not the correct explanation of A
Both are true, but equal sides within one triangle are not what makes two different equilateral triangles similar; their equal angles are.
Q114. $\triangle ABC \sim \triangle XYZ$ with $AB = 10$, $XY = 4$ and $CA = 15$. Then ZX is
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6
The scale factor is $\frac{4}{10} = \frac25$, so $ZX = 15 \times \frac25 = 6$.
Q115. Triangles with sides $6, 8, 10$ and $9, 12, 14$ are
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not similar — the third ratio differs
$\frac69 = \frac8{12} = \frac23$ but $\frac{10}{14} = \frac57$.
Q116. Two triangles are similar with a scale factor of 3. The ratio of their perimeters is
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3 : 1
A perimeter is a sum of sides, so it scales by the same factor.
Q117. State the SAS similarity criterion, and explain the importance of the word 'including'.
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Q118. Determine whether triangles with sides 3, 4, 5 cm and 6, 8, 11 cm are similar.
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Q119. In $\triangle ABC$ and $\triangle PQR$, $\angle A = \angle P$, $AB = 4$ cm, $AC = 6$ cm, $PQ = 6$ cm and $PR = 9$ cm. Prove that the triangles are similar.
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Q120. $\triangle ABC \sim \triangle PQR$ with $AB = 6$ cm, $BC = 9$ cm and $PQ = 4$ cm. Find QR.
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Q121. In $\triangle ABC$, $DE \parallel BC$ with D on AB and E on AC. Prove that $\triangle ADE \sim \triangle ABC$.
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Topper level · 50 questions
Q122. $\triangle ABC \sim \triangle DEF$ with $AB = 4$, $DE = 6$ and the perimeter of $\triangle ABC$ equal to 18. The perimeter of $\triangle DEF$ is
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27
Every side scales by $\frac64 = \frac32$, so the perimeter does too: $18 \times \frac32 = 27$.
Q123. Two similar triangles have sides in the ratio 2 : 5. The ratio of their perimeters is
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2 : 5
Perimeter is a sum of lengths, so it scales by the same factor as the sides.
Q124. A photograph 6 cm by 8 cm is enlarged so that its shorter side becomes 15 cm. Its longer side becomes
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20 cm
The scale factor is $\frac{15}{6} = \frac52$, so $8 \times \frac52 = 20$.
Q125. $ABCD \sim PQRS$ with $AB = 8$, $PQ = 12$ and $RS = 9$. Then $CD$ is
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6
$\frac{AB}{PQ} = \frac{CD}{RS}$ gives $\frac{8}{12} = \frac{CD}{9}$, so $CD = 6$.
Q126. Which condition makes two polygons similar all on its own?
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neither condition alone is enough
The square-and-rectangle and square-and-rhombus examples rule out each in turn.
Q127. A model of a tower is built to a scale of 1 : 200. If the model is 8 cm tall, the tower is
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16 m
$8 \times 200 = 1600$ cm, which is 16 m.
Q128. If $\triangle ABC \sim \triangle PQR$ and $\triangle PQR \sim \triangle XYZ$, then $\triangle ABC$ and $\triangle XYZ$ are
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similar
Equal angles and constant ratios carry through, so similarity is transitive.
Q129. Two similar figures have a scale factor of $\frac{3}{4}$. A side of 20 in the first corresponds to
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$\frac{80}{3}$ in the second
If first : second is $3 : 4$ then $\frac{20}{x} = \frac34$, so $x = \frac{80}{3}$.
Q130. Assertion (A): Congruent figures and similar figures are two entirely separate ideas with nothing in common. Reason (R): Congruence is similarity in which the scale factor equals 1.
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A is false but R is true
Congruence is the special case of similarity with scale factor 1, so the assertion is false. The reason says exactly that.
Q131. The order of the letters in $\triangle ABC \sim \triangle PQR$ matters because
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it names which vertex corresponds to which
Reading the pairing from the letters prevents the commonest error in the chapter.
Q132. Assertion (A): Two figures that are similar to the same third figure are similar to each other. Reason (R): Equal angles and constant side ratios carry through from one similarity to the next.
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Both A and R are true, and R is the correct explanation of A
Similarity is transitive, and R gives the reason.
Q133. A photograph measuring 6 cm by 8 cm is enlarged so that its shorter side becomes 15 cm. Find its new longer side.
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Q134. $\triangle ABC \sim \triangle DEF$ with $AB = 4$ cm and $DE = 6$ cm. If the perimeter of $\triangle ABC$ is 18 cm, find the perimeter of $\triangle DEF$.
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Q135. A model of a building is made to a scale of 1 : 200. The model is 8 cm tall. Find the height of the building in metres.
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Q136. $ABCD \sim PQRS$. The sides of $ABCD$ are $AB = 8$ cm, $BC = 12$ cm, $CD = 10$ cm and $DA = 6$ cm, and $PQ = 12$ cm. (a) Find the scale factor, stating which figure you are taking first. (b) Find $QR$, $RS$ and $SP$. (c) Find the perimeters of both quadrilaterals and the ratio between them, and comment on what you notice.
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1 mark — (a) the scale factor with its direction stated. 2 marks — (b) all three sides. 2 marks — (c) both perimeters, the ratio, and the reason it equals the scale factor.
Q137. A surveyor uses a scale drawing of a rectangular field. On the drawing the field measures 7 cm by 12 cm, and the drawing is made to a scale of 1 : 2500. (a) Explain why the drawing and the field are similar figures. (b) Find the actual dimensions of the field in metres. (c) The surveyor also draws a square plot of side 4 cm on the same drawing. Explain whether the square plot on the drawing is similar to the rectangular field on the drawing, justifying your answer.
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1½ marks — (a) both conditions identified in the scale drawing. 2 marks — (b) both dimensions in metres. 1½ marks — (c) the verdict with the failing condition and its numbers.
Q138. In $\triangle ABC$, $DE \parallel BC$ with $AD = x$, $DB = x - 2$, $AE = x + 2$ and $EC = x - 1$. The value of x is
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4
$\frac{x}{x-2} = \frac{x+2}{x-1}$ gives $x^2 - x = x^2 - 4$, so $x = 4$.
Q139. In $\triangle ABC$, $DE \parallel BC$ and $\frac{AD}{DB} = \frac{3}{4}$. Then $\frac{AD}{AB}$ is
AdvancedShow answer & explanation
$\frac37$
$AB = AD + DB$, so the parts are 3 and 4 out of a whole of 7.
Q140. If $DE \parallel BC$ and $\frac{AD}{AB} = \frac25$, then $\frac{AE}{EC}$ is
AdvancedShow answer & explanation
$\frac23$
$\frac{AD}{AB} = \frac25$ means the parts are 2 and 3, so the part : part ratio is $\frac23$.
Q141. The perpendiculars DM and EN drawn in the proof
AdvancedShow answer & explanation
cancel out and do not appear in the result
They exist only to give the triangles a height, and divide out of both ratios.
Q142. A line cuts $AB$ at $D$ and $AC$ at $E$ with $AD = 6$, $AB = 15$, $AE = 8$ and $AC = 20$. Then $DE$
AdvancedShow answer & explanation
is parallel to BC
$\frac{6}{15} = \frac25$ and $\frac{8}{20} = \frac25$, so by the converse it is parallel.
Q143. In $\triangle ABC$, $DE \parallel BC$ with $AD = 2.4$ cm, $AE = 3.2$ cm and $EC = 4.8$ cm. Then DB is
AdvancedShow answer & explanation
3.6 cm
$\frac{2.4}{DB} = \frac{3.2}{4.8} = \frac23$, so $2 \cdot DB = 7.2$.
Q144. Why can the BPT not be proved using similar triangles?
AdvancedShow answer & explanation
the similarity criteria are themselves proved from the BPT
Using them would make the reasoning circular.
Q145. Adding 1 to both sides of $\frac{AD}{DB} = \frac{AE}{EC}$ gives
AdvancedShow answer & explanation
$\frac{AB}{DB} = \frac{AC}{EC}$
$\frac{AD}{DB} + 1 = \frac{AD + DB}{DB} = \frac{AB}{DB}$, and similarly on the right.
Q146. Assertion (A): In the BPT proof, the step $ar(BDE) = ar(DEC)$ needs a stated reason. Reason (R): Triangles on the same base and between the same parallels are equal in area.
AdvancedShow answer & explanation
Both A and R are true, and R is the correct explanation of A
R is precisely the reason that must be written down, and omitting it loses the mark.
Q147. If $D$ and $E$ divide $AB$ and $AC$ in the ratio $k : 1$ for the same k, then DE is
AdvancedShow answer & explanation
parallel to BC for every value of k
Equal ratios satisfy the converse of the BPT whatever their common value.
Q148. In $\triangle ABC$, $DE \parallel BC$ and $\frac{AD}{DB} = \frac34$. Find $\frac{AD}{AB}$.
AdvancedShow answer & explanation
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Q149. In $\triangle ABC$, $DE \parallel BC$ with $AD = x$, $DB = x - 2$, $AE = x + 2$ and $EC = x - 1$. Find x.
AdvancedShow answer & explanation
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Q150. Why does the proof of the BPT not use similar triangles?
AdvancedShow answer & explanation
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Q151. Prove the Basic Proportionality Theorem: if a line runs parallel to one side of a triangle and meets the other two sides at two separate points, the other two sides are divided in the same ratio. Set out your answer under the headings Given, To prove, Construction and Proof.
AdvancedShow answer & explanation
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1 mark — Given and To prove correctly stated. 1 mark — the construction. 1½ marks — the two area ratios (1) and (2). 1 mark — the equal-area step WITH its reason. ½ mark — the conclusion.
Q152. (a) State the converse of the Basic Proportionality Theorem. (b) In $\triangle ABC$, $D$ lies on $AB$ and $E$ on $AC$ with $AD = 6$ cm, $AB = 15$ cm, $AE = 8$ cm and $AC = 20$ cm. Determine whether $DE \parallel BC$. (c) In the same triangle, a point $F$ on $AC$ has $AF = 9$ cm. Determine whether $DF \parallel BC$, and explain the difference.
AdvancedShow answer & explanation
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1 mark — (a) the converse stated. 2 marks — (b) both ratios and the conclusion, naming the theorem. 2 marks — (c) the unequal ratios, the verdict and the explanation.
Q153. (a) Write the Basic Proportionality Theorem in both its part : part and part : whole forms. (b) Show how the second follows from the first. (c) In $\triangle ABC$ with $DE \parallel BC$, $\frac{AD}{DB} = \frac{2}{5}$. Find $\frac{AD}{AB}$ and $\frac{EC}{AC}$.
AdvancedShow answer & explanation
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1 mark — (a) both forms. 2 marks — (b) the 'add 1' derivation. 2 marks — (c) both fractions.
Q154. A surveyor needs the width of a river. She marks a point $A$ on one bank, and points $B$ and $C$ on the far bank so that $BC$ is the width to be found. She then marks $D$ on $AB$ and $E$ on $AC$ with $DE \parallel BC$, and measures $AD = 12$ m, $DB = 18$ m and $DE = 20$ m. (a) Explain which theorem lets her use these measurements. (b) Find $\frac{AD}{AB}$. (c) Given that $\frac{DE}{BC} = \frac{AD}{AB}$ for parallel lines, find the width $BC$.
AdvancedShow answer & explanation
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1 mark — (a) naming the BPT and why it applies. 1½ marks — (b) AB and the ratio. 2½ marks — (c) the equation and BC = 50 m.
Q155. $\triangle ABC \sim \triangle DEF$ with $AB = 5$, $BC = 8$, $CA = 10$ and $DE = 7.5$. Then EF is
AdvancedShow answer & explanation
12
The scale factor is $\frac{7.5}{5} = \frac32$, so $EF = 8 \times \frac32 = 12$.
Q156. In $\triangle ABC$, $DE \parallel BC$. Then $\triangle ADE$ and $\triangle ABC$ are similar by
AdvancedShow answer & explanation
AA, since the parallel gives equal corresponding angles
$\angle ADE = \angle ABC$ and $\angle A$ is common, so two angle pairs match.
Q157. A vertical stick 1 m long casts a shadow 0.8 m long while a tower casts a shadow 24 m long. The tower's height is
AdvancedShow answer & explanation
30 m
By AA, $\frac{h}{24} = \frac{1}{0.8}$, so $h = 30$ m.
Q158. Two triangles have sides $2, 3, 4$ and $4, 6, 8$. They are similar with scale factor
AdvancedShow answer & explanation
$\frac12$
Every ratio of the first to the second is $\frac12$.
Q159. If $\triangle ABC \sim \triangle PQR$ and their perimeters are 24 and 36, the ratio of $AB$ to $PQ$ is
AdvancedShow answer & explanation
$\frac23$
Perimeters scale exactly like the sides, so the ratio is $\frac{24}{36} = \frac23$.
Q160. In a right triangle, if the hypotenuse and one side are proportional to those of another right triangle, the triangles are similar by
AdvancedShow answer & explanation
the RHS similarity criterion
The textbook notes this criterion for right triangles.
Q161. Which is NOT sufficient to prove two triangles similar?
AdvancedShow answer & explanation
one pair of equal angles alone
A single angle pair leaves the shape completely undetermined.
Q162. $\triangle ABC \sim \triangle PQR$ with a scale factor of 1. The triangles are
AdvancedShow answer & explanation
congruent
Every side equals its match, which is congruence.
Q163. Assertion (A): The similarity criteria cannot be proved using similar triangles. Reason (R): They are themselves proved from the Basic Proportionality Theorem.
AdvancedShow answer & explanation
Both A and R are true, and R is the correct explanation of A
Proving them by similarity would be circular, and R names what they actually rest on.
Q164. Two triangles have $\angle A = \angle D = 90°$ and $\angle B = \angle E$. They are similar by
AdvancedShow answer & explanation
AA
Two pairs of equal angles are given, and no side information is needed.
Q165. A vertical stick 1 m long casts a shadow 0.8 m long. At the same time a tower casts a shadow 24 m long. Find the height of the tower.
AdvancedShow answer & explanation
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Q166. If $\angle A = \angle Q$, $\angle B = \angle R$ and $\angle C = \angle P$, write the correct similarity statement and explain why the order matters.
AdvancedShow answer & explanation
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Q167. Explain why triangles need only one of the two similarity conditions, while polygons in general need both.
AdvancedShow answer & explanation
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Q168. (a) State the AA, SSS and SAS similarity criteria for triangles. (b) For each of the following, say which criterion applies, or that none does: (i) $\angle A = \angle P$, $\angle B = \angle Q$; (ii) sides 4, 6, 8 and 6, 9, 12; (iii) $\angle B = \angle Q$ with $\frac{AB}{PQ} = \frac{AC}{PR}$. (c) Explain your answer to (iii) in particular.
AdvancedShow answer & explanation
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1½ marks — (a) all three criteria. 1½ marks — (b) the three verdicts. 2 marks — (c) identifying that $\angle B$ is not included between AB and AC.
Q169. In $\triangle ABC$, a line $DE$ is drawn with D on AB and E on AC such that $DE \parallel BC$. (a) Prove that $\triangle ADE \sim \triangle ABC$, naming the criterion used. (b) Given $AD = 3$ cm, $DB = 5$ cm and $BC = 12$ cm, find DE. (c) State the relationship between $\frac{DE}{BC}$ and $\frac{AD}{AB}$, and explain why it holds.
AdvancedShow answer & explanation
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2 marks — (a) the equal angles with reasons and the criterion named. 2 marks — (b) AB, the ratio and DE = 4.5 cm. 1 mark — (c) the equality with its reason.
Q170. (a) Explain why the AAA criterion and the AA criterion amount to the same thing. (b) Two isosceles triangles have equal vertical angles. Prove that they are similar. (c) Two isosceles triangles have equal base angles. Are they necessarily similar? Justify.
AdvancedShow answer & explanation
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1½ marks — (a) the angle-sum argument. 2 marks — (b) the base-angle expression and the AA conclusion. 1½ marks — (c) the verdict with the vertical-angle argument.
Q171. Ravi wants to find the height of a lamp post. He stands a metre rule vertically in the ground and measures its shadow as 0.4 m. At the same moment the lamp post's shadow is 3.2 m long. (a) Explain why the two triangles formed are similar, naming the criterion. (b) Find the height of the lamp post. (c) Ravi's friend suggests measuring the shadows at different times of day. Explain why that would make the method fail.
AdvancedShow answer & explanation
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1½ marks — (a) both angle pairs and the criterion. 2 marks — (b) the equation and h = 8 m. 1½ marks — (c) the changing angle of elevation and its effect.
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